Greatest element of a list

From Rosetta Code
Task
Greatest element of a list
You are encouraged to solve this task according to the task description, using any language you may know.
Task

Create a function that returns the maximum value in a provided set of values,
where the number of values may not be known until run-time.

11l

11l already has a "Maximum Value" function.

max(values)

8th

[ 1.0, 2.3, 1.1, 5.0, 3, 2.8, 2.01, 3.14159 ] ' n:max 0 a:reduce . cr

Output: 5

AArch64 Assembly

Works with: as version Raspberry Pi 3B version Buster 64 bits
/* ARM assembly AARCH64 Raspberry PI 3B */
/*  program rechMax64.s   */
 
/*******************************************/
/* Constantes file                         */
/*******************************************/
/* for this file see task include a file in language AArch64 assembly*/
.include "../includeConstantesARM64.inc"
 
/*********************************/
/* Initialized data              */
/*********************************/
.data
szMessResult:  .ascii "Max number is =  @ rank = @ address (hexa) = @ \n"      // message result
 
tTableNumbers:    .quad 50
                  .quad 12
                  .quad -1000
                  .quad 40
                  .quad 255
                  .quad 60
                  .quad 254
.equ NBRANKTABLE,   (. - tTableNumbers) / 8  // number table posts
 
/*********************************/
/* UnInitialized data            */
/*********************************/
.bss 
sZoneConv:         .skip 24
/*********************************/
/*  code section                 */
/*********************************/
.text
.global main 
main:                        // entry of program 
    ldr x1,qAdrtTableNumbers
    mov x2,0
    ldr x4,[x1,x2,lsl #3]    // load first number
    mov x3,x2                // save first indice
    add x2,x2,1              // increment indice
1:
    cmp x2,#NBRANKTABLE      // indice ? maxi
    bge 2f                   // yes -> end search
    ldr x0,[x1,x2,lsl #3]    // load other number
    cmp x0,x4                // > old number max
    csel x4,x0,x4,gt         // if > x4 = x0 else x4=x4
    csel x3,x2,x3,gt         // if > x3 = x2 else x3=x3
    add x2,x2,1              // increment indice
    b 1b                     // and loop
 
2:
    mov x0,x4
    ldr x1,qAdrsZoneConv
    bl conversion10S         // decimal conversion
    ldr x0,qAdrszMessResult
    ldr x1,qAdrsZoneConv
    bl strInsertAtCharInc    // insert result at first @ character
    mov x5,x0                // save address message
    mov x0,x3
    ldr x1,qAdrsZoneConv     // conversion rank maxi
    bl conversion10S         // decimal conversion
    mov x0,x5                // message address
    ldr x1,qAdrsZoneConv
    bl strInsertAtCharInc    // insert result at Second @ character
    mov x5,x0                // save message address
    ldr x0,qAdrtTableNumbers
    lsl x3,x3,3
    add x0,x0,x3
    ldr x1,qAdrsZoneConv     // conversion address maxi
    bl conversion16          // hexa conversion
    mov x0,x5
    ldr x1,qAdrsZoneConv
    bl strInsertAtCharInc    // insert result at third @ character
    bl affichageMess         // display message final
 
 
100:                         // standard end of the program 
    mov x0,0                 // return code
    mov x8,EXIT              // request to exit program
    svc 0                    // perform the system call
qAdrtTableNumbers:    .quad  tTableNumbers
qAdrszMessResult:     .quad szMessResult
qAdrsZoneConv:        .quad sZoneConv

/******************************************************************/
/*     conversion  hexadecimal register                           */ 
/******************************************************************/
/* x0 contains value and x1 address zone receptrice   */
conversion16:
    stp x0,lr,[sp,-48]!        // save  registres
    stp x1,x2,[sp,32]          // save  registres
    stp x3,x4,[sp,16]          // save  registres
    mov x2,#60                 // start bit position
    mov x4,#0xF000000000000000 // mask
    mov x3,x0                  // save entry value
1:                             // start loop
    and x0,x3,x4               // value register and mask
    lsr x0,x0,x2               // right shift
    cmp x0,#10                 // >= 10 ?
    bge 2f                     // yes
    add x0,x0,#48              // no is digit
    b 3f
2:
    add x0,x0,#55              // else is a letter A-F
3:
    strb w0,[x1],#1            // load result  and + 1 in address
    lsr x4,x4,#4               // shift mask 4 bits left
    subs x2,x2,#4              // decrement counter 4 bits <= zero  ?
    bge 1b                     // no -> loop

100:                           // fin standard de la fonction
    ldp x3,x4,[sp,16]          // restaur des  2 registres
    ldp x1,x2,[sp,32]          // restaur des  2 registres
    ldp x0,lr,[sp],48          // restaur des  2 registres
    ret    
/********************************************************/
/*        File Include fonctions                        */
/********************************************************/
/* for this file see task include a file in language AArch64 assembly */
.include "../includeARM64.inc"
Output:
Max number is =  +255 rank = +4 address (hexa) = 000000000041051C

ACL2

(defun maximum (xs)
   (if (endp (rest xs))
       (first xs)
       (max (first xs)
            (maximum (rest xs)))))

Action!

BYTE FUNC Max(BYTE ARRAY tab BYTE size)
  BYTE i,res

  res=tab(0)
  FOR i=1 TO size-1
  DO 
    IF res<tab(i) THEN
      res=tab(i)
    FI
  OD
RETURN (res)

PROC Main()
  BYTE i,m,size=[20]
  BYTE ARRAY tab(size)
  
  FOR i=0 TO size-1
  DO 
    tab(i)=Rand(0)
  OD

  Print("Array:")
  FOR i=0 TO size-1
  DO
    PrintF(" %I",tab(i))
  OD
  PutE()

  m=Max(tab,size)
  PrintF("Greatest: %I%E",m)
RETURN
Output:

Screenshot from Atari 8-bit computer

Array: 106 182 121 251 21 244 46 157 228 251 173 50 106 126 193 230 88 117 114 120
Greatest: 251

ActionScript

function max(... args):Number
{
	var curMax:Number = -Infinity;
	for(var i:uint = 0; i < args.length; i++)
		curMax = Math.max(curMax, args[i]);
	return curMax;
}

Ada

The keys for this task are initializing the compared value to the 'First value of the element type, and use of an unconstrained array type.

with Ada.Text_Io;

procedure Max_Test isco
   -- substitute any array type with a scalar element
   type Flt_Array is array (Natural range <>) of Float;
   
   -- Create an exception for the case of an empty array
   Empty_Array : Exception;
   
   function Max(Item : Flt_Array) return Float is
      Max_Element : Float := Float'First;
   begin
      if Item'Length = 0 then 
         raise Empty_Array;
      end if;
  
      for I in Item'range loop
         if Item(I) > Max_Element then
            Max_Element := Item(I);
         end if;
      end loop;
      return Max_Element;
   end Max;
    
   Buf : Flt_Array := (-275.0, -111.19, 0.0, -1234568.0, 3.14159, -3.14159);
begin
   Ada.Text_IO.Put_Line(Float'Image(Max(Buf)));
end Max_Test;

A generic function Max to deal with any floating-point type.

generic
   type Item is digits <>;
   type Items_Array is array (Positive range <>) of Item;
function Generic_Max (List : Items_Array) return Item;

Implementation of:

function Generic_Max (List : Items_Array) return Item is
   Result : Item := List (List'First);
begin
   for Index in List'First + 1..List'Last loop
      Result := Item'Max (Result, List (Index));
   end loop;
   return Result;
end Generic_Max;

When the argument array is empty, Constraint_Error exception is propagated, because array indexing is checked in Ada. Note also use of the floating-type attribute Max.

Aime

integer
lmax(list l)
{
    integer max, x;

    max = l[0];

    for (, x in l) {
        if (max < x) {
            max = x;
        }
    }

    max;
}

or

integer
lmax(list l)
{
    integer max;

    max = l[0];
    l.ucall(max_i, 1, max);

    max;
}

ALGOL 68

Works with: ALGOL 68 version Revision 1 - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
# substitute any array type with a scalar element #
MODE FLT = REAL;

# create an exception for the case of an empty array #
PROC raise empty array = VOID:(
  GO TO except empty array
);

PROC max = ([]FLT item)FLT:
BEGIN
   IF LWB item > UPB item THEN
      raise empty array; SKIP
   ELSE
     FLT max element := item[LWB item];

     FOR i FROM LWB item + 1 TO UPB item DO
       IF item[i] > max element THEN
         max element := item[i]
       FI
     OD;
     max element
   FI
END # max #;

test:(
  []FLT buf = (-275.0, -111.19, 0.0, -1234568.0, pi, -pi);
  print((max(buf),new line)) EXIT
  except empty array:
    SKIP
)
Output:
+3.14159265358979e  +0

ALGOL W

begin
    % simple list type                                                       %
    record IntList( integer val; reference(IntList) next );

    % find the maximum element of an IntList, returns 0 for an empty list    %
    integer procedure maxElement( reference(IntList) value list ) ;
        begin
            integer maxValue;
            reference(IntList) listPos;
            maxValue := 0;
            listPos  := list;
            if listPos not = null then begin
                % non-empty list                                             %
                maxValue := val(listPos);
                listPos  := next(listPos);
                while listPos not = null do begin
                    if val(listPos) > maxValue then maxValue := val(listPos);
                    listPos := next(listPos)
                end while_listPos_ne_null ;
            end if_listPos_ne_null ;
            maxValue
        end maxElement ;

    % test the maxElement procedure                                          %
    write( maxElement( IntList( -767, IntList( 2397, IntList( 204, null ) ) ) ) )

end.
Output:
          2397  

Amazing Hopper

Version 1:

#include <hopper.h>
main:
  lst=0
  max=0
  file="datos.txt"

  {","}             toksep
  {file}            statsfile
  {file}            load
                    mov        (lst)
  {0}               reshape    (lst)
  {lst}             array      (SORT)
  [end]             get        (lst)
                    mov        (max)
  {"Maximo = "}
  {max}
  {"\n"}            print
exit(0)

Version 2:

#include <hopper.h>
#define SIZE_LIST   100000
main:
  lst=-1
  max=0
  {SIZE_LIST}       rand array (lst)
                    mul by     (SIZE_LIST)
                    mov        (lst)
  {lst}             array      (SORT)
  [end]             get        (lst)
                    mov        (max)
  {"Maximo = "}
  {max}
  {"\n"}            print
exit(0)
Output:
Maximo = 99999.8

AntLang

max|range[10]

APL

LIST2 4 6 3 8
/LIST
Output:
8

AppleScript

max({1, 2, 3, 4, 20, 6, 11, 3, 9, 7})

on max(aList)
	set _curMax to first item of aList
	repeat with i in (rest of aList)
		if i > _curMax then set _curMax to contents of i
	end repeat
	return _curMax
end max


To find the greatest elements of lists which may contain data types other than numbers, we can write a more generic maximumBy function, which returns the maximum value from an array containing a series of any consistent data type, and which takes a type-specific comparison function as an argument.

