Odd word problem

From Rosetta Code
Revision as of 16:34, 22 July 2020 by rosettacode>Davbol (→‎{{header|Lua}}: added Lua solution)
Task
Odd word problem
You are encouraged to solve this task according to the task description, using any language you may know.
Task

Write a program that solves the odd word problem with the restrictions given below.


Description

You are promised an input stream consisting of English letters and punctuations.

It is guaranteed that:

  • the words (sequence of consecutive letters) are delimited by one and only one punctuation,
  • the stream will begin with a word,
  • the words will be at least one letter long,   and
  • a full stop (a period, [.]) appears after, and only after, the last word.


Example

A stream with six words:

what,is,the;meaning,of:life.


The task is to reverse the letters in every other word while leaving punctuations intact, producing:

what,si,the;gninaem,of:efil.

while observing the following restrictions:

  1. Only I/O allowed is reading or writing one character at a time, which means: no reading in a string, no peeking ahead, no pushing characters back into the stream, and no storing characters in a global variable for later use;
  2. You are not to explicitly save characters in a collection data structure, such as arrays, strings, hash tables, etc, for later reversal;
  3. You are allowed to use recursions, closures, continuations, threads, co-routines, etc., even if their use implies the storage of multiple characters.


Test cases

Work on both the   "life"   example given above, and also the text:

we,are;not,in,kansas;any,more.



Ada

This is a rather straightforward approach, using recursion.

<lang Ada>with Ada.Text_IO;

procedure Odd_Word_Problem is

  use Ada.Text_IO; -- Get, Put, and Look_Ahead

  function Current return Character is
     -- reads the current input character, without consuming it
     End_Of_Line: Boolean;
     C: Character;
  begin
     Look_Ahead(C, End_Of_Line);
     if End_Of_Line then
        raise Constraint_Error with "end of line before the terminating '.'";
     end if;
     return C;
  end Current;

  procedure Skip is
     -- consumes the current input character
     C: Character;
  begin
     Get(C);
  end Skip;

  function Is_Alpha(Ch: Character) return Boolean is
  begin
     return (Ch in  'a' .. 'z') or (Ch in 'A' .. 'Z');
  end Is_Alpha;

  procedure Odd_Word(C: Character) is
  begin
     if Is_Alpha(C) then
        Skip;
        Odd_Word(Current);
        Put(C);
     end if;
  end Odd_Word;

begin -- Odd_Word_Problem

  Put(Current);
  while Is_Alpha(Current) loop -- read an even word
     Skip;
     Put(Current);
  end loop;
  if Current /= '.' then -- read an odd word
     Skip;
     Odd_Word(Current);
     Put(Current);
     if Current /= '.' then -- read the remaining words
        Skip;
        Odd_Word_Problem;
     end if;
  end if;

end Odd_Word_Problem;</lang>

Output:

> ./odd_word_problem 
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.
> ./odd_word_problem 
we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.

ALGOL 68

Works with: ALGOL 68G version Any - tested with release 2.8.win32

The words and punctuation should be on a single line. Uses recursion. <lang algol68># recursively reverses the current word in the input and returns the #

  1. the character that followed it #
  2. "ch" should contain the first letter of the word on entry and will be #
  3. updated to the punctuation following the word on exit #

PROC reverse word = ( REF CHAR ch )VOID: BEGIN

   CHAR    next ch;
   read( ( next ch ) );
   IF ( next ch <= "Z" AND next ch >= "A" )
   OR ( next ch <= "z" AND next ch >= "a" )
   THEN
       reverse word( next ch )
   FI;
   print( ( ch ) );
   ch := next ch

END; # reverse word #


  1. recursively prints the current word in the input and returns the #
  2. character that followed it #
  3. "ch" should contain the first letter of the word on entry and will be #
  4. updated to the punctuation following the word on exit #

PROC normal word = ( REF CHAR ch )VOID: BEGIN

   print( ( ch ) );
   read ( ( ch ) );
   IF ( ch <= "Z" AND ch >= "A" )
   OR ( ch <= "z" AND ch >= "a" )
   THEN
       normal word( ch )
   FI

END; # normal word #


  1. read and print words and punctuation from the input stream, reversing #
  2. every second word #

PROC reverse every other word = VOID: BEGIN

   CHAR ch;
   read( ( ch ) );
   WHILE
       ch /= "."
   DO
       normal word( ch );
       IF ch /= "."
       THEN
           print( ( ch ) );
           read ( ( ch ) );
           reverse word( ch )
       FI
   OD;
   print( ( ch ) )

END; # reverse every other word #


main: (

   reverse every other word

)</lang>

Output:
what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

AutoHotkey

<lang AutoHotkey>str := "what,is,the;meaning,of:life." loop, parse, str if (A_LoopField ~= "punct:") res .= A_LoopField, toggle:=!toggle else res := toggle ? RegExReplace(res, ".*punct:\K", A_LoopField ) : res A_LoopField MsgBox % res</lang>

Outputs:

what,si,the;gninaem,of:efil.

BaCon

<lang qbasic>OPEN "/dev/stdin" FOR DEVICE AS in

FUNCTION get_odd()

   LOCAL ch, letter
   ch = MEMORY(1)
   GETBYTE ch FROM in
   IF NOT(REGEX(CHR$(PEEK(ch)), "punct:")) THEN
       letter = get_odd()
       PRINT CHR$(PEEK(ch));
   ELSE
       letter = PEEK(ch)
   END IF
   FREE ch
   RETURN letter

END FUNCTION

mem = MEMORY(1) PRINT "Enter string: ";

WHILE TRUE

   GETBYTE mem FROM in
   PRINT CHR$(PEEK(mem));
   IF REGEX(CHR$(PEEK(mem)), "punct:") THEN
       IF PEEK(mem) <> 46 THEN
           POKE mem, get_odd()
           PRINT CHR$(PEEK(mem));
       END IF
       IF PEEK(mem) = 46 THEN BREAK
   END IF

WEND

FREE mem CLOSE DEVICE in

PRINT</lang> This program uses recursion.

Output:
user@host $ bacon odd_word
Converting 'odd_word.bac'... done, 46 lines were processed in 0.003 seconds.
Compiling 'odd_word.bac'... cc  -c odd_word.bac.c
cc -o odd_word odd_word.bac.o -lbacon -lm 
Done, program 'odd_word' ready.
user@host $ ./odd_word 
Enter string: what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.
user@host $ ./odd_word 
Enter string: we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.

Bracmat

<lang bracmat>( ( odd-word

 =   dothis doother forward backward
   .   ( forward
       =   ch
         .   fil$:?ch
           & put$!ch
           & ( low$!ch:~<a:~>z&forward$
             | !ch:~"."
             )
       )
     & ( backward
       =   ch
         .   fil$:?ch
           & (   low$!ch:~<a:~>z
               & backward$() (put$!ch&)    { This reduces to the return value of backwards$()}
             | '(.put$($ch)&$ch:~".")      { Macro, evaluates to a function with actual ch.  }
             )
       )
     & fil$(!arg,r)
     &   ((=forward$).(=(backward$)$))
       : (?dothis.?doother)
     &   whl
       ' ( !(dothis.)
         & (!doother.!dothis):(?dothis.?doother)
         )
     & (fil$(,SET,-1)|)                 { This is how a file is closed: seek the impossible. }
 )

& put$("what,is,the;meaning,of:life.","life.txt",NEW) & put$("we,are;not,in,kansas;any,more.","kansas.txt",NEW) & odd-word$"life.txt" & put$\n & odd-word$"kansas.txt" { Real file, as Bracmat cannot read a single character from stdin. } );</lang> Output:

what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

C

Using GCC nested function as closures. This can only be passed up the stack, not the other way around. It's also doable with makecontext, and may be possible with setjmp.

<lang c>#include <stdio.h>

  1. include <ctype.h>

int do_char(int odd, void (*f)(void)) { int c = getchar();

void write_out(void) { putchar(c); if (f) f(); }

if (!odd) putchar(c);

if (isalpha(c)) return do_char(odd, write_out);

if (odd) { if (f) f(); putchar(c); }

return c != '.'; }

int main() { int i = 1; while (do_char(i = !i, 0));

return 0; }</lang>

C++

Translation of: Python
Works with: C++11
Works with: gcc version 4.5

Tested with gcc 4.5, with "-std=c++0x" option.

<lang cpp>#include <iostream>

  1. include <cctype>
  2. include <functional>

using namespace std;

bool odd() {

 function<void ()> prev = []{};
 while(true) {
   int c = cin.get();
   if (!isalpha(c)) {
     prev();
     cout.put(c);
     return c != '.';
   }
   prev = [=] { cout.put(c); prev();  };
 }

}

bool even() {

 while(true) {
   int c;
   cout.put(c = cin.get());
   if (!isalpha(c)) return c != '.';
 }

}


int main() {

 bool e = false;
 while( e ? odd() : even() ) e = !e;
 return 0;

}</lang>

Ceylon

<lang ceylon> String[] meaning = ["what,", "is,", "the;", "meaning,", "of:", "life."]; String[] kansas = ["we,", "are,", "not,", "in,", "kansas;", "any,", "more."];

shared void run() {

   print("".join(reverseWords(meaning)));
   print("".join(reverseWords(kansas)));

}

String[] reverseWords(String[] words)

   => recursiveReverseWords(words, []);

String[] recursiveReverseWords(String[] remOrig, String[] revWords)

   => if (nonempty remOrig)
       then recursiveReverseWords(remOrig.rest,
                                  revWords.withTrailing(reverseWordRecursive(remOrig.first.sequence(),
                                                                             [],
                                                                             revWords.size.even)))
       else revWords;

String reverseWordRecursive(Character[] remOldChars, Character[] revChars, Boolean isEven)

   => if (nonempty remOldChars)
       then let (char = remOldChars.first) reverseWordRecursive(remOldChars.rest,
                                                                conditionalAddChar(char, revChars, isEven),
                                                                isEven)
       else String(revChars);

Character[] conditionalAddChar(Character char, Character[] chars, Boolean isEven)

   => if (isEven || isPunctuation(char))
       then chars.withTrailing(char)
       else chars.withLeading(char);

Boolean isPunctuation(Character char)

   => ",.:;".contains(char);

</lang>

Output:
what,si,the;gninaem,of:efil.
we,era,not,ni,kansas;yna,more.

