Sum of the digits of n is substring of n: Difference between revisions

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;Task:
Find and show numbers &nbsp; '''n''' &nbsp; with property that the sum of the decimal digits of &nbsp; '''n''' &nbsp; is substring of &nbsp; '''n''', &nbsp; where &nbsp; '''n <&nbsp; 1000&lt; &nbsp; 1,000'''
 
 
{{Template:Strings}}
<br><br>
 
=={{header|11l}}==
{{trans|Python}}
{{trans|Nim}}
 
<syntaxhighlight lang="11l">V count = 0
L(n) 1000
I String(sum(String(n).map(Int))) C String(n)
count++
print(f:‘{n:3}’, end' I count % 8 == 0 {"\n"} E ‘ ’)</syntaxhighlight>
 
{{out}}
<pre>
0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
</pre>
 
=={{header|8080 Assembly}}==
<langsyntaxhighlight lang="8080asm">puts: equ 9
org 100h
lxi h,-1 ; Number
Line 103 ⟶ 126:
jmp 5
buf0: equ $+32
buf1: equ $+64</langsyntaxhighlight>
{{out}}
<pre style='height:50ex;'>0
Line 153 ⟶ 176:
918
919</pre>
 
=={{header|Action!}}==
<syntaxhighlight lang="action!">INT FUNC SumDigits(INT num)
INT res,a
 
res=0
WHILE num#0
DO
res==+num MOD 10
num=num/10
OD
RETURN (res)
 
BYTE Func IsValidNumber(INT num)
CHAR ARRAY s(5),sub(5)
INT sum,v,len,start
 
sum=SumDigits(num)
StrI(num,s)
FOR len=1 TO s(0)
DO
FOR start=1 TO s(0)-len+1
DO
SCopyS(sub,s,start,start+len-1)
IF ValI(sub)=sum THEN
RETURN (1)
FI
OD
OD
RETURN (0)
 
PROC Main()
INT i,count=[0]
 
FOR i=0 TO 999
DO
IF IsValidNumber(i) THEN
PrintI(i) Put(32)
count==+1
FI
OD
PrintF("%E%EThere are %I numbers",count)
RETURN</syntaxhighlight>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Sum_of_the_digits_of_n_is_substring_of_n.png Screenshot from Atari 8-bit computer]
<pre>
0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179
189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919
 
There are 48 numbers
</pre>
 
=={{header|ALGOL 68}}==
ALGOL 68G has the procedure "string in string" in the prelude, for other compilers, a version is available here: [[ALGOL_68/prelude]].
<langsyntaxhighlight lang="algol68">BEGIN # find n where the sum of the digits is a substring of the representaton of n #
INT max number = 1 000;
INT n count := 0;
Line 173 ⟶ 247:
FI
OD
END</langsyntaxhighlight>
{{out}}
<pre>
Line 185 ⟶ 259:
 
=={{header|ALGOL-M}}==
<langsyntaxhighlight lang="algolm">begin
integer function mod(a,b);
integer a,b;
Line 242 ⟶ 316:
end;
end;
end</langsyntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9
Line 251 ⟶ 325:
 
=={{header|ALGOL W}}==
<langsyntaxhighlight lang="algolw">begin % find numbers n, where the sum of the digits is a substring of n %
% returns true if the digits of s contains the digits of t, false otherwise %
% s and t are assumed to be blank-padded, left-justified numeric strings %
logical procedure containsDigits( integer value s, t ) ;
if s = t then true
else begin
integer tPower, v, u;
logical isContanedisContained;
% find the lowest power of 10 that is greater then t %
tPower := 10;
Line 266 ⟶ 339:
v := v div 10
end while_v_gt_9 ;
isContanedisContained := false;
v := abs t;
u := abs s;
while not isContanedisContained and u > 0 do begin
isContanedisContained := ( u rem tPower ) = v;
u := u div 10
end while_not_isContaned_and_u_gt_0while_not_isContained_and_u_gt_0 ;
isContanedisContained
end containsDigits ;
% find and show the matching numbers up to 1000 %
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end if_n_contains_dSum
end for_n
end.</langsyntaxhighlight>
{{out}}
<pre>
Line 305 ⟶ 378:
=={{header|APL}}==
{{works with|Dyalog APL}}
<langsyntaxhighlight APLlang="apl">(⊢(/⍨)(∨/⍕∘(+/(⍎¨⍕))⍷⍕)¨)0,⍳999</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900
910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|Arturo}}==
 
<syntaxhighlight lang="rebol">print select 1..999 'num ->
contains? to :string num
to :string sum digits num</syntaxhighlight>
 