Translation of: JavaScript
-- maximumByMay :: (a -> a -> Ordering) -> [a] -> Maybe a
on maximumByMay(f, xs)
    set cmp to mReturn(f)
    script max
        on |λ|(a, b)
            if cmp's |λ|(a, b) < 0 then
                b
            else
                a
            end if
        end |λ|
    end script
    
    foldl1May(max, xs)
end maximumByMay

-- TEST -----------------------------------------------------------------------
on run
    
    set lstWords to ["alpha", "beta", "gamma", "delta", "epsilon", ¬
        "zeta", "eta", "theta", "iota", "kappa", "|λ|", "mu"]
    
    set lstCities to [{name:"Shanghai", population:24.15}, ¬
        {name:"Karachi", population:23.5}, ¬
        {name:"Beijing", population:21.5}, ¬
        {name:"Tianjin", population:14.7}, ¬
        {name:"Istanbul", population:14.4}, ¬
        {name:"Lagos", population:13.4}, ¬
        {name:"Tokyo", population:13.3}]
    
    script population
        on |λ|(x)
            population of x
        end |λ|
    end script
    
    
    return catMaybes({¬
        maximumByMay(comparing(|length|), lstWords), ¬
        maximumByMay(comparing(|length|), {}), ¬
        maximumByMay(comparing(population), lstCities)})
    
    --> {"epsilon", {name:"Shanghai", population:24.15}}
    
end run


-- GENERIC FUNCTIONS ----------------------------------------------------------

-- catMaybes :: [Maybe a] -> [a]
on catMaybes(mbs)
    script emptyOrListed
        on |λ|(m)
            if nothing of m then
                {}
            else
                {just of m}
            end if
        end |λ|
    end script
    concatMap(emptyOrListed, mbs)
end catMaybes

-- comparing :: (a -> b) -> (a -> a -> Ordering)
on comparing(f)
    set mf to mReturn(f)
    script
        on |λ|(a, b)
            set x to mf's |λ|(a)
            set y to mf's |λ|(b)
            if x < y then
                -1
            else
                if x > y then
                    1
                else
                    0
                end if
            end if
        end |λ|
    end script
end comparing

-- concatMap :: (a -> [b]) -> [a] -> [b]
on concatMap(f, xs)
    set acc to {}
    tell mReturn(f)
        repeat with x in xs
            set acc to acc & |λ|(contents of x)
        end repeat
    end tell
    return acc
end concatMap

-- foldl1May :: (a -> a -> a) -> [a] -> Maybe a
on foldl1May(f, xs)
    set lng to length of xs
    if lng > 0 then
        if lng > 1 then
            tell mReturn(f)
                set v to item 1 of xs
                set lng to length of xs
                repeat with i from 2 to lng
                    set v to |λ|(v, item i of xs, i, xs)
                end repeat
                return just(v)
            end tell
        else
            just(item 1 of xs)
        end if
    else
        nothing("Empty list")
    end if
end foldl1May

-- just :: a -> Just a
on just(x)
    {nothing:false, just:x}
end just

-- length :: [a] -> Int
on |length|(xs)
    length of xs
end |length|

-- max :: Ord a => a -> a -> a
on max(x, y)
    if x > y then
        x
    else
        y
    end if
end max

-- nothing :: () -> Nothing
on nothing(msg)
    {nothing:true, msg:msg}
end nothing

-- Lift 2nd class handler function into 1st class script wrapper 
-- mReturn :: Handler -> Script
on mReturn(f)
    if class of f is script then
        f
    else
        script
            property |λ| : f
        end script
    end if
end mReturn
Output:
{"epsilon", {name:"Shanghai", population:24.15}}

Applesoft BASIC

 100 REMMAX
 110 R$ = "":E$ = ""
 120 L =  LEN (L$)
 130 IF L = 0 THEN  RETURN
 140 FOR I = 1 TO L
 150     C$ =  MID$ (L$,I,1)
 160     SP = C$ = " "
 170     IF SP THEN  GOSUB 200
 180     E$ = E$ + C$
 190 NEXT I
 200 C$ = ""
 210 IF E$ = "" THEN  RETURN
 220 V =  VAL (E$):V$ = R$
 230 E$ = "":E = V$ = ""
 240 IF E AND V = 0 THEN  RETURN
 250 R$ =  STR$ (V)
 260 IF E THEN  RETURN
 270 R =  VAL (V$)
 280 IF R < V THEN  RETURN
 290 R$ = V$: RETURN
L$ = "1 2 3 4 20 6 11 3 9 7"
GOSUB 100MAX
PRINT R$
Output:
20

ARM Assembly

Works with: as version Raspberry Pi
/* ARM assembly Raspberry PI  */
/*  program rechMax.s   */

/* Constantes    */
.equ STDOUT, 1     @ Linux output console
.equ EXIT,   1     @ Linux syscall
.equ WRITE,  4     @ Linux syscall

/*********************************/
/* Initialized data              */
/*********************************/
.data
szMessResult:  .ascii "Max number is = "      @ message result
sMessValeur:   .fill 12, 1, ' '
                  .ascii " rank = "
sMessRank:   .fill 12, 1, ' '
                  .ascii " address (hexa) = "
sMessAddress:   .fill 12, 1, ' '
                   .asciz "\n"
				   
tTableNumbers:    .int   50
                      .int 12
                      .int -1000
                      .int 40
                      .int 255
                      .int 60
                      .int 254
.equ NBRANKTABLE,   (. - tTableNumbers) / 4  @ number table posts

/*********************************/
/* UnInitialized data            */
/*********************************/
.bss 
/*********************************/
/*  code section                 */
/*********************************/
.text
.global main 
main:                @ entry of program 
    push {fp,lr}      @ saves 2 registers 

    ldr r1,iAdrtTableNumbers
    mov r2,#0
    ldr r4,[r1,r2,lsl #2]
    mov r3,r2
    add r2,#1
1:
    cmp r2,#NBRANKTABLE
	bge 2f
	ldr r0,[r1,r2,lsl #2]
	cmp r0,r4
	movgt r4,r0
	movgt r3,r2
	add r2,#1
	b 1b
	
2:
    mov r0,r4
    ldr r1,iAdrsMessValeur                
    bl conversion10S       @ call conversion
    mov r0,r3
    ldr r1,iAdrsMessRank                
    bl conversion10       @ call conversion
    ldr r0,iAdrtTableNumbers
    add r0,r3,lsl #2
    ldr r1,iAdrsMessAddress                
    bl conversion16       @ call conversion
    ldr r0,iAdrszMessResult
    bl affichageMess            @ display message

 


100:   @ standard end of the program 
    mov r0, #0                  @ return code
    pop {fp,lr}                 @restaur 2 registers
    mov r7, #EXIT              @ request to exit program
    swi 0                       @ perform the system call
iAdrtTableNumbers:    .int  tTableNumbers
iAdrsMessValeur:      .int sMessValeur
iAdrsMessRank:         .int sMessRank
iAdrsMessAddress:     .int sMessAddress
iAdrszMessResult:     .int szMessResult

/******************************************************************/
/*     display text with size calculation                         */ 
/******************************************************************/
/* r0 contains the address of the message */
affichageMess:
    push {fp,lr}    			/* save  registres */ 
    push {r0,r1,r2,r7}    		/* save others registers */
    mov r2,#0   				/* counter length */
1:      	/* loop length calculation */
    ldrb r1,[r0,r2]  			/* read octet start position + index */
    cmp r1,#0       			/* if 0 its over */
    addne r2,r2,#1   			/* else add 1 in the length */
    bne 1b          			/* and loop */
                                /* so here r2 contains the length of the message */
    mov r1,r0        			/* address message in r1 */
    mov r0,#STDOUT      		/* code to write to the standard output Linux */
    mov r7, #WRITE             /* code call system "write" */
    swi #0                      /* call systeme */
    pop {r0,r1,r2,r7}     		/* restaur others registers */
    pop {fp,lr}    				/* restaur des  2 registres */ 
    bx lr	        			/* return  */
/******************************************************************/
/*     Converting a register to hexadecimal                      */ 
/******************************************************************/
/* r0 contains value and r1 address area   */
conversion16:
    push {r1-r4,lr}    /* save registers */ 
    mov r2,#28         @ start bit position
    mov r4,#0xF0000000    @ mask
    mov r3,r0      @ save entry value
1:	   @ start loop
    and r0,r3,r4   @value register and mask
    lsr r0,r2      @ move right 
    cmp r0,#10      @ compare value
    addlt r0,#48        @ <10  ->digit	
    addge r0,#55        @ >10  ->letter A-F
    strb r0,[r1],#1  @ store digit on area and + 1 in area address
    lsr r4,#4       @ shift mask 4 positions
    subs r2,#4         @  counter bits - 4 <= zero  ?
    bge 1b	          @  no -> loop
    @end
    pop {r1-r4,lr}    @ restaur registres 
    bx lr             @return
/******************************************************************/
/*     Converting a register to a decimal                                 */ 
/******************************************************************/
/* r0 contains value and r1 address area   */
conversion10:
    push {r1-r4,lr}    /* save registers */ 
    mov r3,r1
    mov r2,#10

1:	   @ start loop
    bl divisionpar10 @ r0 <- dividende. quotient ->r0 reste -> r1
    add r1,#48        @ digit	
    strb r1,[r3,r2]  @ store digit on area
    sub r2,#1         @ previous position
    cmp r0,#0         @ stop if quotient = 0 */
    bne 1b	          @ else loop
    @ and move spaves in first on area
    mov r1,#' '   @ space	
2:	
    strb r1,[r3,r2]  @ store space in area
    subs r2,#1       @ @ previous position
    bge 2b           @ loop if r2 >= zéro 

100:	
    pop {r1-r4,lr}    @ restaur registres 
    bx lr	          @return
/***************************************************/
/*  Converting a register to a signed decimal      */
/***************************************************/
/* r0 contains value and r1 area address    */
conversion10S:
    push {r0-r4,lr}    @ save registers
    mov r2,r1       /* debut zone stockage */
    mov r3,#'+'     /* par defaut le signe est + */
    cmp r0,#0       @ negative number ? 
    movlt r3,#'-'   @ yes
    mvnlt r0,r0     @ number inversion
    addlt r0,#1   
    mov r4,#10       @ length area
1:  @ start loop
    bl divisionpar10
    add r1,#48   @ digit
    strb r1,[r2,r4]  @ store digit on area
    sub r4,r4,#1      @ previous position
    cmp r0,#0          @ stop if quotient = 0
    bne 1b	

    strb r3,[r2,r4]  @ store signe 
    subs r4,r4,#1    @ previous position
    blt  100f        @ if r4 < 0 -> end

    mov r1,#' '   @ space	
2:
    strb r1,[r2,r4]  @store byte space
    subs r4,r4,#1    @ previous position
    bge 2b           @ loop if r4 > 0
100: 
    pop {r0-r4,lr}   @ restaur registers
    bx lr  
/***************************************************/
/*   division par 10   signé                       */
/* Thanks to http://thinkingeek.com/arm-assembler-raspberry-pi/*  
/* and   http://www.hackersdelight.org/            */
/***************************************************/
/* r0 dividende   */
/* r0 quotient */	
/* r1 remainder  */
divisionpar10:	
  /* r0 contains the argument to be divided by 10 */
   push {r2-r4}   /* save registers  */
   mov r4,r0 
   ldr r3, .Ls_magic_number_10 /* r1 <- magic_number */
   smull r1, r2, r3, r0   /* r1 <- Lower32Bits(r1*r0). r2 <- Upper32Bits(r1*r0) */
   mov r2, r2, ASR #2     /* r2 <- r2 >> 2 */
   mov r1, r0, LSR #31    /* r1 <- r0 >> 31 */
   add r0, r2, r1         /* r0 <- r2 + r1 */
   add r2,r0,r0, lsl #2   /* r2 <- r0 * 5 */
   sub r1,r4,r2, lsl #1   /* r1 <- r4 - (r2 * 2)  = r4 - (r0 * 10) */
   pop {r2-r4}
   bx lr                  /* leave function */
   .align 4
.Ls_magic_number_10: .word 0x66666667

Arturo

arr: [5 4 2 9 7 3]

print max arr
Output:
9

AutoHotkey

CSV Data

list = 1,5,17,-2
Loop Parse, list, `,
   x := x < A_LoopField ? A_LoopField : x
MsgBox Max = %x%

Pseudo-arrays

list = 1,5,17,-2
StringSplit, list, list,`, ; creates a pseudo-array
Loop % List0
   x := x < List%A_Index% ? List%A_Index% : x
MsgBox Max = %x%

True arrays

Works with: AutoHotkey_L
List := [1,5,17,-2]
For each, value in List
   x := x < value ? value : x
MsgBox Max = %x%

AWK

One-liner:

$ awk 'func max(a){for(i in a)if(a[i]>r)r=a[i];return r}BEGIN{a[0]=42;a[1]=33;a[2]=21;print max(a)}'
42

More readable version:

# Usage: awk -f greatest_list_element.awk
#
function max(a) {
    for(i in a) if(a[i]>r) r=a[i];
    return r
}
#
BEGIN { a[0]=42;
        a[1]=33;
        a[2]=21;
        print max(a)
      }

Axe

This example assumes the array is null-terminated so that the program can stop at the end of the data.

