Solve a Holy Knight's tour: Difference between revisions

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m (→‎{{header|Phix}}: added syntax colouring, marked p2js compatible)
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solution found in 61341542 tries, 61341486 backtracks (180.56s)
</pre>
 
=={{header|Picat}}==
<lang Picat>import sat.
 
main =>
S = {".000....",
".0.00...",
".0000000",
"000..0.0",
"0.0..000",
"1000000.",
"..00.0..",
"...000.."},
MaxR = len(S),
MaxC = len(S[1]),
M = new_array(MaxR,MaxC),
StartR = _, % make StartR and StartC global
StartC = _,
foreach (R in 1..MaxR)
fill_row(R, S[R], M[R], 1, StartR, StartC)
end,
NZeros = len([1 : R in 1..MaxR, C in 1..MaxC, M[R,C] == 0]),
M :: 0..MaxR*MaxC-NZeros,
Vs = [{(R,C),1} : R in 1..MaxR, C in 1..MaxC, M[R,C] !== 0],
Es = [{(R,C),(R1,C1),_} : R in 1..MaxR, C in 1..MaxC, M[R,C] !== 0,
neibs(M,MaxR,MaxC,R,C,Neibs),
(R1,C1) in Neibs, M[R1,C1] !== 0],
hcp(Vs,Es),
foreach ({(R,C),(R1,C1),B} in Es)
B #/\ (R1 #!= StartR #\/ C1 #!= StartC) #=> M[R1,C1] #= M[R,C]+1
end,
solve(M),
foreach (R in 1..MaxR)
foreach (C in 1..MaxC)
if M[R,C] == 0 then
printf("%4c", '.')
else
printf("%4d", M[R,C])
end
end,
nl
end.
 
neibs(M,MaxR,MaxC,R,C,Neibs) =>
Connected = [(R+1, C+2),
(R+1, C-2),
(R-1, C+2),
(R-1, C-2),
(R+2, C+1),
(R+2, C-1),
(R-2, C+1),
(R-2, C-1)],
Neibs = [(R1,C1) : (R1,C1) in Connected,
R1 >= 1, R1 =< MaxR, C1 >= 1, C1 =< MaxC,
M[R1,C1] !== 0].
 
fill_row(_R, [], _Row, _C, _StartR, _StartC) => true.
fill_row(R, ['.'|Str], Row, C, StartR, StartC) =>
Row[C] = 0,
fill_row(R,Str, Row, C+1, StartR, StartC).
fill_row(R, ['0'|Str], Row, C, StartR, StartC) =>
fill_row(R, Str, Row, C+1, StartR, StartC).
fill_row(R, ['1'|Str], Row, C, StartR, StartC) =>
Row[C] = 1,
StartR = R,
StartC = C,
fill_row(R, Str, Row, C+1, StartR, StartC).
</lang>
{{out}}
<pre>
. 7 4 25 . . . .
. 26 . 8 5 . . .
. 29 6 3 24 9 18 11
27 2 23 . . 12 . 16
30 . 28 . . 17 10 19
1 22 31 34 13 20 15 .
. . 36 21 . 33 . .
. . . 32 35 14 . .
{/pre}
 
=={{header|Python}}==
Anonymous user