{{out}}
 
<pre>1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|AutoHotkey}}==
<syntaxhighlight lang="autohotkey">result := "", cntr := 1
loop 1000{
n := A_Index-1, sum := 0
for i, v in StrSplit(n)
sum += v
if InStr(n, sum){
result .= n (mod(cntr, 8)?"`t":"`n")
if (++cntr = 50)
break
}
}
MsgBox % result</syntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|AWK}}==
<syntaxhighlight lang="awk">
<lang AWK>
# syntax: GAWK -f SUM_OF_THE_DIGITS_OF_N_IS_SUBSTRING_OF_N.AWK
BEGIN {
Line 330 ⟶ 434:
return(sum)
}
</syntaxhighlight>
</lang>
{{out}}
<pre>
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=={{header|BASIC}}==
<langsyntaxhighlight lang="basic">10 DEFINT I,J,K
20 FOR I=0 TO 999
30 J=0: K=I
Line 349 ⟶ 453:
42 J$=STR$(J): J$=RIGHT$(J$,LEN(J$)-1)
50 IF INSTR(I$,J$) THEN PRINT I,
60 NEXT I</langsyntaxhighlight>
{{out}}
<pre> 0 1 2 3 4
Line 364 ⟶ 468:
 
=={{header|BCPL}}==
<langsyntaxhighlight lang="bcpl">get "libhdr"
 
let dsum(n) = n=0 -> 0, n rem 10 + dsum(n/10)
Line 392 ⟶ 496:
$)
wrch('*N')
$)</langsyntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9
Line 400 ⟶ 504:
912 913 914 915 916 917 918 919</pre>
 
=={{header|BQN}}==
<syntaxhighlight lang="bqn">DigitSum ← +´•Fmt-'0'˙
Contains ← (∨´⍷˜ )○•Fmt
∘‿6⥊ (⊢ Contains DigitSum)¨⊸/↕1000</syntaxhighlight>
{{out}}
<pre>┌─
╵ 0 1 2 3 4 5
6 7 8 9 10 20
30 40 50 60 70 80
90 100 109 119 129 139
149 159 169 179 189 199
200 300 400 500 600 700
800 900 910 911 912 913
914 915 916 917 918 919
┘</pre>
=={{header|C}}==
<langsyntaxhighlight lang="c">#include <stdio.h>
#include <string.h>
 
Line 425 ⟶ 544:
return 0;
}</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|C++}}==
<langsyntaxhighlight lang="cpp">#include <iostream>
 
int digitSum(int n) {
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std::cout << std::endl;
return 0;
}</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
=={{header|CLU}}==
<syntaxhighlight lang="clu">digit_sum = proc (n: int) returns (int)
sum: int := 0
while n > 0 do
sum := sum + n // 10
n := n / 10
end
return (sum)
end digit_sum
 
digit_sum_is_substring = proc (n: int) returns (bool)
n_str: string := int$unparse(n)
ds_str: string := int$unparse(digit_sum(n))
return (string$indexs(ds_str, n_str) ~= 0)
end digit_sum_is_substring
 
match_range = iter (from, to: int, p: proctype (int) returns (bool))
yields (int)
for i: int in int$from_to(from,to) do
if p(i) then yield(i) end
end
end match_range
 