Clojure

Translation of: Common Lisp

<lang Clojure>(defn next-char []

 (char (.read *in*)))

(defn forward []

 (let [ch (next-char)]
   (print ch)
   (if (Character/isLetter ch)
     (forward)
     (not= ch \.))))

(defn backward []

 (let [ch (next-char)]
   (if (Character/isLetter ch)
     (let [result (backward)]
       (print ch)
       result)
     (fn [] (print ch) (not= ch \.)))) )

(defn odd-word [s]

 (with-in-str s
   (loop [forward? true]
     (when (if forward?
             (forward)
             ((backward)))
       (recur (not forward?)))) )
   (println))</lang>

Examples:

<lang clojure>user=> (odd-word "what,is,the;meaning,of:life.") what,si,the;gninaem,of:efil. nil user=> (odd-word "we,are;not,in,kansas;any,more.") we,era;not,ni,kansas;yna,more. nil</lang>

CoffeeScript

<lang CoffeeScript>isWordChar = (c) -> /^\w/.test c isLastChar = (c) -> c is '.'

  1. Pass a function that returns an input character and one that outputs a
  2. character. JS platforms' ideas of single-character I/O vary widely, but this
  3. abstraction is adaptable to most or all.

oddWord = (get, put) -> forwardWord = -> loop # No magic here; buffer then immediately output. c = get() put(c) unless isWordChar(c) return not isLastChar(c)

# NB: (->) is a CoffeeScript idiom for no-op. reverseWord = (outputPending = (->)) -> c = get() if isWordChar(c) # Continue word. # Tell recursive call to output this character, then any previously # pending characters, after the next word character, if any, has # been output. reverseWord -> put(c) outputPending() else # Word is done. # Output previously pending characters, then this punctuation. outputPending() put(c) return not isLastChar(c)

# Alternate between forward and reverse until one or the other reports that # the end-of-input mark has been reached (causing a return of false). continue while forwardWord() and reverseWord()</lang>

Same without comments

<lang CoffeeScript>isWordChar = (c) -> /^\w/.test c isLastChar = (c) -> c is '.'

oddWord = (get, put) -> forwardWord = -> loop c = get() put(c) unless isWordChar(c) return not isLastChar(c)

reverseWord = (outputPending = (->)) -> c = get() if isWordChar(c) reverseWord -> put(c) outputPending() else outputPending() put(c) return not isLastChar(c)

continue while forwardWord() and reverseWord()</lang>

Testing code

<lang CoffeeScript># Redefine as necessary for target platform. println = (z) -> console.log z

testData = [ [ "what,is,the;meaning,of:life." "what,si,the;gninaem,of:efil." ] [ "we,are;not,in,kansas;any,more." "we,era;not,ni,kansas;yna,more." ] ]

results = for [testString, expectedResult] in testData # This test machinery uses string buffers for input and output. If your JS # platform sports single-character I/O, by all means, adapt to taste. getCursor = 0 putBuffer = "" get = -> testString.charAt getCursor++ put = (c) -> putBuffer += c oddWord(get,put) [testString, expectedResult, putBuffer, putBuffer is expectedResult]

println result for result in results</lang>

Output in node.js:

[ 'what,is,the;meaning,of:life.',
  'what,si,the;gninaem,of:efil.',
  'what,si,the;gninaem,of:efil.',
  true ]
[ 'we,are;not,in,kansas;any,more.',
  'we,era;not,ni,kansas;yna,more.',
  'we,era;not,ni,kansas;yna,more.',
  true ]

Common Lisp

Even words are straightforward. For odd words, the final punctuation is printed by a closure passed back up the caller chain. <lang lisp>(defun odd-word (s)

 (let ((stream (make-string-input-stream s)))
   (loop for forwardp = t then (not forwardp)
         while (if forwardp
                   (forward stream)
                   (funcall (backward stream)))) ))

(defun forward (stream)

 (let ((ch (read-char stream)))
   (write-char ch)
   (if (alpha-char-p ch)

(forward stream)

       (char/= ch #\.))))

(defun backward (stream)

 (let ((ch (read-char stream)))
   (if (alpha-char-p ch)
       (prog1 (backward stream) (write-char ch))
       #'(lambda () (write-char ch) (char/= ch #\.)))) )

</lang>

Examples:

<lang lisp>? (odd-word "what,is,the;meaning,of:life.") what,si,the;gninaem,of:efil. NIL ? (odd-word "we,are;not,in,kansas;any,more.") we,era;not,ni,kansas;yna,more. NIL</lang>

D

Translation of: C

<lang d>bool doChar(in bool odd, in void delegate() nothrow f=null) nothrow {

   import core.stdc.stdio, std.ascii;
   immutable int c = getchar;
   if (!odd)
       c.putchar;
   if (c.isAlpha)
       return doChar(odd, { c.putchar; if (f) f(); });
   if (odd) {
       if (f) f();
       c.putchar;
   }
   return c != '.';

}

void main() {

   bool i = true;
   while (doChar(i = !i)) {}

}</lang>

Output:
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.

EchoLisp

No character input stream in EchoLisp, which runs in a browser window. We simultate it with a character stream, with the only function read-char, as specified in the task. <lang scheme> (lib 'sequences) (define input-stream null) (define output-stream "")

---------------------------
character I/O simulation
--------------------------

(define (read-char) (next input-stream)) ;; #f if EOF (define (write-char c) (when c (set! output-stream (string-append output-stream c))))

(define (init-streams sentence) (set! input-stream (procrastinator sentence)) (set! output-stream ""))

---------------------------------
task , using read-char/write-char
----------------------------------

(define (flop) ; reverses, and returns first non-alpha after word, or EOF (define c (read-char)) (if (string-alphabetic? c) (begin0 (flop) (write-char c)) c))

(define (flip)

   (define c (read-char))
   (if (string-alphabetic? c) (begin (write-char c)  (flip)) c))
   

(define (task sentence) (init-streams sentence) (while (and (write-char (flip)) (write-char (flop)))) output-stream )


</lang>

Output:

<lang scheme> (task "what,is,the;meaning,of:life.")

   → "what,si,the;gninaem,of:efil."
check diacritical

(task "Longtemps,je me suis couché,héhé,hôhô,de bonne heure.")

   → "Longtemps,ej me sius couché,éhéh,hôhô,ed bonne erueh."

</lang>

Elixir

Translation of: Erlang

<lang elixir>defmodule Odd_word do

 def handle(s, false, i, o) when ((s >= "a" and s <= "z") or (s >= "A" and s <= "Z")) do
   o.(s)
   handle(i.(), false, i, o)
 end
 def handle(s, t, i, o) when ((s >= "a" and s <= "z") or (s >= "A" and s <= "Z")) do
   d = handle(i.(), :rec, i, o)
   o.(s)
   if t == true, do: handle(d, t, i, o), else: d
 end
 def handle(s, :rec, _, _), do: s
 def handle(?., _, _, o), do: o.(?.); :done 
 def handle(:eof, _, _, _), do: :done
 def handle(s, t, i, o) do
   o.(s)
   handle(i.(), not t, i, o)
 end
 
 def main do
   i = fn() -> IO.getn("") end
   o = fn(s) -> IO.write(s) end
   handle(i.(), false, i, o)
 end

end

Odd_word.main</lang>

Output:
C:\Elixir>elixir Odd_word.exs
we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.

Erlang

<lang erlang> handle(S, false, I, O) when (((S >= $a) and (S =< $z)) or ((S >= $A) and (S =< $Z))) ->

   O(S),
   handle(I(), false, I, O);

handle(S, T, I, O) when (((S >= $a) and (S =< $z)) or ((S >= $A) and (S =< $Z))) ->

   D = handle(I(), rec, I, O),
   O(S),
   case T of true -> handle(D, T, I, O); _ -> D end;

handle(S, rec, _, _) -> S; handle($., _, _, O) -> O($.), done; handle(eof, _, _, _) -> done; handle(S, T, I, O) -> O(S), handle(I(), not T, I, O).

main([]) ->

   I = fun() -> hd(io:get_chars([], 1)) end,
   O = fun(S) -> io:put_chars([S]) end,
   handle(I(), false, I, O).

</lang>

F#

A recursive solution.

<lang fsharp>open System open System.Text.RegularExpressions

let mutable Inp = Console.In

let Out c = printf "%c" c; (if c = '.' then Environment.Exit 0)

let In() = Inp.Read() |> Convert.ToChar

let (|WordCharacter|OtherCharacter|) c =

   if Regex.IsMatch(c.ToString(),"[a-zA-Z]") then
       WordCharacter
   else
       OtherCharacter

let rec forward () =

   let c = In()
   let rec backward () : char =
       let c = In()
       match c with
       | WordCharacter ->
           let s = backward() in Out c; s
       | OtherCharacter -> c
   Out c
   match c with
   | WordCharacter -> forward()
   | OtherCharacter -> backward() 

[<EntryPoint>] let main argv =

   if argv.Length > 0 then Inp <- new System.IO.StringReader(argv.[0])
   let rec loop () = forward() |> Out;  loop()
   loop()
   0</lang>
Output:
>echo we,are;not,in,kansas;any,more. | RosettaCode
we,era;not,ni,kansas;yna,more.
>echo what,is,the;meaning,of:life. | RosettaCode
what,si,the;gninaem,of:efil.

