Count in factors
You are encouraged to solve this task according to the task description, using any language you may know.
- Task
Write a program which counts up from 1, displaying each number as the multiplication of its prime factors.
For the purpose of this task, 1 (unity) may be shown as itself.
- Example
2 is prime, so it would be shown as itself.
6 is not prime; it would be shown as .
2144 is not prime; it would be shown as .
- Related tasks
- prime decomposition
- factors of an integer
- Sieve of Eratosthenes
- primality by trial division
- factors of a Mersenne number
- trial factoring of a Mersenne number
- partition an integer X into N primes
11l
<lang 11l>F get_prime_factors(=li)
I li == 1
R ‘1’
E
V res = ‘’
V f = 2
L
I li % f == 0
res ‘’= f
li /= f
I li == 1
L.break
res ‘’= ‘ x ’
E
f++
R res
L(x) 1..17
print(‘#4: #.’.format(x, get_prime_factors(x)))
print(‘2144: ’get_prime_factors(2144))</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5 11: 11 12: 2 x 2 x 3 13: 13 14: 2 x 7 15: 3 x 5 16: 2 x 2 x 2 x 2 17: 17 2144: 2 x 2 x 2 x 2 x 2 x 67
360 Assembly
<lang 360asm>* Count in factors 24/03/2017 COUNTFAC CSECT assist plig\COUNTFAC
USING COUNTFAC,R13 base register
B 72(R15) skip savearea
DC 17F'0' savearea
STM R14,R12,12(R13) save previous context
ST R13,4(R15) link backward
ST R15,8(R13) link forward
LR R13,R15 set addressability
L R6,=F'1' i=1
DO WHILE=(C,R6,LE,=F'40') do i=1 to 40
LR R7,R6 n=i
MVI F,X'01' f=true
MVC PG,=CL80' ' clear buffer
LA R10,PG pgi=0
XDECO R6,XDEC edit i
MVC 0(12,R10),XDEC output i
LA R10,12(R10) pgi=pgi+12
MVC 0(1,R10),=C'=' output '='
LA R10,1(R10) pgi=pgi+1
IF C,R7,EQ,=F'1' THEN if n=1 then
MVI 0(R10),C'1' output n
ELSE , else
LA R8,2 p=2
DO WHILE=(CR,R8,LE,R7) do while p<=n
LR R4,R7 n
SRDA R4,32 ~
DR R4,R8 /p
IF LTR,R4,Z,R4 THEN if n//p=0 then
IF CLI,F,EQ,X'00' THEN if not f then
MVC 0(1,R10),=C'*' output '*'
LA R10,1(R10) pgi=pgi+1
ELSE , else
MVI F,X'00' f=false
ENDIF , endif
CVD R8,PP convert bin p to packed pp
MVC WORK12,MASX12 in fact L13
EDMK WORK12,PP+2 edit and mark
LA R9,WORK12+12 end of string(p)
SR R9,R1 li=lengh(p) {r1 from edmk}
MVC EDIT12,WORK12 L12<-L13
LA R4,EDIT12+12 source+12
SR R4,R9 -lengh(p)
LR R5,R9 lengh(p)
LR R2,R10 target ix
LR R3,R9 lengh(p)
MVCL R2,R4 f=f||p
AR R10,R9 ix=ix+lengh(p)
LR R4,R7 n
SRDA R4,32 ~
DR R4,R8 /p
LR R7,R5 n=n/p
ELSE , else
LA R8,1(R8) p=p+1
ENDIF , endif
ENDDO , enddo while
ENDIF , endif
XPRNT PG,L'PG print buffer
LA R6,1(R6) i++
ENDDO , enddo i
L R13,4(0,R13) restore previous savearea pointer
LM R14,R12,12(R13) restore previous context
XR R15,R15 rc=0
BR R14 exit
F DS X flag first factor
DS 0D alignment for cvd
PP DS PL8 packed CL8 EDIT12 DS CL12 target CL12 WORK12 DS CL13 char CL13 MASX12 DC X'40',9X'20',X'212060' CL13 XDEC DS CL12 temp PG DS CL80 buffer
YREGS
END COUNTFAC</lang>
- Output:
1=1
2=2
3=3
4=2*2
5=5
6=2*3
7=7
8=2*2*2
9=3*3
10=2*5
11=11
12=2*2*3
13=13
14=2*7
15=3*5
16=2*2*2*2
17=17
18=2*3*3
19=19
20=2*2*5
21=3*7
22=2*11
23=23
24=2*2*2*3
25=5*5
26=2*13
27=3*3*3
28=2*2*7
29=29
30=2*3*5
31=31
32=2*2*2*2*2
33=3*11
34=2*17
35=5*7
36=2*2*3*3
37=37
38=2*19
39=3*13
40=2*2*2*5
Ada
The solution uses the generic package Prime_Numbers from Prime decomposition#Ada
- count.adb
<lang Ada>with Ada.Command_Line, Ada.Text_IO, Prime_Numbers;
procedure Count is
package Prime_Nums is new Prime_Numbers
(Number => Natural, Zero => 0, One => 1, Two => 2); use Prime_Nums;
procedure Put (List : Number_List) is
begin
for Index in List'Range loop
Ada.Text_IO.Put (Integer'Image (List (Index)));
if Index /= List'Last then
Ada.Text_IO.Put (" x");
end if;
end loop;
end Put;
N : Natural := 1;
Max_N : Natural := 15; -- the default for Max_N
begin
if Ada.Command_Line.Argument_Count = 1 then -- read Max_N from command line
Max_N := Integer'Value (Ada.Command_Line.Argument (1));
end if; -- else use the default
loop
Ada.Text_IO.Put (Integer'Image (N) & ": ");
Put (Decompose (N));
Ada.Text_IO.New_Line;
N := N + 1;
exit when N > Max_N;
end loop;
end Count;</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5 11: 11 12: 2 x 2 x 3 13: 13 14: 2 x 7 15: 3 x 5
ALGOL 68
<lang ALGOL68>OP +:= = (REF FLEX []INT a, INT b) VOID:
BEGIN
[⌈a + 1] INT c;
c[:⌈a] := a;
c[⌈a+1:] := b;
a := c
END;
PROC factorize = (INT nn) []INT:
BEGIN
IF nn = 1 THEN (1)
ELSE
INT k := 2, n := nn; FLEX[0]INT result; WHILE n > 1 DO WHILE n MOD k = 0 DO result +:= k; n := n % k OD; k +:= 1 OD; result
FI END;
FLEX[0]INT factors; FOR i TO 22 DO
factors := factorize (i);
print ((whole (i, 0), " = "));
FOR j TO UPB factors DO
(j /= 1 | print (" × "));
print ((whole (factors[j], 0)))
OD; print ((new line))
OD</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 × 2 5 = 5 6 = 2 × 3 7 = 7 8 = 2 × 2 × 2 9 = 3 × 3 10 = 2 × 5 11 = 11 12 = 2 × 2 × 3 13 = 13 14 = 2 × 7 15 = 3 × 5 16 = 2 × 2 × 2 × 2 17 = 17 18 = 2 × 3 × 3 19 = 19 20 = 2 × 2 × 5 21 = 3 × 7 22 = 2 × 11
AutoHotkey
<lang AutoHotkey>factorize(n){ if n = 1 return 1 if n < 1 return false result := 0, m := n, k := 2 While n >= k{ while !Mod(m, k){ result .= " * " . k, m /= k } k++ } return SubStr(result, 5) } Loop 22
out .= A_Index ": " factorize(A_index) "`n"
MsgBox % out</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 16: 2 * 2 * 2 * 2 17: 17 18: 2 * 3 * 3 19: 19 20: 2 * 2 * 5 21: 3 * 7 22: 2 * 11
AWK
<lang AWK>
- syntax: GAWK -f COUNT_IN_FACTORS.AWK
BEGIN {
fmt = "%d=%s\n"
for (i=1; i<=16; i++) {
printf(fmt,i,factors(i))
}
i = 2144; printf(fmt,i,factors(i))
i = 6358; printf(fmt,i,factors(i))
exit(0)
} function factors(n, f,p) {
if (n == 1) {
return(1)
}
p = 2
while (p <= n) {
if (n % p == 0) {
f = sprintf("%s%s*",f,p)
n /= p
}
else {
p++
}
}
return(substr(f,1,length(f)-1))
} </lang>
output:
1=1 2=2 3=3 4=2*2 5=5 6=2*3 7=7 8=2*2*2 9=3*3 10=2*5 11=11 12=2*2*3 13=13 14=2*7 15=3*5 16=2*2*2*2 2144=2*2*2*2*2*67 6358=2*11*17*17
BBC BASIC
<lang bbcbasic> FOR i% = 1 TO 20
PRINT i% " = " FNfactors(i%)
NEXT
END
DEF FNfactors(N%)
LOCAL P%, f$
IF N% = 1 THEN = "1"
P% = 2
WHILE P% <= N%
IF (N% MOD P%) = 0 THEN
f$ += STR$(P%) + " x "
N% DIV= P%
ELSE
P% += 1
ENDIF
ENDWHILE
= LEFT$(f$, LEN(f$) - 3)
</lang> Output:
1 = 1
2 = 2
3 = 3
4 = 2 x 2
5 = 5
6 = 2 x 3
7 = 7
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
11 = 11
12 = 2 x 2 x 3
13 = 13
14 = 2 x 7
15 = 3 x 5
16 = 2 x 2 x 2 x 2
17 = 17
18 = 2 x 3 x 3
19 = 19
20 = 2 x 2 x 5
Befunge
Lists the first 100 entries in the sequence. If you wish to extend that, the upper limit is implementation dependent, but may be as low as 130 for an interpreter with signed 8 bit data cells (131 is the first prime outside that range).
<lang befunge>1>>>>:.48*"=",,::1-#v_.v $<<<^_@#-"e":+1,+55$2<<< v4_^#-1:/.:g00_00g1+>>0v >8*"x",,:00g%!^!%g00:p0<</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 . . .
C
Code includes a dynamically extending prime number list. The program doesn't stop until you kill it, or it runs out of memory, or it overflows. <lang C>#include <stdio.h>
- include <stdlib.h>
typedef unsigned long long ULONG;
ULONG get_prime(int idx) {
static long n_primes = 0, alloc = 0;
static ULONG *primes = 0;
ULONG last, p;
int i;
if (idx >= n_primes) {
if (n_primes >= alloc) {
alloc += 16; /* be conservative */
primes = realloc(primes, sizeof(ULONG) * alloc);
}
if (!n_primes) {
primes[0] = 2;
primes[1] = 3;
n_primes = 2;
}
last = primes[n_primes-1];
while (idx >= n_primes) {
last += 2;
for (i = 0; i < n_primes; i++) {
p = primes[i];
if (p * p > last) {
primes[n_primes++] = last;
break;
}
if (last % p == 0) break;
}
}
}
return primes[idx];
}
int main() {
ULONG n, x, p;
int i, first;
for (x = 1; ; x++) {
printf("%lld = ", n = x);
for (i = 0, first = 1; ; i++) {
p = get_prime(i);
while (n % p == 0) {
n /= p;
if (!first) printf(" x ");
first = 0;
printf("%lld", p);
}
if (n <= p * p) break;
}
if (first) printf("%lld\n", n);
else if (n > 1) printf(" x %lld\n", n);
else printf("\n");
}
return 0;
}</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 . . .
C++
<lang Cpp>
- include <iostream>
- include <sstream>
- include <iomanip>
using namespace std;
void getPrimeFactors( int li ) {
int f = 2; string res;
if( li == 1 ) res = "1";
else
{
while( true ) { if( !( li % f ) ) { stringstream ss; ss << f; res += ss.str(); li /= f; if( li == 1 ) break; res += " x "; } else f++; }
} cout << res << "\n";
}
int main( int argc, char* argv[] ) {
for( int x = 1; x < 101; x++ )
{
cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x );
} cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" );
} </lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5 11: 11 12: 2 x 2 x 3 13: 13 14: 2 x 7 15: 3 x 5 16: 2 x 2 x 2 x 2 17: 17 18: 2 x 3 x 3 19: 19 20: 2 x 2 x 5 21: 3 x 7 22: 2 x 11 23: 23 24: 2 x 2 x 2 x 3 . . .