start_up = proc ()
po: stream := stream$primary_output()
col: int := 0
for i: int in match_range(0, 999, digit_sum_is_substring) do
stream$putright(po, int$unparse(i), 4)
col := col + 1
if col // 10 = 0 then stream$putc(po, '\n') end
end
end start_up</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9
10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|COBOL}}==
<syntaxhighlight lang="cobol"> IDENTIFICATION DIVISION.
PROGRAM-ID. SUM-SUBSTRING.
DATA DIVISION.
WORKING-STORAGE SECTION.
01 CALCULATION.
02 N PIC 9999.
02 X PIC 9.
02 DSUM PIC 99.
02 N-DIGITS REDEFINES N.
03 ND PIC 9 OCCURS 4 TIMES.
02 S-DIGITS REDEFINES DSUM.
03 SUMD PIC 9 OCCURS 2 TIMES.
01 OUTPUT-FORMAT.
02 N-OUT PIC ZZZ9.
PROCEDURE DIVISION.
BEGIN.
PERFORM TESTNUMBER VARYING N FROM 0 BY 1
UNTIL N IS EQUAL TO 1000.
STOP RUN.
TESTNUMBER SECTION.
BEGIN.
PERFORM SUM-DIGITS.
SET X TO 1.
IF DSUM IS LESS THAN 10 GO TO ONE-DIGIT-CHECK.
TWO-DIGIT-CHECK.
IF X IS GREATER THAN 3 GO TO DONE.
IF ND(X) = SUMD(1) AND ND(X + 1) = SUMD(2) GO TO SHOW.
ADD 1 TO X.
GO TO TWO-DIGIT-CHECK.
ONE-DIGIT-CHECK.
IF X IS GREATER THAN 4 GO TO DONE.
IF ND(X) = SUMD(2) GO TO SHOW.
ADD 1 TO X.
GO TO ONE-DIGIT-CHECK.
SHOW.
MOVE N TO N-OUT.
DISPLAY N-OUT.
DONE. EXIT.
SUM-DIGITS SECTION.
BEGIN.
SET DSUM TO 0.
SET X TO 1.
LOOP.
ADD ND(X) TO DSUM.
ADD 1 TO X.
IF X IS LESS THAN 5 GO TO LOOP.</syntaxhighlight>
{{out}}
<pre style='height:50ex;'> 0
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=={{header|Comal}}==
<syntaxhighlight lang="comal">0010 FUNC digit'sum#(n#) CLOSED
0020 sum#:=0
0030 WHILE n# DO sum#:+n# MOD 10;n#:=n# DIV 10
0040 RETURN sum#
0050 ENDFUNC digit'sum#
0060 //
0070 col#:=0
0080 ZONE 4
0090 FOR i#:=0 TO 999 DO
0100 IF STR$(digit'sum#(i#)) IN STR$(i#) THEN
0110 PRINT i#,
0120 col#:+1
0130 IF col# MOD 15=0 THEN PRINT
0140 ENDIF
0150 ENDFOR i#
0160 PRINT
0170 END</syntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50
60 70 80 90 100 109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911 912 913 914 915 916
917 918 919</pre>
 
=={{header|Cowgol}}==
<langsyntaxhighlight lang="cowgol">include "cowgol.coh";
 
sub digitSum(n: uint16): (s: uint16) is
Line 495 ⟶ 782:
i := i + 1;
end loop;
print_nl();</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|D}}==
{{trans|C++}}
<syntaxhighlight lang="d">import std.algorithm;
import std.conv;
import std.stdio;
 
int digitSum(int n) {
int s = 0;
do {
s += n % 10;
} while (n /= 10);
return s;
}
 
void main() {
foreach (i; 0 .. 1000) {
if (i.to!string.canFind(digitSum(i).to!string)) {
write(i, ' ');
}
}
writeln;
}</syntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|SysUtils,StdCtrls}}
 
 
<syntaxhighlight lang="Delphi">
 
 
{This code would normally be in a library, but is included here for clarity}
 
procedure GetDigits(N: integer; var IA: TIntegerDynArray);
{Get an array of the integers in a number}
{Numbers returned from least to most significant}
var T,I,DC: integer;
begin
DC:=Trunc(Log10(N))+1;
SetLength(IA,DC);
for I:=0 to DC-1 do
begin
T:=N mod 10;
N:=N div 10;
IA[I]:=T;
end;
end;
 
 
procedure SumDigitsSubstring(Memo: TMemo);
var N,J,Cnt,Sum: integer;
var Dg: TIntegerDynArray;
var NS,SS,S: string;
begin
S:='';
Cnt:=0;
for N:=0 to 1000-1 do
begin
GetDigits(N,Dg);
Sum:=0;
for J:=0 to High(Dg) do
Sum:=Sum+Dg[J];
NS:=IntToStr(N);
SS:=IntToStr(Sum);
if Pos(SS,NS)>0 then
begin
Inc(Cnt);
S:=S+Format('%4d',[N]);
if (Cnt mod 10)=0 then S:=S+CRLF;
end;
end;
Memo.Lines.Add(S);
end;
 
 
 
</syntaxhighlight>
{{out}}
<pre>
0 1 2 3 4 5 6 7 8 9
10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
 
Elapsed Time: 1.433 ms.
 
