Pangram checker
You are encouraged to solve this task according to the task description, using any language you may know.
Write a function or method to check a sentence to see if it is a pangram or not and show its use.
A pangram is a sentence that contains all the letters of the English alphabet at least once, for example: The quick brown fox jumps over the lazy dog.
E
<lang e>def isPangram(sentence :String) {
return ("abcdefghijklmnopqrstuvwxyz".asSet() &! sentence.toLowerCase().asSet()).size() == 0
}</lang>
&!
is the “but-not” or set difference operator.
Factor
<lang factor>: pangram? ( str -- ? )
[ "abcdefghijklmnopqrstuvwxyz" ] dip >lower diff length 0 = ;
"How razorback-jumping frogs can level six piqued gymnasts!" pangram? .</lang>
Haskell
<lang haskell>import Data.Char (toLower) import Data.List ((\\))
pangram :: String -> Bool pangram = null . (['a' .. 'z'] \\) . map toLower
main = print $ pangram "How razorback-jumping frogs can level six piqued gymnasts!"</lang>
J
Solution: <lang j>require 'strings' isPangram=: (a. {~ 97+i.26) */@e. tolower</lang>
Example use: <lang j> isPangram 'The quick brown fox jumps over the lazy dog.' 1
isPangram 'The quick brown fox falls over the lazy dog.'
0</lang>
Java
<lang java>public class Pangram {
public static boolean isPangram(String test){ boolean pangram = true; String lcTest = test.toLowerCase(); for(char a = 'a'; a <= 'z'; a++){ pangram &= lcTest.contains("" + a); } return pangram; }
public static void main(String[] args){ System.out.println(isPangram("the quick brown fox jumps over the lazy dog"));//true System.out.println(isPangram("the quick brown fox jumped over the lazy dog"));//false, no s System.out.println(isPangram("ABCDEFGHIJKLMNOPQRSTUVWXYZ"));//true System.out.println(isPangram("ABCDEFGHIJKLMNOPQSTUVWXYZ"));//false, no r System.out.println(isPangram("ABCDEFGHIJKL.NOPQRSTUVWXYZ"));//false, no m System.out.println(isPangram("ABC.D.E.FGHI*J/KL-M+NO*PQ R\nSTUVWXYZ"));//true System.out.println(isPangram(""));//false }
}</lang> Output:
true false true false false true false
JavaScript
<lang javascript>function is_pangram(str) {
var s = str.toLowerCase(); for (var a = 97; a <= 122; a++) if (s.indexOf(String.fromCharCode(a)) == -1) return false; return true;
}
is_pangram("is this a pangram"); // false is_pangram("The quick brown fox jumps over the lazy dog"); // true</lang>
OCaml
<lang ocaml>let pangram str =
let ar = Array.make 26 false in String.iter (function | 'a'..'z' as c -> ar.(Char.code c - Char.code 'a') <- true | _ -> () ) (String.lowercase str); Array.fold_left ( && ) true ar</lang>
<lang ocaml>let check str =
Printf.printf " %b -- %s\n" (pangram str) str
let () =
check "this is a sentence"; check "The quick brown fox jumps over the lazy dog.";
- </lang>
outputs:
false -- this is a sentence true -- The quick brown fox jumps over the lazy dog.
Oz
<lang oz>declare
fun {IsPangram Xs} {List.sub {List.number &a &z 1} {Sort {Map Xs Char.toLower} Value.'<'}} end
in
{Show {IsPangram "The quick brown fox jumps over the lazy dog."}}</lang>
Perl
<lang perl>use List::MoreUtils 'all';
sub pangram {all {$_[0] =~ /$_/i} 'a' .. 'z';}
print "Yes.\n" if pangram 'Cozy lummox gives smart squid who asks for job pen.';</lang>
Python
Using set arithmetic: <lang python>import string, sys if sys.version_info[0] < 3:
input = raw_input
def ispangram(sentence, alphabet=string.ascii_lowercase):
alphaset = set(alphabet) return not alphaset - set(sentence.lower())
print ( ispangram(input('Sentence: ')) )</lang>
Sample output:
Sentence: The quick brown fox jumps over the lazy dog True
Ruby
<lang ruby>def pangram?(sentence)
unused_letters = ('a'..'z').to_a - str.downcase.chars.to_a unused_letters.empty?
end
p pangram?('this is a sentence') # ==> false p pangram?('The quick brown fox jumps over the lazy dog.') # ==> true</lang>
Tcl
<lang tcl>proc pangram? {sentence} {
set letters [regexp -all -inline {[a-z]} [string tolower $sentence]] expr { [llength [lsort -unique $letters]] == 26 }
}
puts [pangram? "This is a sentence"]; # ==> false puts [pangram? "The quick brown fox jumps over the lazy dog."]; # ==> true</lang>