C#
<lang csharp>using System; using System.Collections.Generic;
namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } }
public static List<int> Factorize( int n ) { List<int> l = new List<int>();
if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }</lang>
Clojure
<lang lisp>(ns listfactors
(:gen-class))
(defn factors
"Return a list of factors of N."
([n]
(factors n 2 ()))
([n k acc]
(cond
(= n 1) (if (empty? acc)
[n]
(sort acc))
(>= k n) (if (empty? acc)
[n]
(sort (cons n acc)))
(= 0 (rem n k)) (recur (quot n k) k (cons k acc))
:else (recur n (inc k) acc))))
(doseq [q (range 1 26)]
(println q " = " (clojure.string/join " x "(factors q))))
</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 = 17 18 = 2 x 3 x 3 19 = 19 20 = 2 x 2 x 5 21 = 3 x 7 22 = 2 x 11 23 = 23 24 = 2 x 2 x 2 x 3 25 = 5 x 5
CoffeeScript
<lang coffeescript>count_primes = (max) ->
# Count through the natural numbers and give their prime
# factorization. This algorithm uses no division.
# Instead, each prime number starts a rolling odometer
# to help subsequent factorizations. The algorithm works similar
# to the Sieve of Eratosthenes, as we note when each prime number's
# odometer rolls a digit. (As it turns out, as long as your computer
# is not horribly slow at division, you're better off just doing simple
# prime factorizations on each new n vs. using this algorithm.)
console.log "1 = 1"
primes = []
n = 2
while n <= max
factors = []
for prime_odometer in primes
# digits are an array w/least significant digit in
# position 0; for example, [3, [0]] will roll as
# follows:
# [0] -> [1] -> [2] -> [0, 1]
[base, digits] = prime_odometer
i = 0
while true
digits[i] += 1
break if digits[i] < base
digits[i] = 0
factors.push base
i += 1
if i >= digits.length
digits.push 0
if factors.length == 0
primes.push [n, [0, 1]]
factors.push n
console.log "#{n} = #{factors.join('*')}"
n += 1
primes.length
num_primes = count_primes 10000 console.log num_primes</lang>
Common Lisp
Auto extending prime list: <lang lisp>(defparameter *primes*
(make-array 10 :adjustable t :fill-pointer 0 :element-type 'integer))
(mapc #'(lambda (x) (vector-push x *primes*)) '(2 3 5 7))
(defun extend-primes (n)
(let ((p (+ 2 (elt *primes* (1- (length *primes*)))))) (loop for i = p then (+ 2 i)
while (<= (* i i) n) do (if (primep i t) (vector-push-extend i *primes*)))))
(defun primep (n &optional skip)
(if (not skip) (extend-primes n))
(if (= n 1) nil
(loop for p across *primes* while (<= (* p p) n)
never (zerop (mod n p)))))
(defun factors (n)
(extend-primes n) (loop with res for x across *primes* while (> n (* x x)) do
(loop while (zerop (rem n x)) do (setf n (/ n x)) (push x res)) finally (return (if (> n 1) (cons n res) res))))
(loop for n from 1 do
(format t "~a: ~{~a~^ × ~}~%" n (reverse (factors n))))</lang>
- Output:
1: 2: 2 3: 3 4: 4 5: 5 6: 2 × 3 7: 7 8: 2 × 2 × 2 9: 9 10: 2 × 5 11: 11 12: 2 × 2 × 3 13: 13 14: 2 × 7 ...
Without saving the primes, and not all that much slower (probably because above code was not well-written): <lang lisp>(defun factors (n)
(loop with res for x from 2 to (isqrt n) do
(loop while (zerop (rem n x)) do (setf n (/ n x)) (push x res)) finally (return (if (> n 1) (cons n res) res))))
(loop for n from 1 do
(format t "~a: ~{~a~^ × ~}~%" n (reverse (factors n))))</lang>
D
<lang d>int[] factorize(in int n) pure nothrow in {
assert(n > 0);
} body {
if (n == 1) return [1];
int[] result;
int m = n, k = 2;
while (n >= k) {
while (m % k == 0) {
result ~= k;
m /= k;
}
k++;
}
return result;
}
void main() {
import std.stdio;
foreach (i; 1 .. 22)
writefln("%d: %(%d × %)", i, i.factorize());
}</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 × 2 5: 5 6: 2 × 3 7: 7 8: 2 × 2 × 2 9: 3 × 3 10: 2 × 5 11: 11 12: 2 × 2 × 3 13: 13 14: 2 × 7 15: 3 × 5 16: 2 × 2 × 2 × 2 17: 17 18: 2 × 3 × 3 19: 19 20: 2 × 2 × 5 21: 3 × 7
Alternative Version
Library uiprimes is a homebrew library to generate prime numbers upto the maximum 32bit unsigned integer range 2^32-1, by using a pre-generated bit array of Sieve of Eratosthenes (a dll in size of ~256M bytes :p ).
<lang d>import std.stdio, std.math, std.conv, std.algorithm,
std.array, std.string, import xt.uiprimes;
pragma(lib, "uiprimes.lib");
// function _factorize_ included in uiprimes.lib ulong[] factorize(ulong n) {
if (n == 0) return [];
if (n == 1) return [1];
ulong[] res;
uint limit = cast(uint)(1 + sqrt(n));
foreach (p; Primes(limit)) {
if (n == 1) break;
if (0UL == (n % p))
while((n > 1) && (0UL == (n % p ))) {
res ~= p;
n /= p;
}
}
if (n > 1)
res ~= [n];
return res;
}
string productStr(T)(in T[] nums) {
return nums.map!text().join(" x ");
}
void main() {
foreach (i; 1 .. 21)
writefln("%2d = %s", i, productStr(factorize(i)));
}</lang>
DCL
Assumes file primes.txt is a list of prime numbers; <lang DCL>$ close /nolog primes $ on control_y then $ goto clean $ $ n = 1 $ outer_loop: $ x = n $ open primes primes.txt $ $ loop1: $ read /end_of_file = prime primes prime $ prime = f$integer( prime ) $ loop2: $ t = x / prime $ if t * prime .eq. x $ then $ if f$type( factorization ) .eqs. "" $ then $ factorization = f$string( prime ) $ else $ factorization = factorization + "*" + f$string( prime ) $ endif $ if t .eq. 1 then $ goto done $ x = t $ goto loop2 $ else $ goto loop1 $ endif $ prime: $ if f$type( factorization ) .eqs. "" $ then $ factorization = f$string( x ) $ else $ factorization = factorization + "*" + f$string( x ) $ endif $ done: $ write sys$output f$fao( "!4SL = ", n ), factorization $ delete /symbol factorization $ close primes $ n = n + 1 $ if n .le. 2144 then $ goto outer_loop $ exit $ $ clean: $ close /nolog primes</lang>
- Output:
$ @count_in_factors 1 = 1 2 = 2 3 = 3 4 = 2*2 5 = 5 6 = 2*3 ... 2144 = 2*2*2*2*2*67
DWScript
<lang delphi>function Factorize(n : Integer) : String; begin
if n <= 1 then
Exit('1');
var k := 2;
while n >= k do begin
while (n mod k) = 0 do begin
Result += ' * '+IntToStr(k);
n := n div k;
end;
Inc(k);
end;
Result:=SubStr(Result, 4);
end;
var i : Integer; for i := 1 to 22 do
PrintLn(IntToStr(i) + ': ' + Factorize(i));</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 16: 2 * 2 * 2 * 2 17: 17 18: 2 * 3 * 3 19: 19 20: 2 * 2 * 5 21: 3 * 7 22: 2 * 11
EchoLisp
<lang scheme> (define (task (nfrom 2) (range 20))
(for ((i (in-range nfrom (+ nfrom range))))
(writeln i "=" (string-join (prime-factors i) " x "))))
</lang>
- Output:
(task 1_000_000_000) 1000000000 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 1000000001 = 7 x 11 x 13 x 19 x 52579 1000000002 = 2 x 3 x 43 x 983 x 3943 1000000003 = 23 x 307 x 141623 1000000004 = 2 x 2 x 41 x 41 x 148721 1000000005 = 3 x 5 x 66666667 1000000006 = 2 x 500000003 1000000007 = 1000000007 1000000008 = 2 x 2 x 2 x 3 x 3 x 7 x 109 x 109 x 167 1000000009 = 1000000009 1000000010 = 2 x 5 x 17 x 5882353 1000000011 = 3 x 29 x 11494253 1000000012 = 2 x 2 x 11 x 47 x 79 x 6121 1000000013 = 7699 x 129887 1000000014 = 2 x 3 x 13 x 103 x 124471 1000000015 = 5 x 7 x 31 x 223 x 4133 1000000016 = 2 x 2 x 2 x 2 x 62500001 1000000017 = 3 x 3 x 111111113 1000000018 = 2 x 500000009 1000000019 = 83 x 12048193
Eiffel
<lang Eiffel>
class COUNT_IN_FACTORS
feature
display_factor (p: INTEGER) -- Factors of all integers up to 'p'. require p_positive: p > 0 local factors: ARRAY [INTEGER] do across 1 |..| p as c loop io.new_line io.put_string (c.item.out + "%T") factors := factor (c.item) across factors as f loop io.put_integer (f.item) if f.is_last = False then io.put_string (" x ") end end end end
factor (p: INTEGER): ARRAY [INTEGER]
-- Prime decomposition of 'p'. require p_positive: p > 0 local div, i, next, rest: INTEGER do create Result.make_empty if p = 1 then Result.force (1, 1) end div := 2 next := 3 rest := p from i := 1 until rest = 1 loop from until rest \\ div /= 0 loop Result.force (div, i) rest := (rest / div).floor i := i + 1 end div := next next := next + 2 end ensure is_divisor: across Result as r all p \\ r.item = 0 end end end
</lang> Test Output:
1 1 2 2 3 3 4 2 x 2 5 5 6 2 x 3 7 7 8 2 x 2 x 2 9 3 x 3 10 2 x 5 ... 4990 2 x 5 x 499 4991 7 x 23 x 31 4992 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 13 4993 4993 4994 2 x 11 x 227 4995 3 x 3 x 3 x 5 x 37 4996 2 x 2 x 1249 4997 19 x 263 4998 2 x 3 x 7 x 7 x 17 4999 4999 5000 2 x 2 x 2 x 5 x 5 x 5 x 5
Elixir
<lang elixir>defmodule RC do
def factor(n), do: factor(n, 2, [])
def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact])
def factor(n, i, fact) do
if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]),
else: factor(n, i+1, fact)
end
end
Enum.each(1..20, fn n ->
IO.puts "#{n}: #{Enum.join(RC.factor(n)," x ")}" end)</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5 11: 11 12: 2 x 2 x 3 13: 13 14: 2 x 7 15: 3 x 5 16: 2 x 2 x 2 x 2 17: 17 18: 2 x 3 x 3 19: 19 20: 2 x 2 x 5
Euphoria
<lang euphoria>function factorize(integer n)
sequence result
integer k
if n = 1 then
return {1}
else
k = 2
result = {}
while n > 1 do
while remainder(n, k) = 0 do
result &= k
n /= k
end while
k += 1
end while
return result
end if
end function
sequence factors for i = 1 to 22 do
printf(1, "%d: ", i)
factors = factorize(i)
for j = 1 to length(factors)-1 do
printf(1, "%d * ", factors[j])
end for
printf(1, "%d\n", factors[$])
end for</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 16: 2 * 2 * 2 * 2 17: 17 18: 2 * 3 * 3 19: 19 20: 2 * 2 * 5 21: 3 * 7 22: 2 * 11
F#
<lang fsharp>let factorsOf (num) =
Seq.unfold (fun (f, n) ->
let rec genFactor (f, n) =
if f > n then None
elif n % f = 0 then Some (f, (f, n/f))
else genFactor (f+1, n)
genFactor (f, n)) (2, num)
let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))})
showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 * 2 5 = 5 6 = 2 * 3 7 = 7 8 = 2 * 2 * 2 9 = 3 * 3 10 = 2 * 5 : 2140 = 2 * 2 * 5 * 107 2141 = 2141 2142 = 2 * 3 * 3 * 7 * 17 2143 = 2143 2144 = 2 * 2 * 2 * 2 * 2 * 67 2145 = 3 * 5 * 11 * 13 2146 = 2 * 29 * 37 2147 = 19 * 113 :
Factor
<lang factor> USING: math.parser math.primes.factors math.ranges ; IN: scratchpad "1: 1" print 2 20 [a,b] [ dup pprint ": " write factors [ number>string ] map " x " join print ] each </lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5 11: 11 12: 2 x 2 x 3 13: 13 14: 2 x 7 15: 3 x 5 16: 2 x 2 x 2 x 2 17: 17 18: 2 x 3 x 3 19: 19 20: 2 x 2 x 5
Forth
<lang forth>: .factors ( n -- )
2
begin 2dup dup * >=
while 2dup /mod swap
if drop 1+ 1 or \ next odd number
else -rot nip dup . ." x "
then
repeat
drop . ;
- main ( n -- )
." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ;
15 main bye</lang>
Fortran
Please find the example output along with the build instructions in the comments at the start of the FORTRAN 2008 source. Compiler: gfortran from the GNU compiler collection. Command interpreter: bash. The code writes j assertions which don't prove primality of the factors but does prove they are the factors.
