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Talk:Cipolla's algorithm: Difference between revisions
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::::::: Let ω = 2.64575 (in other words: <math>\sqrt{7}</math>) then -1 - 3ω =(mod 13) 4.06275 however, -92 - 16ω =(mod 13) 8.66798. And, ok, there's a slight precision issue because I've only shown the first six digits of those numbers. But neither that precision issue, nor the mod 13 issue, convinces me that 4.06275 equals 8.66798. --[[User:Rdm|Rdm]] ([[User talk:Rdm|talk]]) 03:11, 27 March 2016 (UTC)
::::::: Let a = -1 -3ω , b = -92 -16ω , hence -a = 1 +3ω , then -a + b = -91 -13ω (mod 13). Remarking that -91 - 13ω = 0 + 0ω (mod 13), we have -a + b = 0. This seems to indicate that a = b. But I may be wrong.--[[User:G.Brougnard|G.Brougnard]] ([[User talk:G.Brougnard|talk]]) 08:50, 27 March 2016 (UTC)
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