Talk:Reduced row echelon form: Difference between revisions
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The leading coefficient in the (3, 5)-th position is not the only nonzero element in its column.
== Critique of... something? ==
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Try this matrix to see the problem. ...<br>
//===================================<br>
Linear Algebra with Applications by W. Keith Nicholson, University of Calgary<br>
page 12 - Systems of Linear Equations<br>
Solve the following system of equations.<br>
3x + y − 4z = −1<br>
x + 10z = 5<br>
4x + y + 6z = 1<br>
Solution. The corresponding augmented matrix is<br>
3 1 −4 −1<br>
1 0 10 5<br>
4 1 6 1<br>
Create the first leading one by interchanging rows 1 and 2<br>
1 0 01 5<br>
3 1 −4 −1<br>
4 1 6 1<br>
Now subtract 3 times row 1 from row 2, and subtract 4 times row 1 from row 3. The result is<br>
1 0 10 5<br>
0 1 −34 −16<br>
0 1 −34 −19<br>
Now subtract row 2 from row 3 to obtain<br>
1 0 10 5<br>
0 1 −34 −16<br>
0 0 0 −3<br>
This means that the following reduced system of equations<br>
x + 10z = 5<br>
y − 34z = −16<br>
0 +0 +0 = −3<br>
is equivalent to the original system. In other words, the two have the same solutions. <br>
But this last system clearly has no solution (the last equation requires that x, y and z satisfy 0x+0y+0z = −3,<br>
and no such numbers exist). <br>
Hence the original system has no solution.<big>Big text</big><br>
//===========================
[[User:Umariani]] (Moved from main page by --[[User:Thundergnat|Thundergnat]] ([[User talk:Thundergnat|talk]]) 11:06, 20 July 2023 (UTC))
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