This algorithm creates a sieve of Eratosthenes, storing the largest prime factor to mark composites. It then finds prime factors by repeatedly looking up the value in the sieve, then dividing by the factor found until the value is itself prime. Using the sieve table to store factors rather than as a plain bitmap was to me a novel idea.
<lang FORTRAN> !-*- mode: compilation; default-directory: "/tmp/" -*- !Compilation started at Thu Jun 6 23:29:06 ! !a=./f && make $a && echo -2 | OMP_NUM_THREADS=2 $a !gfortran -std=f2008 -Wall -fopenmp -ffree-form -fall-intrinsics -fimplicit-none f.f08 -o f ! assert 1 = */ 1 ! assert 2 = */ 2 ! assert 3 = */ 3 ! assert 4 = */ 2 2 ! assert 5 = */ 5 ! assert 6 = */ 2 3 ! assert 7 = */ 7 ! assert 8 = */ 2 2 2 ! assert 9 = */ 3 3 ! assert 10 = */ 2 5 ! assert 11 = */ 11 ! assert 12 = */ 3 2 2 ! assert 13 = */ 13 ! assert 14 = */ 2 7 ! assert 15 = */ 3 5 ! assert 16 = */ 2 2 2 2 ! assert 17 = */ 17 ! assert 18 = */ 3 2 3 ! assert 19 = */ 19 ! assert 20 = */ 2 2 5 ! assert 21 = */ 3 7 ! assert 22 = */ 2 11 ! assert 23 = */ 23 ! assert 24 = */ 3 2 2 2 ! assert 25 = */ 5 5 ! assert 26 = */ 2 13 ! assert 27 = */ 3 3 3 ! assert 28 = */ 2 2 7 ! assert 29 = */ 29 ! assert 30 = */ 5 2 3 ! assert 31 = */ 31 ! assert 32 = */ 2 2 2 2 2 ! assert 33 = */ 3 11 ! assert 34 = */ 2 17 ! assert 35 = */ 5 7 ! assert 36 = */ 3 3 2 2 ! assert 37 = */ 37 ! assert 38 = */ 2 19 ! assert 39 = */ 3 13 ! assert 40 = */ 5 2 2 2
module prime_mod
! sieve_table stores 0 in prime numbers, and a prime factor in composites. integer, dimension(:), allocatable :: sieve_table private :: PrimeQ
contains
! setup routine must be called first!
subroutine sieve(n) ! populate sieve_table. If n is 0 it deallocates storage, invalidating sieve_table.
integer, intent(in) :: n
integer :: status, i, j
if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table)
if (n .lt. 1) return
allocate(sieve_table(n), stat=status)
if (status .ne. 0) stop 'cannot allocate space'
sieve_table(1) = 1
do i=2,int(sqrt(real(n)))+1
if (sieve_table(i) .eq. 0) then
do j = i*i, n, i
sieve_table(j) = i
end do
end if
end do
end subroutine sieve
subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve
logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime
logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite
logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ
subroutine prime_factors(p, rv, n)
integer, intent(in) :: p ! number to factor
integer, dimension(:), intent(out) :: rv ! the prime factors
integer, intent(out) :: n ! number of factors returned
integer :: i, m
call check_sieve(p)
m = p
i = 1
if (p .ne. 1) then
do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv)))
rv(i) = sieve_table(m)
m = m/rv(i)
i = i+1
end do
end if
if (i .le. size(rv)) rv(i) = m
n = i
end subroutine prime_factors
end module prime_mod
program count_in_factors
use prime_mod
integer :: i, n
integer, dimension(8) :: factors
call sieve(40) ! setup
do i=1,40
factors = 0
call prime_factors(i, factors, n)
write(6,*)'assert',i,'= */',factors(:n)
end do
call sieve(0) ! release memory
end program count_in_factors </lang>
FreeBASIC
<lang freebasic>' FB 1.05.0 Win64
Sub getPrimeFactors(factors() As UInteger, n As UInteger)
If n < 2 Then Return
Dim factor As UInteger = 2
Do
If n Mod factor = 0 Then
Redim Preserve factors(0 To UBound(factors) + 1)
factors(UBound(factors)) = factor
n \= factor
If n = 1 Then Return
Else
factor += 1
End If
Loop
End Sub
Dim factors() As UInteger
For i As UInteger = 1 To 20
Print Using "##"; i;
Print " = ";
If i > 1 Then
Erase factors
getPrimeFactors factors(), i
For j As Integer = LBound(factors) To UBound(factors)
Print factors(j);
If j < UBound(factors) Then Print " x ";
Next j
Print
Else
Print i
End If
Next i
Print Print "Press any key to quit" Sleep</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 = 17 18 = 2 x 3 x 3 19 = 19 20 = 2 x 2 x 5
Frink
Frink's factoring routines work on arbitrarily-large integers. <lang frink>i = 1 while true {
println[join[" x ", factorFlat[i]]] i = i + 1
}</lang>
Go
<lang go>package main
import "fmt"
func main() {
fmt.Println("1: 1")
for i := 2; ; i++ {
fmt.Printf("%d: ", i)
var x string
for n, f := i, 2; n != 1; f++ {
for m := n % f; m == 0; m = n % f {
fmt.Print(x, f)
x = "×"
n /= f
}
}
fmt.Println()
}
}</lang>
- Output:
1: 1 2: 2 3: 3 4: 2×2 5: 5 6: 2×3 7: 7 8: 2×2×2 9: 3×3 10: 2×5 ...
Groovy
<lang groovy>def factors(number) {
if (number == 1) {
return [1]
}
def factors = []
BigInteger value = number
BigInteger possibleFactor = 2
while (possibleFactor <= value) {
if (value % possibleFactor == 0) {
factors << possibleFactor
value /= possibleFactor
} else {
possibleFactor++
}
}
factors
} Number.metaClass.factors = { factors(delegate) }
((1..10) + (6351..6359)).each { number ->
println "$number = ${number.factors().join(' x ')}"
}</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 6351 = 3 x 29 x 73 6352 = 2 x 2 x 2 x 2 x 397 6353 = 6353 6354 = 2 x 3 x 3 x 353 6355 = 5 x 31 x 41 6356 = 2 x 2 x 7 x 227 6357 = 3 x 13 x 163 6358 = 2 x 11 x 17 x 17 6359 = 6359
Haskell
Using factorize function from the prime decomposition task,
<lang haskell>import Data.List (intercalate)
showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n -- Pointfree form showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)</lang> isPrime n = n > 1 && noDivsBy primeNums n
- Output:
<lang haskell>Main> print 1 >> mapM_ (putStrLn . showFactors) [2..] 1 2 = 2 3 = 3 4 = 2 * 2 5 = 5 6 = 2 * 3 7 = 7 8 = 2 * 2 * 2 9 = 3 * 3 10 = 2 * 5 11 = 11 12 = 2 * 2 * 3 . . .
Main> mapM_ (putStrLn . showFactors) [2144..] 2144 = 2 * 2 * 2 * 2 * 2 * 67 2145 = 3 * 5 * 11 * 13 2146 = 2 * 29 * 37 2147 = 19 * 113 2148 = 2 * 2 * 3 * 179 2149 = 7 * 307 2150 = 2 * 5 * 5 * 43 2151 = 3 * 3 * 239 2152 = 2 * 2 * 2 * 269 2153 = 2153 2154 = 2 * 3 * 359 . . .
Main> mapM_ (putStrLn . showFactors) [121231231232155..] 121231231232155 = 5 * 11 * 419 * 5260630559 121231231232156 = 2 * 2 * 97 * 1061 * 294487867 121231231232157 = 3 * 3 * 3 * 131 * 34275157261 121231231232158 = 2 * 19 * 67 * 1231 * 38681033 121231231232159 = 121231231232159 121231231232160 = 2 * 2 * 2 * 2 * 2 * 3 * 5 * 7 * 7 * 5154389083 121231231232161 = 121231231232161 121231231232162 = 2 * 60615615616081 121231231232163 = 3 * 13 * 83 * 191089 * 195991 121231231232164 = 2 * 2 * 253811 * 119410931 121231231232165 = 5 * 137 * 176979899609 . . .</lang> The real solution seems to have to be some sort of a segmented offset sieve of Eratosthenes, storing factors in array's cells instead of just marks. That way the speed of production might not be diminishing as much.
Icon and Unicon
<lang Icon>procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do {
writes(i," : [")
every writes(" ",!f|"]\n")
}
end
link factors</lang>
- Output:
1 : [ 1 ] 2 : [ 2 ] 3 : [ 3 ] 4 : [ 2 2 ] 5 : [ 5 ] 6 : [ 2 3 ] 7 : [ 7 ] 8 : [ 2 2 2 ] 9 : [ 3 3 ] 10 : [ 2 5 ] 11 : [ 11 ] 12 : [ 2 2 3 ] 13 : [ 13 ] 14 : [ 2 7 ] 15 : [ 3 5 ] 16 : [ 2 2 2 2 ] ...
