Arithmetic derivative
The arithmetic derivative of an integer (more specifically, the Lagarias arithmetic derivative) is a function defined for integers, based on prime factorization, by analogy with the product rule for the derivative of a function that is used in mathematical analysis. Accordingly, for natural numbers n, the arithmetic derivative D(n) is defined as follows:
- D(0) = D(1) = 0.
- D(p) = 1 for any prime p.
- D(mn) = D(m)n + mD(n) for any m,n ∈ N. (Leibniz rule for derivatives).
Additionally, for negative integers the arithmetic derivative may be defined as -D(-n) (n < 0).
- Examples
D(2) = 1 and D(3) = 1 (both are prime) so if mn = 2 * 3, D(6) = (1)(3) + (1)(2) = 5.
D(9) = D(3)(3) + D(3)(3) = 6
D(27) = D(3)*9 + D(9)*3 = 9 + 18 = 27
D(30) = D(5)(6) + D(6)(5) = 6 + 5 * 5 = 31.
- Task
Find and show the arithmetic derivatives for -99 through 100.
- Stretch task
Find (the arithmetic derivative of 10^m) then divided by 7, where m is from 1 to 20.
- See also
J
Implementation: <lang J>D=: {{ (*y)*+/1*/\.q:1>.|y }}"0</lang>
In other words: find the prime factors of the absolute value of y as a sequence, find and sum each of the products with exactly one value removed from this sequence and multiply by the sign of y. (And since 0's prime factor list does not exist, use the empty list of prime factors of 1 for that case. (The sum of the elements of an empty list is zero, the product of the elements of an empty list is 1.))
Task example:
<lang J> D _99+i.20 10 _75 _77 _1 _272 _24 _49 _34 _96 _20 _123
_1 _140 _32 _45 _22 _124 _1 _43 _108 _176 _1 _71 _18 _80 _55 _39 _1 _156 _1 _59
_26 _72 _1 _61 _18 _192 _51 _33 _1 _92
_1 _31 _22 _92 _16 _81 _1 _56 _20 _45
_14 _112 _1 _25 _39 _48 _1 _41 _1 _68 _16 _21 _1 _60 _12 _19 _14 _80 _1 _31
_1 _32 _27 _15 _10 _44 _1 _13 _10 _24 _1 _21 _1 _32 _8 _9 _1 _16 _1 _7 _6 _12 _1 _5 _1 _4 _1 _1 0 0 0 1 1 4 1 5 1 12 6 7 1 16 1 9 8 32 1 21 1 24 10 13 1 44 10 15 27 32 1 31 1 80 14 19 12 60 1 21 16 68 1 41 1 48 39 25 1 112 14 45 20 56 1 81 16 92 22 31 1 92 1 33 51 192 18 61 1 72 26 59 1 156 1 39 55 80 18 71 1 176
108 43 1 124 22 45 32 140 1 123
20 96 34 49 24 272 1 77 75 140</lang>
Also, it seems like it's worth verifying that order of evaluation does not create an ambiguity for the value of D:
<lang J> 15 10 6 + 2 3 5 * D 15 10 6 31 31 31</lang>
Stretch task:
<lang j> (D 10x^1+i.4 5)%7
1 20 300 4000 50000
600000 7000000 80000000 900000000 10000000000
110000000000 1200000000000 13000000000000 140000000000000 1500000000000000
16000000000000000 170000000000000000 1800000000000000000 19000000000000000000 200000000000000000000</lang>
Julia
<lang ruby>using Primes
D(n) = n < 0 ? -D(-n) : n < 2 ? zero(n) : isprime(n) ? one(n) : typeof(n)(sum(e * n ÷ p for (p, e) in eachfactor(n)))
foreach(p -> print(lpad(p[2], 5), p[1] % 10 == 0 ? "\n" : ""), pairs(map(D, -99:100)))
println() for m in 1:20
println("D for 10^", rpad(m, 3), "divided by 7 is ", D(Int128(10)^m) ÷ 7)
end
</lang>
- Output:
-75 -77 -1 -272 -24 -49 -34 -96 -20 -123
-1 -140 -32 -45 -22 -124 -1 -43 -108 -176
-1 -71 -18 -80 -55 -39 -1 -156 -1 -59
-26 -72 -1 -61 -18 -192 -51 -33 -1 -92
-1 -31 -22 -92 -16 -81 -1 -56 -20 -45
-14 -112 -1 -25 -39 -48 -1 -41 -1 -68
-16 -21 -1 -60 -12 -19 -14 -80 -1 -31
-1 -32 -27 -15 -10 -44 -1 -13 -10 -24
