Abundant odd numbers: Difference between revisions
m
→{{header|Julia}}
Line 174:
<lang julia>using Primes
function
f = [one(n)]
for (p, x) in factor(n)
Line 183:
end
isabundant(n) = sum(
prettyprintfactors(n) = (a =
function oddabundantsfrom(startingint, needed, nprint=0, targetf=(x -> false))
|