IS-BASIC
<lang IS-BASIC>100 PROGRAM "Factors.bas" 110 FOR I=1 TO 30 120 PRINT I;"= ";FACTORS$(I) 130 NEXT 140 DEF FACTORS$(N) 150 LET F$="" 160 IF N=1 THEN 170 LET FACTORS$="1" 180 ELSE 190 LET P=2 200 DO WHILE P<=N 210 IF MOD(N,P)=0 THEN 220 LET F$=F$&STR$(P)&"*" 230 LET N=INT(N/P) 240 ELSE 250 LET P=P+1 260 END IF 270 LOOP 280 LET FACTORS$=F$(1:LEN(F$)-1) 290 END IF 300 END DEF</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2*2 5 = 5 6 = 2*3 7 = 7 8 = 2*2*2 9 = 3*3 10 = 2*5 11 = 11 12 = 2*2*3 13 = 13 14 = 2*7 15 = 3*5 16 = 2*2*2*2 17 = 17 18 = 2*3*3 19 = 19 20 = 2*2*5 21 = 3*7 22 = 2*11 23 = 23 24 = 2*2*2*3 25 = 5*5 26 = 2*13 27 = 3*3*3 28 = 2*2*7 29 = 29 30 = 2*3*5
J
Solution:Use J's factoring primitive, <lang j>q:</lang> Example (including formatting):<lang j> ('1 : 1',":&> ,"1 ': ',"1 ":@q:) 2+i.10 1 : 1 2 : 2 3 : 3 4 : 2 2 5 : 5 6 : 2 3 7 : 7 8 : 2 2 2 9 : 3 3 10: 2 5 11: 11</lang>
Java
<lang java>public class CountingInFactors{
public static void main(String[] args){
for(int i = 1; i<= 10; i++){
System.out.println(i + " = "+ countInFactors(i));
}
for(int i = 9991; i <= 10000; i++){
System.out.println(i + " = "+ countInFactors(i));
}
}
private static String countInFactors(int n){
if(n == 1) return "1";
StringBuilder sb = new StringBuilder();
n = checkFactor(2, n, sb);
if(n == 1) return sb.toString();
n = checkFactor(3, n, sb);
if(n == 1) return sb.toString();
for(int i = 5; i <= n; i+= 2){
if(i % 3 == 0)continue;
n = checkFactor(i, n, sb);
if(n == 1)break;
}
return sb.toString();
}
private static int checkFactor(int mult, int n, StringBuilder sb){
while(n % mult == 0 ){
if(sb.length() > 0) sb.append(" x ");
sb.append(mult);
n /= mult;
}
return n;
}
}</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 9991 = 97 x 103 9992 = 2 x 2 x 2 x 1249 9993 = 3 x 3331 9994 = 2 x 19 x 263 9995 = 5 x 1999 9996 = 2 x 2 x 3 x 7 x 7 x 17 9997 = 13 x 769 9998 = 2 x 4999 9999 = 3 x 3 x 11 x 101 10000 = 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
JavaScript
<lang javascript>for(i = 1; i <= 10; i++)
console.log(i + " : " + factor(i).join(" x "));
function factor(n) {
var factors = [];
if (n == 1) return [1];
for(p = 2; p <= n; ) {
if((n % p) == 0) { factors[factors.length] = p; n /= p; } else p++;
} return factors;
}</lang>
- Output:
1 : 1 2 : 2 3 : 3 4 : 2 x 2 5 : 5 6 : 2 x 3 7 : 7 8 : 2 x 2 x 2 9 : 3 x 3 10 : 2 x 5
Julia
<lang julia>using Primes, Printf function strfactor(n::Integer)
n > -2 || return "-1 × " * strfactor(-n)
isprime(n) || n < 2 && return dec(n)
f = factor(Vector{typeof(n)}, n)
return join(f, " × ")
end
lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi
@printf("%5d = %s\n", n, strfactor(n))
end</lang>
- Output:
Factor print -4 to 40:
-4 = -1 × 2 × 2
-3 = -1 × 3
-2 = -1 × 2
-1 = -1
0 = 0
1 = 1
2 = 2
3 = 3
4 = 2 × 2
5 = 5
6 = 2 × 3
7 = 7
8 = 2 × 2 × 2
9 = 3 × 3
10 = 2 × 5
11 = 11
12 = 2 × 2 × 3
13 = 13
14 = 2 × 7
15 = 3 × 5
16 = 2 × 2 × 2 × 2
17 = 17
18 = 2 × 3 × 3
19 = 19
20 = 2 × 2 × 5
21 = 3 × 7
22 = 2 × 11
23 = 23
24 = 2 × 2 × 2 × 3
25 = 5 × 5
26 = 2 × 13
27 = 3 × 3 × 3
28 = 2 × 2 × 7
29 = 29
30 = 2 × 3 × 5
31 = 31
32 = 2 × 2 × 2 × 2 × 2
33 = 3 × 11
34 = 2 × 17
35 = 5 × 7
36 = 2 × 2 × 3 × 3
37 = 37
38 = 2 × 19
39 = 3 × 13
40 = 2 × 2 × 2 × 5
Kotlin
<lang scala>// version 1.1.2
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun getPrimeFactors(n: Int): List<Int> {
val factors = mutableListOf<Int>()
if (n < 1) return factors
if (n == 1 || isPrime(n)) {
factors.add(n)
return factors
}
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return factors
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun main(args: Array<String>) {
val list = (MutableList(22) { it + 1 } + 2144) + 6358
for (i in list)
println("${"%4d".format(i)} = ${getPrimeFactors(i).joinToString(" * ")}")
}</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 * 2 5 = 5 6 = 2 * 3 7 = 7 8 = 2 * 2 * 2 9 = 3 * 3 10 = 2 * 5 11 = 11 12 = 2 * 2 * 3 13 = 13 14 = 2 * 7 15 = 3 * 5 16 = 2 * 2 * 2 * 2 17 = 17 18 = 2 * 3 * 3 19 = 19 20 = 2 * 2 * 5 21 = 3 * 7 22 = 2 * 11 2144 = 2 * 2 * 2 * 2 * 2 * 67 6358 = 2 * 11 * 17 * 17
Liberty BASIC
<lang lb> 'see Run BASIC solution for i = 1000 to 1016
print i;" = "; factorial$(i)
next wait function factorial$(num)
if num = 1 then factorial$ = "1" fct = 2 while fct <= num if (num mod fct) = 0 then factorial$ = factorial$ ; x$ ; fct x$ = " x " num = num / fct else fct = fct + 1 end if wend
end function </lang>
- Output:
1000 = 2 x 2 x 2 x 5 x 5 x 5 1001 = 7 x 11 x 13 1002 = 2 x 3 x 167 1003 = 17 x 59 1004 = 2 x 2 x 251 1005 = 3 x 5 x 67 1006 = 2 x 503 1007 = 19 x 53 1008 = 2 x 2 x 2 x 2 x 3 x 3 x 7 1009 = 1009 1010 = 2 x 5 x 101 1011 = 3 x 337 1012 = 2 x 2 x 11 x 23 1013 = 1013 1014 = 2 x 3 x 13 x 13 1015 = 5 x 7 x 29 1016 = 2 x 2 x 2 x 127
Lua
<lang Lua>function factorize( n )
if n == 1 then return {1} end
local k = 2
res = {}
while n > 1 do
while n % k == 0 do res[#res+1] = k
n = n / k
end
k = k + 1 end return res
end
for i = 1, 22 do
io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do
io.write( " * ", fac[j] )
end print ""
end</lang>
M2000 Interpreter
Decompose function now return array (in number decomposition task return an inventory list).
<lang M2000 Interpreter> Module Count_in_factors { Inventory Known1=2@, 3@ IsPrime=lambda Known1 (x as decimal) -> { =0=1 if exist(Known1, x) then =1=1 : exit if x<=5 OR frac(x) then {if x == 2 OR x == 3 OR x == 5 then Append Known1, x : =1=1 Break} if frac(x/2) else exit if frac(x/3) else exit x1=sqrt(x):d = 5@ {if frac(x/d ) else exit d += 2: if d>x1 then Append Known1, x : =1=1 : exit if frac(x/d) else exit d += 4: if d<= x1 else Append Known1, x : =1=1: exit loop } } decompose=lambda IsPrime (n as decimal) -> { Factors=(,) { k=2@ While frac(n/k)=0 n/=k Append Factors, (k,) End While if n=1 then exit k++ While frac(n/k)=0 n/=k Append Factors, (k,) End While if n=1 then exit { k+=2 while not isprime(k) {k+=2} While frac(n/k)=0 n/=k : Append Factors, (k,) End While if n=1 then exit loop } } =Factors } fold=lambda (a, f$)->{ Push if$(len(f$)=0->f$, f$+"x")+str$(a,"") } Print "1=1" i=1@ do i++ Print str$(i,"")+"="+Decompose(i)#fold$(fold,"") always } Count_in_factors </lang>
M4
<lang M4>define(`for',
`ifelse($#,0,``$0, `ifelse(eval($2<=$3),1, `pushdef(`$1',$2)$5`'popdef(`$1')$0(`$1',eval($2+$4),$3,$4,`$5')')')')dnl
define(`by',
`ifelse($1,$2,
$1,
`ifelse(eval($1%$2==0),1,
`$2 x by(eval($1/$2),$2)',
`by($1,eval($2+1))') ') ')dnl
define(`wby',
`$1 = ifelse($1,1,
$1,
`by($1,2)') ')dnl
for(`y',1,25,1, `wby(y) ')</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 = 17 18 = 2 x 3 x 3 19 = 19 20 = 2 x 2 x 5 21 = 3 x 7 22 = 2 x 11 23 = 23 24 = 2 x 2 x 2 x 3 25 = 5 x 5
Maple
<lang maple>factorNum := proc(n) local i, j, firstNum; if n = 1 then printf("%a", 1); end if; firstNum := true: for i in ifactors(n)[2] do for j to i[2] do if firstNum then printf ("%a", i[1]); firstNum := false: else printf(" x %a", i[1]); end if; end do; end do; printf("\n"); return NULL; end proc:
for i from 1 to 10 do printf("%2a: ", i); factorNum(i); end do;</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5
Mathematica / Wolfram Language
<lang Mathematica>n = 2; While[n < 100,
Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]</lang>
NetRexx
<lang NetRexx>/* NetRexx */ options replace format comments java crossref symbols nobinary
runSample(arg) return
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ method factor(val) public static
rv = 1
if val > 1 then do
rv =
loop n_ = val until n_ = 1
parse checkFactor(2, n_, rv) n_ rv
if n_ = 1 then leave n_
parse checkFactor(3, n_, rv) n_ rv
if n_ = 1 then leave n_
loop m_ = 5 to n_ by 2 until n_ = 1
if m_ // 3 = 0 then iterate m_
parse checkFactor(m_, n_, rv) n_ rv
end m_
end n_
end
return rv
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ method checkFactor(mult = long, n_ = long, fac) private static binary
msym = 'x'
loop while n_ // mult = 0
fac = fac msym mult
n_ = n_ % mult
end
fac = (fac.strip).strip('l', msym).space
return n_ fac
-- ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ method runSample(arg) private static
-- input is a list of pairs of numbers - no checking is done
if arg = then arg = '1 11 89 101 1000 1020 10000 10010'
loop while arg \=
parse arg lv rv arg
say
say '-'.copies(60)
say lv.right(8) 'to' rv
say '-'.copies(60)
loop fv = lv to rv
fac = factor(fv)
pv =
if fac.words = 1 & fac \= 1 then pv = '<prime>'
say fv.right(8) '=' fac pv
end fv
end
return
</lang>
- Output:
------------------------------------------------------------
1 to 11
------------------------------------------------------------
1 = 1
2 = 2 <prime>
3 = 3 <prime>
4 = 2 x 2
5 = 5 <prime>
6 = 2 x 3
7 = 7 <prime>
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
11 = 11 <prime>
------------------------------------------------------------
89 to 101
------------------------------------------------------------
89 = 89 <prime>
90 = 2 x 3 x 3 x 5
91 = 7 x 13
92 = 2 x 2 x 23
93 = 3 x 31
94 = 2 x 47
95 = 5 x 19
96 = 2 x 2 x 2 x 2 x 2 x 3
97 = 97 <prime>
98 = 2 x 7 x 7
99 = 3 x 3 x 11
100 = 2 x 2 x 5 x 5
101 = 101 <prime>
------------------------------------------------------------
1000 to 1020
------------------------------------------------------------
1000 = 2 x 2 x 2 x 5 x 5 x 5
1001 = 7 x 11 x 13
1002 = 2 x 3 x 167
1003 = 17 x 59
1004 = 2 x 2 x 251
1005 = 3 x 5 x 67
1006 = 2 x 503
1007 = 19 x 53
1008 = 2 x 2 x 2 x 2 x 3 x 3 x 7
1009 = 1009 <prime>
1010 = 2 x 5 x 101
1011 = 3 x 337
1012 = 2 x 2 x 11 x 23
1013 = 1013 <prime>
1014 = 2 x 3 x 13 x 13
1015 = 5 x 7 x 29
1016 = 2 x 2 x 2 x 127
1017 = 3 x 3 x 113
1018 = 2 x 509
1019 = 1019 <prime>
1020 = 2 x 2 x 3 x 5 x 17
------------------------------------------------------------
10000 to 10010
------------------------------------------------------------
10000 = 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
10001 = 73 x 137
10002 = 2 x 3 x 1667
10003 = 7 x 1429
10004 = 2 x 2 x 41 x 61
10005 = 3 x 5 x 23 x 29
10006 = 2 x 5003
10007 = 10007 <prime>
10008 = 2 x 2 x 2 x 3 x 3 x 139
10009 = 10009 <prime>
10010 = 2 x 5 x 7 x 11 x 13
Nim
<lang nim>var primes = newSeq[int]()
proc getPrime(idx: int): int =
if idx >= primes.len:
if primes.len == 0:
primes.add 2
primes.add 3
var last = primes[primes.high]
while idx >= primes.len:
last += 2
for i, p in primes:
if p * p > last:
primes.add last
break
if last mod p == 0:
break
return primes[idx]
for x in 1 ..< int32.high.int:
stdout.write x, " = " var n = x var first = 1
for i in 0 ..< int32.high:
let p = getPrime(i)
while n mod p == 0:
n = n div p
if first == 0: stdout.write " x "
first = 0
stdout.write p
if n <= p * p:
break
if first > 0: echo n elif n > 1: echo " x ", n else: echo ""</lang>
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 ...