-1 -21 -1 -32 -8 -9 -1 -16 -1 -7
-6 -12 -1 -5 -1 -4 -1 -1 0 0
0 1 1 4 1 5 1 12 6 7
1 16 1 9 8 32 1 21 1 24
10 13 1 44 10 15 27 32 1 31
1 80 14 19 12 60 1 21 16 68
1 41 1 48 39 25 1 112 14 45
20 56 1 81 16 92 22 31 1 92
1 33 51 192 18 61 1 72 26 59
1 156 1 39 55 80 18 71 1 176
108 43 1 124 22 45 32 140 1 123
20 96 34 49 24 272 1 77 75 140
D for 10^1 divided by 7 is 1
D for 10^2 divided by 7 is 20
D for 10^3 divided by 7 is 300
D for 10^4 divided by 7 is 4000
D for 10^5 divided by 7 is 50000
D for 10^6 divided by 7 is 600000
D for 10^7 divided by 7 is 7000000
D for 10^8 divided by 7 is 80000000
D for 10^9 divided by 7 is 900000000
D for 10^10 divided by 7 is 10000000000
D for 10^11 divided by 7 is 110000000000
D for 10^12 divided by 7 is 1200000000000
D for 10^13 divided by 7 is 13000000000000
D for 10^14 divided by 7 is 140000000000000
D for 10^15 divided by 7 is 1500000000000000
D for 10^16 divided by 7 is 16000000000000000
D for 10^17 divided by 7 is 170000000000000000
D for 10^18 divided by 7 is 1800000000000000000
D for 10^19 divided by 7 is 19000000000000000000
D for 10^20 divided by 7 is 200000000000000000000
Python
<lang python>from sympy.ntheory import factorint
def D(n):
if n < 0:
return -D(-n)
elif n < 2:
return 0
else:
fdict = factorint(n)
if len(fdict) == 1 and 1 in fdict: # is prime
return 1
return sum([n * e // p for p, e in fdict.items()])
for n in range(-99, 101):
print('{:5}'.format(D(n)), end='\n' if n % 10 == 0 else )
print() for m in range(1, 21):
print('(D for 10**{}) divided by 7 is {}'.format(m, D(10 ** m) // 7))
</lang>
- Output:
-75 -77 -1 -272 -24 -49 -34 -96 -20 -123
-1 -140 -32 -45 -22 -124 -1 -43 -108 -176
-1 -71 -18 -80 -55 -39 -1 -156 -1 -59
-26 -72 -1 -61 -18 -192 -51 -33 -1 -92
-1 -31 -22 -92 -16 -81 -1 -56 -20 -45
-14 -112 -1 -25 -39 -48 -1 -41 -1 -68
-16 -21 -1 -60 -12 -19 -14 -80 -1 -31
-1 -32 -27 -15 -10 -44 -1 -13 -10 -24
-1 -21 -1 -32 -8 -9 -1 -16 -1 -7
-6 -12 -1 -5 -1 -4 -1 -1 0 0
0 1 1 4 1 5 1 12 6 7
1 16 1 9 8 32 1 21 1 24
10 13 1 44 10 15 27 32 1 31
1 80 14 19 12 60 1 21 16 68
1 41 1 48 39 25 1 112 14 45
20 56 1 81 16 92 22 31 1 92
1 33 51 192 18 61 1 72 26 59
1 156 1 39 55 80 18 71 1 176
108 43 1 124 22 45 32 140 1 123
20 96 34 49 24 272 1 77 75 140
(D for 10**1) divided by 7 is 1
(D for 10**2) divided by 7 is 20
(D for 10**3) divided by 7 is 300
(D for 10**4) divided by 7 is 4000
(D for 10**5) divided by 7 is 50000
(D for 10**6) divided by 7 is 600000
(D for 10**7) divided by 7 is 7000000
(D for 10**8) divided by 7 is 80000000
(D for 10**9) divided by 7 is 900000000
(D for 10**10) divided by 7 is 10000000000
(D for 10**11) divided by 7 is 110000000000
(D for 10**12) divided by 7 is 1200000000000
(D for 10**13) divided by 7 is 13000000000000
(D for 10**14) divided by 7 is 140000000000000
(D for 10**15) divided by 7 is 1500000000000000
(D for 10**16) divided by 7 is 16000000000000000
(D for 10**17) divided by 7 is 170000000000000000
(D for 10**18) divided by 7 is 1800000000000000000
(D for 10**19) divided by 7 is 19000000000000000000
(D for 10**20) divided by 7 is 200000000000000000000
Raku
<lang perl6>use Prime::Factor;
multi D (0) { 0 } multi D (1) { 0 } multi D ($n where &is-prime) { 1 } multi D ($n where * < 0 ) { -D -$n } multi D ($n) { sum $n.&prime-factors.Bag.map: { $n × .value / .key } }