</pre>
 
 
=={{header|Draco}}==
<syntaxhighlight lang="draco">\util.g
 
proc nonrec digit_sum(word n) word:
word sum;
sum := 0;
while n ~= 0 do
sum := sum + n % 10;
n := n / 10;
od;
sum
corp
 
proc nonrec itoa(word n; *char buf) void:
channel output text ch;
open(ch, buf);
write(ch; n);
close(ch)
corp
 
proc nonrec digit_sum_is_substring(word n) bool:
[10] char dstr, dsub;
itoa(n, &dstr[0]);
itoa(digit_sum(n), &dsub[0]);
CharsIndex(&dstr[0], &dsub[0]) ~= -1
corp
 
proc nonrec main() void:
word i, seen;
seen := 0;
for i from 0 upto 999 do
if digit_sum_is_substring(i) then
write(i:4);
seen := seen + 1;
if seen % 20 = 0 then writeln() fi
fi
od
corp</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|F_Sharp|F#}}==
<langsyntaxhighlight lang="fsharp">
// Sum digits of n is substring of n: Nigel Galloway. April 16th., 2021
let rec fG n g=match (n/10,n%(if g<10 then 10 else 100)) with (_,n) when n=g->true |(0,_)->false |(n,_)->fG n g
let rec fN g=function n when n<10->n+g |n->fN(g+n%10)(n/10)
{1..999}|>Seq.filter(fun n->fG n (fN 0 n))|>Seq.iter(printf "%d "); printfn ""
</syntaxhighlight>
</lang>
{{out}}
<pre>
Line 511 ⟶ 933:
Real: 00:00:00.003
</pre>
 
=={{header|Factor}}==
{{works with|Factor|0.99 2021-02-05}}
<langsyntaxhighlight lang="factor">USING: grouping kernel math.text.utils present prettyprint
sequences ;
 
1000 <iota>
[ [ 1 digit-groups sum present ] [ present ] bi subseq? ] filter
8 group simple-table.</langsyntaxhighlight>
{{out}}
<pre>
Line 527 ⟶ 950:
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
</pre>
 
=={{header|Fermat}}==
No string conversion.
<syntaxhighlight lang="fermat">Func Digsum(n, b) =
ds:=0; {digital sum of n in base b}
while n>0 do
ds:+(n|b);
n:=n\b;
od;
ds.;
 
Func Numdig(n, b) =
nd:=0; {number of digits of n in base b}
while n > 0 do
nd:+;
n:=n\b;
od;
nd.;
 
for n = 1 to 999 do
ds:=Digsum(n, 10); {digital sum of n}
nd:=Numdig(ds, 10); {how many digits does the digital sum itself have?}
nt:=n; {temporary copy of n}
while nt>0 do
if ds=(nt|(10^(nd))) then
!!n; {if the last nt digits of n are the digital sum, print and exit the loop}
&>;
fi;
nt:=nt\10;
od;
od;</syntaxhighlight>
{{out}}<pre>
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</pre>
 
=={{header|FOCAL}}==
<langsyntaxhighlight lang="focal">01.10 F N=0,999;D 2;D 4
01.20 Q
 
Line 554 ⟶ 1,057:
04.70 I (P)4.2,4.8,4.2
04.80 R
04.90 T %3,N,!</langsyntaxhighlight>
{{out}}
<pre style='height:50ex;'>= 0
Line 604 ⟶ 1,107:
= 918
= 919</pre>
 
=={{header|FreeBASIC}}==
<langsyntaxhighlight lang="freebasic">function is_substring( s as string, j as string ) as boolean
dim as integer nj = len(j), ns = len(s)
for i as integer = 1 to ns - nj + 1
Line 624 ⟶ 1,128:
for i as uinteger = 0 to 999
if is_substring( str(i), str(sumdig(i))) then print i;" ";
next i : print : end</langsyntaxhighlight>
{{out}}<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|Fōrmulæ}}==
 
{{FormulaeEntry|page=https://formulae.org/?script=examples/Sum_of_the_digits_of_n_is_substring_of_n}}
 
'''Solution'''
 
[[File:Fōrmulæ - Sum of the digits of n is substring of n 01.png]]
 
[[File:Fōrmulæ - Sum of the digits of n is substring of n 02.png]]
 
=={{header|Go}}==
{{trans|Wren}}
{{libheader|Go-rcu}}
<langsyntaxhighlight lang="go">package main
 
import (
Line 651 ⟶ 1,165:
fmt.Println()
fmt.Println(len(numbers), "such numbers found.")
}</langsyntaxhighlight>
 
{{out}}
Line 667 ⟶ 1,181:
 
=={{header|Haskell}}==
<langsyntaxhighlight lang="haskell">import Data.Char (digitToInt)
import Data.List (isInfixOf)
import Data.List.Split (chunksOf)
Line 702 ⟶ 1,216:
 
justifyRight :: Int -> Char -> String -> String
justifyRight n c = (drop . length) <*> (replicate n c <>)</langsyntaxhighlight>
{{Out}}
<pre>48 matches in [0..999]
Line 752 ⟶ 1,266:
 