Factor

This is a delicate program with arcane control flow. To reverse each odd word, this code uses continuations to jump-back into earlier iterations of a while loop. This trick reverses the letters by reversing the loop!

This code is difficult to follow, because it twists its control flow like spaghetti. These continuations form a singly-linked list, where each continuation contains a letter and a previous continuation. The program effectively reverses this linked list.

<lang factor>USING: continuations kernel io io.streams.string locals unicode.categories ; IN: rosetta.odd-word

<PRIVATE ! Save current continuation.

savecc ( -- continuation/f )
   [ ] callcc1 ; inline

! Jump back to continuation, where savecc will return f.

jump-back ( continuation -- )
   f swap continue-with ; inline

PRIVATE>

read-odd-word ( -- )
   f :> first-continuation!
   f :> last-continuation!
   f :> reverse!
   ! Read characters. Loop until end of stream.
   [ read1 dup ] [
       dup Letter? [
           ! This character is a letter.
           reverse [
               ! Odd word: Write letters in reverse order.
               last-continuation savecc dup [
                   last-continuation!
                   2drop       ! Drop letter and previous continuation.
               ] [
                   ! After jump: print letters in reverse.
                   drop                ! Drop f.
                   swap write1         ! Write letter.
                   jump-back           ! Follow chain of continuations.
               ] if
           ] [
               ! Even word: Write letters immediately.
               write1
           ] if
       ] [
           ! This character is punctuation.
           reverse [
               ! End odd word. Fix trampoline, follow chain of continuations
               ! (to print letters in reverse), then bounce off trampoline.
               savecc dup [
                   first-continuation!
                   last-continuation jump-back
               ] [ drop ] if
               write1                  ! Write punctuation.
               f reverse!              ! Begin even word.
           ] [
               write1                  ! Write punctuation.
               t reverse!              ! Begin odd word.
               ! Create trampoline to bounce to (future) first-continuation.
               savecc dup [
                   last-continuation!
               ] [ drop first-continuation jump-back ] if
           ] if
       ] if
   ] while
   ! Drop f from read1. Then print a cosmetic newline.
   drop nl ;
odd-word ( string -- )
   [ read-odd-word ] with-string-reader ;</lang>
USE: rosetta.odd-word
( scratchpad ) "what,is,the;meaning,of:life." odd-word
what,si,the;gninaem,of:efil.
( scratchpad ) "we,are;not,in,kansas;any,more." odd-word
we,era;not,ni,kansas;yna,more.

FALSE

This solution uses recursion to read the backwards words, to output the characters after having done the rest of that word. <lang false>[$$$$'.=\',=|\';=|\':=|~[^s;!\,]?]s: {recursive reading} [s;!$'.=~[,^f;!]?]r: {reverse words} [[$$$$'.=\',=|\';=|\':=|~][,^]#$'.=~[,^r;!]?]f: {forward words} ^f;!, {start}</lang>

Forth

<lang forth>: word? dup [char] . <> over bl <> and ;

?quit dup [char] . = if emit quit then ;
eatbl begin dup bl = while drop key repeat ?quit ;
even begin word? while emit key repeat ;
odd word? if key recurse swap emit then ;
main cr key eatbl begin even eatbl space odd eatbl space again ;</lang>

Fortran

By not allowing the use of arrays of characters to facilitate the reversing of texts, the obvious solution involves recursion with storage via the stack so that its last-on, first-off style will achieve the required goal. But alas, Fortran compilers were typically written for computers that did not employ a stack mechanism so recursion was not expected even after the introduction of Algol in the 1960s, and the failure of recursively-invoked routines to return correctly became accepted. The standard murmur was that "Fortran is not a recursive language" even though the language contains recursive definitions such as for arithmetic expressions. By contrast, the B6700 system did employ a hardware stack, and, without any fuss, recursion just worked.

But with F90, the language definition was augmented by the menacing word RECURSIVE, and so... <lang Fortran> MODULE ELUDOM !Uses the call stack for auxiliary storage.

      INTEGER MSG,INF	!I/O unit numbers.
      LOGICAL DEFER	!To stumble, or not to stumble.
      CONTAINS
       CHARACTER*1 RECURSIVE FUNCTION GET(IN)	!Returns one character, going forwards.
        INTEGER IN	!The input file.
        CHARACTER*1 C	!The single character to be read therefrom.
         READ (IN,1,ADVANCE="NO",EOR=3,END=4) C	!Thus. Not advancing to the next record.
   1     FORMAT (A1,$)	!For output, no advance to the next line either.
   2     IF (("A"<=C .AND. C<="Z").OR.("a"<=C .AND. C<="z")) THEN	!Unsafe for EBCDIC.
           IF (DEFER) THEN	!Are we to reverse the current text?
             GET = GET(IN)	!Yes. Go for the next letter.
             WRITE (MSG,1) C	!And now, backing out, reveal the letter at this level.
             RETURN		!Retreat another level.
           END IF		!Thus passing back the ending non-letter that was encountered.
          ELSE		!And if we've encountered a non-letter,
           DEFER = .NOT. DEFER	!Then our backwardness flips.
         END IF	!Enough inspection of C.
   3     GET = C	!Pass it back.
         RETURN	!And we're done.
   4     GET = CHAR(0)	!Reserving this for end-of-file.
       END FUNCTION GET!That was strange.
     END MODULE ELUDOM	!But as per the specification.
     PROGRAM CONFUSED	!Just so.
     USE ELUDOM	!Forwards? Backwards?
     CHARACTER*1 C	!A scratchpad for multiple inspections.
     MSG = 6	!Standard output.
     INF = 10	!This will do.
     OPEN (INF,NAME = "Confused.txt",STATUS="OLD",ACTION="READ")	!Go for the file.

Chew through the input. A full stop marks the end.

  10 DEFER = .FALSE.	!Start off going forwards.
  11 C = GET(INF)		!Get some character from file INF.
     IF (ICHAR(C).LE.0) STOP		!Perhaps end-of-file is reported.
     IF (C.NE." ") WRITE (MSG,12) C	!Otherwise, write it. A blank for end-of-record.
  12 FORMAT (A1,$)			!Obviously, not finishing the line each time.
     IF (C.NE.".") GO TO 11	!And if not a full stop, do it again.
     WRITE (MSG,"()")	!End the line of output.
     GO TO 10		!And have another go.
     END	!That was confusing.</lang>

With file Confused.txt containing the obvious input, the output is

what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.
hot,star.

The basic ploy is that the function returns the next character from the input, but, should DEFER be true, it secretly invokes itself until a non-letter is found then returns (bearing that non-letter as its result) and on the way back out, secretly writes the letter previously read. Each level of recursion has its own version of that letter and by revealing them as the returns proceed, they are written in reverse order of input. Seen from the outside of GET, the value of DEFER is always true but this variable is static with regard to the invocations of GET, it being defined outside GET. If it were defined within there would be a new instance allocated with each level of recursion (as with variable C), which is not what is wanted.

Testing showed that the F90 feature of ADVANCE="NO" was required for the READ action because the $ format code that works for output does not work for input. Should an end-of-record interfere with the READ, the EOR=label is taken, and the character read will be a space. To avoid ugly system messages on running into end-of-file, character zero is reserved, just as a space is reserved for end-of-record encounters and skipped for output. Fortunately, the specification does not include spaces as allowed input. No checks are made as to whether the input conforms to the given specifications.

If the ADVANCE feature is unavailable, then the file could be read as UNFORMATTED, one character at a go with a record length of one. And then would arise the annoyance of dealing with the ASCII world's usage of CR, CRLF, LFCR, or CR as markers for the ends of records.

Go

<lang go>package main

import (

   "bytes"
   "fmt"
   "io"
   "os"
   "unicode"

)

func main() {

   owp(os.Stdout, bytes.NewBufferString("what,is,the;meaning,of:life."))
   fmt.Println()
   owp(os.Stdout, bytes.NewBufferString("we,are;not,in,kansas;any,more."))
   fmt.Println()

}

func owp(dst io.Writer, src io.Reader) {

   byte_in := func () byte {
       bs := make([]byte, 1)
       src.Read(bs)
       return bs[0]
   }
   byte_out := func (b byte) { dst.Write([]byte{b}) }    
   var odd func() byte
   odd = func() byte {
       s := byte_in()
       if unicode.IsPunct(rune(s)) {
           return s
       }
       b := odd()
       byte_out(s)
       return b
   }
   for {
       for {
           b := byte_in()
           byte_out(b)
           if b == '.' {
               return
           }
           if unicode.IsPunct(rune(b)) {
               break
           }
       }
       b := odd()
       byte_out(b)
       if b == '.' {
           return
       }
   }

}</lang> Output:

what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

Using defer

<lang go>package main

import (

   "bytes"
   "fmt"
   "io"
   "os"
   "unicode"

)

func main() {

   owp(os.Stdout, bytes.NewBufferString("what,is,the;meaning,of:life."))
   fmt.Println()
   owp(os.Stdout, bytes.NewBufferString("we,are;not,in,kansas;any,more."))
   fmt.Println()

}

func owp(dst io.Writer, src io.Reader) {

   byte_in := func () byte {
       bs := make([]byte, 1)
       src.Read(bs)
       return bs[0]
   }
   byte_out := func (b byte) { dst.Write([]byte{b}) }    
   odd := func() byte {
       for {
           b := byte_in()
           if unicode.IsPunct(int(b)) {
               return b
           }
           defer byte_out(b)
       }
       panic("impossible")
   }
   for {
       for {
           b := byte_in()
           byte_out(b)
           if b == '.' {
               return
           }
           if unicode.IsPunct(rune(b)) {
               break
           }
       }
       b := odd()
       byte_out(b)
       if b == '.' {
           return
       }
   }

