Append numbers at same position in strings

Append numbers at same position in strings is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Task

Let given three list:
list1 = [1,2,3,4,5,6,7,8,9]
list2 = [10,11,12,13,14,15,16,17,18]
list3 = [19,20,21,22,23,24,25,26,27]
Append numbers at same position in strings.
The result should be:
list = [11019,21120,31221,41322,51423,61524,71625,81726,91827][11019,21120,31221,41322,51423,61524,71625,81726,91827]

Raku

Not really seeing why we need to show the result twice but that's what the requirement is... ¯\_(ツ)_/¯ (I find myself making that gesture often in response to Calmosofts tasks.)

<lang perl6>say ([Z~] [1,2,3,4,5,6,7,8,9], [10,11,12,13,14,15,16,17,18], [19,20,21,22,23,24,25,26,27]) xx 2;</lang>

Output:

((11019 21120 31221 41322 51423 61524 71625 81726 91827) (11019 21120 31221 41322 51423 61524 71625 81726 91827))

Ring

<lang ring> load "stdlib.ring" list1 = [1,2,3,4,5,6,7,8,9] list2 = [10,11,12,13,14,15,16,17,18] list3 = [19,20,21,22,23,24,25,26,27] list = []

for n = 1 to len(list1)

   str1 = string(list1[n])
   str2 = string(list2[n])
   str3 = string(list3[n])
   str = str1 + str2 + str3
   add(list,str)

next

showArray(list)

func showArray(array)

    txt = ""
    see "["
    for n = 1 to len(array)
        txt = txt + array[n] + ","
    next
    txt = left(txt,len(txt)-1)
    txt = txt + "]"
    see txt

</lang>

Output:

list = [11019,21120,31221,41322,51423,61524,71625,81726,91827][11019,21120,31221,41322,51423,61524,71625,81726,91827]
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