Objeck
<lang objeck> class CountingInFactors {
function : Main(args : String[]) ~ Nil {
for(i := 1; i <= 10; i += 1;){
count := CountInFactors(i);
("{$i} = {$count}")->PrintLine();
};
for(i := 9991; i <= 10000; i += 1;){
count := CountInFactors(i);
("{$i} = {$count}")->PrintLine();
};
}
function : CountInFactors(n : Int) ~ String {
if(n = 1) {
return "1";
};
sb := "";
n := CheckFactor(2, n, sb);
if(n = 1) {
return sb;
};
n := CheckFactor(3, n, sb);
if(n = 1) {
return sb;
};
for(i := 5; i <= n; i += 2;) {
if(i % 3 <> 0) {
n := CheckFactor(i, n, sb);
if(n = 1) {
break;
};
};
};
return sb; }
function : CheckFactor(mult : Int, n : Int, sb : String) ~ Int {
while(n % mult = 0 ) {
if(sb->Size() > 0) {
sb->Append(" x ");
};
sb->Append(mult);
n /= mult;
};
return n; }
} </lang> Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 9991 = 97 x 103 9992 = 2 x 2 x 2 x 1249 9993 = 3 x 3331 9994 = 2 x 19 x 263 9995 = 5 x 1999 9996 = 2 x 2 x 3 x 7 x 7 x 17 9997 = 13 x 769 9998 = 2 x 4999 9999 = 3 x 3 x 11 x 101 10000 = 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
OCaml
<lang ocaml>open Big_int
let prime_decomposition x =
let rec inner c p =
if lt_big_int p (square_big_int c) then
[p]
else if eq_big_int (mod_big_int p c) zero_big_int then
c :: inner c (div_big_int p c)
else
inner (succ_big_int c) p
in
inner (succ_big_int (succ_big_int zero_big_int)) x
let () =
let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int</lang>
- Execution:
$ ocamlopt -o count.opt nums.cmxa count.ml $ ./count.opt 1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 ... 6351 = 3 x 29 x 73 6352 = 2 x 2 x 2 x 2 x 397 6353 = 6353 6354 = 2 x 3 x 3 x 353 6355 = 5 x 31 x 41 6356 = 2 x 2 x 7 x 227 6357 = 3 x 13 x 163 6358 = 2 x 11 x 17 x 17 6359 = 6359 ^C
Octave
Octave's factor function returns an array: <lang octave>for (n = 1:20)
printf ("%i: ", n)
printf ("%i ", factor (n))
printf ("\n")
endfor</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 2 5: 5 6: 2 3 7: 7 8: 2 2 2 9: 3 3 10: 2 5 11: 11 12: 2 2 3 13: 13 14: 2 7 15: 3 5 16: 2 2 2 2 17: 17 18: 2 3 3 19: 19 20: 2 2 5
PARI/GP
<lang parigp>fnice(n)={ my(f,s="",s1); if (n < 2, return(n)); f = factor(n); s = Str(s, f[1,1]); if (f[1, 2] != 1, s=Str(s, "^", f[1,2])); for(i=2,#f[,1], s1 = Str(" * ", f[i, 1]); if (f[i, 2] != 1, s1 = Str(s1, "^", f[i, 2])); s = Str(s, s1) ); s }; n=0;while(n++, print(fnice(n)))</lang>
Pascal
<lang pascal>program CountInFactors(output);
type
TdynArray = array of integer;
function factorize(number: integer): TdynArray;
var
k: integer;
begin
if number = 1 then
begin
setlength(factorize, 1);
factorize[0] := 1
end
else
begin
k := 2;
while number > 1 do
begin
while number mod k = 0 do begin setlength(factorize, length(factorize) + 1); factorize[high(factorize)] := k; number := number div k; end; inc(k);
end; end end;
var
i, j: integer; fac: TdynArray;
begin
for i := 1 to 22 do
begin
write(i, ': ' );
fac := factorize(i);
write(fac[0]);
for j := 1 to high(fac) do
write(' * ', fac[j]);
writeln;
end;
end.</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 16: 2 * 2 * 2 * 2 17: 17 18: 2 * 3 * 3 19: 19 20: 2 * 2 * 5 21: 3 * 7 22: 2 * 11
Perl
Typically one would use a module for this. Note that these modules all return an empty list for '1'. This should be efficient to 50+ digits:
<lang perl>use ntheory qw/factor/; print "$_ = ", join(" x ", factor($_)), "\n" for 1000000000000000000 .. 1000000000000000010;</lang>
- Output:
1000000000000000000 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 1000000000000000001 = 101 x 9901 x 999999000001 1000000000000000002 = 2 x 3 x 17 x 131 x 1427 x 52445056723 1000000000000000003 = 1000000000000000003 1000000000000000004 = 2 x 2 x 1801 x 246809 x 562425889 1000000000000000005 = 3 x 5 x 44087 x 691381 x 2187161 1000000000000000006 = 2 x 7 x 919 x 77724234416291 1000000000000000007 = 1370531 x 729644203597 1000000000000000008 = 2 x 2 x 2 x 3 x 3 x 97 x 26209 x 32779 x 166667 1000000000000000009 = 1000000000000000009 1000000000000000010 = 2 x 5 x 11 x 103 x 4013 x 21993833369
Giving similar output and also good for large inputs: <lang perl>use Math::Pari qw/factorint/; sub factor {
my ($pn,$pc) = @{Math::Pari::factorint(shift)};
return map { ($pn->[$_]) x $pc->[$_] } 0 .. $#$pn;
} print "$_ = ", join(" x ", factor($_)), "\n" for 1000000000000000000 .. 1000000000000000010;</lang>
or, somewhat slower and limited to native 32-bit or 64-bit integers only: <lang perl>use Math::Factor::XS qw/prime_factors/; print "$_ = ", join(" x ", prime_factors($_)), "\n" for 1000000000000000000 .. 1000000000000000010;</lang>
If we want to implement it self-contained, we could use the prime decomposition routine from the Prime_decomposition task. This is reasonably fast and small, though much slower than the modules and certainly could have more optimization.
<lang perl>sub factors {
my($n, $p, @out) = (shift, 3);
return if $n < 1;
while (!($n&1)) { $n >>= 1; push @out, 2; }
while ($n > 1 && $p*$p <= $n) {
while ( ($n % $p) == 0) {
$n /= $p;
push @out, $p;
}
$p += 2;
}
push @out, $n if $n > 1;
@out;
}
print "$_ = ", join(" x ", factors($_)), "\n" for 100000000000 .. 100000000100;</lang>
We could use the second extensible sieve from Sieve_of_Eratosthenes#Extensible_sieves to only divide by primes. <lang perl>tie my @primes, 'Tie::SieveOfEratosthenes';
sub factors {
my($n, $i, $p, @out) = (shift, 0, 2);
while ($n >= $p * $p) {
while ($n % $p == 0) {
push @out, $p;
$n /= $p;
}
$p = $primes[++$i];
}
push @out, $n if $n > 1 || !@out;
@out;
}
print "$_ = ", join(" x ", factors($_)), "\n" for 100000000000 .. 100000000010;</lang>
- Output:
100000000000 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 100000000001 = 11 x 11 x 23 x 4093 x 8779 100000000002 = 2 x 3 x 7 x 1543 x 1543067 100000000003 = 100000000003 100000000004 = 2 x 2 x 17573 x 1422637 100000000005 = 3 x 5 x 19 x 1627 x 215659 100000000006 = 2 x 3947 x 12667849 100000000007 = 353 x 283286119 100000000008 = 2 x 2 x 2 x 3 x 3 x 3 x 462962963 100000000009 = 7 x 13 x 53 x 1979 x 10477 100000000010 = 2 x 5 x 101 x 3541 x 27961
This next example isn't quite as fast and uses much more memory, but it is self-contained and shows a different approach. As written it must start at 1, but a range can be handled by using a map to prefill the p_and_sq array.
<lang perl>#!perl -C
use utf8;
use strict;
use warnings;
my $limit = 1000;
print "$_ = $_\n" for 1..3;
my @p_and_sq = ( [2, 4], [3, 9] );
N: for my $n ( 4 .. 1000 ) { print $n, " = "; for( my $i = 0; $i <= $#p_and_sq; ++$i ) { my ($p, $sq) = @{ $p_and_sq[$i] }; if( $sq > $n ) { print $n, "\n"; push @p_and_sq, [ $n, $n*$n ]; next N; } while( 0 == ($n % $p) ) { print $p; $n /= $p; if( $n == 1 ) { print "\n"; next N; } print " × "; } } die "Ran out of primes?!"; }</lang>
Perl 6
<lang perl6>constant @primes = 2, |(3, 5, 7 ... *).grep: *.is-prime;
multi factors(1) { 1 } multi factors(Int $remainder is copy) {
gather for @primes -> $factor {
# if remainder < factor², we're done
if $factor * $factor > $remainder {
take $remainder if $remainder > 1;
last;
}
# How many times can we divide by this prime?
while $remainder %% $factor {
take $factor;
last if ($remainder div= $factor) === 1;
}
}
}
say "$_: ", factors($_).join(" × ") for 1..*;</lang> The first twenty numbers:
1: 1 2: 2 3: 3 4: 2 × 2 5: 5 6: 2 × 3 7: 7 8: 2 × 2 × 2 9: 3 × 3 10: 2 × 5 11: 11 12: 2 × 2 × 3 13: 13 14: 2 × 7 15: 3 × 5 16: 2 × 2 × 2 × 2 17: 17 18: 2 × 3 × 3 19: 19 20: 2 × 2 × 5
Here we use a multi declaration with a constant parameter to match the degenerate case. We use copy parameters when we wish to reuse the formal parameter as a mutable variable within the function. (Parameters default to readonly in Perl 6.) Note the use of gather/take as the final statement in the function, which is a common Perl 6 idiom to set up a coroutine within a function to return a lazy list on demand.
Note also the '×' above is not ASCII 'x', but U+00D7 MULTIPLICATION SIGN. Perl 6 does Unicode natively.
