Special pythagorean triplet

Special pythagorean triplet is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Task

The following problem is taken from Project Euler

Julia

julia> [(a, b, c) for a in 1:1000, b in 1:1000, c in 1:1000 if a + b + c == 1000 && a^2 + b^2 == c^2]
2-element Vector{Tuple{Int64, Int64, Int64}}:
 (375, 200, 425)
 (200, 375, 425)

Python

Python 3.8.8 (default, Apr 13 2021, 15:08:03)
Type "help", "copyright", "credits" or "license" for more information.
>>> [(a, b, c) for a in range(1, 1000) for b in range(1, 1000) for c in range(1000) if a + b + c == 1000 and a*a + b*b == c*c]
[(200, 375, 425), (375, 200, 425)]

Ring

<lang ring> load "stdlib.ring" see "working..." + nl

time1 = clock() for a = 1 to 1000

    for b = a+1 to 1000   
        for c = b+1 to 1000
            if (pow(a,2)+pow(b,2)=pow(c,2))
                if a+b+c = 1000
                   see "a = " + a + " b = " + b + " c = " + c + nl
                   exit 3
                ok
            ok
         next
    next

next

time2 = clock() time3 = time2/1000 - time1/1000 see "Elapsed time = " + time3 + " s" + nl see "done..." + nl </lang>

Output:

working...
a = 200 b = 375 c = 425
Elapsed time = 497.61 s
done...

Wren

Very simple approach, only takes 0.013 seconds even in Wren. <lang ecmascript>var a = 3 while (true) {

   var b = a + 1
   while (true) {
       var c = 1000 - a - b
       if (c <= b) break
       if (a*a + b*b == c*c) {
           System.print("a = %(a), b = %(b), c = %(c)")
           System.print("a + b + c = %(a + b + c)")
           System.print("a * b * c = %(a * b * c)")
           return
       }
       b = b + 1
   }
   a = a + 1

}</lang>

Output:

a = 200, b = 375, c = 425
a + b + c = 1000
a * b * c = 31875000