}</lang>

Using channels and goroutines

Translation of: Ruby
Translation of: Tcl

<lang go>package main

import (

   "bytes"
   "fmt"
   "io"
   "os"
   "unicode"

)

func main() {

   owp(os.Stdout, bytes.NewBufferString("what,is,the;meaning,of:life."))
   fmt.Println()
   owp(os.Stdout, bytes.NewBufferString("we,are;not,in,kansas;any,more."))
   fmt.Println()

}

type Coroutine struct {

   out <-chan Coroutine
   in chan<- byte

}

func owp(dst io.Writer, src io.Reader) {

   byte_in := func () (byte, error) {
       bs := make([]byte, 1)
       _, err := src.Read(bs)
       return bs[0], err
   }
   byte_out := func (b byte) { dst.Write([]byte{b}) }    
   var f, r Coroutine
   f = func () Coroutine {
       out := make(chan Coroutine)

in := make(chan byte)

       var fwd func (byte) byte
       fwd = func (c byte) (z byte) {
           if unicode.IsLetter(rune(c)) {
               byte_out(c)
               out <- f
               z = fwd(<- in)
           } else {
               z = c
           }
           return
       }
       go func () {
           for {
               x, ok := <- in
               if !ok { break }
               byte_out(fwd(x))
               out <- r
           }
       } ()
       return Coroutine{ out, in }
   } ()
   r = func () Coroutine {
       out := make(chan Coroutine)

in := make(chan byte)

       var rev func (byte) byte
       rev = func (c byte) (z byte) {
           if unicode.IsLetter(rune(c)) {
               out <- r
               z = rev(<- in)
               byte_out(c)
           } else {
               z = c
           }
           return
       }
       go func () {
           for {
               x, ok := <- in
               if !ok { break }
               byte_out(rev(x))
               out <- f
           }
       } ()
       return Coroutine{ out, in }
   } ()
   for coro := f; ; coro = <- coro.out {
       c, err := byte_in()
       if err != nil { break }
       coro.in <- c
   }
   close(f.in)
   close(r.in)

}</lang>

Haskell

While it seems like this solution would break the task's rules, Haskell is non-strict, therefore this yields the same behavior of reading and printing one character at a time, without excess storage into a "string". To prove it, run the program and manually enter the input string (Windows command prompt does not respect buffering settings, but urxvt on on Linux does). <lang Haskell>import System.IO

isAlpha :: Char -> Bool isAlpha = flip elem $ ['a'..'z'] ++ ['A'..'Z']

split :: String -> (String, String) split = break $ not . isAlpha

parse :: String -> String parse [] = [] parse l =

 let (a, w) = split l
     (b, x) = splitAt 1 w
     (c, y) = split x
     (d, z) = splitAt 1 y
 in a ++ b ++ reverse c ++ d ++ parse z

main :: IO () main = hSetBuffering stdin NoBuffering >> hSetBuffering stdout NoBuffering >>

      getContents >>= putStr . (takeWhile (/= '.')) . parse >> putStrLn "."</lang>

If the above is not acceptable, or if Haskell was implicitly strict, then this solution would satisfy the requirements: <lang Haskell>isAlpha :: Char -> Bool isAlpha = flip elem $ ['a'..'z'] ++ ['A'..'Z']

parse :: IO () parse = do

 x <- getChar
 putChar x
 case () of
  _ | x == '.'  -> return ()
    | isAlpha x -> parse
    | otherwise -> do
        c <- revParse
        putChar c
        if c == '.'
          then return ()
          else parse

revParse :: IO Char revParse = do

 x <- getChar
 case () of
  _ | x == '.'  -> return x
    | isAlpha x -> do
        c <- revParse
        putChar x
        return c
    | otherwise -> return x

main :: IO () main = hSetBuffering stdin NoBuffering >> hSetBuffering stdout NoBuffering >>

      parse >> putStrLn ""</lang>

Linux urxvt output:

$ ./OddWord
wwhhaatt,,is,si,tthhee;;meaning,gninaem,ooff::life.efil.
$ echo "what,is,the;meaning,of:life." | ./OddWord
what,si,the;gninaem,of:efil.
$ echo "we,are;not,in,kansas;any,more." | ./OddWord
we,era;not,ni,kansas;yna,more.

Windows command prompt output:

>OddWord.exe
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.
>echo what,is,the;meaning,of:life. | OddWord.exe

what,si,the;gninaem,of;efil.
>echo we,are;not,in,kansas;any,more. | OddWord.exe

we,era;not,ni,kansas;yna,more.

Icon and Unicon

The following recursive version is based on the non-deferred GO version. A co-expression is used to turn the parameter to the wrapper into a character at a time stream.

<lang Icon>procedure main() every OddWord(!["what,is,the;meaning,of:life.",

               "we,are;not,in,kansas;any,more."])

end

procedure OddWord(stream) #: wrapper for demonstration

  write("Input stream: ",stream)
  writes("Output stream: ") & eWord(create !stream,'.,;:') & write()

end

procedure eWord(stream,marks) #: handle even words

  repeat {                               
     repeat 
        writes(@stream) ? if ="." then return else if any(marks) then break
     if writes(oWord(stream,marks)) == '.' then return
     }

end

procedure oWord(stream,marks) #: handle odd words (reverse)

  if any(marks,s := @stream) then return s
  return 1(oWord(stream,marks), writes(s))  

end</lang>

Output:

Input stream: what,is,the;meaning,of:life.
Output stream: what,si,the;gninaem,of:efil.
Input stream: we,are;not,in,kansas;any,more.
Output stream: we,era;not,ni,kansas;yna,more.

A slightly different solution which uses real I/O from stdin is: <lang Unicon>procedure main(A)

   repeat (while writes((any(&letters, c := reads(&input,1)),c))) |
          (writes(c) ~== "." ~== writes(rWord())) | break write()

end

procedure rWord(c)

   c1 := rWord((any(&letters, c1 := reads(&input,1)),c1))
   writes(\c)
   return c1

end</lang> And some sample runs:

->rw
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.
->rw
we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.
->

J

This task's requirement to perform buffering implicitly rather than explicitly was perplexing from a J point of view (see talk page for some of that discussion). To avoid this issue, this implementation uses a coroutine-like utility.

J also lacks character stream support, so this implementation uses a stream-like implementation.

<lang j>putch=: 4 :0 NB. coroutine verb

 outch y
 return x

)

isletter=: toupper ~: tolower

do_char=: 3 :0 NB. coroutine verb

 ch=. getch
 if. isletter ch do.
   if. odd do.
     putch&ch yield do_char  return.
   end.
 else.
   odd=: -. odd
 end.
 return ch

)

evenodd=: 3 :0

 clear_outstream begin_instream y
 odd=: 0
 whilst. '.'~:char do.
   outch char=. do_char coroutine 
 end.

)</lang>

Note that in the couroutine-like support page we defined u yield v y such that it produces a result which, when returned to the coroutine helper verb, will cause the deferred execute u v y in a context where both u and v are expected to be coroutine verbs (they will produce a result either wrapped with yield or with return). Likewise return wraps the result with instructions for the coroutine helper, instructing it to use the returned result "as-is". (And, if return is used with an empty stack in the helper, that instance would be the result of the coroutine helper.)

Note that when we curry putch with ch (in putch&ch) we get a verb which needs only one argument. So in this case, x in putch (its left argument) will be the right argument of the derived verb. In other words, in this example, it will be the result of the do_char instance that uses return ch -- this will be the first non-letter character that is seen when dealing with the odd case.

With this implementation:

<lang j> evenodd 'what,is,the;meaning,of:life.' what,si,the;gninaem,of:efil.

  evenodd 'we,are;not,in,kansas;any,more.'

we,era;not,ni,kansas;yna,more.</lang>

That said, note that this implementation has significant overhead when compared to a more direct implementation of the algorithm.

Java

<lang java>public class OddWord {

   interface CharHandler {

CharHandler handle(char c) throws Exception;

   }
   final CharHandler fwd = new CharHandler() {

public CharHandler handle(char c) { System.out.print(c); return (Character.isLetter(c) ? fwd : rev); }

   };
   class Reverser extends Thread implements CharHandler {

Reverser() { setDaemon(true); start(); } private Character ch; // For inter-thread comms private char recur() throws Exception { notify(); while (ch == null) wait(); char c = ch, ret = c; ch = null; if (Character.isLetter(c)) { ret = recur(); System.out.print(c); } return ret; } public synchronized void run() { try { while (true) { System.out.print(recur()); notify(); } } catch (Exception e) {} } public synchronized CharHandler handle(char c) throws Exception { while (ch != null) wait(); ch = c; notify(); while (ch != null) wait(); return (Character.isLetter(c) ? rev : fwd); }

   }
   final CharHandler rev = new Reverser();
   public void loop() throws Exception {

CharHandler handler = fwd; int c; while ((c = System.in.read()) >= 0) { handler = handler.handle((char) c); }

   }
   public static void main(String[] args) throws Exception {

new OddWord().loop();

   }

}</lang> Output is equivalent to that of the Python solution.

