Abundant odd numbers: Difference between revisions

prettyprintfactors(n) = (a = propfact(n); println("$n has proper divisors $a, these sum to $(sum(a))."))

 

n = isodd(startingint) ? startingint : startingint + 1

count = 0

prettyprintfactors(n)

end

prettyprintfactors(n)

break

 

println("The first abundant odd number greater than one billion:")

</lang>{{out}}

<pre>