HTTP

HTTP
You are encouraged to solve this task according to the task description, using any language you may know.

Print a URL's content.

Erlang

Synchronous

-module(main).
-export([main/1]).

main([Url|[]]) ->
   inets:start(),
   case http:request(Url) of
       {ok, {_V, _H, Body}} -> io:fwrite("~p~n",[Body]);
       {error, Res} -> io:fwrite("~p~n", Res)
   end.

Asynchronous

-module(main).
-export([main/1]).

main([Url|[]]) ->
   inets:start(),
   http:request(get, {Url, [] }, [], [{sync, false}]),
   receive
       {http, {_ReqId, Res}} -> io:fwrite("~p~n",[Res]);
       _Any -> io:fwrite("Error: ~p~n",[_Any])
       after 10000 -> io:fwrite("Timed out.~n",[])
   end.

Using it

|escript ./req.erl http://www.rosettacode.org

Java

<java>import java.net.*; import java.io.*;

public class Main {

   public static void main(String[] args) throws Exception {
       URL url = new URL("http://www.rosettacode.org"); 
       InputStreamReader isr = new InputStreamReader(url.openStream());
       BufferedReader reader = new BufferedReader(isr);
       String line = "";
               
       while ( (line = reader.readLine()) != null) {
           System.out.println(line);
       }
       
       reader.close();  
   }   

}</java>

Perl

<perl>using LWP::Simple; print get("http://www.rosettacode.org");</perl>

PHP

<php>print(file_get_contents("http://www.rosettacode.org"));</php>

Python

<python>import urllib print urllib.urlopen("http://www.rosettacode.org").read()</python>

One-liner

<bash>$ python -c 'print __import__("urllib").urlopen("http://www.rosettacode.org").read()'</bash>