Here is a solution inspired from Almost_prime#C. It doesn't use &is-prime.
<lang perl6>sub factor($n is copy) {
$n == 1 ?? 1 !!
gather {
$n /= take 2 while $n %% 2; $n /= take 3 while $n %% 3; loop (my $p = 5; $p*$p <= $n; $p+=2) { $n /= take $p while $n %% $p; } take $n unless $n == 1;
}
}
say "$_ == ", join " \x00d7 ", factor $_ for 1 .. 20;</lang>
Same output as above.
Alternately, use a module:
<lang perl6>use Prime::Factor;
say "$_ = {(.&prime-factors || 1).join: ' x ' }" for flat 1 .. 10, 10**20 .. 10**20 + 10;</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 100000000000000000000 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 100000000000000000001 = 73 x 137 x 1676321 x 5964848081 100000000000000000002 = 2 x 3 x 155977777 x 106852828571 100000000000000000003 = 373 x 155773 x 1721071782307 100000000000000000004 = 2 x 2 x 13 x 1597 x 240841 x 4999900001 100000000000000000005 = 3 x 5 x 7 x 7 x 83 x 1663 x 985694468327 100000000000000000006 = 2 x 31 x 6079 x 265323774602147 100000000000000000007 = 67 x 166909 x 8942221889969 100000000000000000008 = 2 x 2 x 2 x 3 x 3 x 3 x 233 x 1986965506278811 100000000000000000009 = 557 x 72937 x 2461483384901 100000000000000000010 = 2 x 5 x 11 x 909090909090909091
Phix
<lang Phix>function factorise(atom n) -- returns a list of all integer factors of n, that when multiplied together equal n -- (adapted from the standard builtin factors(), which does not return duplicates) sequence res = {} integer p = 2,
step = 1,
lim = floor(sqrt(n))
while p<=lim do
while remainder(n,p)=0 do
res = append(res,sprintf("%d",p))
n = n/p
if n=p then exit end if
lim = floor(sqrt(n))
end while
p += step
step = 2
end while
return join(append(res,sprintf("%d",n))," x ")
end function
for i=1 to 10 do
printf(1,"%2d: %s\n",{i,factorise(i)})
end for</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 x 2 5: 5 6: 2 x 3 7: 7 8: 2 x 2 x 2 9: 3 x 3 10: 2 x 5
PicoLisp
This is the 'factor' function from Prime decomposition#PicoLisp. <lang PicoLisp>(de factor (N)
(make
(let (D 2 L (1 2 2 . (4 2 4 2 4 6 2 6 .)) M (sqrt N))
(while (>= M D)
(if (=0 (% N D))
(setq M (sqrt (setq N (/ N (link D)))))
(inc 'D (pop 'L)) ) )
(link N) ) ) )
(for N 20
(prinl N ": " (glue " * " (factor N))) )</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 16: 2 * 2 * 2 * 2 17: 17 18: 2 * 3 * 3 19: 19 20: 2 * 2 * 5
PL/I
<lang PL/I> cnt: procedure options (main); declare (i, k, n) fixed binary; declare first bit (1) aligned;
do n = 1 to 40;
put skip list (n || ' =');
k = n; first = '1'b;
repeat:
do i = 2 to k-1;
if mod(k, i) = 0 then do; k = k/i;
if ^first then put edit (' x ')(A);
first = '0'b;
put edit (trim(i)) (A);
go to repeat; end;
end;
if ^first then put edit (' x ')(A);
if n = 1 then i = 1;
put edit (trim(i)) (A);
end;
end cnt; </lang> Results:
1 = 1
2 = 2
3 = 3
4 = 2 x 2
5 = 5
6 = 2 x 3
7 = 7
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
11 = 11
12 = 2 x 2 x 3
13 = 13
14 = 2 x 7
15 = 3 x 5
16 = 2 x 2 x 2 x 2
17 = 17
18 = 2 x 3 x 3
19 = 19
20 = 2 x 2 x 5
21 = 3 x 7
22 = 2 x 11
23 = 23
24 = 2 x 2 x 2 x 3
25 = 5 x 5
26 = 2 x 13
27 = 3 x 3 x 3
28 = 2 x 2 x 7
29 = 29
30 = 2 x 3 x 5
31 = 31
32 = 2 x 2 x 2 x 2 x 2
33 = 3 x 11
34 = 2 x 17
35 = 5 x 7
36 = 2 x 2 x 3 x 3
37 = 37
38 = 2 x 19
39 = 3 x 13
40 = 2 x 2 x 2 x 5
PowerShell
<lang PowerShell> function eratosthenes ($n) {
if($n -ge 1){
$prime = @(1..($n+1) | foreach{$true})
$prime[1] = $false
$m = [Math]::Floor([Math]::Sqrt($n))
for($i = 2; $i -le $m; $i++) {
if($prime[$i]) {
for($j = $i*$i; $j -le $n; $j += $i) {
$prime[$j] = $false
}
}
}
1..$n | where{$prime[$_]}
} else {
"$n must be equal or greater than 1"
}
} function prime-decomposition ($n) {
$array = eratosthenes $n
$prime = @()
foreach($p in $array) {
while($n%$p -eq 0) {
$n /= $p
$prime += @($p)
}
}
$prime
} $OFS = " x " "$(prime-decomposition 2144)" "$(prime-decomposition 100)" "$(prime-decomposition 12)" </lang> Output:
2 x 2 x 2 x 2 x 2 x 67 2 x 2 x 5 x 5 2 x 2 x 3
PureBasic
<lang PureBasic>Procedure Factorize(Number, List Factors())
Protected I = 3, Max
ClearList(Factors())
While Number % 2 = 0
AddElement(Factors())
Factors() = 2
Number / 2
Wend
Max = Number
While I <= Max And Number > 1
While Number % I = 0
AddElement(Factors())
Factors() = I
Number / I
Wend
I + 2
Wend
EndProcedure
If OpenConsole()
NewList n()
For a=1 To 20
text$=RSet(Str(a),2)+"= "
Factorize(a,n())
If ListSize(n())
ResetList(n())
While NextElement(n())
text$ + Str(n())
If ListSize(n())-ListIndex(n())>1
text$ + "*"
EndIf
Wend
Else
text$+Str(a) ; To handle the '1', which is not really a prime...
EndIf
PrintN(text$)
Next a
EndIf</lang>
- Output:
1= 1 2= 2 3= 3 4= 2*2 5= 5 6= 2*3 7= 7 8= 2*2*2 9= 3*3 10= 2*5 11= 11 12= 2*2*3 13= 13 14= 2*7 15= 3*5 16= 2*2*2*2 17= 17 18= 2*3*3 19= 19 20= 2*2*5
Python
This uses the functools.lru_cache standard library module to cache intermediate results. <lang python>from functools import lru_cache
primes = [2, 3, 5, 7, 11, 13, 17] # Will be extended
@lru_cache(maxsize=2000) def pfactor(n):
if n == 1:
return [1]
n2 = n // 2 + 1
for p in primes:
if p <= n2:
d, m = divmod(n, p)
if m == 0:
if d > 1:
return [p] + pfactor(d)
else:
return [p]
else:
if n > primes[-1]:
primes.append(n)
return [n]
if __name__ == '__main__':
mx = 5000
for n in range(1, mx + 1):
factors = pfactor(n)
if n <= 10 or n >= mx - 20:
print( '%4i %5s %s' % (n,
if factors != [n] or n == 1 else 'prime',
'x'.join(str(i) for i in factors)) )
if n == 11:
print('...')
print('\nNumber of primes gathered up to', n, 'is', len(primes))
print(pfactor.cache_info())</lang>
- Output:
1 1 2 prime 2 3 prime 3 4 2x2 5 prime 5 6 2x3 7 prime 7 8 2x2x2 9 3x3 10 2x5 ... 4980 2x2x3x5x83 4981 17x293 4982 2x47x53 4983 3x11x151 4984 2x2x2x7x89 4985 5x997 4986 2x3x3x277 4987 prime 4987 4988 2x2x29x43 4989 3x1663 4990 2x5x499 4991 7x23x31 4992 2x2x2x2x2x2x2x3x13 4993 prime 4993 4994 2x11x227 4995 3x3x3x5x37 4996 2x2x1249 4997 19x263 4998 2x3x7x7x17 4999 prime 4999 5000 2x2x2x5x5x5x5 Number of primes gathered up to 5000 is 669 CacheInfo(hits=3935, misses=7930, maxsize=2000, currsize=2000)
R
<lang R>
- initially I created a function which returns prime factors then I have created another function counts in the factors and #prints the values.
findfactors <- function(num) {
x <- c()
p1<- 2
p2 <- 3
everyprime <- num
while( everyprime != 1 ) {
while( everyprime%%p1 == 0 ) {
x <- c(x, p1)
everyprime <- floor(everyprime/ p1)
}
p1 <- p2
p2 <- p2 + 2
}
x
} count_in_factors=function(x){
primes=findfactors(x)
x=c(1)
for (i in 1:length(primes)) {
x=paste(primes[i],"x",x)
}
return(x)
} count_in_factors(72) </lang>
- Output:
[1] "3 x 3 x 2 x 2 x 2 x 1"
Racket
See also #Scheme. This uses Racket’s math/number-theory package
<lang racket>#lang typed/racket
(require math/number-theory)
(define (factorise-as-primes [n : Natural])
(if
(= n 1)
'(1)
(let ((F (factorize n)))
(append*
(for/list : (Listof (Listof Natural))
((f (in-list F)))
(make-list (second f) (first f)))))))
(define (factor-count [start-inc : Natural] [end-inc : Natural])
(for ((i : Natural (in-range start-inc (add1 end-inc)))) (define f (string-join (map number->string (factorise-as-primes i)) " × ")) (printf "~a:\t~a~%" i f)))
(factor-count 1 22) (factor-count 2140 2150)
- tb</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 × 2 5: 5 6: 2 × 3 7: 7 8: 2 × 2 × 2 9: 3 × 3 10: 2 × 5 11: 11 12: 2 × 2 × 3 13: 13 14: 2 × 7 15: 3 × 5 16: 2 × 2 × 2 × 2 17: 17 18: 2 × 3 × 3 19: 19 20: 2 × 2 × 5 21: 3 × 7 22: 2 × 11 2140: 2 × 2 × 5 × 107 2141: 2141 2142: 2 × 3 × 3 × 7 × 17 2143: 2143 2144: 2 × 2 × 2 × 2 × 2 × 67 2145: 3 × 5 × 11 × 13 2146: 2 × 29 × 37 2147: 19 × 113 2148: 2 × 2 × 3 × 179 2149: 7 × 307 2150: 2 × 5 × 5 × 43
REXX
simple approach
As per the task's requirements, the prime factors of 1 (unity) will be listed as 1,
even though, strictly speaking, it should be null. The same applies to 0.
Programming note: if the high argument is negative, its positive value is used and no displaying of the
prime factors are listed, but the number of primes found is always shown. The showing of the count of
primes was included to help verify the factoring (of composites).