Julia

Works with: Julia version 0.6
Translation of: Python

<lang julia># io = readstring(STDIN) io = "what,is,the;meaning,of:life." i = 0

readbyte!() = io[global i += 1] writebyte(c) = print(Char(c))

function odd(prev::Function = () -> false)

   a = readbyte!()
   if !isalpha(a)
       prev()
       writebyte(a)
       return a != '.'
   end
   # delay action until later, in the shape of a closure
   clos() = (writebyte(a); prev())
   return odd(clos)

end

function even()

   while true
       c = readbyte!()
       writebyte(c)
       if !isalpha(c) return c != '.' end
   end

end

evn = false while evn ? odd() : even()

   evn = !evn

end</lang>

Output:
what,si,the;gninaem,of:efil.

Kotlin

Translation of: C

<lang scala>// version 1.1.3

typealias Func = () -> Unit

fun doChar(odd: Boolean, f: Func?): Boolean {

   val c = System.`in`.read()
   if (c == -1) return false // end of stream reached
   val ch = c.toChar()
   fun writeOut() {
       print(ch)
       if (f != null) f()
   }
   if (!odd) print(ch)
   if (ch.isLetter()) return doChar(odd, ::writeOut)
   if (odd) {
       if (f != null) f()
       print(ch)
   } 
   return ch != '.'

}

fun main(args: Array<String>) {

   repeat(2) {
       var b = true
       while (doChar(!b, null)) b = !b
       System.`in`.read() // remove '\n' from buffer
       println("\n")        
   }

}</lang>

Output:
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.

we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.

Lasso

<lang Lasso>define odd_word_processor(str::string) => { local( isodd = false, pos = 1, invpos = 1, lastpos = 1 ) while(#str->get(#pos) != '.' && #pos <= #str->size) => { if(not #str->isAlpha(#pos)) => { not #isodd ? #isodd = true | #isodd = false } if(#isodd) => { #lastpos = 1 #invpos = 1 while(#str->isAlpha(#pos+#lastpos) && #pos+#lastpos <= #str->size) => { #lastpos++ } 'odd lastpos: '+#lastpos+'\r' local(maxpos = #pos+#lastpos-1) while(#invpos < (#lastpos+1)/2) => { local(i,o,ipos,opos) #ipos = #pos+#invpos #opos = #pos+(#lastpos-#invpos) #i = #str->get(#ipos) #o = #str->get(#opos)

//'switching '+#i+' and '+#o+'\r'

//'insert '+#o+' at '+(#ipos)+'\r' #str = string_insert(#str,-position=(#ipos),-text=#o)

//'remove redundant pos '+(#ipos+1)+'\r' #str->remove(#ipos+1,1)

//'insert '+#i+' at '+(#opos)+'\r' #str = string_insert(#str,-position=(#opos),-text=#i)

//'remove redundant pos '+(#opos+1)+'\r' #str->remove(#opos+1,1)

#invpos++ } #pos += #lastpos - 1 } //#str->get(#pos) + #isodd + '\r' #pos += 1 } return #str }

'orig:\rwhat,is,the;meaning,of:life.\r' 'new:\r' odd_word_processor('what,is,the;meaning,of:life.') '\rShould have:\rwhat,si,the;gninaem,of:efil.'</lang>

Output:
orig:
what,is,the;meaning,of:life.
new:
what,si,the;gninaem,of:efil.
Should have:
what,si,the;gninaem,of:efil.

Lua

<lang lua>function reverse()

 local ch = io.read(1)
 if not ch then return end
 if ch:find("%w") then
   local rc = reverse()
   io.write(ch)
   return rc
 end
 return ch

end

function forward()

 ch = io.read(1)
 if not ch then return false end
 io.write(ch)
 if ch == "." then return false end
 if ch:find("%w") then
   return forward()
 else
   ch = reverse()
   if ch then io.write(ch) end
 end
 return true

end

while forward() do end</lang>

Output:
$ echo we,are;not,in,kansas;any,more.|oddword.lua
we,era;not,ni,kansas;yna,more.

$ echo what,is,the;meaning,of:life.|oddword.lua
what,si,the;gninaem,of:efil.

M2000 Interpreter

Using Recursion

PepareStream$() with null string set a lambda which read from keyboard and end reading when . found.

PepareStream$() with not a null string make a file and set a lambda to read it So code works with any stream, until get a null string We can pass by reference the lambda function but here we pass by reference the f factor, which for keyboard check the end, and for file work as file handler and at then end as a flag which check the end.

<lang M2000 Interpreter> Module Checkit {

      global out$
      document out$
     Function PrepareStream$ (buf$) {
           \\ get a temporary file 
           if buf$="" then {
                 class ref {
                        f
                 class:
                       module ref (.f) { }
                 }
                 \\ make f closure by reference
                 m->ref(false)
                 =lambda$  m->{
                       if m=>f then exit
                       r$=Key$
                       m=>f=r$="."
                       =r$
                 }
                 \\ exit function
                 break
           }
           name$=tempname$
           \\ we use Ansi type files
           Open name$ for output as F
                 Print #F, buf$;
           Close #F
           Open name$ for input as #f
           class ref {
                  f
           class:
                 module ref (.f) { }
           }
           \\ make f closure by reference
           m->ref(f)
           =lambda$ m -> {
                 if m=>f=-1000 then exit
                 def r$
                 if not eof(#m=>f) then  r$=Input$(#m=>f,2)
                 =r$
                 if r$="" or r$="." then close #m=>f : m=>f=-1000 
           }
     }
     Module Odd(c$) {
           one$=""
           Module MyEven(c$, &last$) {
                one$=If$(last$=""->c$(), last$)
                if one$="" then exit
                if not one$ ~"[a-zA-Z]" Then last$=one$: exit
                \\ print before
                Print one$; 
                out$<=one$
                Call MyEven, c$, &last$
           }
           Module MyOdd(c$, &last$) {
                one$=If$(last$=""->c$(), last$)
                if one$="" then exit
                if not one$ ~"[a-zA-Z]" Then last$=one$: exit
                Call MyOdd, c$, &last$
                \\ print after
                Print one$; 
                 out$<=one$
           }
           Do {
                 one$=""
                 Call MyEven, c$, &one$
                 if one$="" then exit
                 Print one$;
                 out$<=one$
                 one$=""
                 Call MyOdd, c$, &one$
                 if one$="" then exit
                 Print one$;
                 out$<=one$
           }   Always
           Print
           out$<={
           }
     }
     \\ Feeding keyboard
     keyboard "what,is,the;meaning,of:life."
     Odd PrepareStream$("")
     \\ Use a file for input
     Odd PrepareStream$("we,are;not,in,kansas;any,more.")
     clipboard out$

} Checkit </lang>

Using Closure

<lang M2000 Interpreter> Module OddWord {

     k$=lambda$->""
     state=false
     odd=True
     do {
           a$=key$
           if a$ ~"[a-zA-Z]" then {
                 If state Else state~ : odd~
                 if state and odd then k$=lambda$ k$, a$->a$+k$() : Continue
                 Print a$;
           } Else {
                 If state Then state~
                 if odd then Print k$(); : k$=lambda$->""
                 Print a$;      
           }
     } until a$="."
     Print

} keyboard "what,is,the;meaning,of:life." OddWord Keyboard "we,are;not,in,kansas;any,more." OddWord </lang>

Output:
what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

Nim

Translation of: Python

<lang nim>import os, unicode, future

proc nothing(): bool{.closure.} = false

proc odd(prev = nothing): bool =

 let a = stdin.readChar()
 if not isAlpha(Rune(ord(a))):
   discard prev()
   stdout.write(a)
   return a != '.'
 # delay action until later, in the shape of a closure
 proc clos(): bool =
   stdout.write(a)
   prev()
 return odd(clos)

proc even(): bool =

 while true:
   let c = stdin.readChar()
   stdout.write(c)
   if not isAlpha(Rune(ord(c))):
     return c != '.'

var e = false while (if e: odd() else: even()):

 e = not e</lang>

Output:

$ echo "what,is,the;meaning,of:life." | ./oddword
what,si,the;gninaem,of:efil.
echo "we,are;not,in,kansas;any,more." | ./oddword
we,era;not,ni,kansas;yna,more.

OCaml

<lang ocaml>let is_alpha c =

 c >= 'a' && c <= 'z' ||
 c >= 'A' && c <= 'Z'

let rec odd () =

 let c = input_char stdin in
 if is_alpha c
 then (let e = odd () in print_char c; e)
 else (c)

let rec even () =

 let c = input_char stdin in
 if is_alpha c
 then (print_char c; even ())
 else print_char c

let rev_odd_words () =

 while true do
   even ();
   print_char (odd ())
 done

let () =

 try rev_odd_words ()
 with End_of_file -> ()</lang>

Executing:

$ echo "what,is,the;meaning,of:life." | ocaml odd_word_problem.ml
what,si,the;gninaem,of:efil.

Ol

Use string iterators. <lang scheme> (define (odd_word_problem words)

  (letrec ((odd (lambda (s out)
              (let loop ((s s) (l '()))
                 (cond
                    ((null? s)
                       out)
                    ((pair? s)
                       (if (<= #\a (car s) #\z)
                          (loop (cdr s) (cons (car s) l))
                          (even (cdr s) (cons (cons (reverse l) (car s)) out))))
                    (else
                       (loop (s) l))))))
           (even (lambda (s out)
              (let loop ((s s) (l '()))
                 (cond
                    ((null? s)
                       out)
                    ((pair? s)
                       (if (<= #\a (car s) #\z)
                          (loop (cdr s) (cons (car s) l))
                          (odd (cdr s) (cons (cons l (car s)) out))))
                    (else
                       (loop (s) l)))))))
     (for-each (lambda (p)
                 (display (runes->string (car p)))
                 (display (string (cdr p))))
        (reverse
           (odd (str-iter words) '()))))
     (print))

(odd_word_problem "what,is,the;meaning,of:life.") (odd_word_problem "we,are;not,in,kansas;any,more.") </lang>

Output:

what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

Perl

All versions process text until EOF, not dot.