Lbl MAX
0→M
While {r₁}
 {r₁}>M?{r₁}→M
End
M
Return

BASIC

Works with: QBasic
DECLARE SUB addVal (value AS INTEGER)
DECLARE FUNCTION findMax% ()

REDIM SHARED vals(0) AS INTEGER
DIM SHARED valCount AS INTEGER
DIM x AS INTEGER, y AS INTEGER

valCount = -1

'''''begin test run
RANDOMIZE TIMER
FOR x = 1 TO 10
    y = INT(RND * 100)
    addVal y
    PRINT y; " ";
NEXT
PRINT ": "; findMax
'''''end test run

SUB addVal (value AS INTEGER)
    DIM tmp AS INTEGER
    IF valCount > -1 THEN
        'this is needed for BASICs that don't support REDIM PRESERVE
        REDIM v2(valCount) AS INTEGER
        FOR tmp = 0 TO valCount
            v2(tmp) = vals(tmp)
        NEXT
    END IF
    valCount = valCount + 1
    REDIM vals(valCount)
    IF valCount > 0 THEN
        'also needed for BASICs that don't support REDIM PRESERVE
        FOR tmp = 0 TO valCount - 1
            vals(tmp) = v2(tmp)
        NEXT
    END IF
    vals(valCount) = value
END SUB

FUNCTION findMax%
    DIM tmp1 AS INTEGER, tmp2 AS INTEGER
    FOR tmp1 = 0 TO valCount
        IF vals(tmp1) > tmp2 THEN tmp2 = vals(tmp1)
    NEXT
    findMax = tmp2
END FUNCTION
Output:
 8162   5139   7004   7393   5151   4476   577   4419   3333   4649  :  8162

BaCon

' Greatest element from list
' Populate sample array of numbers
READ elements
DECLARE numbers TYPE NUMBER ARRAY elements
FOR i = 0 TO elements - 1
    READ numbers[i]
NEXT
DATA 6
DATA 100,-2,300,4,500,6

' Demonstrate the function
PRINT greatest(elements, numbers)
END

' Return greatest element given count and list of numbers
FUNCTION greatest(n, NUMBER a[])
    LOCAL mx = a[0]
    FOR i = 1 TO n - 1
        mx = MAX(mx, a[i])
    NEXT
    RETURN mx
END FUNCTION
Output:
prompt$  ./greatest-element
500

See also: BBC BASIC, Liberty BASIC, PowerBASIC, PureBasic, Run BASIC, TI-89 BASIC, Visual Basic

BASIC256

Translation of: Yabasic
l$ = "1,1234,62,234,12,34,6"
dim n$(1)
n$ = explode(l$, ",")
m$ = "" : m = 0

for i = 1 to n$[?]-1
	t$ = n$[i]
	if t$ > m$ then m$ = t$
	if int(t$) > m then m = int(t$)
next i

print "Alphabetic order: "; m$; ", numeric order: "; m

Chipmunk Basic

The GW-BASIC solution works without any changes.

Minimal BASIC

Translation of: Quite BASIC
10 PRINT "HOW MANY ITEMS? "
20 INPUT N
30 FOR J = 0 TO N-1
40 PRINT "VALUE OF ITEM #";J
50 INPUT T
60 LET A(J) = T
70 NEXT J
80 LET C = A(0)
90 LET I = 0
100 FOR J = 1 TO N-1
110 IF A(J) > C THEN 130
120 GOTO 150
130 LET C = A(J)
140 LET I = J
150 NEXT J
160 PRINT "THE MAXIMUM VALUE WAS ";C;" AT INDEX ";I;"."
170 END

IS-BASIC

1000 DEF FINDMAX(REF ARR)
1010   LET MX=ARR(LBOUND(ARR))
1020   FOR I=LBOUND(ARR)+1 TO UBOUND(ARR)
1030     LET MX=MAX(MX,ARR(I))
1040   NEXT
1050   LET FINDMAX=MX
1060 END DEF

MSX Basic

Works with: MSX BASIC version any
Translation of: GW-BASIC
10 INPUT "How many items"; N%
20 DIM ARR(N%)
30 FOR I% = 0 TO N% - 1
40 PRINT "Value of item #"; I%
50 INPUT ARR(I%)
60 NEXT I%
70 CHAMP = ARR(0) : INDEX = 0
80 FOR I% = 1 TO N% - 1
90 IF ARR(I%) > CHAMP THEN CHAMP = ARR(I%): INDEX = I%
100 NEXT I%
110 PRINT "The maximum value was "; CHAMP; " at index "; INDEX; "."
120 END

Quite BASIC

Translation of: GW-BASIC
10 INPUT "How many items? "; n
20 ARRAY a
30 FOR j = 0 TO n-1
40 PRINT "Value of item #"; j
50 INPUT ""; t
60 LET a(j) = t
70 NEXT j
80 LET c = a(0)
90 LET i = 0
100 FOR j = 1 TO n-1
110 IF a(j) > c THEN LET c = a(j) : LET i = j
120 NEXT j
130 PRINT "The maximum value was "; c; " at index "; i; "."
140 END

Batch File

::max.cmd
@echo off
setlocal enabledelayedexpansion
set a=.%~1
if "%a%" equ "." set /p a="Input stream: "
call :max res %a%
echo %res%
endlocal
goto :eof

:max
set %1=%2
:loop
shift /2
if "%2" equ "" goto :eof
if %2 gtr !%1! set res=%2
goto loop

Invocation from command line or from internal prompt

>max "123 456 3 234243 12"
234243

>max
Input stream: 5 4 3 2 67 1
67

BBC BASIC

      ListOfValues$ = "13, 0, -6, 2, 37, -10, 12"
      PRINT "Maximum value = " ; FNmax(ListOfValues$)
      END

      DEF FNmax(list$)
      LOCAL index%, number, max
      max = VAL(list$)
      REPEAT
        index% = INSTR(list$, ",", index%+1)
        number = VAL(MID$(list$, index%+1))
        IF number > max THEN max = number
      UNTIL index% = 0
      = max

bc

define m(a[], n) {
    auto m, i

    m = a[0]
    for (i = 1; i < n; i++) {
        if (a[i] > m) m = a[i]
    }
    return(m)
}

Befunge

001pv            <
    >&:01g`#v_1+#^_01g.@
    ^p10    <

Only works with positive integers. List must be terminated with -1.

BQN

Max  ´
Output:
   Max ¯275‿¯111‿0‿¯1234568‿π‿¯π
3.141592653589793


Bracmat

When comparing two rational numbers, Bracmat compares numerically. In all other cases Bracmat compares lexically.

  ( biggest
  =   max
    .   !arg:
      |   !arg:%?max ?arg
        & !arg:? (%@:>!max:?max) (?&~)
      | !max
  )
& out$("1:" biggest$(5 100000 -5 aap 3446 NOOT mies 0))
& out$("2:" biggest$)
&   out
  $ ( "3:"
        biggest
      $ (5 100000 -5 43756243978569758/13 3365864921428443 87512487957139516/27 3446)
    )
Output:
1: mies
2:
3: 3365864921428443

Brat

Arrays have a max function, but here's a manual implementation.

max = { list |
  list.reduce { n, max |
    true? n > max
      { max = n }
      { max }
  }
}

p max [3 4 1 2]

Burlesque

blsq ) {88 99 77 66 55}>]
99

C

This works well with floats. Replace with double, int or what-have-you before passing a different data type.

#include <assert.h>

float max(unsigned int count, float values[]) {
     assert(count > 0);
     size_t idx;
     float themax = values[0];
     for(idx = 1; idx < count; ++idx) {
          themax = values[idx] > themax ? values[idx] : themax;
     }
     return themax;
}

The following macro can be used with any number and type of arguments, provided that the arguments are simple, i.e. must not contain subexpressions where commas appear (this is because of the way the arguments are counted; the macro can be modified so that it is up to the caller to count the number of arguments passed).

Works with: GCC
#include <stdarg.h>

#define MAX(A,...) ({ inline __typeof__ (A) _max_(__typeof__ (A) a, ...) {\
  va_list l; int i,c; const char *s = #__VA_ARGS__; __typeof__ (A) max = a;\
  __typeof__ (A) t;\
  for(c=1;*s!=0;s++) if (*s==',') c++;\
  va_start(l, a);\
  for(i=0;i<=c;i++) {\
  if ((t=va_arg(l,__typeof__ (A))) > max) max = t;\
  }\
  va_end(l); return max;\
}\
_max_((A),__VA_ARGS__);\
})

C#

C# already has a "Maximum Value" function.

int[] values = new int[] {1,2,3,4,5,6,7,8,9,10};

int max = values.Max();

C++

A simple wrapper around the standard library function max_element(). Requires C++17.

#include <algorithm>  //std::max_element
#include <iterator>   //std::begin and std::end
#include <functional> //std::less

template<class It, class Comp = std::less<>>
    //requires ForwardIterator<It> && Compare<Comp>
constexpr auto max_value(It first, It last, Comp compare = std::less{})
{
    //Precondition: first != last
    return *std::max_element(first, last, compare);
}

template<class C, class Comp = std::less<>>
    //requires Container<C> && Compare<Comp>
constexpr auto max_value(const C& container, Comp compare = std::less{})
{
    //Precondition: !container.empty()
    using std::begin; using std::end;
    return max_value(begin(container), end(container), compare);
}

CFEngine

Note: CFEngine bundles are NOT functions, however they can behave in some ways that are similar to functions.

bundle agent __main__
{
  vars:
      "number_of_list_elements"
        int => randomint( "0", 100 ),
        unless => isvariable( "$(this.promiser)" );

      "idx"
        slist => expandrange( "[0-$(number_of_list_elements)]", 1 ),
        unless => isvariable( "$(this.promiser)" );

      "number[$(idx)]"
        int => randomint( "0", "100" ),
        unless => isvariable( "$(this.promiser)" );

      "numbers" slist => sort( getvalues( number ), int );

  methods:
      "Get the greatest value"
        usebundle => greatest_value( @(numbers) ),
        useresult => "returned";

  reports:
      "'$(returned[max])' is the largest number in $(with)"
        with => join( ",", numbers );


}
bundle agent greatest_value(list_of_values)
{
   reports:
      "$(with)"
        with => max( list_of_values, int ),
        bundle_return_value_index => "max";
}
Output:
R: '97' is the largest number in 3,5,6,13,15,30,34,37,47,49,49,53,54,59,59,59,60,62,64,67,78,83,95,97

Clojure

The Clojure.core function max returns the max of its arguments.

(max 1 2 3 4) ; evaluates to 4
;; If the values are already in a collection, use apply:
(apply max [1 2 3 4]) ; evaluates to 4

CLU

% This "maximum" procedure is fully general, as long as
% the container type has an elements iterator and the 
% data type is comparable.
% It raises an exception ("empty") if there are no elements.

maximum = proc [T,U: type] (a: T) returns (U) 
          signals (empty)
          where T has elements: itertype (T) yields (U),
                U has gt: proctype (U,U) returns (bool)
    max: U
    seen: bool := false
    
    for item: U in T$elements(a) do
        if ~seen cor item > max then 
            max := item 
            seen := true
        end
    end
    if (~seen) then
        signal empty
    else
        return(max)
    end
end maximum
      

start_up = proc ()
    po: stream := stream$primary_output()
    
    % try it on an array of ints
    ints: array[int] := array[int]$[1,5,17,2,53,99,61,3]
    imax: int := maximum[array[int], int](ints)
    stream$putl(po, "maximum int: " || int$unparse(imax))    

    % try it on a sequence of reals
    reals: sequence[real] := sequence[real]$[-0.5, 2.6, 3.14, 2.72]
    rmax: real := maximum[sequence[real], real](reals)
    stream$putl(po, "maximum real: " || real$unparse(rmax))
end start_up
Output:
maximum int: 99
maximum real: 3.140000e+00

CMake

Only for lists of integers.

# max(var [value1 value2...]) sets var to the maximum of a list of
# integers. If list is empty, sets var to NO.
function(max var)
  set(first YES)
  set(choice NO)
  foreach(item ${ARGN})
    if(first)
      set(choice ${item})
      set(first NO)
    elseif(choice LESS ${item})
      set(choice ${item})
    endif()
  endforeach(item)
  set(${var} ${choice} PARENT_SCOPE)
endfunction(max)

set(list 33 11 44 22 66 55)
max(maximum ${list})
message(STATUS "maximum of ${list} => ${maximum}")
-- maximum of 33;11;44;22;66;55 => 66

COBOL

This is already built into the language for tables of numbers.

DISPLAY FUNCTION MAX(nums (ALL))

A sample implementation:

       IDENTIFICATION DIVISION.
       FUNCTION-ID. greatest-elt.

