N'th

N'th is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Write a function/method/subroutine/... that when given an integer greater than or equal to zero returns a string of the number followed by an apostrophe then the ordinal suffix.
Example returns would include 1'st 2'nd 3'rd 11'th 1001'st

Task

Use your routine to show here the output for at least the following (inclusive) ranges of integer inputs: 0..25, 250..265, 1000..1025

D

Translation of: Python

<lang d>import std.stdio, std.string, std.range, std.algorithm;

string nth(in uint n) pure {

   static immutable suffix = "th st nd rd th th th th th th".split;
   return "%d'%s".format(n, (n % 100 <= 10 || n % 100 > 20) ?
                            suffix[n % 10] : "th");

}

void main() {

   foreach (r; [iota(26), iota(250, 266), iota(1000, 1026)])
       writefln("%-(%s %)", r.map!nth);

}</lang>

Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th
250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th
1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

J

Implementation:

<lang J>suf=: (;:'th st nd rd th'){::~4<.10 10(* 1&~:)~/@#:]

nth=: [:;:inv (":,',suf)each</lang>

Task:

<lang J> thru=: <./ + i.@(+ *)@-~

  nth 0 thru 25

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th

  nth 250 thru 265

250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th

  nth 1000 thru 1025

1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th</lang>

Perl 6

<lang perl6>my %irregulars = <1 st 2 nd 3 rd>, (11..13 X=> 'th');

sub N'th ($n) { "$n'" ~ ( %irregulars{$n % 100} // %irregulars{$n % 10} // 'th' ) }

say .list».&N'th.join: ' ' for [^26], [250..265], [1000..1025];</lang>

Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th
250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th
1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th

Python

<lang python>_suffix = ['th', 'st', 'nd', 'rd', 'th', 'th', 'th', 'th', 'th', 'th']

def nth(n):

   return "%i'%s" % (n, _suffix[n%10] if n % 100 <= 10 or n % 100 > 20 else 'th')

if __name__ == '__main__':

   for j in range(0,1001, 250):
       print(' '.join(nth(i) for i in list(range(j, j+25))))</lang>

Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th
250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th
500'th 501'st 502'nd 503'rd 504'th 505'th 506'th 507'th 508'th 509'th 510'th 511'th 512'th 513'th 514'th 515'th 516'th 517'th 518'th 519'th 520'th 521'st 522'nd 523'rd 524'th
750'th 751'st 752'nd 753'rd 754'th 755'th 756'th 757'th 758'th 759'th 760'th 761'st 762'nd 763'rd 764'th 765'th 766'th 767'th 768'th 769'th 770'th 771'st 772'nd 773'rd 774'th
1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th

Tcl

<lang tcl>proc ordinal {n} {

   if {$n%100<10 || $n%100>20} {

set suff [lindex {th st nd rd th th th th th th} [expr {$n % 10}]]

   } else {

set suff th

   }
   return "$n'$suff"

}

foreach start {0 250 1000} {

   for {set n $start; set l {}} {$n<=$start+25} {incr n} {

lappend l [ordinal $n]

   }
   puts $l

}</lang>

Output:

0'th 1'st 2'nd 3'rd 4'th 5'th 6'th 7'th 8'th 9'th 10'th 11'th 12'th 13'th 14'th 15'th 16'th 17'th 18'th 19'th 20'th 21'st 22'nd 23'rd 24'th 25'th
250'th 251'st 252'nd 253'rd 254'th 255'th 256'th 257'th 258'th 259'th 260'th 261'st 262'nd 263'rd 264'th 265'th 266'th 267'th 268'th 269'th 270'th 271'st 272'nd 273'rd 274'th 275'th
1000'th 1001'st 1002'nd 1003'rd 1004'th 1005'th 1006'th 1007'th 1008'th 1009'th 1010'th 1011'th 1012'th 1013'th 1014'th 1015'th 1016'th 1017'th 1018'th 1019'th 1020'th 1021'st 1022'nd 1023'rd 1024'th 1025'th