=={{header|J}}==
<langsyntaxhighlight lang="j">([#~(":+./@E.~[:":+/@(10&#.^:_1))"0)i.999</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
 
=={{header|jq}}==
{{works with|jq}}
'''Works with gojq, the Go implementation of jq'''
<syntaxhighlight lang="jq">
def sum_of_digits_is_substring:
tostring
| . as $s
| (explode | map([.]|implode))
| (map(tonumber)|add|tostring) as $ss
| $s | index($ss);
 
[range(0;1000) | select(sum_of_digits_is_substring)]</syntaxhighlight>
{{out}}
<pre>
[0,1,2,3,4,5,6,7,8,9,10,20,30,40,50,60,70,80,90,100,109,119,129,139,149,159,169,179,189,199,200,300,400,500,600,700,800,900,910,911,912,913,914,915,916,917,918,919]
</pre>
 
=={{header|Julia}}==
<langsyntaxhighlight lang="julia">issumsub(n, base=10) = occursin(string(sum(digits(n, base=base)), base=base), string(n, base=base))
 
foreach(p -> print(rpad(p[2], 4), p[1] % 10 == 0 ? "\n" : ""), enumerate(filter(issumsub, 0:999)))
</langsyntaxhighlight>{{out}}
<pre>
0 1 2 3 4 5 6 7 8 9
Line 771 ⟶ 1,302:
=={{header|Kotlin}}==
{{trans|Go}}
<langsyntaxhighlight lang="scala">fun digitSum(n: Int): Int {
var nn = n
var sum = 0
Line 796 ⟶ 1,327:
}
println()
}</langsyntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7
Line 806 ⟶ 1,337:
 
=={{header|MAD}}==
<langsyntaxhighlight MADlang="mad"> NORMAL MODE IS INTEGER
INTERNAL FUNCTION(A,B)
Line 859 ⟶ 1,390:
 
VECTOR VALUES FMT = $I3*$
END OF PROGRAM </langsyntaxhighlight>
{{out}}
<pre style='height:50ex;'> 0
Line 909 ⟶ 1,440:
918
919</pre>
 
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<syntaxhighlight lang="mathematica">ClearAll[SumAsSubString]
SumAsSubString[n_Integer] := Module[{id, s},
id = IntegerDigits[n];
s = Total[id];
SequenceCount[id, IntegerDigits[s]] > 0
]
Select[Range[999], SumAsSubString]</syntaxhighlight>
{{out}}
<pre>{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 109, 119, 129, 139, 149, 159, 169, 179, 189, 199, 200, 300, 400, 500, 600, 700, 800, 900, 910, 911, 912, 913, 914, 915, 916, 917, 918, 919}</pre>
 
=={{header|Miranda}}==
<syntaxhighlight lang="miranda">main :: [sys_message]
main = [Stdout (table 5 10 taskresults)]
where taskresults = filter digit_sum_is_substring [0..999]
 
table :: num->num->[num]->[char]
table cw w ns = lay (map concat (split (map fmt ns)))
where split [] = []
split ls = take w ls : split (drop w ls)
fmt n = reverse (take cw ((reverse (shownum n)) ++ repeat ' '))
 
digit_sum_is_substring :: num->bool
digit_sum_is_substring n = (digitsum n) $infix n
 
digitsum :: num->num
digitsum 0 = 0
digitsum n = n mod 10 + digitsum (n div 10)
 
infix :: num->num->bool
infix n h = True, if n = h
= False, if h = 0
= True, if n $infix (h div 10)
= True, if n $infix (chop h)
= False, otherwise
 
chop :: num->num
chop n = 0, if n<10
= n mod mask, otherwise
where mask = last (takewhile (<n) (iterate (*10) 1))</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9
10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|Nim}}==
<syntaxhighlight lang="nim">import strutils
 
func digitsum(n: Natural): int =
if n == 0: return 0
var n = n
while n != 0:
result += n mod 10
n = n div 10
 
var count = 0
for n in 0..<1000:
let sn = $n
if $digitsum(n) in sn:
inc count
stdout.write sn.align(3), if count mod 8 == 0: '\n' else: ' '</syntaxhighlight>
 
{{out}}
<pre> 0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|Perl}}==
as one-liner ..
<langsyntaxhighlight lang="perl">// 20210415 Perl programming solution
 
perl -e 'for(0..999){my$n;s/(\d)/$n+=$1/egr;print"$_ "if/$n/}'</langsyntaxhighlight>
{{out}}
<pre>
Line 921 ⟶ 1,524:
 