Input:

what,is,the;meaning,of:life.

Output:

what,si,the;gninaem,of:efil.

Closure version

<lang Perl>sub r { my ($f, $c) = @_; return sub { print $c; $f->(); }; }

$r = sub {};

while (read STDIN, $_, 1) { $w = /^[a-zA-Z]$/; $n++ if ($w && !$l); $l = $w; if ($n & 1 || !$w) { $r->(); $r = sub{}; print; } else { $r = r($r, $_); } } $r->();</lang>

Recursion version

<lang Perl>sub rev { my $c; read STDIN, $c, 1; if ($c =~ /^[a-zA-Z]$/) { my $r = rev(); print $c; return $r; } else { return $c; } }

while (read STDIN, $_, 1) { $w = /^[a-zA-Z]$/; $n++ if ($w && !$l); $l = $w; if ($n & 1) { print; } else { my $r = rev(); print $_; print $r; $n = 0; $l = 0; } }</lang>

Threads (processes) version

Perl still has weak threads support. Far more safe yet portable is to use processes (fork).

Here, fork is used instead of threads and pipe is used instead of conditional variable. <lang Perl>$|=1;

while (read STDIN, $_, 1) { $w = /^[a-zA-Z]$/; $n++ if ($w && !$l); $l = $w; if ($n & 1 || !$w) { close W; while(wait()!=-1){} print; } else { open W0, ">&", \*W; close W; pipe R,W; if (!fork()) { close W; <R>; print $_; close W0; exit; } close W0; close R; } }</lang>

Phix

Uses plain and simple recursion, no closures, and no other tricks.
To test direct console input, comment out string s .. getchar(), and uncomment getc(0) and the prompt.
Likewise use integer fn = open("somefile","r"), and getc(fn) should you want to test file i/o. <lang Phix>string s = "what,is,the;meaning,of:life." --string s = "we,are;not,in,kansas;any,more." integer i = 0

function getchar()

   i += 1
   return s[i]

end function

function wrod(integer rev)

   integer ch = getchar(), nch

-- integer ch = getc(0), nch

   if not find(ch," .,:;!?") then
       if rev then
           nch = wrod(rev)
       end if
       puts(1,ch)
       if not rev then
           nch = wrod(rev)
       end if
       ch = nch
   end if
   return ch

end function

--puts(1,"Enter words separated by a single punctuation mark (i.e. !?,.;:) and ending with .\n") integer rev = 0 while 1 do

   integer ch = wrod(rev)
   puts(1,ch)
   if ch='.' then exit end if
   rev = 1-rev

end while</lang>

Output:
what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

PHP

Translation of: Python

<lang PHP>$odd = function ($prev) use ( &$odd ) { $a = fgetc(STDIN); if (!ctype_alpha($a)) { $prev(); fwrite(STDOUT, $a); return $a != '.'; } $clos = function () use ($a , $prev) { fwrite(STDOUT, $a); $prev(); }; return $odd($clos); }; $even = function () { while (true) { $c = fgetc(STDIN); fwrite(STDOUT, $c); if (!ctype_alpha($c)) { return $c != "."; } } }; $prev = function(){}; $e = false; while ($e ? $odd($prev) : $even()) { $e = !$e; }</lang>

PicoLisp

<lang PicoLisp>(de oddWords ()

  (use C
     (loop
        (until (sub? (prin (setq C (char))) "!,.:;?"))
        (T (= "." C))
        (setq C (char))
        (T
           (= "."
              (prin
                 (recur (C)
                    (if (sub? C "!,.:;?")
                       C
                       (prog1 (recurse (char)) (prin C)) ) ) ) ) ) )
  (prinl) ) )</lang>

Test: <lang PicoLisp>(in "txt1" (oddWords)) (in "txt2" (oddWords))</lang> Output:

what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

PL/I

<lang PL/I>test: procedure options (main); /* 2 August 2014 */

  declare (ch, ech) character (1);
  declare odd file;

get_word: procedure recursive;

  declare ch character (1);
  get file (odd) edit (ch) (a(1));
  if index('abcdefghijklmnopqrstuvwxyz', ch) > 0 then call get_word;
  if index('abcdefghijklmnopqrstuvwxyz', ch) > 0 then
     put edit (ch) (a);
  else ech = ch;

end get_word;

  open file (odd) input title ('/ODDWORD.DAT,TYPE(text),recsize(100)');
  do forever;
     do  until (index('abcdefghijklmnopqrstuvwxyz', ch) = 0 );
        get file (odd) edit (ch) (a(1)); put edit (ch) (a);
     end;
     if ch = '.' then leave;
     call get_word;
     put edit (ech) (a);
     if ech = '.' then leave;
  end;

end test;</lang> file:

what,is,the;meaning,of:life.

output:

what,si,the;gninaem,of:efil.

file:

we,are;not,in,kansas;any,more.

output:

we,era;not,ni,kansas;yna,more.

Prolog

Works with SWI-Prolog. <lang Prolog>odd_word_problem :- read_line_to_codes(user_input, L), even_word(L, Out, []), string_to_list(Str, Out), writeln(Str).

even_word(".") --> ".".

even_word([H | T]) --> {char_type(H,alnum)}, [H], even_word(T).

even_word([H | T]) --> [H], odd_word(T, []).

odd_word(".", R) --> R, ".".

odd_word([H|T], R) --> {char_type(H,alnum)}, odd_word(T, [H | R]).

odd_word([H|T], R) --> R, [H], even_word(T). </lang> Output :

?- odd_word_problem.
|: what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.
true .

?- odd_word_problem.
|: we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.
true .

PureBasic

This example uses recursion. <lang PureBasic>#False = 0

  1. True = 1

Global *inputPtr.Character

Macro nextChar()

 *inputPtr + SizeOf(Character)

EndMacro

Procedure isPunctuation(c.s)

 If FindString("!?()[]{},.;:-'" + #DQUOTE$, c)
   ProcedureReturn #True
 EndIf
 ProcedureReturn #False

EndProcedure

Procedure oddWord()

 Protected c.c
 c = *inputPtr\c
 If isPunctuation(Chr(*inputPtr\c))
   ProcedureReturn
 Else
   nextChar()
   oddWord()
 EndIf 
 Print(Chr(c))

EndProcedure

Procedure oddWordProblem(inputStream.s)

 *inputPtr = @inputStream
 Define isOdd = #False
 While *inputPtr\c
   If isOdd
     oddWord()
   Else
     Repeat
       Print(Chr(*inputPtr\c))
       nextChar()
     Until isPunctuation(Chr(*inputPtr\c))
   EndIf
   Print(Chr(*inputPtr\c))
   isOdd ! 1 ;toggle word indicator
   nextChar()
 Wend 

EndProcedure

Define inputStream.s If OpenConsole()

 Repeat
   PrintN(#CRLF$ + #CRLF$ + "Enter a series of words consisting only of English letters (i.e. a-z, A-Z)")
   PrintN("and that are separated by a punctuation mark (i.e. !?()[]{},.;:-' or " + #DQUOTE$ + ").")
   inputStream = Input()
   oddWordProblem(inputStream) ;assume input is correct
 Until inputStream = ""
  
 Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input()
 CloseConsole()

EndIf</lang> Sample output:

Enter a series of words consisting only of English letters (i.e. a-z, A-Z)
and that are separated by a punctuation mark (i.e. !?()[]{},.;:-' or ").
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.

Enter a series of words consisting only of English letters (i.e. a-z, A-Z)
and that are separated by a punctuation mark (i.e. !?()[]{},.;:-' or ").
we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.

Python

<lang python>from sys import stdin, stdout

def char_in(): return stdin.read(1) def char_out(c): stdout.write(c)

def odd(prev = lambda: None): a = char_in() if not a.isalpha(): prev() char_out(a) return a != '.'

# delay action until later, in the shape of a closure def clos(): char_out(a) prev()

return odd(clos)

def even(): while True: c = char_in() char_out(c) if not c.isalpha(): return c != '.'

e = False while odd() if e else even(): e = not e</lang> Running:<lang>$ echo "what,is,the;meaning,of:life." | python odd.py what,si,the;gninaem,of:efil. $ echo "we,are;not,in,kansas;any,more." | python odd.py we,era;not,ni,kansas;yna,more.</lang>

Translation of: Scheme

In this version, the action of printing the terminating punctuation is put in a closure and returned by odd(). <lang python>from sys import stdin, stdout

def char_in(): return stdin.read(1) def char_out(c): stdout.write(c)

def odd(): a = char_in() if a.isalpha(): r = odd() char_out(a) return r

# delay printing terminator until later, in the shape of a closure def clos(): char_out(a) return a != '.'

return clos

def even(): while True: c = char_in() char_out(c) if not c.isalpha(): return c != '.'

e = False while odd()() if e else even(): e = not e</lang>

Using coroutines and recursion

Translation of: Ruby
Translation of: Tcl
Works with: Python version 3.3+

<lang python>from sys import stdin, stdout

def fwd(c):

   if c.isalpha():
       return [stdout.write(c), (yield from fwd((yield f)))][1]
   else:
       return c

def rev(c):

   if c.isalpha():
       return [(yield from rev((yield r))), stdout.write(c)][0]
   else:
       return c

def fw():

   while True:
       stdout.write((yield from fwd((yield r))))

def re():

   while True:
       stdout.write((yield from rev((yield f))))

f = fw() r = re() next(f) next(r)

coro = f while True:

   c = stdin.read(1)
   if not c:
       break
   coro = coro.send(c)</lang>

Racket

Simple solution, using a continuation thunk for the reverse parts. <lang racket>

  1. !/bin/sh
  2. |

exec racket -tm- "$0" "$@" |#

  1. lang racket

(define (even k)

 (define c (read-char))
 (cond [(eq? c eof) (k)]
       [(not (char-alphabetic? c)) (k) (write-char c) (odd)]
       [else (even (λ() (write-char c) (k)))]))

(define (odd)

 (define c (read-char))
 (unless (eq? c eof)
   (write-char c)
   (if (char-alphabetic? c) (odd) (even void))))

(provide main) (define (main) (odd) (newline))

(with-input-from-string "what,is,the;meaning,of
life." main)
;; -> what,si,the;gninaem,of
efil.
(with-input-from-string "we,are;not,in,kansas;any,more." main)
;; -> we,era;not,ni,kansas;yna,more.

