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Talk:Hash join: Difference between revisions
→clarification needed: updated status for the REXX code.
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:Agree on the draft status for now. And despite the, er, fireworks accompanying its creation, I suspect it'll be a good task. I don't see how the built-in-ness of hashes plays one way or the other. The task merely assumes that an appropriate hash implementation will be used, whether built-in or imported or implemented as part of the solution. --[[User:TimToady|TimToady]] ([[User talk:TimToady|talk]]) 04:05, 3 December 2013 (UTC)
:: And it is now a full task, with 5 implementations (right now). I'll do a bit more editing (adding in a print requirement and giving test data) but that won't break the existing implementations. –[[User:Dkf|Donal Fellows]] ([[User talk:Dkf|talk]]) 10:48, 12 December 2013 (UTC)
==clarification needed==
Is Popeye's entry to be '''not''' listed, either because it has no nemesis, or because it wasn't in the 2nd relation list? -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:41, 17 December 2013 (UTC)
: '''Popeye''' shouldn't be in the resulting relation because it isn't in the second relation. See also [[wp:Join_%28SQL%29#Inner_join]]. --[[User:AndiPersti|Andreas Perstinger]] ([[User talk:AndiPersti|talk]]) 19:49, 7 March 2014 (UTC)
(If not, I'll enable the '''if''' statement that bypasses the check for the above condition.) -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:43, 17 December 2013 (UTC)
: The above REXX code ('''if''' statement) was removed. -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 20:08, 7 March 2014 (UTC)
Can the nemeses (plural) be listed on one line (as the REXX example shows)? To me, it looks cleaner, more succint, less screen (output) clutter. -- [[User:Gerard Schildberger|Gerard Schildberger]] ([[User talk:Gerard Schildberger|talk]]) 00:41, 17 December 2013 (UTC)
== Is identity a hash? ==
If the easiest way of implementing this is to use the identity function as the hash function, would that qualify? Why or why not? --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 04:29, 6 January 2014 (UTC)
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