=={{header|Phix}}==
<!--<langsyntaxhighlight Phixlang="phix">(phixonline)-->
<span style="color: #008080;">function</span> <span style="color: #000000;">sdn</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">string</span> <span style="color: #000000;">sn</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">sprint</span><span style="color: #0000FF;">(</span><span style="color: #000000;">n</span><span style="color: #0000FF;">)</span>
Line 930 ⟶ 1,533:
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"Found %d such numbers &lt; %d: %s\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">res</span><span style="color: #0000FF;">),</span><span style="color: #000000;">n</span><span style="color: #0000FF;">+</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">join</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">shorten</span><span style="color: #0000FF;">(</span><span style="color: #000000;">res</span><span style="color: #0000FF;">,</span><span style="color: #008000;">""</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">),</span><span style="color: #008000;">", "</span><span style="color: #0000FF;">)})</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<!--</langsyntaxhighlight>-->
{{out}}
<pre>
Line 936 ⟶ 1,539:
Found 365 such numbers < 10001: 0, 1, 2, 3, 4, ..., 9926, 9927, 9928, 9929, 10000
</pre>
 
=={{header|PL/I}}==
<syntaxhighlight lang="pli">sumOfDigitsIsSubstring: procedure options(main);
digitSum: procedure(n) returns(fixed);
declare (ds, x, n) fixed;
ds = 0;
do x=n repeat(x/10) while(x>0);
ds = ds + mod(x, 10);
end;
return(ds);
end digitSum;
chop: procedure(n) returns(fixed);
declare (i, n) fixed;
i = 1;
do while(i<n);
i = i * 10;
end;
i = i/10;
if i=0 then return(0);
else return(mod(n, i));
end chop;
infix: procedure(n, h) returns(bit) recursive;
declare (n, h) fixed;
if n=h then return('1'b);
if h=0 then return('0'b);
if infix(n, h/10) then return('1'b);
return(infix(n, chop(h)));
end infix;
declare (i, col) fixed;
col = 0;
do i=0 to 999;
if infix(digitSum(i), i) then do;
put edit(i) (F(5));
col = col + 1;
if mod(col, 10)=0 then put skip;
end;
end;
put skip;
end sumOfDigitsIsSubstring;</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9
10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|PL/M}}==
<langsyntaxhighlight lang="plm">100H:
DIGIT$SUM: PROCEDURE (N) BYTE;
DECLARE N ADDRESS, SUM BYTE;
Line 1,010 ⟶ 1,661:
 
CALL BDOS(0,0);
EOF</langsyntaxhighlight>
{{out}}
<pre>0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919</pre>
Line 1,017 ⟶ 1,668:
Just using the command line:
 
<langsyntaxhighlight lang="python">Python 3.9.0 (tags/v3.9.0:9cf6752, Oct 5 2020, 15:34:40) [MSC v.1927 64 bit (AMD64)] on win32
Type "help", "copyright", "credits" or "license()" for more information.
>>> x = [n for n in range(1000) if str(sum(int(d) for d in str(n))) in str(n)]
Line 1,029 ⟶ 1,680:
200, 300, 400, 500, 600, 700, 800, 900, 910, 911
912, 913, 914, 915, 916, 917, 918, 919
>>> </langsyntaxhighlight>
 
 
or as a full script, taking an alternative route, and slightly reducing the number of str conversions required:
 
<langsyntaxhighlight lang="python">'''Sum of the digits of n is substring of n'''
 
from functools import reduce
Line 1,107 ⟶ 1,758:
if __name__ == '__main__':
main()
</syntaxhighlight>
</lang>
{{Out}}
<pre>48 matches < 1000:
Line 1,116 ⟶ 1,767:
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|Quackery}}==
 
<syntaxhighlight lang="Quackery"> [ over findseq swap found ] is hasseq ( [ [ --> b )
 
[ [] swap
[ 10 /mod
rot join swap
dup 0 = until ]
drop ] is digits ( n --> [ )
 
[ digits
0 over witheach +
digits hasseq ] is subsum ( n --> b )
 
[] 1000 times
[ i^ subsum if
[ i^ join ] ]
dup echo
cr cr
say "There are " size echo say " numbers."</syntaxhighlight>
 
{{out}}
 
<pre>[ 0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919 ]
 
There are 48 numbers.</pre>
 
=={{header|Raku}}==
<syntaxhighlight lang="raku" perl6line>say "{+$_} matching numbers\n{.batch(10)».fmt('%3d').join: "\n"}" given (^1000).grep: { .contains: .comb.sum }</langsyntaxhighlight>
{{out}}
<pre>48 matching numbers
Line 1,126 ⟶ 1,804:
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|Refal}}==
<syntaxhighlight lang="refal">$ENTRY Go {
= <Table (8 5) <Filter DigitSumSubstring <Iota 0 999>>>;
};
 