       DATA DIVISION.
       LOCAL-STORAGE SECTION.
       01  idx                     USAGE INDEX.

       01  Table-Len               CONSTANT 50.

       LINKAGE SECTION.
       01  num-table-area.
           03  num-table           PIC 9(8) OCCURS Table-Len TIMES.

       01  max-elt                 PIC 9(8).

       PROCEDURE DIVISION USING VALUE num-table-area RETURNING max-elt.
           PERFORM VARYING idx FROM 1 BY 1 UNTIL idx > Table-Len
               IF num-table (idx) > max-elt
                   MOVE num-table (idx) TO max-elt
               END-IF
           END-PERFORM

           GOBACK
           .
       END FUNCTION greatest-elt.

CoffeeScript

# using Math library
max1 = (list) ->
 Math.max.apply null, list

# using no libraries
max2 = (list) ->
 maxVal = list[0]
 for value in list
  maxVal = value if value > maxVal
 maxVal
 
 
 
# Test it
a = [0,1,2,5,4];
alert(max1(a)+". The answer is "+max2(a));

ColdFusion

<Cfset theList = '1, 1000, 250, 13'>
<Cfparam name="maxNum" default=0>
<Cfloop list="#theList#" index="i">
  <Cfif i gt maxNum><Cfset maxNum = i></Cfif>
</Cfloop>
<Cfoutput>#maxNum#</Cfoutput>
<Cfset theList = '1, 1000, 250, 13'>
<Cfset maxNum = ListFirst(ListSort(thelist, "numeric", "desc"))>
<Cfoutput>#maxNum#</Cfoutput>

Common Lisp

The built-in Common Lisp function max takes the max of all its arguments.

(max 1 2 3 4)
(reduce #'max values) ; find max of a list
(loop for x in values
      maximize x) ; alternative way to find max of a list

Component Pascal

BalckBox Component Builder

MODULE Operations;
IMPORT StdLog,Args,Strings;

PROCEDURE Max(s: ARRAY OF INTEGER): INTEGER;
VAR
	i: INTEGER;
	max: INTEGER;
BEGIN
	max := MIN(INTEGER);
	FOR i := 0 TO LEN(s) - 1 DO
		max := MAX(max,s[i]);
	END;
	RETURN max
END Max;

PROCEDURE DoMax*;
VAR	
	sq: POINTER TO ARRAY OF INTEGER;
	p: Args.Params;
	i,n,done: INTEGER;
BEGIN
	Args.Get(p);
	IF p.argc > 0 THEN
		NEW(sq,p.argc);
		FOR i := 0 TO p.argc - 1 DO
			Strings.StringToInt(p.args[i],n,done);
			sq[i] := n
		END;
		StdLog.String("max:> ");StdLog.Int(Max(sq));StdLog.Ln
	END
END DoMax;

END Operations.

Execute: ^Q Operations..DoMax 23 12 3 45 34 54 84 ~

Output:
max:>  84

Crystal

values.max

D

D already has a "Maximum Element" function.

void main()
{
    import std.algorithm.searching : maxElement;
    import std.stdio : writeln;

    [9, 4, 3, 8, 5].maxElement.writeln;
}
Output:
9

Dart

/*This is a function which returns the greatest element in a list of numbers */
num findGreatestElement(List<num> list){
  num greatestElement = list[0];
  for (num element in list){
    if (element>greatestElement) {
      greatestElement = element;
    }
  }  
  return greatestElement;
}
/* and this is a shorter version */
import 'dart:math';
num findGreatestElement(List<num> list){
  return list.reduce(max);
}

dc

[sm llx] sg
[lm p q] sq
[d lm <u s_ z 0 =q llx] sl
[d sm] su

["Put list of numbers on the stack starting here, then execute g"] s_

3.14159265358979 sp

_275.0 _111.19 0.0 _1234568.0 lp lp _1 *

lgx
Output:
3.14159265358979

DCL

$ list = "45,65,81,12,0,13,-56,123,-123,888,12,0"
$ max = f$integer( f$element( 0, ",", list ))
$ i = 1
$ loop:
$  element = f$element( i, ",", list )
$  if element .eqs. "," then $ goto done
$  element = f$integer( element )
$  if element .gt. max then $ max = element
$  i = i + 1
$  goto loop
$ done:
$ show symbol max
Output:
$ @greatest
  MAX = 888   Hex = 00000378  Octal = 00000001570

Delphi

program GElemLIst;
{$IFNDEF FPC}
  {$Apptype Console}
{$ENDIF}

uses
  math;
const
  MaxCnt = 10000;
var
  IntArr : array of integer;
  fltArr : array of double;
  i: integer;
begin
  setlength(fltArr,MaxCnt); //filled with 0
  setlength(IntArr,MaxCnt); //filled with 0.0
  randomize;
  i := random(MaxCnt);      //choose a random place
  IntArr[i] := 1;
  fltArr[i] := 1.0;
  writeln(Math.MaxIntValue(IntArr)); // Array of Integer
  writeln(Math.MaxValue(fltArr));
end.

Dyalect

func max(xs) {
    var y
    for x in xs {
        if y == nil || x > y {
            y = x
        }
    }
    y
}
 
var xs = [1..10]
max(xs)

Déjà Vu

max lst:
    lst! 0
    for item in copy lst:
         if > item dup:
              item drop

!. max [ 10 300 999 9 ]
Output:
999

Draco

/* Find the greatest element in an array of ints */
proc nonrec max([*] int a) int:
    int INT_MIN = ~((~0) >> 1);
    int nmax, i;
    nmax := INT_MIN;
    for i from 0 upto dim(a,1)-1 do
        if a[i] > nmax then nmax := a[i] fi
    od;
    nmax 
corp

/* Test on an array */
proc nonrec main() void:
    type arr = [8] int;
    writeln("Maximum: ", max(arr(1,5,17,2,53,99,61,3)))
corp
Output:
Maximum: 99

E

This function works for any value which responds to max/1:

pragma.enable("accumulator") # non-finalized syntax feature

def max([first] + rest) { 
    return accum first for x in rest { _.max(x) }
}
? max([1, 2, 3])
# value: 3

To require only the comparison protocol, one needs to write out the algorithm a little more explicitly:

def max([var bestSoFar] + rest) {
    for x ? (x > bestSoFar) in rest {
        bestSoFar := x
    }
    return bestSoFar
}
? max([1, 3, 2])
# value: 3

? max([[1].asSet(), [2].asSet(), [1, 2].asSet()])
# value: [1, 2].asSet()

EasyLang

a[] = [ 2 9 4 3 8 5 ]
for e in a[]
  max = higher e max
.
print max

EchoLisp

;; a random length list of random values
(define L (map random (make-list (random 50) 100)))  L
L  (24 60 83 8 24 60 31 97 96 65 9 41 64 24 22 57 73 17 6 28 77 58 18 13 27 22 41 69 85)

;; find max
(apply max L)  97

ECL

MaxVal(SET OF INTEGER s) := MAX(s);

//example usage

SetVals := [4,8,16,2,1];
MaxVal(SetVals) //returns 16;

Efene

list_max = fn ([Head:Rest]) {
  list_max(Rest, Head)
}

list_max = fn ([], Res) {
  Res
} 
fn ([Head:Rest], Max) when Head > Max {
  list_max(Rest, Head)
} 
fn ([_Head:Rest], Max) {
  list_max(Rest, Max)
}

list_max1 = fn ([H:T]) {
  lists.foldl(fn erlang.max:2, H, T)
}

@public
run = fn () {
    io.format("~p~n", [list_max([9, 4, 3, 8, 5])])
    io.format("~p~n", [list_max1([9, 4, 3, 8, 5])])
}

Eiffel

The GREATEST_ELEMENT class:

class
	GREATEST_ELEMENT [G -> COMPARABLE]

create
	make

feature {NONE} --Implementation

	is_max (element: G maximum: G): BOOLEAN
		do
			Result := maximum >= element
		end

	max (list: ARRAY [G]): G
		require
			not_empty: not list.is_empty
		do
			Result := list [list.lower]
			across
				list as i
			loop
				Result := i.item.max (Result)
			end
		ensure
			is_part_of_array: list.has (Result)
			is_maximum: list.for_all (agent is_max(?, Result))
		end

feature -- Initialization

	make
		do
		end

	greatest_element (a: ARRAY [G]): G
		do
			Result := max (a)
		end

end

A test application:

class
	APPLICATION

create
	make

feature {NONE} -- Initialization

	make
			-- Run application.
		local
			numbers: ARRAY [INTEGER]
			greatest: GREATEST_ELEMENT [INTEGER]
		do
			create greatest.make
			numbers := <<1, 2, 3, 4, 5, 6, 7, 8, 9>>
			print (greatest.greatest_element (numbers))
		end

end

Ela

open list

findBy p (x::xs) = foldl (\x y | p x y -> x | else -> y) x xs
maximum = findBy (>)

maximum [1..10]

Elena

ELENA 6.x :

import extensions;
 
extension op
{
    get Maximal()
    {
        auto en := cast Enumerator(self.enumerator());
 
        object maximal := nil;
        while (en.next())
        {
            var item := *en;
            if (nil == maximal)
            {
                maximal := item
            } 
            else if (maximal < item)
            {
                maximal := item
            }
        };
 
        ^ maximal   
    }
}
 
public program()
{
    console.printLine(new int[]{1,2,3,4,20,10,9,8}.Maximal)
}
Output:
20

Elixir

iex(1)> Enum.max([3,1,4,1,5,9,2,6,5,3])
9

Emacs Lisp

(defun find-maximum (items)
  (let (max)
    (dolist (item items)
      (when (or (not max) (> item max))
        (setq max item)))
    max))

(find-maximum '(2 7 5)) ;=> 7

Built-in:

(max '(2 7 5)) ;=> 7
Library: cl-lib
(cl-loop for el in '(2 7 5) maximize el) ;=> 7
(cl-reduce #'max '(2 7 5)) ;=> 7
Library: seq.el
(seq-max '(2 7 5)) ;=> 7

Erlang

Builtin. Using it from the Erlang shell:

>lists:max([9,4,3,8,5]).
9

ERRE

PROGRAM MAXLIST

!
! for rosettacode.org
!

! VAR L$,EL$,CH$,I%,MAX

BEGIN
  PRINT(CHR$(12);) ! CLS
  INPUT("Lista",L$)
  L$=L$+CHR$(32)
  MAX=-1.7E+38
  FOR I%=1 TO LEN(L$) DO
    CH$=MID$(L$,I%,1)
    IF CH$<>CHR$(32) THEN ! blank is separator
       EL$=EL$+CH$
     ELSE
       IF VAL(EL$)>MAX THEN MAX=VAL(EL$) END IF
       EL$=""
    END IF
  END FOR
  PRINT("Max list element is";MAX)
END PROGRAM

Note: The limit of this program is string variable lenght (255 chars). The advantage is no array use.

Euler

Euler allows hetrogenous lists, the real operator converts boolean and symbol (short character strings) to a number (leaving numeric values unchanged) and the isu operator tests whether its operand is undefined or not.

begin new greatest;
   greatest <- ` formal ls;
                 begin new L; new i; new result; label iLoop;
                    L      <- ls;
                    result <- undefined;
                    i      <- 0;
iLoop:              if [ i <- i + 1 ] <= length L then begin
                       if isu result or real L[ i ] > real result
                          then result <- L[ i ] else 0;
                       goto iLoop
                    end else 0;
                    result
                 end
               ';
   out greatest( ( false, 99.0, -271, "b", 3, 4 ) )
end $

Euler Math Toolbox

>v=random(1,100);
>max(v)
 0.997492478596

Euphoria

Applying a function to each element of an array

function aeval( sequence sArr, integer id )
    for i = 1 to length( sArr ) do
        sArr[ i ] = call_func( id, { sArr[ i ] } )
    end for
    return sArr
end function

object biggun
function biggest( object elem )
    if compare(elem, biggun) > 0 then
        biggun = elem
    end if
    return elem
end function

biggun = 0
object a
a = aeval( {1,1234,62,234,12,34,6}, routine_id("biggest") )
printf( 1, "%d\n", biggun )

sequence s
s = {"antelope", "dog", "cat", "cow", "wolf", "wolverine", "aardvark"} 
biggun = "ant"
a = aeval( s, routine_id("biggest") )
printf( 1, "%s\n", {biggun} )
Output:
1234
wolverine

More trivial example

function get_biggest(sequence s)
    object biggun
    biggun = s[1]
    for i = 2 to length(s) do
        if compare(s[i], biggun) > 0 then
            biggun = s[i]
        end if
    end for
    return biggun
end function

constant numbers = {1,1234,62,234,12,34,6}
printf(1,"%d\n",get_biggest(numbers))

constant animals = {"ant", "antelope", "dog", "cat", "cow", "wolf", "wolverine", "aardvark"}
printf(1,"%s\n",{get_biggest(animals)})
Output:
1234
wolverine

Excel

Use the function MAX

=MAX(3;2;1;4;5;23;1;2)
Output:
23

F#

I generate a list of 10 random numbers at runtime then use F#'s built in function to find the maximum value of the list.

let N = System.Random()
let G = List.init 10 (fun _->N.Next())
List.iter (printf "%d ") G
printfn "\nMax value of list is %d" (List.max G)
Output:
401566008 1378437959 1806806326 2010005455 1973773308 1216833747 268836584 1963610340 2120237482 1412806752 
Max value of list is 2120237482

Factor

The following word is in factor's standard library.

