Anonymous user
Talk:Combinations: Difference between revisions
→Formula
(→Formula: new section) |
|||
Line 14:
Strictlly speaking, combinations with repetiotions 5 of 5 give you 126 variants, just combinations give you just 1 variant
Formula for comb. with repet: http://hijos.ru/wp-content/ql-cache/quicklatex-7f6e17e6e05e9a62c1188bd95ff7e8ad.gif
Also, we should distinguish third thing - when we have a deal with combinations with repetitions with additional condition.
Sorry for this sentence looking like folk verses.
With respect to you, Ivan Gavryushin (dcc0@).
| |||