</lang>

Raku

(formerly Perl 6) A recursive solution, with the added feature that it treats each line separately. <lang perl6>my &in = { $*IN.getc // last }

loop {

   ew(in);
   ow(in).print;

}

multi ew ($_ where /\w/) { .print; ew(in); } multi ew ($_) { .print; next when "\n"; }

multi ow ($_ where /\w/) { ow(in) x .print; } multi ow ($_) { $_; }</lang>

Output:
$ ./oddword
we,are;not,in,kansas;any,more.
we,era;not,ni,kansas;yna,more.
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.

Note how the even/oddness is reset on the line boundary; if not, the second line might have started out in an odd state and reversed "what" instead of "is". The call to next prevents that by sending the loop back to its initial state.

There is one clever trick here with the x operator; it evaluates both its arguments in order, but in this case only returns the left argument because the right one is always 1 (True). You can think of it as a reversed C-style comma operator.

REXX

The REXX program writes some header information to aid in visual fidelity when displaying the output to the
screen (also a blank line is written to make the screen display righteous;   it's assumed that writing titles and
blank lines doesn't break the spirit of the restrictions (single character I/O)   [the 8th line with the three says].
This displaying of informative messages is only to help the observer to know what is being performed.

No recursion or the stack is used.   The program could've been written without subroutines. <lang rexx>/*REXX program solves the odd word problem by only using byte input/output. */ iFID_ = 'ODDWORD.IN' /*Note: numeric suffix is added later.*/ oFID_ = 'ODDWORD.' /* " " " " " " */

    do case=1  for 2;   #=0                     /*#:  is the number of characters read.*/
    iFID=iFID_ || case                          /*read   ODDWORD.IN1  or  ODDWORD.IN2  */
    oFID=oFID_ || case                          /*write  ODDWORD.1    or  ODDWORD.2    */
    say;   say;    say '════════ reading file: '        iFID        "════════"                /* ◄■■■■■■■■■ optional. */
        do  until x==.                               /* [↓]  perform for  "odd"  words.*/
           do  until \isMix(x);                      /* [↓]  perform until punct found.*/
           call readChar;    call writeChar          /*read and write a letter.        */
           end   /*until ¬isMix(x)*/                 /* [↑]  keep reading    "     "   */
        if x==.  then leave                          /*is this the  end─of─sentence ?  */
        call readLetters;    punct=#                 /*save the location of punctuation*/
           do j=#-1  by -1;  call readChar j         /*read previous word (backwards). */
           if \isMix(x)  then leave;  call writeChar /*Found punctuation?  Then leave. */
           end   /*j*/                               /* [↑]  perform for  "even" words.*/
        call readLetters;   call writeChar;  #=punct /*read/write letters; new location*/
        end      /*until x==.*/
    end          /*case*/                            /* [↑]  process both input files. */

exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ isMix: return datatype( arg(1), 'M') /*return 1 if argument is a letter.*/ readLetters: do until \isMix(x); call readChar; end; return writeChar: call charout , x; call charout oFID, x; return /*──────────────────────────────────────────────────────────────────────────────────────*/ readChar: if arg(1)== then do; x=charin(iFID); #=#+1; end /*read the next char*/

                           else      x=charin(iFID, arg(1))        /*  "  specific   " */
            return</lang>

output   when using two (default) input files which contain:

  •   input file   ODDWORD.IN1   ───►   what,is,the;meaning,of:life.
  •   input file   ODDWORD.IN2   ───►   we,are;not,in,kansas;any,more.


The output is written to the terminal screen as well as to a couple of unique files.   Only the screen output is
shown here, the output files mirror the display except for the headers   (reading file:   xxx)   and the writing
(SAYing) of blank lines which helps keep the screen righteous after using the REXX   charout   BIF   which
wrote to the terminal.

════════ reading file:  ODDWORD.IN1 ════════
what,si,the;gninaem,of:efil.

════════ reading file:  ODDWORD.IN2 ════════
we,era;not,ni,kansas;yna,more.

Ring

<lang ring>

  1. Project : Odd word problem

test = "what,is,the;meaning,of:life." n1 = 1 testarr = [] testorigin = test test = substr(test, ",", " ") test = substr(test, ";", " ") test = substr(test, ":", " ") test = substr(test, ".", " ")

while true

     n2 = substring(test, " ", n1)
     n3 = substring(test, " ", n2 + 1)
     if n2>0 and n3>0
        strcut = substr(test, n2 + 1, n3 - n2)
        strcut = trim(strcut)
        if strcut != ""
           add(testarr, strcut)
           n1 = n3 + 1
        else
           exit
        ok
     ok

end

for n = 1 to len(testarr)

   strrev = revstr(testarr[n])
   testorigin = substr(testorigin, testarr[n], strrev)

next see testorigin + nl

func Substring str,substr,n

    newstr=right(str,len(str)-n+1)
    nr = substr(newstr, substr)
    return n + nr -1

func revstr(cStr)

    cStr2 = ""
    for x = len(cStr) to 1 step -1
        cStr2 += cStr[x]
    next
    return cStr2

</lang> Output:

what,si,the;gninaem,of:efil.

Ruby

These Ruby programs store each character in a single-character string.

Using fibers and recursion

Translation of: Tcl
Works with: Ruby version 1.9

<lang ruby>f, r = nil fwd = proc {|c|

 c =~ /alpha:/ ? [(print c), fwd[Fiber.yield f]][1] : c }

rev = proc {|c|

 c =~ /alpha:/ ? [rev[Fiber.yield r], (print c)][0] : c }

(f = Fiber.new { loop { print fwd[Fiber.yield r] }}).resume (r = Fiber.new { loop { print rev[Fiber.yield f] }}).resume

coro = f until $stdin.eof?

 coro = coro.resume($stdin.getc)

end</lang>

Using continuations

Translation of: Factor
Library: continuation

<lang ruby>require 'continuation' unless defined? Continuation require 'stringio'

  1. Save current continuation.

def savecc(*data)

 # With MRI 1.8 (but not 1.9), the array literal
 #   [callcc {|cc| cc}, *data]
 # used the wrong return value from callcc. The workaround is to
 # put callcc outside the array literal.
 continuation = callcc {|cc| cc}
 [continuation, *data]

end

  1. Jump back to continuation, where savecc will return [nil, *data].

def jump_back(continuation)

 continuation[nil]

end

def read_odd_word(input, output)

 first_continuation, last_continuation = nil
 reverse = false
 # Read characters. Loop until end of stream.
 while c = input.getc
   c = c.chr   # For Ruby 1.8, convert Integer to String.
   if c =~ /alpha:/
     # This character is a letter.
     if reverse
       # Odd word: Write letters in reverse order.
       saving, last_continuation, c = savecc(last_continuation, c)
       if saving
         last_continuation = saving
       else
         # After jump: print letters in reverse.
         output.print c
         jump_back last_continuation
       end
     else
       # Even word: Write letters immediately.
       output.print c
     end
   else
     # This character is punctuation.
     if reverse
       # End odd word. Fix trampoline, follow chain of continuations
       # (to print letters in reverse), then bounce off trampoline.
       first_continuation, c = savecc(c)
       if first_continuation
         jump_back last_continuation
       end
       output.print c      # Write punctuation.
       reverse = false     # Begin even word.
     else
       output.print c      # Write punctuation.
       reverse = true      # Begin odd word.
       # Create trampoline to bounce to (future) first_continuation.
       last_continuation, = savecc
       unless last_continuation
         jump_back first_continuation
       end
     end
   end
 end
 output.puts   # Print a cosmetic newline.

end

def odd_word(string)

 read_odd_word StringIO.new(string), $stdout

end

odd_word "what,is,the;meaning,of:life." odd_word "we,are;not,in,kansas;any,more."</lang>

Run BASIC

This example is incorrect. Please fix the code and remove this message.

Details: Restriction #1 violated - only single character I/O allowed. Restriction #2 violated - explicit storage in string for later reversal not allowed.

<lang runbasic>open "oddWord.txt" for input as #f ' read input stream while not(eof(#f)) line input #f, a$ oddW$ = "" ' begin the result oddW with blank px = 0 ' begin word search location with 0 count = 0 ' begin the word count to 0 while x < len(a$) ' look at each character x = instr(a$,",",px) ' search for comma (,) if x = 0 then x = len(a$) ' no more commas? x1 = instr(a$,";",px) ' search for (;) x2 = instr(a$,":",px) ' search for (:) if x1 <> 0 then x = min(x,x1) ' what came first the , ; or : if x2 <> 0 then x = min(x,x2)

w$ = mid$(a$,px,x - px) ' get the word seperated by , ; or :

if count and 1 then ' is it the odd word w1$ = "" for i = len(w$) to 1 step -1 w1$ = w1$ + mid$(w$,i,1) ' reverse odd words next i w$ = w1$ end if

       oddW$ = oddW$ + w$ + mid$(a$,x,1)        ' add the word to the end of oddW$

px = x + 1 ' bump word search location for next while count = count + 1 ' count the words wend print a$;" -> ";oddW$ ' print the original and result next ii wend close #f</lang>

what,is,the;meaning,of:life.   -> what,si,the;gninaem,of:efil.
we,are;not,in,kansas;any,more. -> we,era;not,ni,kansas;yna,more.