: supremum ( seq -- elt ) [ ] [ max ] map-reduce ;

Fancy

[1,-2,2,4,6,-4,-1,5] max println  # => 6

Fantom

Has a built-in method to get maximum from a list.

class Greatest
{
  public static Void main () 
  {
    Int[] values := [1,2,3,4,5,6,7,8,9]
    Int greatest := values.max
    echo (greatest)
  }
}

Forth

: array-max ( addr len -- max )
  dup 0= if nip exit then
  over @  rot cell+  rot 1-
  cells bounds ?do  i @ max  cell +loop ;

: stack-max ( n ... m count -- max ) 1 ?do max loop ;

Fortran

Works with: Fortran version 2003

The intrinsic function maxval returns the maximum value of the elements in an integer or real array:

program test_maxval
 
integer,dimension(5),parameter :: x = [10,100,7,1,2]
real,dimension(5),parameter :: y = [5.0,60.0,1.0,678.0,0.0]
 
write(*,'(I5)') maxval(x)
write(*,'(F5.1)') maxval(y)

end program test_maxval
Output:
 100
 678.0

The intrinsic function max accepts any number of arguments. The type of these arguments can be integer, real, character, string of characters or arrays of these.

program test_max

  implicit none

  write (*, '(i0)') &
    & max (1, 2, 3)
  write (*, '(f3.1)') &
    & max (1.0, 2.0, 3.0)
  write (*, '(a)') &
    & max ('a', 'b', 'c')
  write (*, '(a)') &
    & max ('abc', 'bca', 'cab')
  write (*, '(i0, 2 (1x, i0))') &
    & max ([1, 8, 6], [7, 5, 3], [4, 2, 9])
  write (*, '(f3.1, 2 (1x, f3.1))') &
    & max ([1.0, 8.0, 6.0], [7.0, 5.0, 3.0], [4.0, 2.0, 9.0])
  write (*, '(a, 2 (1x, a))') &
    & max (['a', 'h', 'f'], ['g', 'e', 'c'], ['d', 'b', 'i'])
  write (*, '(a, 2 (1x, a))') &
    & max (['abc', 'hig', 'fde'], ['ghi', 'efd', 'cab'], ['def', 'bca', 'igh'])

end program test_max
Output:
 3
 3.0
 c
 cab
 7 8 9
 7.0 8.0 9.0
 g h i
 ghi hig igh

FreeBASIC

' FB 1.05.0 Win64

Function MaxElement(a() As Double) As Double
  Dim max As Double = a(LBound(a))
  For i As Integer = LBound(a) + 1 To UBound(a)
    If a(i) > max Then max = a(i)
  Next
  Return max
End Function

Dim As Integer i, n
Input "How many values are to be input ";  n
If n < 1 Then End
Dim a(1 To n) As Double
For i = 1 To n
  Print "  Value"; i; " : ";
  Input "", a(i)
Next
Dim max As Double = MaxElement(a())
Print
Print "The greatest value is"; max
Print
Print "Press any key to quit"
Sleep

Example of use :

Output:
How many values are to be input ? 4
  Value 1 : 70.5
  Value 2 : 23.67
  Value 3 : 150.2
  Value 4 : 145

The greatest value is 150.2

Frink

println[max[[1,2,3,5,10,20]]]

FunL

Using the pre-defined function max:

println( max([1,2,3,-1,0]) )
Output:
3

It can be implemented as:

def
  maximum( xs ) =
    def
      max( a, b )             = if a <= b then b else a

      foldl( f, z, [] )       = z
      foldl( f, z, x:xs )     = foldl( f, f(z, x), xs )

      foldl1( f, x:xs )       = foldl( f, x, xs )
      foldl1( _, [] )         = error( "foldl1: empty list" )

    foldl1( max, xs )


Futhark

This parallel formulation exploits the fact that negative infinity constitutes a neutral element for the maximum operator.

let main (xs: []f64) = reduce f64.max (-f64.inf) xs


FutureBasic

The function fn GreatestElementInList() will sort and return the greatest element of any list that supports the @"compare:" operator.

include "NSLog.incl"

local fn GreatestElementInList( list as CFArrayRef ) as CFTypeRef
  CfArrayRef array = fn ArraySortedArrayUsingSelector( list, @"compare:" )
  CFTypeRef result = fn ArrayLastObject( array )
end fn = result

CFArrayRef array

array = @[@1, @-2, @10, @5.0, @10.5]
NSLog( @"%@", fn GreatestElementInList( array ) )

// Greatest element will be letter with highest ASCII value
array = @[@"A", @"b", @"C", @"d", @"E"]
NSLog( @"%@", fn GreatestElementInList( array ) )

array = @[@"ant", @"antelope", @"dog", @"cat", @"cow", @"wolf", @"wolverine", @"aardvark"]
NSLog( @"%@", fn GreatestElementInList( array ) )

array = @[@"abc", @"123", @"zyx", @"def"]
NSLog( @"%@", fn GreatestElementInList( array ) )

HandleEvents
Output:
10.5
d
wolverine
zyx


Fōrmulæ

Fōrmulæ programs are not textual, visualization/edition of programs is done showing/manipulating structures but not text. Moreover, there can be multiple visual representations of the same program. Even though it is possible to have textual representation —i.e. XML, JSON— they are intended for storage and transfer purposes more than visualization and edition.

Programs in Fōrmulæ are created/edited online in its website.

In this page you can see and run the program(s) related to this task and their results. You can also change either the programs or the parameters they are called with, for experimentation, but remember that these programs were created with the main purpose of showing a clear solution of the task, and they generally lack any kind of validation.

Solution

Fōrmulæ provides a built-in expression "Max" that reduces to the maximum element of a given list:

Case 1. With numbers

Case 2. With strings

Case 3. With time expressions

GW-BASIC

10 INPUT "How many items? ", N%
20 DIM ARR(N%)
30 FOR I% = 0 TO N%-1
40 PRINT "Value of item #";I%
50 INPUT ARR(I%)
60 NEXT I%
70 CHAMP = ARR(0) : INDEX = 0
80 FOR I% = 1 TO N%-1
90 IF ARR(I%)>CHAMP THEN CHAMP=ARR(I%):INDEX=I%
100 NEXT I%
110 PRINT "The maximum value was ";CHAMP;" at index ";INDEX;"."
120 END

GAP

# Built-in

L := List([1 .. 100], n -> Random(1, 10));

MaximumList(L);
# 10

Go

Library
package main

import (
    "fmt"

    "github.com/gonum/floats"
)

func main() {
	fmt.Println(floats.Max([]float64{63, 70, 37, 34, 83, 27, 19, 97, 9, 17})) // prt 97
	fmt.Println(floats.Min([]float64{63, 70, 37, 34, 83, 27, 19, 97, 9, 17})) // prt 9
}
package main

import "fmt"

func main() {
	x := []int{
		48, 96, 86, 68,
		57, 82, 63, 70,
		37, 34, 83, 27,
		19, 97, 9, 17,
	}

	smallest, biggest := x[0], x[0]
	for _, v := range x {
		if v > biggest {
			biggest = v
		}
		if v < smallest {
			smallest = v
		}
	}

	fmt.Println("The biggest number is ", biggest) // prt 97
	fmt.Println("The smallest number is ", smallest) // prt 9
}
List

The task title says list. This solution uses a Go slice as a list.

package main

import (
    "fmt"
    "math/rand"
    "time"
)

// function, per task description
func largest(a []int) (lg int, ok bool) {
    if len(a) == 0 {
        return
    }
    lg = a[0]
    for _, e := range a[1:] {
        if e > lg {
            lg = e
        }
    }
    return lg, true
}

func main() {
    // random size slice
    rand.Seed(time.Now().UnixNano())
    a := make([]int, rand.Intn(11))
    for i := range a {
        a[i] = rand.Intn(101) - 100 // fill with random numbers
    }

    fmt.Println(a)
    lg, ok := largest(a)
    if ok {
        fmt.Println(lg)
    } else {
        fmt.Println("empty list.  no maximum.")
    }
}
Set

The task description says set. This solution uses a Go map as a set.

package main

import (
    "fmt"
    "math"
    "math/rand"
    "time"
)

// Function, per task description.  Interesting with the float64 type because
// of the NaN value.  NaNs do not compare to other values, so the result of
// a "largest" function on a set containing a NaN might be open to
// interpretation.  The solution provided here is to return the largest
// of the non-NaNs, and also return a bool indicating the presense of a NaN.
func largest(s map[float64]bool) (lg float64, ok, nan bool) {
    if len(s) == 0 {
        return
    }
    for e := range s {
        switch {
        case math.IsNaN(e):
            nan = true
        case !ok || e > lg:
            lg = e
            ok = true
        }
    }
    return
}

func main() {
    rand.Seed(time.Now().UnixNano())
    // taking "set" literally from task description
    s := map[float64]bool{}
    // pick number of elements to add to set
    n := rand.Intn(11)
    // add random numbers, also throw in an occasional NaN or Inf.
    for i := 0; i < n; i++ {
        switch rand.Intn(10) {
        case 0:
            s[math.NaN()] = true
        case 1:
            s[math.Inf(1)] = true
        default:
            s[rand.ExpFloat64()] = true
        }
    }

    fmt.Print("s:")
    for e := range s {
        fmt.Print(" ", e)
    }
    fmt.Println()
    switch lg, ok, nan := largest(s); {
    case ok && !nan:
        fmt.Println("largest:", lg)
    case ok:
        fmt.Println("largest:", lg, "(NaN present in data)")
    case nan:
        fmt.Println("no largest, all data NaN")
    default:
        fmt.Println("no largest, empty set")
    }
}

Golfscript

{$-1=}:max;
[1 4 8 42 6 3]max # Example usage

Groovy

println ([2,4,0,3,1,2,-12].max())
Output:
4

Haskell

The built-in Haskell function maximum returns a maximum based on default comparison between members of an ordered type.

my_max = maximum

It can alternately be defined as a "fold" on the built-in two-argument max function.

my_max = foldl1 max

More generally, maximum is a special case of maximumBy, which allows us to define or supply our own comparison function, and define the particular type of maximum that we need:

import Data.List (maximumBy)
import Data.Ord (comparing)

wds :: [String]
wds = ["alpha", "beta", "gamma", "delta", "epsilon", "zeta"]

main :: IO ()
main = print $ maximumBy (comparing length) wds

As a fold, maximumBy could be defined along the lines of:

maximumBy
  :: Foldable t
  => (a -> a -> Ordering) -> t a -> a
maximumBy cmp =
  let max_ x y =
        case cmp x y of
          GT -> x
          _ -> y
  in foldr1 max_

hexiscript

fun greatest a
  let l len a
  let max a[0]
  for let i 1; i < l; i++
    if max < a[i]
      let max a[i]
    endif
  endfor
  return max
endfun

HicEst

   max_value = MAX( -123,  234.56, 345.678, -456E3, -455) ! built-in function MAX(...)