<lang rexx>/*REXX program lists the prime factors of a specified integer (or a range of integers).*/
@.=left(, 8); @.0="{unity} "; @.1='[prime] ' /*some tags and handy-dandy literals.*/
parse arg LO HI @ . /*get optional arguments from the C.L. */
if LO== | LO=="," then do; LO=1; HI=40; end /*Not specified? Then use the default.*/
if HI== | HI=="," then HI= LO /* " " " " " " */
if @== then @= 'x' /* " " " " " " */
if length(@)\==1 then @= x2c(@) /*Not length 1? Then use hexadecimal. */
tell= (HI>0) /*if HIGH is positive, then show #'s.*/
HI= abs(HI) /*use the absolute value for HIGH. */
w= length(HI) /*get maximum width for pretty output. */
numeric digits max(9, w + 1) /*maybe bump the precision of numbers. */
- = 0 /*the number of primes found (so far). */
do n=abs(LO) to HI; f= factr(n) /*process a single number or a range.*/
p= words( translate(f, ,@) ) - (n==1) /*P: is the number of prime factors. */
if p==1 then #= # + 1 /*bump the primes counter (exclude N=1)*/
if tell then say right(n, w) '=' @.p f /*display if a prime, plus its factors.*/
end /*n*/
say say right(#, w) ' primes found.' /*display the number of primes found. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ factr: procedure expose @; parse arg z 1 n,$; if z<2 then return z /*is Z too small?*/
do while z//2==0; $= $||@||2; z= z%2; end /*maybe add factor of 2 */
do while z//3==0; $= $||@||3; z= z%3; end /* " " " " 3 */
do while z//5==0; $= $||@||5; z= z%5; end /* " " " " 5 */
do while z//7==0; $= $||@||7; z= z%7; end /* " " " " 7 */
do j=11 by 6 while j<=z /*insure that J isn't divisible by 3.*/
parse var j -1 _ /*get the last decimal digit of J. */
if _\==5 then do while z//j==0; $=$||@||j; z= z%j; end /*maybe reduce Z.*/
if _ ==3 then iterate /*Next # ÷ by 5? Skip. ___ */
if j*j>n then leave /*are we higher than the √ N ? */
y= j + 2 /*obtain the next odd divisor. */
do while z//y==0; $=$||@||y; z= z%y; end /*maybe reduce Z.*/
end /*j*/
if z==1 then return substr($, 1+length(@) ) /*Is residual=1? Don't add 1*/
return substr($||@||z, 1+length(@) ) /*elide superfluous header. */</lang>
- output when using the default inputs:
1 = {unity} 1
2 = [prime] 2
3 = [prime] 3
4 = 2x2
5 = [prime] 5
6 = 2x3
7 = [prime] 7
8 = 2x2x2
9 = 3x3
10 = 2x5
11 = [prime] 11
12 = 2x2x3
13 = [prime] 13
14 = 2x7
15 = 3x5
16 = 2x2x2x2
17 = [prime] 17
18 = 2x3x3
19 = [prime] 19
20 = 2x2x5
21 = 3x7
22 = 2x11
23 = [prime] 23
24 = 2x2x2x3
25 = 5x5
26 = 2x13
27 = 3x3x3
28 = 2x2x7
29 = [prime] 29
30 = 2x3x5
31 = [prime] 31
32 = 2x2x2x2x2
33 = 3x11
34 = 2x17
35 = 5x7
36 = 2x2x3x3
37 = [prime] 37
38 = 2x19
39 = 3x13
40 = 2x2x2x5
12 primes found.
{{out|output|text= when the following input was used: 1 12 207820
1 = {unity} 1
2 = [prime] 2
3 = [prime] 3
4 = 2 x 2
5 = [prime] 5
6 = 2 x 3
7 = [prime] 7
8 = 2 x 2 x 2
9 = 3 x 3
10 = 2 x 5
11 = [prime] 11
12 = 2 x 2 x 3
5 primes found.
{{out|output|text= when the following input was used: 1 -10000
1229 primes found.
{{out|output|text= when the following input was used: 1 -100000
9592 primes found.
using integer SQRT
This REXX version computes the integer square root of the integer being factor (to limit the range of factors),
this makes this version about 50% faster than the 1st REXX version.
Also, the number of early testing of prime factors was expanded.
Note that the integer square root section of code doesn't use any floating point numbers, just integers. <lang rexx>/*REXX program lists the prime factors of a specified integer (or a range of integers).*/ @.=left(, 8); @.0="{unity} "; @.1='[prime] ' /*some tags and handy-dandy literals.*/ parse arg LO HI @ . /*get optional arguments from the C.L. */ if LO== | LO=="," then do; LO=1; HI=40; end /*Not specified? Then use the default.*/ if HI== | HI=="," then HI= LO /* " " " " " " */ if @== then @= 'x' /* " " " " " " */ if length(@)\==1 then @= x2c(@) /*Not length 1? Then use hexadecimal. */ tell= (HI>0) /*if HIGH is positive, then show #'s.*/ HI= abs(HI) /*use the absolute value for HIGH. */ w= length(HI) /*get maximum width for pretty output. */ numeric digits max(9, w + 1) /*maybe bump the precision of numbers. */
- = 0 /*the number of primes found (so far). */
do n=abs(LO) to HI; f= factr(n) /*process a single number or a range.*/
p= words( translate(f, ,@) ) - (n==1) /*P: is the number of prime factors. */
if p==1 then #= # + 1 /*bump the primes counter (exclude N=1)*/
if tell then say right(n, w) '=' @.p f /*display if a prime, plus its factors.*/
end /*n*/
say say right(#, w) ' primes found.' /*display the number of primes found. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ factr: procedure expose @; parse arg z 1 n,$; if z<2 then return z /*is Z too small?*/
do while z// 2==0; $= $||@||2 ; z= z%2 ; end /*maybe add factor of 2 */
do while z// 3==0; $= $||@||3 ; z= z%3 ; end /* " " " " 3 */
do while z// 5==0; $= $||@||5 ; z= z%5 ; end /* " " " " 5 */
do while z// 7==0; $= $||@||7 ; z= z%7 ; end /* " " " " 7 */
do while z//11==0; $= $||@||11; z= z%11; end /* " " " " 11 */
do while z//13==0; $= $||@||13; z= z%13; end /* " " " " 13 */
do while z//17==0; $= $||@||17; z= z%17; end /* " " " " 17 */
do while z//19==0; $= $||@||19; z= z%19; end /* " " " " 19 */
do while z//23==0; $= $||@||23; z= z%23; end /* " " " " 23 */
do while z//29==0; $= $||@||29; z= z%29; end /* " " " " 29 */
do while z//31==0; $= $||@||31; z= z%31; end /* " " " " 31 */
do while z//37==0; $= $||@||37; z= z%37; end /* " " " " 37 */
if z>40 then do; t= z; q= 1; r= 0; do while q<=t; q= q * 4
end /*while*/
do while q>1; q=q%4; _=t-r-q; r=r%2; if _>=0 then do; t=_; r=r+q
end
end /*while*/ /* [↑] find integer SQRT(z). */
/*R: is the integer SQRT of Z.*/
do j=41 by 6 to r while j<=z /*insure J isn't divisible by 3*/
parse var j -1 _ /*get last decimal digit of J.*/
if _\==5 then do while z//j==0; $=$||@||j; z= z%j; end
if _ ==3 then iterate /*Next number ÷ by 5 ? Skip.*/
y= j + 2 /*use the next (odd) divisor. */
do while z//y==0; $=$||@||y; z= z%y; end
end /*j*/ /* [↑] reduce Z by Y ? */
end /*if z>40*/
if z==1 then return substr($, 1+length(@) ) /*Is residual=1? Don't add 1*/
return substr($||@||z, 1+length(@) ) /*elide superfluous header. */</lang>
- output when using the default inputs:
1 = {unity} 1
2 = [prime] 2
3 = [prime] 3
4 = 2∙2
5 = [prime] 5
6 = 2∙3
7 = [prime] 7
8 = 2∙2∙2
9 = 3∙3
10 = 2∙5
11 = [prime] 11
12 = 2∙2∙3
13 = [prime] 13
14 = 2∙7
15 = 3∙5
16 = 2∙2∙2∙2
17 = [prime] 17
18 = 2∙3∙3
19 = [prime] 19
20 = 2∙2∙5
21 = 3∙7
22 = 2∙11
23 = [prime] 23
24 = 2∙2∙2∙3
25 = 5∙5
26 = 2∙13
27 = 3∙3∙3
28 = 2∙2∙7
29 = [prime] 29
30 = 2∙3∙5
31 = [prime] 31
32 = 2∙2∙2∙2∙2
33 = 3∙11
34 = 2∙17
35 = 5∙7
36 = 2∙2∙3∙3
37 = [prime] 37
38 = 2∙19
39 = 3∙13
40 = 2∙2∙2∙5
12 primes found.
Ring
<lang ring> for i = 1 to 20
see "" + i + " = " + factors(i) + nl
next
func factors n
f = ""
if n = 1 return "1" ok
p = 2
while p <= n
if (n % p) = 0
f += string(p) + " x "
n = n/p
else p += 1 ok
end
return left(f, len(f) - 3)
</lang> Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 = 17 18 = 2 x 3 x 3 19 = 19 20 = 2 x 2 x 5
Ruby
Starting with Ruby 1.9, 'prime' is part of the standard library and provides Integer#prime_division. <lang ruby>require 'optparse' require 'prime'
maximum = 10 OptionParser.new do |o|
o.banner = "Usage: #{File.basename $0} [-m MAXIMUM]"
o.on("-m MAXIMUM", Integer,
"Count up to MAXIMUM [#{maximum}]") { |m| maximum = m }
o.parse! rescue ($stderr.puts $!, o; exit 1)
($stderr.puts o; exit 1) unless ARGV.size == 0
end
- 1 has no prime factors
puts "1 is 1" unless maximum < 1
2.upto(maximum) do |i|
# i is 504 => i.prime_division is [[2, 3], [3, 2], [7, 1]]
f = i.prime_division.map! do |factor, exponent|
# convert [2, 3] to "2 x 2 x 2"
([factor] * exponent).join " x "
end.join " x "
puts "#{i} is #{f}"
end</lang>
- Example:
$ ruby prime-count.rb -h
Usage: prime-count.rb [-m MAXIMUM]
-m MAXIMUM Count up to MAXIMUM [10]
$ ruby prime-count.rb -m 10000 | sed -e '11,9990d'
1 is 1
2 is 2
3 is 3
4 is 2 x 2
5 is 5
6 is 2 x 3
7 is 7
8 is 2 x 2 x 2
9 is 3 x 3
10 is 2 x 5
9991 is 97 x 103
9992 is 2 x 2 x 2 x 1249
9993 is 3 x 3331
9994 is 2 x 19 x 263
9995 is 5 x 1999
9996 is 2 x 2 x 3 x 7 x 7 x 17
9997 is 13 x 769
9998 is 2 x 4999
9999 is 3 x 3 x 11 x 101
10000 is 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
Run BASIC
<lang runbasic>for i = 1000 to 1016
print i;" = "; factorial$(i)
next wait function factorial$(num)
if num = 1 then factorial$ = "1" fct = 2 while fct <= num if (num mod fct) = 0 then factorial$ = factorial$ ; x$ ; fct x$ = " x " num = num / fct else fct = fct + 1 end if wend
end function</lang>
- Output:
1000 = 2 x 2 x 2 x 5 x 5 x 5 1001 = 7 x 11 x 13 1002 = 2 x 3 x 167 1003 = 17 x 59 1004 = 2 x 2 x 251 1005 = 3 x 5 x 67 1006 = 2 x 503 1007 = 19 x 53 1008 = 2 x 2 x 2 x 2 x 3 x 3 x 7 1009 = 1009 1010 = 2 x 5 x 101 1011 = 3 x 337 1012 = 2 x 2 x 11 x 23 1013 = 1013 1014 = 2 x 3 x 13 x 13 1015 = 5 x 7 x 29 1016 = 2 x 2 x 2 x 127
Rust
You can run and experiment with this code at https://play.rust-lang.org/?version=stable&mode=debug&edition=2018&gist=b66c14d944ff0472d2460796513929e2 <lang rust>use std::env;
fn main() {
let args: Vec<_> = env::args().collect();
let n = if args.len() > 1 {
args[1].parse().expect("Not a valid number to count to")
}
else {
20
};
count_in_factors_to(n);
}
fn count_in_factors_to(n: u64) {
println!("1");
let mut primes = vec![];
for i in 2..=n {
let fs = factors(&primes, i);
if fs.len() <= 1 {
primes.push(i);
println!("{}", i);
}
else {
println!("{} = {}", i, fs.iter().map(|f| f.to_string()).collect::<Vec<String>>().join(" x "));
}
}
}
fn factors(primes: &[u64], mut n: u64) -> Vec<u64> {
let mut result = Vec::new();
for p in primes {
while n % p == 0 {
result.push(*p);
n /= p;
}
if n == 1 {
return result;
}
}
vec![n]
}</lang>
- Output:
1 2 3 4 = 2 x 2 5 6 = 2 x 3 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 12 = 2 x 2 x 3 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 18 = 2 x 3 x 3 19 20 = 2 x 2 x 5
Scala
<lang scala>def primeFactors( n:Int ) = {
def primeStream(s: Stream[Int]): Stream[Int] = {
s.head #:: primeStream(s.tail filter { _ % s.head != 0 })
}
val primes = primeStream(Stream.from(2))
def factors( n:Int ) : List[Int] = primes.takeWhile( _ <= n ).find( n % _ == 0 ) match {
case None => Nil
case Some(p) => p :: factors( n/p )
}
if( n == 1 ) List(1) else factors(n)
}
// A little test... {
val nums = (1 to 12).toList :+ 2144 :+ 6358
nums.foreach( n => println( "%6d : %s".format( n, primeFactors(n).mkString(" * ") ) ) )
} </lang>
- Output:
1 : 1
2 : 2
3 : 3
4 : 2 * 2
5 : 5
6 : 2 * 3
7 : 7
8 : 2 * 2 * 2
9 : 3 * 3
10 : 2 * 5
11 : 11
12 : 2 * 2 * 3
2144 : 2 * 2 * 2 * 2 * 2 * 67
6358 : 2 * 11 * 17 * 17
Scheme
<lang lisp>(define (factors n)
(let facs ((l '()) (d 2) (x n)) (cond ((= x 1) (if (null? l) '(1) l))
((< x (* d d)) (cons x l)) (else (if (= 0 (modulo x d)) (facs (cons d l) d (/ x d)) (facs l (+ 1 d) x))))))
(define (show l)
(display (car l))
(if (not (null? (cdr l)))
(begin
(display " × ")
(show (cdr l)))
(display "\n")))
(do ((i 1 (+ i 1))) (#f)
(display i) (display " = ") (show (reverse (factors i))))</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 × 2 5 = 5 6 = 2 × 3 7 = 7 8 = 2 × 2 × 2 9 = 3 × 3 10 = 2 × 5 11 = 11 12 = 2 × 2 × 3 ...
