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tomorrow = today + timedelta( days=1 )
tomorrow = today + timedelta( days=1 )
print "Tomorrow is: ", tomorrow.strftime('%B %d, %Y')
print "Tomorrow is: ", tomorrow.strftime('%B %d, %Y')

==[[Raven]]==
[[Category:Raven]]

time int as today

Short form:

today '%Y-%m-%d' date

Long form:

today '%A, %B %d, %Y' date

Revision as of 13:31, 12 November 2007

Task
Date format
You are encouraged to solve this task according to the task description, using any language you may know.

Display a given date in the formats of "2007-11-10" and "Sunday, November 10, 2007".

Ada

This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.


with Ada.Calendar; use Ada.Calendar;
with Ada.Calendar.Arithmetic; use Ada.Calendar.Arithmetic;
with Ada.Strings.Unbounded; use Ada.Strings.Unbounded;
with Ada.Text_Io; use Ada.Text_IO;

procedure Date_Format is
   type Month_Names is array(Month_Number) of Unbounded_String;
   Months : constant Month_Names := (
      To_Unbounded_String("January"),
      To_Unbounded_String("February"),
      To_Unbounded_String("March"),
      To_Unbounded_String("April"),
      To_Unbounded_String("May"),
      To_Unbounded_String("June"),
      To_Unbounded_String("July"),
      To_Unbounded_String("August"),
      To_Unbounded_String("September"),
      To_Unbounded_String("October"),
      To_Unbounded_String("November"),
      To_Unbounded_String("December"));
   The_Day : Time;
   Increment : constant Day_Count := 1;
begin
   The_Day := Clock;
   Put_Line("Today is: " & To_String(Months(Month(The_Day))) &
      Day_Number'Image(Day(The_Day)) & "," &
      Year_Number'Image(Year(The_Day)));
   The_Day := The_Day + Increment;
   Put_Line("Tomorrow is: " & To_String(Months(Month(The_Day))) &
      Day_Number'Image(Day(The_Day)) & "," &
      Year_Number'Image(Year(The_Day)));
end Date_Format;


Forth

: str-table
  create ( n -- ) 0 do , loop
  does>  ( n -- str len ) swap cells + @ count ;
 here ," December"
 here ," November"
 here ," October"
 here ," September"
 here ," August"
 here ," July"
 here ," June"
 here ," May"
 here ," April"
 here ," March"
 here ," February"
 here ," January"
12 str-table months

: .long-date
  time&date ( s m h D M Y )
  >R 1- months type space 1 .r [char] , emit space R> .
  drop drop drop ;
: .-  [char] - emit ;
: .short-date
  time&date  1 .r .- 1 .r .- 1 .r  drop drop drop ;

Python

This task has been clarified. Its programming examples are in need of review to ensure that they still fit the requirements of the task.

Formatting rules: http://docs.python.org/lib/module-time.html (strftime)

from datetime import *

# Print today's date:
today = date.today()
print "Today is: ", today.strftime('%B %d, %Y')

# Print tomorrow's date:
tomorrow = today + timedelta( days=1 )
print "Tomorrow is: ", tomorrow.strftime('%B %d, %Y')

Raven

time int as today

Short form:

today '%Y-%m-%d' date

Long form:

today '%A, %B %d, %Y' date