! or for an array:
   max_value = MAX( array_of_values )

! or to find a maximum value in a file named filename:
   CHARACTER List, filename='Greatest element of a list.hic' ! filename contains this script
   REAL values(1) ! unknown number of values, allocate more below

   OPEN(FIle=filename, BINary, LENgth=len)
   ALLOCATE(values, len/2) ! number of values <= half byte count of file
   ! read all values, returns item count in values_found:
   READ(FIle=filename, ItemS=values_found, CLoSe=1) values ! no Format needed for plain text numbers

   max_value = MAX(values)

   ! write values found in filename and result to spreadsheet type dialog window:
   DLG(Text=values, Text=max_value, TItle=values_found)

   WRITE(ClipBoard, Name) max_value, values_found, values ! pasted to line below
   ! max_value=345.678; values_found=30; values(1)=-123; values(2)=234.56; values(3)=345.678; values(4)=-456E3; values(5)=-455; values(6)=1; values(7)=2; values(8)=1; values(9)=0; values(10)=0; ...truncated
 END

Hoon

:-  %say
|=  [^ [a=(list ,@) ~] ~]
:-  %noun
  (snag 0 (sort a gte))

Usage: Add to a file gen/max.hoon

> +max [1 2 3 ~]
3

i

concept largest(l) {
	large = l[0]
	for element in l
		if element > large
			large = element
		end
	end
	return large
}

software {
	print(largest([23, 1313, 21, 35757, 4, 434, 232, 2, 2342]))
}

Icon and Unicon

procedure main()
   local l
   l := [7,8,6,9,4,5,2,3,1]
   write(max(l))
end

procedure max(l)
   local max
   max := l[1]
   every max <:= !l
   return max
end

Insitux

max is a built-in operation.

(max 1 2 3 4)
;or
(... max [1 2 3 4])
Output:
4

J

Solution:
   >./
Example:
   >./ 1 2 3 2 1
3
   >./''  NB.  Maximum value of an empty list = identity element (or neutral) of max = -∞
__

(J's lists know how long they are.)

Janet

(def elems @[3 1 3 2])

# Use extreme function from stdlib with > function.
(extreme > elems)

# Unpack list as arguments to max function.
(max ;elems)

Java

int max(int[] values) {
    int max = values[0];
    for (int value : values)
        if (max < value) max = value;
    return max;
}


The first function works with arrays of floats. Replace with arrays of double, int, or other primitive data type.

public static float max(float[] values) throws NoSuchElementException {
    if (values.length == 0)
        throw new NoSuchElementException();
    float themax = values[0];
    for (int idx = 1; idx < values.length; ++idx) {
        if (values[idx] > themax)
            themax = values[idx];
    }
    return themax;
}

Optionally, if it is OK to rearrange the contents of the original array:

public static float max(float[] values) throws NoSuchElementException {
    if (values.length == 0)
        throw new NoSuchElementException();
    Arrays.sort(values);//sorts the values in ascending order
    return values[values.length-1];
}

The following functions work with Lists or arrays of reference types, respectively. Note that the type is required to implement Comparable, to ensure we can compare them. For Lists, there is a utility method Collections.max() that already does this. For arrays, we can just use the Arrays.asList() wrapper to wrap it into a list and then use the function for lists.

import java.util.List;
import java.util.Collections;
import java.util.Arrays;

public static <T extends Comparable<? super T>> T max(List<T> values) {
    return Collections.max(values);
}

public static <T extends Comparable<? super T>> T max(T[] values) {
    return Collections.max(Arrays.asList(values));
}

JavaScript

ES3-5

Math.max.apply(null, [ 0, 1, 2, 5, 4 ]); // 5

ES 5 maxima beyond simple numeric data types

Math.max() serves well with simple numeric types, but for less restricted use we can write a generic maximumBy function which returns the maximum value from an array containing a series of any consistent data type, and which takes a type-specific comparison function as an argument.

(function () {

    // (a -> a -> Ordering) -> [a] -> a 
    function maximumBy(f, xs) {
        return xs.reduce(function (a, x) {
            return a === undefined ? x : (
                f(x, a) > 0 ? x : a
            );
        }, undefined);
    }

    // COMPARISON FUNCTIONS FOR SPECIFIC DATA TYPES

    //Ordering: (LT|EQ|GT)
    //  GT: 1 (or other positive n)
    //  EQ: 0
    //  LT: -1 (or other negative n) 

    function wordSortFirst(a, b) {
        return a < b ? 1 : (a > b ? -1 : 0)
    }

    function wordSortLast(a, b) {
        return a < b ? -1 : (a > b ? 1 : 0)
    }

    function wordLongest(a, b) {
        return a.length - b.length;
    }

    function cityPopulationMost(a, b) {
        return a.population - b.population;
    }

    function cityPopulationLeast(a, b) {
        return b.population - a.population;
    }

    function cityNameSortFirst(a, b) {
        var strA = a.name,
            strB = b.name;

        return strA < strB ? 1 : (strA > strB ? -1 : 0);
    }

    function cityNameSortLast(a, b) {
        var strA = a.name,
            strB = b.name;

        return strA < strB ? -1 : (strA > strB ? 1 : 0);
    }

    var lstWords = [
            'alpha', 'beta', 'gamma', 'delta', 'epsilon', 'zeta', 'eta',
            'theta', 'iota', 'kappa', 'lambda'
        ];

    var lstCities = [
        {
            name: 'Shanghai',
            population: 24.15
            }, {
            name: 'Karachi',
            population: 23.5
            }, {
            name: 'Beijing',
            population: 21.5
            }, {
            name: 'Tianjin',
            population: 14.7
            }, {
            name: 'Istanbul',
            population: 14.4
            }, , {
            name: 'Lagos',
            population: 13.4
            }, , {
            name: 'Tokyo',
            population: 13.3
            }
        ];

    return [
        maximumBy(wordSortFirst, lstWords),
        maximumBy(wordSortLast, lstWords),
        maximumBy(wordLongest, lstWords),
        maximumBy(cityPopulationMost, lstCities),
        maximumBy(cityPopulationLeast, lstCities),
        maximumBy(cityNameSortFirst, lstCities),
        maximumBy(cityNameSortLast, lstCities)
    ]

})();


Output:
[
  "alpha",
  "zeta",
  "epsilon",
  {
    "name": "Shanghai",
    "population": 24.15
  },
  {
    "name": "Tokyo",
    "population": 13.3
  },
  {
    "name": "Beijing",
    "population": 21.5
  },
  {
    "name": "Tokyo",
    "population": 13.3
  }
]

ES6

For, numbers, a method of the standard Math object:

Math.max(...[ 0, 1, 2, 5, 4 ]); // 5

and for orderings defined over other datatypes:

(() => {
    "use strict";

    // ----------- GREATEST ELEMENT OF A LIST ------------

    // maximumByMay :: (a -> a -> Ordering) ->
    // [a] -> Maybe a
    const maximumByMay = f =>
        // Nothing, if the list is empty,
        // or just the maximum value when compared
        // in terms of f.
        xs => Boolean(xs.length) ? (
            Just(xs.slice(1).reduce(
                (a, x) => 0 < f(a)(x) ? (
                    a
                ) : x,
                xs[0]
            ))
        ) : Nothing();


    // ---------------------- TEST -----------------------
    const main = () =>
        JSON.stringify(
            catMaybes([
                maximumByMay(
                    comparing(x => x.length)
                )([
                    "alpha", "beta", "gamma", "delta",
                    "epsilon", "zeta", "eta"
                ]),
                maximumByMay(comparing(x => x.length))([]),
                maximumByMay(comparing(x => x.n))([{
                    k: "Bejing",
                    n: 21.5
                }, {
                    k: "Delhi",
                    n: 16.7
                }, {
                    k: "Karachi",
                    n: 23.5
                }, {
                    k: "Lagos",
                    n: 16.0
                }, {
                    k: "Shanghai",
                    n: 24.3
                }, {
                    k: "Tokyo",
                    n: 13.2
                }])
            ]),
            null, 2
        );

    // --------------------- GENERIC ---------------------

    // Just :: a -> Maybe a
    const Just = x => ({
        type: "Maybe",
        Nothing: false,
        Just: x
    });


    // Nothing :: Maybe a
    const Nothing = () => ({
        type: "Maybe",
        Nothing: true
    });


    // catMaybes :: [Maybe a] -> [a]
    const catMaybes = mbs =>
        mbs.flatMap(
            m => m.Nothing ? (
                []
            ) : [m.Just]
        );


    // comparing :: (a -> b) -> (a -> a -> Ordering)
    const comparing = f =>
        x => y => {
            const
                a = f(x),
                b = f(y);

            return a < b ? -1 : (a > b ? 1 : 0);
        };

    // MAIN ---
    return main();
})();
Output:
[
  "epsilon",
  {
    "k": "Shanghai",
    "n": 24.3
  }
]

Joy

DEFINE maximum == unswons [max] fold.

jq

jq defines a total ordering of all JSON entities, and the max filter can accordingly be used on any JSON array:

[1, 3, 1.0] | max # => 3

[ {"a": 1},  {"a":3}, {"a":1.0}] | max  # => {"a": 3}

Warning: both "[null]|max" and "[]|max" yield null.

Given a stream, s, of JSON values, the following filter will emit null if the stream is empty, or the maximum value otherwise:

reduce s as $x (null; if $x > . then $x else . end)

Julia

Using the built-in maximum function:

julia> maximum([1,3,3,7])
7

julia> maximum([pi,e+2/5,cos(6)/5,sqrt(91/10)])
3.141592653589793

julia> maximum([1,6,Inf])
Inf

julia> maximum(Float64[])
maximum: argument is empty
at In[138]:1
 in maximum at abstractarray.jl:1591

(Note that it throws an exception on an empty array.)

K

   |/ 6 1 7 4
7

Klingphix

include ..\Utilitys.tlhy

( "1" "1234" "62" "234" "12" "34" "6" )
 
dup "Alphabetic order: " print lmax ?
 
:f tonum ;
 
@f map
 
"Numeric order: " print lmax ?

" " input

Klong

list::[ 1.0 2.3 1.1 5.0 3 2.8 2.01 3.14159 77 ]
|/list
|/ [ 1.0 2.3 1.1 5.0 3 2.8 2.01 3.14159 66 ]
|/ 1.0,2.3,1.1,5.0,3,2.8,2.01,3.14159,55
Output:
77
66
55

Kotlin

Kotlin has a max() function in its standard library that applies to collection of Iterable :

fun main() {
    listOf(1.0, 3.5, -1.1).max().also { println(it) } // 3.5
    listOf(1, 3, -1).max().also { println(it) }       // 3
    setOf(1, 3, -1).max().also { println(it) }        // 3
}

Lambdatalk

1) using the builtin primitive 

{max 556 1 7344 4 7 52 22 55 88 122 55 99 1222 578}
-> 7344

2) buidling a function

{def my-max
 {def max-h
  {lambda {:l :greatest}
   {if {A.empty? :l}
    then :greatest
    else {max-h {A.rest :l} 
                {if {> {A.first :l} :greatest}
                 then {A.first :l}
                 else :greatest}}}}}
 {lambda {:l}
  {if {A.empty? :l} then empty else {max-h :l {A.first :l}}}}}
-> my-max

{my-max {A.new 556 1 7344 4 7 52 22 55 88 122 55 99 1222 578}}
-> 7344

Lasso

define greatest(a::array) => {
	return (#a->sort&)->last
}

local(x = array(556,1,7344,4,7,52,22,55,88,122,55,99,1222,578))
greatest(#x)
Output:
7344

LDPL

data:
values is number list
n is number

procedure:
sub max
    parameters:
        x is number list
        result is number
    local data:
        i is number
    procedure:
        store x:0 in result
        for each i in values do
            if i is greater than result then
                store i in result
            end if
        repeat
end sub
create statement "get maximum of list $ in $" executing max

# Now let's use the sub-procedure.
push 1 to values
push 11 to values
push 5 to values
push 33 to values
push 99 to values
push 13 to values
push 37 to values
push 50 to values

get maximum of list values in n
display "The maximum is " n lf
Output:
The maximum is 99

LFE

Builtin. Using it from the LFE shell:

>(: lists max '[9 4 3 8 5])
9

Liberty BASIC

aList$= "1 15 -5 6 39 1.5 14"

maxVal = val(word$(aList$, 1))
token$ = "?"
while token$ <> ""
    index = index + 1
    token$ = word$(aList$, index)
    aVal = val(token$)
    if aVal > maxVal then maxVal = aVal
wend

print "maxVal = ";maxVal

Lingo

l = [1,7,5]
put max(l)
-- 7

LiveCode

Max is built-in
put max(2,3,6,7,4,1)

Result: 7

To be fair to the exercise, an alternative implementation could be
function max2 lst
    local maxNum
    put item 1 of lst into maxNum
    repeat with n = 1 to the number of items of lst
        if item n of lst > maxNum then
            put item n of lst into maxNum
        end if
    end repeat
    return maxNum
end max2
on mouseUp
 answer max2("1,2,5,6,7,4,3,2")
end mouseUp

Works with: UCB Logo

If the template is, like SUM, the name of a procedure that is capable of accepting arbitrarily many inputs, it is more efficient to use APPLY instead of REDUCE. The latter is good for associative procedures that have been written to accept exactly two inputs:

to max :a :b
output ifelse :a > :b [:a] [:b]
end

print reduce "max [...]