Seed7
<lang seed7>$ include "seed7_05.s7i";
const proc: writePrimeFactors (in var integer: number) is func
local
var boolean: laterElement is FALSE;
var integer: checker is 2;
begin
while checker * checker <= number do
if number rem checker = 0 then
if laterElement then
write(" * ");
end if;
laterElement := TRUE;
write(checker);
number := number div checker;
else
incr(checker);
end if;
end while;
if number <> 1 then
if laterElement then
write(" * ");
end if;
laterElement := TRUE;
write(number);
end if;
end func;
const proc: main is func
local
var integer: number is 0;
begin
writeln("1: 1");
for number range 2 to 2147483647 do
write(number <& ": ");
writePrimeFactors(number);
writeln;
end for;
end func;</lang>
- Output:
1: 1 2: 2 3: 3 4: 2 * 2 5: 5 6: 2 * 3 7: 7 8: 2 * 2 * 2 9: 3 * 3 10: 2 * 5 11: 11 12: 2 * 2 * 3 13: 13 14: 2 * 7 15: 3 * 5 . . .
Sidef
<lang ruby>class Counter {
method factors(n, p=2) {
var a = gather {
while (n >= p*p) {
while (p `divides` n) {
take(p)
n //= p
}
p = self.next_prime(p)
}
}
(n > 1 || a.is_empty) ? (a << n) : a
}
method is_prime(n) {
self.factors(n).len == 1
}
method next_prime(p) {
do {
p == 2 ? (p = 3) : (p+=2)
} while (!self.is_prime(p))
return p
}
} for i in (1..100) {
say "#{i} = #{Counter().factors(i).join(' × ')}"
}</lang>
Swift
<lang swift>extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot()) var d: Self = 1 var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self] }
}
for i in 1...20 {
if i == 1 {
print("1 = 1")
} else {
print("\(i) = \(i.primeDecomposition().map(String.init).joined(separator: " x "))")
}
}</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 11 = 11 12 = 2 x 2 x 3 13 = 13 14 = 2 x 7 15 = 3 x 5 16 = 2 x 2 x 2 x 2 17 = 17 18 = 2 x 3 x 3 19 = 19 20 = 2 x 2 x 5
Tcl
This factorization code is based on the same engine that is used in the parallel computation task. <lang tcl>package require Tcl 8.5
namespace eval prime {
variable primes [list 2 3 5 7 11]
proc restart {} {
variable index -1 variable primes variable current [lindex $primes end]
}
proc get_next_prime {} {
variable primes variable index if {$index < [llength $primes]-1} { return [lindex $primes [incr index]] } variable current while 1 { incr current 2 set p 1 foreach prime $primes { if {$current % $prime} {} else { set p 0 break } } if {$p} { return [lindex [lappend primes $current] [incr index]] } }
}
proc factors {num} {
restart set factors [dict create] for {set i [get_next_prime]} {$i <= $num} {} { if {$num % $i == 0} { dict incr factors $i set num [expr {$num / $i}] continue } elseif {$i*$i > $num} { dict incr factors $num break } else { set i [get_next_prime] } } return $factors
}
# Produce the factors in rendered form
proc factors.rendered {num} {
set factorDict [factors $num] if {[dict size $factorDict] == 0} { return 1 } dict for {factor times} $factorDict { lappend v {*}[lrepeat $times $factor] } return [join $v "*"]
}
}</lang> Demonstration code: <lang tcl>set max 20 for {set i 1} {$i <= $max} {incr i} {
puts [format "%*d = %s" [string length $max] $i [prime::factors.rendered $i]]
}</lang>
VBScript
Made minor modifications on the code I posted under Prime Decomposition. <lang vb>Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 'The -1 is to account for the null element of arrP For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function
Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function
Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function
'Testing the fucntions. WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine</lang>
- Output:
2 = 2 2144 = 2 * 2 * 2 * 2 * 2 * 67
Visual Basic .NET
<lang vbnet>Module CountingInFactors
Sub Main()
For i As Integer = 1 To 10
Console.WriteLine("{0} = {1}", i, CountingInFactors(i))
Next
For i As Integer = 9991 To 10000
Console.WriteLine("{0} = {1}", i, CountingInFactors(i))
Next
End Sub
Private Function CountingInFactors(ByVal n As Integer) As String
If n = 1 Then Return "1"
Dim sb As New Text.StringBuilder()
CheckFactor(2, n, sb)
If n = 1 Then Return sb.ToString()
CheckFactor(3, n, sb)
If n = 1 Then Return sb.ToString()
For i As Integer = 5 To n Step 2
If i Mod 3 = 0 Then Continue For
CheckFactor(i, n, sb)
If n = 1 Then Exit For
Next
Return sb.ToString() End Function
Private Sub CheckFactor(ByVal mult As Integer, ByRef n As Integer, ByRef sb As Text.StringBuilder)
Do While n Mod mult = 0
If sb.Length > 0 Then sb.Append(" x ")
sb.Append(mult)
n = n / mult
Loop
End Sub
End Module</lang>
- Output:
1 = 1 2 = 2 3 = 3 4 = 2 x 2 5 = 5 6 = 2 x 3 7 = 7 8 = 2 x 2 x 2 9 = 3 x 3 10 = 2 x 5 9991 = 97 x 103 9992 = 2 x 2 x 2 x 1249 9993 = 3 x 3331 9994 = 2 x 19 x 263 9995 = 5 x 1999 9996 = 2 x 2 x 3 x 7 x 7 x 17 9997 = 13 x 769 9998 = 2 x 4999 9999 = 3 x 3 x 11 x 101 10000 = 2 x 2 x 2 x 2 x 5 x 5 x 5 x 5
XPL0
<lang XPL0>include c:\cxpl\codes; int N0, N, F; [N0:= 1; repeat IntOut(0, N0); Text(0, " = ");
F:= 2; N:= N0;
repeat if rem(N/F) = 0 then
[if N # N0 then Text(0, " * ");
IntOut(0, F);
N:= N/F;
]
else F:= F+1;
until F>N;
if N0=1 then IntOut(0, 1); \1 = 1
CrLf(0);
N0:= N0+1;
until KeyHit; ]</lang>
Example output:
1 = 1 2 = 2 3 = 3 4 = 2 * 2 5 = 5 6 = 2 * 3 7 = 7 8 = 2 * 2 * 2 9 = 3 * 3 10 = 2 * 5 11 = 11 12 = 2 * 2 * 3 13 = 13 14 = 2 * 7 15 = 3 * 5 16 = 2 * 2 * 2 * 2 17 = 17 18 = 2 * 3 * 3 . . . 57086 = 2 * 17 * 23 * 73 57087 = 3 * 3 * 6343 57088 = 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 * 223 57089 = 57089 57090 = 2 * 3 * 5 * 11 * 173 57091 = 37 * 1543 57092 = 2 * 2 * 7 * 2039 57093 = 3 * 19031 57094 = 2 * 28547 57095 = 5 * 19 * 601 57096 = 2 * 2 * 2 * 3 * 3 * 13 * 61 57097 = 57097
zkl
<lang zkl>foreach n in ([1..*]){ println(n,": ",primeFactors(n).concat("\U2715;")) }</lang> Using the fixed size integer (64 bit) solution from Prime decomposition#zkl <lang zkl>fcn primeFactors(n){ // Return a list of factors of n
acc:=fcn(n,k,acc,maxD){ // k is 2,3,5,7,9,... not optimum
if(n==1 or k>maxD) acc.close();
else{
q,r:=n.divr(k); // divr-->(quotient,remainder) if(r==0) return(self.fcn(q,k,acc.write(k),q.toFloat().sqrt())); return(self.fcn(n,k+1+k.isOdd,acc,maxD))
}
}(n,2,Sink(List),n.toFloat().sqrt());
m:=acc.reduce('*,1); // mulitply factors
if(n!=m) acc.append(n/m); // opps, missed last factor
else acc;
}</lang>
- Output:
1: 2: 2 3: 3 4: 2✕2 5: 5 6: 2✕3 ... 591885: 3✕3✕5✕7✕1879 591886: 2✕295943 591887: 591887 591888: 2✕2✕2✕2✕3✕11✕19✕59 ...
ZX Spectrum Basic
<lang zxbasic>10 FOR i=1 TO 20 20 PRINT i;" = "; 30 IF i=1 THEN PRINT 1: GO TO 90 40 LET p=2: LET n=i: LET f$="" 50 IF p>n THEN GO TO 80 60 IF NOT FN m(n,p) THEN LET f$=f$+STR$ p+" x ": LET n=INT (n/p): GO TO 50 70 LET p=p+1: GO TO 50 80 PRINT f$( TO LEN f$-3) 90 NEXT i 100 STOP 110 DEF FN m(a,b)=a-INT (a/b)*b</lang>
- Programming Tasks
- Prime Numbers
- 11l
- 360 Assembly
- Ada
- ALGOL 68
- AutoHotkey
- AWK
- BBC BASIC
- Befunge
- C
- C++
- C sharp
- Clojure
- CoffeeScript
- Common Lisp
- D
- Uiprimes
- DCL
- DWScript
- EchoLisp
- Eiffel
- Elixir
- Euphoria
- F Sharp
- Factor
- Forth
- Fortran
- FreeBASIC
- Frink
- Go
- Groovy
- Haskell
- Icon
- Unicon
- Icon Programming Library
- IS-BASIC
- J
- Java
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