Cell {
s.W s.N, <Repeat s.W ' '> <Symb s.N>: e.C,
<Last s.W e.C>: (e.X) e.CI = e.CI;
}
 
Table {
(s.Cols s.CW) e.X = <Table () (s.Cols s.Cols s.CW) e.X>;
(e.Row) (s.Cols s.N s.CW), e.Row: {
= ;
e.Row = <Prout e.Row>;
};
(e.Row) (s.Cols 0 s.CW) e.X =
<Prout e.Row>
<Table () (s.Cols s.Cols s.CW) e.X>;
(e.Row) (s.Cols s.N s.CW) s.I e.X =
<Table (e.Row <Cell s.CW s.I>) (s.Cols <- s.N 1> s.CW) e.X>;
};
 
Repeat {
0 s.C = ;
s.N s.C = s.C <Repeat <- s.N 1> s.C>;
};
 
Filter {
s.F = ;
s.F s.I e.X, <Mu s.F s.I>: {
True = s.I <Filter s.F e.X>;
False = <Filter s.F e.X>;
};
};
 
Iota {
s.End s.End = s.End;
s.Start s.End = s.Start <Iota <+ 1 s.Start> s.End>;
};
 
DigitSumSubstring {
s.N, <Symb <DigitSum s.N>>: e.2,
<Symb s.N>: e.1 e.2 e.3 = True;
s.N = False;
};
 
DigitSum {
0 = 0;
s.N, <Divmod s.N 10>: (s.R) s.D = <+ s.D <DigitSum s.R>>;
};</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919</pre>
 
=={{header|REXX}}==
<langsyntaxhighlight lang="rexx">/*REXX pgm finds integers whose sum of decimal digits is a substring of N, N < 1000. */
parse arg hi cols . /*obtain optional argument from the CL.*/
if hi=='' | hi=="," then hi= 1000 /*Not specified? Then use the default.*/
Line 1,156 ⟶ 1,893:
/*──────────────────────────────────────────────────────────────────────────────────────*/
commas: parse arg ?; do jc=length(?)-3 to 1 by -3; ?=insert(',', ?, jc); end; return ?
sumDigs:procedure; parse arg x 1 s 2;do j=2 for length(x)-1;s=s+substr(x,j,1);end;return s</langsyntaxhighlight>
{{out|output|text=&nbsp; when using the default inputs:}}
<pre>
Line 1,172 ⟶ 1,909:
 
=={{header|Ring}}==
<langsyntaxhighlight lang="ring">
load "stdlib.ring"
see "working..." + nl
Line 1,199 ⟶ 1,936:
see nl + "Found " + row + " numbers" + nl
see "done..." + nl
</syntaxhighlight>
</lang>
{{out}}
<pre>
Line 1,211 ⟶ 1,948:
Found 48 numbers
done...
</pre>
 
=={{header|RPL}}==
≪ →STR 0 1 3 PICK SIZE '''FOR''' j
OVER j DUP SUB STR→ + '''NEXT'''
→STR POS
≫ ‘'''∑DIN?'''’ STO
 
≪ { } 1 1000 '''FOR''' j '''IF''' j '''∑DIN? THEN''' j + '''END NEXT''' ≫ EVAL
{{out}}
<pre>
1: { 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919 1000 }
</pre>
 
=={{header|Ruby}}==
<syntaxhighlight lang="ruby">p (0...1000).select{|n| n.to_s.match? n.digits.sum.to_s}
</syntaxhighlight>
{{out}}
<pre>[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 109, 119, 129, 139, 149, 159, 169, 179, 189, 199, 200, 300, 400, 500, 600, 700, 800, 900, 910, 911, 912, 913, 914, 915, 916, 917, 918, 919, 1000]
</pre>
 
=={{header|Rust}}==
<syntaxhighlight lang="Rust">fn sum_digits( mut num : u32 ) -> u32 {
let mut sum : u32 = 0 ;
while num != 0 {
sum += num % 10 ;
num /= 10 ;
}
sum
}
 
fn main() {
let solution : Vec<u32> = (0..1000).filter( | &d | {
let digit_sum : u32 = sum_digits( d ) ;
let sumstring = digit_sum.to_string( ) ;
let sumstr : &str = sumstring.as_str( ) ;
let numstring : String = d.to_string( ) ;
let numstr : &str = numstring.as_str( ) ;
numstr.contains( &sumstr )
}).collect( ) ;
println!("{:?}" , solution ) ;
}</syntaxhighlight>
{{out}}
<pre>
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100, 109, 119, 129, 139, 149, 159, 169, 179, 189, 199, 200, 300, 400, 500, 600, 700, 800, 900, 910, 911, 912, 913, 914, 915, 916, 917, 918, 919]
</pre>
 