Scala

<lang Scala>import scala.io.Source import java.io.PrintStream

def process(s: Source, p: PrintStream, w: Int = 0): Unit = if (s.hasNext) s.next match {

 case '.' => p append '.'
 case c if !Character.isAlphabetic(c) => p append c; reverse(s, p, w + 1)
 case c => p append c; process(s, p, w)

}

def reverse(s: Source, p: PrintStream, w: Int = 0, x: Char = '.'): Char = s.next match {

 case c if !Character.isAlphabetic(c) => p append x; c
 case c => val n = reverse(s, p, w, c);
   if (x == '.') {p append n; process(s, p, w + 1)} else p append x; n

}

process(Source.fromString("what,is,the;meaning,of:life."), System.out); println process(Source.fromString("we,are;not,in,kansas;any,more."), System.out); println</lang>

Output:
what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.

Scheme

Output is identical to python. <lang lisp>(define (odd)

 (let ((c (read-char)))
   (if (char-alphabetic? c)
     (let ((r (odd)))

(write-char c) r)

     (lambda () (write-char c) (char=? c #\.)))))

(define (even)

 (let ((c (read-char)))
   (write-char c)
   (if (char-alphabetic? c)
     (even)
     (char=? c #\.))))

(let loop ((i #f))

 (if (if i ((odd)) (even))
   (exit)
   (loop (not i))))</lang>

Seed7

<lang seed7>$ include "seed7_05.s7i";

 include "chartype.s7i";

const func char: doChar (in boolean: doReverse) is func

 result
   var char: delimiter is ' ';
 local
   var char: ch is ' ';
 begin
   ch := getc(IN);
   if ch in letter_char then
     if doReverse then
       delimiter := doChar(doReverse);
       write(ch);
     else
       write(ch);
       delimiter := doChar(doReverse);
     end if;
   else
     delimiter := ch;
   end if;
 end func;

const proc: main is func

 local
   var char: delimiter is ' ';
   var boolean: doReverse is FALSE;
 begin
   repeat
     delimiter := doChar(doReverse);
     write(delimiter);
     doReverse := not doReverse;
   until delimiter = '.';
   writeln;
 end func;</lang>
Output:
> s7 oddWordProblem
SEED7 INTERPRETER Version 5.0.5203  Copyright (c) 1990-2014 Thomas Mertes
what,is,the;meaning,of:life.
what,si,the;gninaem,of:efil.

Sidef

Recursive solution:

Translation of: Perl

<lang ruby>func rev {

   (var c = STDIN.getc) \\ return()
   if (c ~~ /^[a-z]\z/i) {
       var r = rev()
       print c
       return r
   }
   return c

}

var (n=0, l=false) while (defined(var c = STDIN.getc)) {

   var w = (c ~~ /^[a-z]\z/i)
   ++n if (w && !l)
   l = w
   if (n & 1) {
       print c
   } else {
       var r = rev()
       print(c, r)
       n = 0
       l = false
   }

}</lang>

Output:
$ echo 'what,is,the;meaning,of:life.' | sidef script.sf
what,si,the;gninaem,of:efil.

$ echo 'we,are;not,in,kansas;any,more.' | sidef script.sf
we,era;not,ni,kansas;yna,more.

Tcl

Although the input is handled as strings, they're all as single-character strings.

Works with: Tcl version 8.6

<lang tcl>package require Tcl 8.6

proc fwd c {

   expr {[string is alpha $c] ? "[fwd [yield f][puts -nonewline $c]]" : $c}

} proc rev c {

   expr {[string is alpha $c] ? "[rev [yield r]][puts -nonewline $c]" : $c}

} coroutine f while 1 {puts -nonewline [fwd [yield r]]} coroutine r while 1 {puts -nonewline [rev [yield f]]} for {set coro f} {![eof stdin]} {} {

   set coro [$coro [read stdin 1]]

}</lang> Output is identical to Python and Scheme versions.

The only difference between the two coroutines (apart from the different names used when flipping back and forth) is the timing of the write of the character with respect to the recursive call.

TUSCRIPT

This example is incorrect. Please fix the code and remove this message.

Details: You are supposed to read characters one by one and not store them in arrays.

<lang tuscript> $$ MODE TUSCRIPT inputstring=* DATA what,is,the;meaning,of:life. DATA we,are;not,in,kansas;any,more.

BUILD C_GROUP >[pu]=".,;:-"

LOOP i=inputstring pu=STRINGS (i,"|>[pu]|") wo=STRINGS (i,"|<></|") outputstring=""

loop n,w=wo,p=pu
r=MOD(n,2)
IF (r==0) w=TURN (w)
outputstring=CONCAT(outputstring,w,p)

ENDLOOP PRINT outputstring ENDLOOP </lang> Output:

what,si,the;gninaem,of:efil.Brian:
we,era;not,ni,kansas;yna,more. 

VBA

First way : <lang vb>Private Function OddWordFirst(W As String) As String Dim i As Integer, count As Integer, l As Integer, flag As Boolean, temp As String

  count = 1
  Do
     flag = Not flag
     l = FindNextPunct(i, W) - count + 1
     If flag Then
        temp = temp & ExtractWord(W, count, l)
     Else
        temp = temp & ReverseWord(W, count, l)
     End If
  Loop While count < Len(W)
  OddWordFirst = temp

End Function

Private Function FindNextPunct(d As Integer, W As String) As Integer Const PUNCT As String = ",;:."

  Do
     d = d + 1
  Loop While InStr(PUNCT, Mid(W, d, 1)) = 0
  FindNextPunct = d

End Function

Private Function ExtractWord(W As String, c As Integer, i As Integer) As String

  ExtractWord = Mid(W, c, i)
  c = c + Len(ExtractWord)

End Function

Private Function ReverseWord(W As String, c As Integer, i As Integer) As String Dim temp As String, sep As String

  temp = Left(Mid(W, c, i), Len(Mid(W, c, i)) - 1)
  sep = Right(Mid(W, c, i), 1)
  ReverseWord = StrReverse(temp) & sep
  c = c + Len(ReverseWord)

End Function</lang> Second way : <lang vb>Private Function OddWordSecond(Words As String) As String Dim i&, count&, t$, cpt&, j&, l&, d&, f As Boolean Const PUNCT As String = ",;:"

  For i = 1 To Len(Words)
     'first word
     If i = 1 Then
        cpt = 1
        Do
           t = t & Mid(Words, cpt, 1)
           cpt = cpt + 1
        Loop While InStr(PUNCT, Mid(Words, cpt, 1)) = 0 And cpt < Len(Words)
        i = cpt
        t = t & Mid(Words, i, 1)
     End If
     If Right(t, 1) = "." Then Exit For
     'Odd words ==> reverse
     While InStr(PUNCT, Mid(Words, cpt + 1, 1)) = 0 And cpt < Len(Words)
        cpt = cpt + 1
     Wend
     l = IIf(f = True, i, i + 1)
     d = IIf(cpt = Len(Words), cpt - 1, cpt)
     For j = d To l Step -1
        t = t & Mid(Words, j, 1)
     Next
     If cpt = Len(Words) Then t = t & ".": Exit For
     f = True
     i = cpt + 1
     t = t & Mid(Words, i, 1)
     'Even words
     cpt = i + 1
     t = t & Mid(Words, cpt, 1)
     Do
        cpt = cpt + 1
        t = t & Mid(Words, cpt, 1)
     Loop While InStr(PUNCT, Mid(Words, cpt, 1)) = 0 And cpt < Len(Words)
     i = cpt
  Next
  OddWordSecond = t

End Function</lang> To call Functions : <lang vb>Option Explicit

Sub Main()

  Debug.Print "Input : " & "we,are;not,in,kansas;any,more."
  Debug.Print "First way : " & OddWordFirst("we,are;not,in,kansas;any,more.")
  Debug.Print "Second way : " & OddWordSecond("we,are;not,in,kansas;any,more.")
  Debug.Print ""
  Debug.Print "Input : " & "what,is,the;meaning,of:life."
  Debug.Print "First way : " & OddWordFirst("what,is,the;meaning,of:life.")
  Debug.Print "Second way : " & OddWordSecond("what,is,the;meaning,of:life.")

End Sub</lang>

Output:
Input : we,are;not,in,kansas;any,more.
First way : we,era;not,ni,kansas;yna,more.
Second way : we,era;not,ni,kansas;yna,more.

Input : what,is,the;meaning,of:life.
First way : what,si,the;gninaem,of:efil.
Second way : what,si,the;gninaem,of:efil.

zkl

Translation of: D

<lang zkl>var [const] delim=",:;/?!@#$%^&*()_+", stop="."; fcn oddly(inStream){

  inStream=inStream.walker(3);  // character iterator: string, file, etc
  doWord:=fcn(inStream,rev,f){  // print next word forewards or reverse
     c:=inStream.next();
     if(not rev) c.print();
     if(not (c==stop or delim.holds(c)))

return(self.fcn(inStream,rev,'{ c.print(); f(); }));

     if(rev){ f(); c.print(); }
     return(c!=stop);
  };
  tf:=Walker.cycle(False,True);  // every other word printed backwords
  while(doWord(inStream, tf.next(), Void)) {}
  println();

}</lang> Showing two different input streams: <lang zkl>oddly("what,is,the;meaning,of:life."); oddly(Data(0,String,"we,are;not,in,kansas;any,more."));</lang>

Output:
what,si,the;gninaem,of:efil.
we,era;not,ni,kansas;yna,more.