Alternatively, REDUCE can be used to write MAX as a procedure that accepts any number of inputs, as SUM does:

to max [:inputs] 2
if emptyp :inputs ~
   [(throw "error [not enough inputs to max])]
output reduce [ifelse ?1 > ?2 [?1] [?2]] :inputs
end
==Logo==
Works with: UCB Logo
to bigger :a :b
  output ifelse [greater? :a :b] [:a] [:b]
end

to max :lst
  output reduce "bigger :lst
end

Logtalk

max([X| Xs], Max) :-
    max(Xs, X, Max).

max([], Max, Max).
max([X| Xs], Aux, Max) :-
    (   X @> Aux ->
        max(Xs, X, Max)
    ;   max(Xs, Aux, Max)
    ).

Lua

-- Table to store values
local values = {}
-- Read in the first number from stdin
local new_val = io.read"*n"
-- Append all numbers passed in
-- until there are no more numbers (io.read'*n' = nil) 
while new_val do
  values[#values+1] = new_val
  new_val = io.read"*n"
end

-- Print the max
print(math.max(unpack(values)))

M2000 Interpreter

Module TestThis {
      Print "Search a tuple type list (is an array also)"
      A=(,)
      For i=1 to Random(1,10)
      Append A, (Random(1,100),)
      Next
      Print Len(A)
      Print A
      Print A#max()
      
      Print "Search an array"
      B=lambda->Random(1,100)
      Rem Dim A(1 to Random(1,10))<<B()
      Dim A(1 to Random(1,10))<<lambda->{=Random(1,100)}()
      Print Len(A())
      Print A()
      Print A()#max()
      
      \\ #max() skip non numeric values
      Rem Print (1,"100",3)#max()=3
      
      Print "Search an inventory list"
      Inventory C
      for i=1 to Random(1,10)
            do
                  key=random(10000)
            until not exist(c, key)
            \\ we can put a number as string
            if random(1,2)=1 then Append c, key:=B() else Append c, key:=str$(B())
      Next
      
      \\ if inventory item is string with a number work fine
      Function MaxItem(a) {
            k=each(a,2)
            val=a(0!)
            while k
                  \\ using stack of values
                  \\ over -equal to over 1 - copy value from 1 to top, means double the top value
                  \\ number - pop top value
                  \\ drop -equal to drop 1 : drop top value 
                  Push a(k^!): Over : If Number>val then Read Val else drop
                  Rem If a(k^!)>Val Then Val=a(k^!)
            end while
            =val
      }
      Print Len(C)
      Print C
      Print MaxItem(C)
      
      Print "Search a stack object"
      \\ a stack object is the same as the stack of values
      \\ which always is present
      D=stack
      I=0
      J=Random(1,10)
      \\ Stack stackobjext {}
      \\ hide current stack and attach the D stack
      Stack D {
            Push B() : I++ : IF I>J Else Loop
      }
      \\ if stack item isn't numeric we get a run time error
      Function MaxItemStack(a) {
            Stack a {env$=envelope$()}
            if replace$("N","", env$)<>"" then error "only numbers allowed"
            k=each(a,2)
            val=Stackitem(a,1)
            while k
                  If Stackitem(k)>val then Val=stackitem(k)
            end while
            =val
      }
      Print Len(D)
      Print D
      Print MaxItemStack(D)     	
}
TestThis

Maple

This is a built-in, polymorphic procedure in Maple.

> max( { 1, 2,  Pi, exp(1) } ); # set
                                   Pi

> max( [ 1, 2,  Pi, exp(1) ] ); # list
                                   Pi

> max( 1, 2,  Pi, exp(1) ); # sequence
                                   Pi

> max( Array( [ 1, 2,  Pi, exp(1) ] ) ); # Array
                                   Pi

For numeric data in (multi-dimensional) rtables, a particularly flexible and powerful method for finding the maximum (and many other things) is the use of "rtable_scanblock". The maximum of an Array is a built-in rtable_scanblock operation and can be found as follows.

> A := Array([1,2,4/5,3,11]): rtable_scanblock( A, [rtable_dims(A)], Maximum ); 
                                   11

Mathematica / Wolfram Language

Input:

Max[1, 3, 3, 7]
Max[Pi,E+2/5,17 Cos[6]/5,Sqrt[91/10]]
Max[1,6,Infinity]
Max[]
Output:
 7
 17 Cos[6]/5
 Infinity
-Infinity

Note that Max returns minus infinity if supplied with no arguments; as it should:

Max[Max[],Max[a,b,c]]
Max[Max[a],Max[b,c]]
Max[Max[a,b],Max[c]]
Max[Max[a,b,c],Max[]]

should all give the same results, therefore max[] should give -Infinity. If it WOULD give 0 strange things can happen:

Max[Max[], Max[-4, -3]]

WOULD give 0 instead of -3

MATLAB

function [maxValue] = findmax(setOfValues)
   maxValue = max(setOfValues);

Maxima

u : makelist(random(1000), 50)$

/* Three solutions */
lreduce(max, u);

apply(max, u);

lmax(u);

MAXScript

MAXScript has a built-in function called amax(), which will return the maximum of an array or the values supplied to it. The following custom function will return the maximum of the array supplied to it, or 'undefined' if an empty array is supplied.

fn MaxValue AnArray = 
(
	if AnArray.count != 0 then
	(
		local maxVal = 0
		for i in AnArray do if i > maxVal then maxVal = i
		maxVal
	)
	else undefined
)

Metafont

The max macro (in the base set of macro for Metafont) accepts any number of arguments, and accepts both numerics (numbers), pairs (bidimensional vectors), and strings (not mixed).

show max(4,5,20,1);
show max((12,3), (10,10), (25,5));
show max("hello", "world", "Hello World");

min

Works with: min version 0.37.0
(() ('> 'pop 'nip if) map-reduce) ^max

(5 3 2 7 4) max puts!

MiniScript

There is a list.max function in the listUtil module, but if you're working in an environment without this module or just want to write it yourself, you might do it as follows.

list.max = function()
    if not self then return null
    result = self[0]
    for item in self
        if item > result then result = item
    end for
    return result
end function

print [47, 11, 42, 102, 13].max

МК-61/52

П0	С/П	x=0	07	ИП0	x<0	00	max	БП	00

or

П0	ИП0	С/П	-	x<0	01	Вx	П0	БП	01

Modula-3

Modula-3 provides a builtin MAX function, but it only works on two elements (or enumerations) but not arrays or sets.

We provide a generic Maximum implementation:

GENERIC INTERFACE Maximum(Elem);

EXCEPTION Empty;

PROCEDURE Max(READONLY a: ARRAY OF Elem.T): Elem.T RAISES {Empty};

END Maximum.
GENERIC MODULE Maximum(Elem);

PROCEDURE Max(READONLY arr: ARRAY OF Elem.T): Elem.T RAISES {Empty} =
  VAR max := FIRST(Elem.T);
  BEGIN
    IF NUMBER(arr) = 0 THEN
      RAISE Empty;
    END;
    FOR i := FIRST(arr) TO LAST(arr) DO
      IF arr[i] > max THEN
        max := arr[i];
      END;
    END;
    RETURN max;
  END Max;

BEGIN
END Maximum.

Elem can be instantiated to any type (any type that can be compared with the '>' function). For convenience Modula-3 provides interfaces/modules for the built in types, like Integer, Real, LongReal, etc, which contain type definitions as well as properties specific to the type.

To make a generic interface/module for a specific type, you must instantiate it:

INTERFACE RealMax = Maximum(Real) END RealMax.
MODULE RealMax = Maximum(Real) END RealMax.

Now we can import RealMax into our source and use the Max function:

MODULE Main;

IMPORT RealMax, IO, Fmt;

VAR realarr := ARRAY [1..5] OF REAL {1.1, 1.0, 0.0, 2.4, 3.3};

BEGIN
  IO.Put(Fmt.Real(RealMax.Max(realarr)) & "\n");
END Main.

MontiLang

MontiLang has a builtin statement MAX which finds the maximum of the top two items on the stack. By looping through an array and pushing to the stack, the largest item in an array can be found.

2 5 3 12 9 9 56 2 ARR

LEN VAR l .
0 VAR i .
FOR l
    GET i SWAP
    i 1 + VAR i .
ENDFOR .
STKLEN 1 - VAR st .
FOR st
    MAX
ENDFOR PRINT

Another way to do it.

2 5 3 12 9 9 56 2 ARR
print 
LEN VAR l .
0 VAR i .
0
FOR l
    swap
    GET i rot max
    i 1 + VAR i .
ENDFOR
|Greatest number in the list: | out . print
|Press ENTER to exit | input
clear

MUMPS

MV(A,U)
 ;A is a list of values separated by the string U
 NEW MAX,T,I
 FOR I=1:1 SET T=$PIECE(A,U,I) QUIT:T=""  S MAX=$SELECT(($DATA(MAX)=0):T,(MAX<T):T,(MAX>=T):MAX)
 QUIT MAX

Usage:

USER>SET V=","
 
USER>SET B="-1,-1000,1000,2.3E5,8A,""A"",F"
 
USER>W $$MV^ROSETTA(B,V)
2.3E5

Nanoquery

def max(list)
	if len(list) = 0
		return null
	end

	largest = list[0]
	for val in list
		if val > largest
			largest = val
		end
	end
	return largest
end

Neko

/**
 greatest element from a list (Neko Array)
 Tectonics:
   nekoc greatest-element.neko
   neko greatest-element
*/

var greatest = function(list) {
  var max, element;
  var pos = 1;

  if $asize(list) > 0  max = list[0];

  while pos < $asize(list) {
    element = list[pos];
    if max < element  max = element;
    pos += 1;
  }

  return max;
}

$print(greatest($array(5, 1, 3, 5)), "\n");
$print(greatest($array("abc", "123", "zyx", "def")), "\n");
Output:
prompt$ nekoc greatest-element.neko
prompt$ neko ./greatest-element.n
5
zyx

Nemerle

using System;
using Nemerle.Collections;
using System.Linq;
using System.Console;

module SeqMax
{
    SeqMax[T, U] (this seq : T) : U
      where T : Seq[U]
      where U : IComparable
    {
        $[s | s in seq].Fold(seq.First(), (x, y) => {if (x.CompareTo(y) > 0) x else y})
    }
    
    Main() : void
    {
        def numbers = [1, 12, 3, -5, 6, 23];
        def letters = ['s', 'p', 'a', 'm'];
        
        // using SeqMax() method (as task says to "create a function")
        WriteLine($"numbers.SeqMax() = $(numbers.SeqMax())");
        WriteLine($"letters.SeqMax() = $(letters.SeqMax())");
        
        // using the already available Max() method
        WriteLine($"numbers.Max() = $(numbers.Max())");
        WriteLine($"letters.Max() = $(letters.Max())")
    }
}
Output:
numbers.SeqMax() = 23
letters.SeqMax() = s
numbers.Max() = 23
letters.Max() = s

NetRexx

/* NetRexx */

options replace format comments java crossref savelog symbols binary

rn = Random()
maxElmts = 100
dlist = double[maxElmts]
rlist = Rexx[maxElmts]
loop r_ = 0 to maxElmts - 1
  nr = rn.nextGaussian * 100.0
  dlist[r_] = nr
  rlist[r_] = Rexx(nr)
  end r_

say 'Max double:' Rexx(getMax(dlist)).format(4, 9)
say 'Max   Rexx:' getMax(rlist).format(4, 9)

return

method getMax(dlist = double[]) public static binary returns double
  dmax = Double.MIN_VALUE
  loop n_ = 0 to dlist.length - 1
    if dlist[n_] > dmax then dmax = dlist[n_]
    end n_
  return dmax

method getMax(dlist = Rexx[]) public static binary returns Rexx
  dmax = Rexx(Double.MIN_VALUE)
  loop n_ = 0 to dlist.length - 1
    dmax = dlist[n_].max(dmax)
    end n_
  return dmax
Output:
Max double:  274.457568703
Max   Rexx:  274.457568703

