Talk:Remove duplicate elements: Difference between revisions
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Does anybody know how to do it with Bash (or any other shell)?
for example, if I start with "-I/usr/include -I/usr/include -I/usr/other" I would like to get "-I/usr/include -I/usr/other"
: sort -u will take a line delimited list and eliminate non-unique lines. The trick for your example is that you have everything on one line. But you can use fmt to split lines and xargs to reassemble them:
$ echo -I/usr/include -I/usr/include -I/usr/other | fmt -sw1 | sort -u | xargs echo
-I/usr/include -I/usr/other
== APL ==
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