=={{header|Sidef}}==
<syntaxhighlight lang="ruby">var upto = 1000
var base = 10
 
var list = (^upto -> grep {
.digits(base).contains(.sumdigits(base).digits(base)...)
})
 
say "Numbers under #{upto} whose sum of digits is a substring of themselves:"
 
list.each_slice(8, {|*a|
say a.map { '%3s' % _ }.join(' ')
})
 
say "\n#{list.len} such numbers found."</syntaxhighlight>
{{out}}
<pre>
Numbers under 1000 whose sum of digits is a substring of themselves:
0 1 2 3 4 5 6 7
8 9 10 20 30 40 50 60
70 80 90 100 109 119 129 139
149 159 169 179 189 199 200 300
400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
 
48 such numbers found.
</pre>
 
=={{header|SNOBOL4}}==
<langsyntaxhighlight lang="snobol4"> define('digsum(n)') :(digsum_end)
digsum digsum = 0
dsloop digsum = digsum + remdr(n,10)
Line 1,227 ⟶ 2,037:
loop output = sumsub(i) i
i = lt(i,999) i + 1 :s(loop)
end</langsyntaxhighlight>
{{out}}
<pre style='height:50ex'>0
Line 1,280 ⟶ 2,090:
=={{header|Wren}}==
{{libheader|Wren-math}}
{{libheader|Wren-seq}}
{{libheader|Wren-fmt}}
<langsyntaxhighlight ecmascriptlang="wren">import "./math" for Int
import "./seqfmt" for LstFmt
import "/fmt" for Fmt
 
var numbers = []
Line 1,293 ⟶ 2,101:
}
System.print("Numbers under 1,000 whose sum of digits is a substring of themselves:")
Fmt.tprint("$3d", numbers, 8)
for (chunk in Lst.chunks(numbers, 8)) Fmt.print("$3d", chunk)
System.print("\n%(numbers.count) such numbers found.")</langsyntaxhighlight>
 
{{out}}
Line 1,308 ⟶ 2,116:
48 such numbers found.
</pre>
 
=={{header|XPL0}}==
<syntaxhighlight lang="xpl0">func Check(N); \Return 'true' if sum of digits of N is a substring of N
int N, Sum, A, B, C;
[N:= N/10;
C:= rem(0);
N:= N/10;
B:= rem(0);
A:= N;
Sum:= A+B+C;
if Sum=A or Sum=B or Sum=C then return true;
if Sum = B*10 + C then return true;
if Sum = A*10 + B then return true;
return false;
];
 
int Count, N;
[Count:= 0;
for N:= 0 to 1000-1 do
if Check(N) then
[IntOut(0, N);
Count:= Count+1;
if rem(Count/10) = 0 then CrLf(0) else ChOut(0, 9\tab\);
];
CrLf(0);
IntOut(0, Count);
Text(0, " such numbers found below 1000.
");
]</syntaxhighlight>
 
{{out}}
<pre>
0 1 2 3 4 5 6 7 8 9
10 20 30 40 50 60 70 80 90 100
109 119 129 139 149 159 169 179 189 199
200 300 400 500 600 700 800 900 910 911
912 913 914 915 916 917 918 919
48 such numbers found below 1000.
</pre>
 
=={{header|Yabasic}}==
<syntaxhighlight lang="yabasic">// Rosetta Code problem: http://rosettacode.org/wiki/Sum_of_the_digits_of_n_is_substring_of_n
// by Galileo, 04/2022
 
for n = 0 to 999
if isSubstring(n) print n using "####";
next
print
sub isSubstring(n)
local n$, lon, i, p
n$ = str$(n)
lon = len(n$)
for i = 1 to lon
p = p + val(mid$(n$,i,1))
next
return instr(n$, str$(p))
end sub</syntaxhighlight>
{{out}}
<pre> 0 1 2 3 4 5 6 7 8 9 10 20 30 40 50 60 70 80 90 100 109 119 129 139 149 159 169 179 189 199 200 300 400 500 600 700 800 900 910 911 912 913 914 915 916 917 918 919
---Program done, press RETURN---</pre>
2,093

edits