Floyd-Warshall algorithm

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Revision as of 23:45, 9 October 2015 by rosettacode>Emeraude (Creating the page with three languages : javascript, ruby and PHP)
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Task
Floyd-Warshall algorithm
You are encouraged to solve this task according to the task description, using any language you may know.

The Floyd–Warshall algorithm is an algorithm for finding shortest paths in a weighted graph with positive or negative edge weights.


JavaScript

<lang javascript>var graph = []; for (i = 0; i < 10; ++i) {

 graph.push([]);
 for (j = 0; j < 10; ++j)
   graph[i].push(i == j ? 0 : 9999999);

}

for (i = 1; i < 10; ++i) {

 graph[0][i] = graph[i][0] = parseInt(Math.random() * 9 + 1);

}

for (k = 0; k < 10; ++k) {

 for (i = 0; i < 10; ++i) {
   for (j = 0; j < 10; ++j) {
     if (graph[i][j] > graph[i][k] + graph[k][j])
       graph[i][j] = graph[i][k] + graph[k][j]
   }
 }

}

console.log(graph);</lang>

PHP

<lang php><?php $graph = array(); for ($i = 0; $i < 10; ++$i) {

   $graph[] = array();
   for ($j = 0; $j < 10; ++$j)
       $graph[$i][] = $i == $j ? 0 : 9999999;

}

for ($i = 1; $i < 10; ++$i) {

   $graph[0][$i] = $graph[$i][0] = rand(1, 9);

}

for ($k = 0; $k < 10; ++$k) {

   for ($i = 0; $i < 10; ++$i) {
       for ($j = 0; $j < 10; ++$j) {
           if ($graph[$i][$j] > $graph[$i][$k] + $graph[$k][$j])
               $graph[$i][$j] = $graph[$i][$k] + $graph[$k][$j];
       }
   }

}

print_r($graph); ?></lang>

Ruby

<lang ruby>require 'matrix'

graph = [] 10.times{|i| graph[i] = [].fill(9999999, 0, 10)} 10.times{|i| graph[i][i] = 0} (1..9).each{|i| graph[i][0] = graph[0][i] = Random.rand(9) + 1}

10.times do |k|

 10.times do |i|
   10.times do |j|
     graph[i][j] = graph[i][k] + graph[k][j] if graph[i][j] > graph[i][k] + graph[k][j]
   end
 end

end

puts Matrix[graph]</lang>