put (-99 .. 100).map(&D).batch(10)».fmt("%4d").join: "\n";
put ;
put join "\n", (1..20).map: { sprintf "D(10**%-2d) / 7 == %d", $_, D(10**$_) / 7 }</lang>
- Output:
-75 -77 -1 -272 -24 -49 -34 -96 -20 -123 -1 -140 -32 -45 -22 -124 -1 -43 -108 -176 -1 -71 -18 -80 -55 -39 -1 -156 -1 -59 -26 -72 -1 -61 -18 -192 -51 -33 -1 -92 -1 -31 -22 -92 -16 -81 -1 -56 -20 -45 -14 -112 -1 -25 -39 -48 -1 -41 -1 -68 -16 -21 -1 -60 -12 -19 -14 -80 -1 -31 -1 -32 -27 -15 -10 -44 -1 -13 -10 -24 -1 -21 -1 -32 -8 -9 -1 -16 -1 -7 -6 -12 -1 -5 -1 -4 -1 -1 0 0 0 1 1 4 1 5 1 12 6 7 1 16 1 9 8 32 1 21 1 24 10 13 1 44 10 15 27 32 1 31 1 80 14 19 12 60 1 21 16 68 1 41 1 48 39 25 1 112 14 45 20 56 1 81 16 92 22 31 1 92 1 33 51 192 18 61 1 72 26 59 1 156 1 39 55 80 18 71 1 176 108 43 1 124 22 45 32 140 1 123 20 96 34 49 24 272 1 77 75 140 D(10**1 ) / 7 == 1 D(10**2 ) / 7 == 20 D(10**3 ) / 7 == 300 D(10**4 ) / 7 == 4000 D(10**5 ) / 7 == 50000 D(10**6 ) / 7 == 600000 D(10**7 ) / 7 == 7000000 D(10**8 ) / 7 == 80000000 D(10**9 ) / 7 == 900000000 D(10**10) / 7 == 10000000000 D(10**11) / 7 == 110000000000 D(10**12) / 7 == 1200000000000 D(10**13) / 7 == 13000000000000 D(10**14) / 7 == 140000000000000 D(10**15) / 7 == 1500000000000000 D(10**16) / 7 == 16000000000000000 D(10**17) / 7 == 170000000000000000 D(10**18) / 7 == 1800000000000000000 D(10**19) / 7 == 19000000000000000000 D(10**20) / 7 == 200000000000000000000
Wren
As integer arithmetic in Wren is inaccurate above 2^53 we need to use BigInt here. <lang ecmascript>import "./big" for BigInt import "./fmt" for Fmt
var D = Fn.new { |n|
if (n < 0) return -D.call(-n) if (n < 2) return BigInt.zero var f = BigInt.primeFactors(n) var c = f.count if (c == 1) return BigInt.one if (c == 2) return f[0] + f[1] var d = n / f[0] return D.call(d) * f[0] + d
}
var ad = List.filled(200, 0) for (n in -99..100) ad[n+99] = D.call(BigInt.new(n)) Fmt.tprint("$4i", ad, 10) System.print() for (m in 1..20) {
Fmt.print("D(10^$-2d) / 7 = $i", m, D.call(BigInt.ten.pow(m))/7)
}</lang>
- Output:
-75 -77 -1 -272 -24 -49 -34 -96 -20 -123 -1 -140 -32 -45 -22 -124 -1 -43 -108 -176 -1 -71 -18 -80 -55 -39 -1 -156 -1 -59 -26 -72 -1 -61 -18 -192 -51 -33 -1 -92 -1 -31 -22 -92 -16 -81 -1 -56 -20 -45 -14 -112 -1 -25 -39 -48 -1 -41 -1 -68 -16 -21 -1 -60 -12 -19 -14 -80 -1 -31 -1 -32 -27 -15 -10 -44 -1 -13 -10 -24 -1 -21 -1 -32 -8 -9 -1 -16 -1 -7 -6 -12 -1 -5 -1 -4 -1 -1 0 0 0 1 1 4 1 5 1 12 6 7 1 16 1 9 8 32 1 21 1 24 10 13 1 44 10 15 27 32 1 31 1 80 14 19 12 60 1 21 16 68 1 41 1 48 39 25 1 112 14 45 20 56 1 81 16 92 22 31 1 92 1 33 51 192 18 61 1 72 26 59 1 156 1 39 55 80 18 71 1 176 108 43 1 124 22 45 32 140 1 123 20 96 34 49 24 272 1 77 75 140 D(10^1 ) / 7 = 1 D(10^2 ) / 7 = 20 D(10^3 ) / 7 = 300 D(10^4 ) / 7 = 4000 D(10^5 ) / 7 = 50000 D(10^6 ) / 7 = 600000 D(10^7 ) / 7 = 7000000 D(10^8 ) / 7 = 80000000 D(10^9 ) / 7 = 900000000 D(10^10) / 7 = 10000000000 D(10^11) / 7 = 110000000000 D(10^12) / 7 = 1200000000000 D(10^13) / 7 = 13000000000000 D(10^14) / 7 = 140000000000000 D(10^15) / 7 = 1500000000000000 D(10^16) / 7 = 16000000000000000 D(10^17) / 7 = 170000000000000000 D(10^18) / 7 = 1800000000000000000 D(10^19) / 7 = 19000000000000000000 D(10^20) / 7 = 200000000000000000000