NewLISP

(max 1 2 3 5 2 3 4)
(apply max '(1 2 3 5 2 3 4)) ; apply to list
; Added by Nehal-Singhal 2018-05-29

Nial

The behavior of multi-dimensional arrays is like J

max 1 2 3 4
=4

Nim

echo max([2,3,4,5,6,1])
Output:
6

Oberon-2

Works with: oo2c Version 2
MODULE GreatestElement1;
IMPORT
  ADT:ArrayList,
  Object:Boxed,
  Out;
  
VAR
  a: ArrayList.ArrayList(Boxed.LongInt);
  max: Boxed.LongInt;
  
  
  PROCEDURE Max(al: ArrayList.ArrayList(Boxed.LongInt)): Boxed.LongInt;
  VAR
    i: LONGINT;
    item, max: Boxed.LongInt;
  BEGIN
    max := NEW(Boxed.LongInt,MIN(LONGINT));
    
    i := 0;
    WHILE (i < al.size) DO
      item := al.Get(i);
      IF item.value > max.value THEN max := item END;
      INC(i)  
    END;
    RETURN max
  END Max;
  
BEGIN
  a := NEW(ArrayList.ArrayList(Boxed.LongInt),5);
  a.Append(NEW(Boxed.LongInt,10));
  a.Append(NEW(Boxed.LongInt,32));
  a.Append(NEW(Boxed.LongInt,4));
  a.Append(NEW(Boxed.LongInt,43));
  a.Append(NEW(Boxed.LongInt,9));
  
  max := Max(a);
  Out.String("Max: ");Out.LongInt(max.value,4);Out.Ln
END GreatestElement1.

Simple version

MODULE GreatestElement2;
IMPORT
  Out;
VAR
  a: ARRAY 10 OF LONGINT;
  
  PROCEDURE Max(a: ARRAY OF LONGINT): LONGINT;
  VAR
    i, max: LONGINT;
  BEGIN
    max := MIN(LONGINT);
    FOR i := 0 TO LEN(a) - 1 DO
      IF a[i] > max THEN max := a[i] END;
    END;
    
    RETURN max
  END Max;
BEGIN
  a[0] := 10;
  a[1] := 32;
  a[2] := 4;
  a[3] := 43;
  a[4] := 9;
  
  Out.String("Max: ");Out.LongInt(Max(a),4);Out.Ln
END GreatestElement2.
Output:
(in both programs)
Max:   43

Objeck

The language has a "Max" method for vectors.

values := IntVector->New([4, 1, 42, 5]);
values->Max()->PrintLine();

Objective-C

Works with: GNUstep
Works with: Cocoa

This code "extends" (through Objective-C categories) the NSArray adding the method maximumValue; this one iterates over the objects of the collection calling the method compare, if it exists for the object of the collection. Since normally comparing makes sense between numbers, the code also check if the objects being compared are of "kind" NSNumber. If one eliminates this check (substituting it maybe with one that checks if the two object are of the same "kind"), the code is able to get a maximum value for any objects for which make sense a compare method (e.g. strings), that must be implemented.

If there's no a known way of comparing two objects of the collection (or if the objects are not "NSNumber"), the the method return nil (the void object).


#import <Foundation/Foundation.h>

@interface NSArray (WithMaximum)
- (id)maximumValue;
@end

@implementation NSArray (WithMaximum)
- (id)maximumValue
{
  if ( [self count] == 0 ) return nil;
  id maybeMax = self[0];
  for ( id el in self ) {
    if ( [maybeMax respondsToSelector: @selector(compare:)] &&
	 [el respondsToSelector: @selector(compare:)]       &&
	 [el isKindOfClass: [NSNumber class]]               &&
	 [maybeMax isKindOfClass: [NSNumber class]] ) {
      if ( [maybeMax compare: el] == NSOrderedAscending )
	maybeMax = el;
    } else { return nil; }
  }
  return maybeMax;
}
@end

This example mixes integers with a double value, just to show that everything is fine until they are NSNumber.

int main()
{
  @autoreleasepool {
    NSArray *collection = @[@1, @2, @10, @5, @10.5];
  
    NSLog(@"%@", [collection maximumValue]);
  }
  return 0;
}

OCaml

let my_max = function
    [] -> invalid_arg "empty list"
  | x::xs -> List.fold_left max x xs
# my_max [4;3;5;9;2;3] ;;
- : int = 9

Octave

Octave's max accepts a vector (and can return also the index of the maximum value in the vector)

m = max( [1,2,3,20,10,9,8] );       % m = 20
[m, im] = max( [1,2,3,20,10,9,8] ); % im = 4

Oforth

[1, 2.3, 5.6, 1, 3, 4 ] reduce(#max)

Ol

Basics:

; builtin function
(max 1 2 3 4 5) ; 5

(define x '(1 2 3 4 5))

; using to numbers list
(apply max x) ; 5

; using list reducing
(fold max (car x) x) ; 5

; manual lambda-comparator
(print (fold (lambda (a b)
   (if (less? a b) b a))
   (car x) x)) ; 5

ooRexx

version

-- routine that will work with any ordered collection or sets and bags containing numbers.
::routine listMax
  use arg list 
  items list~makearray   -- since we're dealing with different collection types, reduce to an array
  if items~isEmpty then return .nil   -- return a failure indicator.  could also raise an error, if desired
  largest = items[1]

 
  -- note, this method does call max one extra time.  This could also use the 
  -- do i = 2 to items~size to avoid this
  do item over items 
     largest = max(item, largest) 
  end  

  return largest

version 2 works with any strings

/* REXX ***************************************************************
* 30.07.2013 Walter Pachl as for REXX
**********************************************************************/
s=.list~of('Walter','lives','in','Vienna')
say listMax(s)
-- routine that will work with any ordered collection or sets and bags.
::routine listMax
  use arg list
  items=list~makearray   -- since we're dealing with different collection types, reduce to an array
  if items~isEmpty then return .nil   -- return a failure indicator.  could also raise an error, if desired
  largest = items[1]
  -- note, this method uses one extra comparison.  It could use
  -- do i = 2 to items~size to avoid this
  do item over items
     If item>>largest Then
       largest = item
  end
  return largest

OxygenBasic

'Works on any list with element types which support '>' comparisons

macro max any(R,  A, N,   i)
============================
  scope
    indexbase 1
    int i
    R=A(1)
    for i=2 to N
      if A(i)>R
        R=A(i)
      endif
    next
  end scope
end macro

'DEMO
=====
redim double d(100)
d={ 1.1, 1.2, 5.5, -0.1, -12.0 }
double m=max(d,5)
print "greatest element of d(): " m '5.5

Oz

declare
  fun {Maximum X|Xr}         %% pattern-match on argument to make sure the list is not empty
     {FoldL Xr Value.max X}  %% fold the binary function Value.max over the list
  end
in
  {Show {Maximum [1 2 3 4 3]}}

PARI/GP

vecmax(v)

Pascal

See Delphi

Works with: Free Pascal

or try this, for it shows the according position

program GElemLIst;
{$IFNDEF FPC}
  {$Apptype Console}
{$else}
  {$Mode Delphi}
{$ENDIF}

uses
  sysutils;
const
  MaxCnt = 1000000;
type
   tMaxIntPos= record
                  mpMax,
                  mpPos : integer;
                end;
   tMaxfltPos= record
                  mpMax : double;
                  mpPos : integer;
                end;


function FindMaxInt(const ia: array of integer):tMaxIntPos;
//delivers the highest Element and position of integer array
var
  i  : NativeInt;
  tmp,max,ps: integer;
Begin
  max := -MaxInt-1;
  ps := -1;
  //i = index of last Element
  i := length(ia)-1;
  IF i>=0 then Begin
    max := ia[i];
    ps := i;
    dec(i);
    while i> 0 do begin
      tmp := ia[i];
      IF max< tmp then begin
        max := tmp;
        ps := i;
        end;
      dec(i);
      end;
    end;
  result.mpMax := Max;
  result.mpPos := ps;
end;

function FindMaxflt(const ia: array of double):tMaxfltPos;
//delivers the highest Element and position of double array
var
  i,
  ps: NativeInt;
  max : double;
  tmp : ^double;//for 32-bit version runs faster

Begin
  max := -MaxInt-1;
  ps := -1;
  //i = index of last Element
  i := length(ia)-1;
  IF i>=0 then Begin
    max := ia[i];
    ps := i;
    dec(i);
    tmp := @ia[i];
    while i> 0 do begin
      IF tmp^>max  then begin
        max := tmp^;
        ps := i;
        end;
      dec(i);
      dec(tmp);
      end;
    end;
  result.mpMax := Max;
  result.mpPos := ps;
end;

var
  IntArr : array of integer;
  fltArr : array of double;
  ErgInt : tMaxINtPos;
  ErgFlt : tMaxfltPos;
  i: NativeInt;
begin
  randomize;
  setlength(fltArr,MaxCnt); //filled with 0
  setlength(IntArr,MaxCnt); //filled with 0.0
  For i := High(fltArr) downto 0 do
    fltArr[i] := MaxCnt*random();
  For i := High(IntArr) downto 0 do
    IntArr[i] := round(fltArr[i]);

  ErgInt := FindMaxInt(IntArr);
  writeln('FindMaxInt ',ErgInt.mpMax,' @ ',ErgInt.mpPos);

  Ergflt := FindMaxflt(fltArr);
  writeln('FindMaxFlt ',Ergflt.mpMax:0:4,' @ ',Ergflt.mpPos);
end.

Out, because of the searchdirection Position of FindMaxFlt is below FindMaxInt

FindMaxInt 999999 @ 691620
FindMaxFlt 999999.0265 @ 14824

Perl

sub max {
    my $max = shift;
    for (@_) { $max = $_ if $_ > $max }
    return $max;
}

It is already implemented in the module List::Util's max() function:

use List::Util qw(max);

max(@values);

Phix

with javascript_semantics
?max({1,1234,62,234,12,34,6})
?max({"ant", "antelope", "dog", "cat", "cow", "wolf", "wolverine", "aardvark"})
Output:
1234
"wolverine"

Phixmonti

"1" "1234" "62" "234" "12" "34" "6" stklen tolist
dup "Alphabetic order: " print max print nl

len for
    var i
    i get tonum i set
endfor
"Numeric order: " print max print

With syntactic sugar

include ..\Utilitys.pmt

( "1" "1234" "62" "234" "12" "34" "6" )

dup "Alphabetic order: " print max print nl

def f
    tonum
enddef

getid f map

dup "Numeric order: " print max print

PHP

The built-in PHP function max() already does this.

max($values)

PicoLisp

: (max 2 4 1 3)               # Return the maximal argument
-> 4
: (apply max (2 4 1 3))       # Apply to a list
-> 4
: (maxi abs (2 -4 -1 3))      # Maximum according to given function
-> -4

PL/I

maximum = A(lbound(A,1));
do i = lbound(A,1)+1 to hbound(A,1);
  if maximum < A(i) then maximum = A(i);
end;

PostScript

Ghostscript has a max built-in:

Works with: Ghostscript
/findmax {
  dup 0 get exch    % put the first element underneath the array
  {max} forall      % replace it by the respective larger value if necessary
} def

If not using Ghostscript this gets a bit longer:

/findmax {
  dup 0 get exch    % put the first element underneath the array
  {
    dup             % duplicate the current item
    2 index         % duplicate the current maximum value
    gt              % if the current item is larger
    {exch} if       % swap the two items so the previous maximum is now the top of the stack
    pop             % remove it
  } forall
} def
Library: initlib
[1 2 3 4 5 4 3 2 1] uncons exch {max} fold

PowerBASIC

FUNCTION PBMAIN()
    DIM x AS LONG, y AS LONG, z AS LONG
    RANDOMIZE TIMER

    FOR x = 1 TO 10
        y = INT(RND * 10000)
        z = MAX(y, z)
    NEXT

    ? STR$(z) & " was the highest value"
END FUNCTION
Output:
 8104 was the highest value

PowerShell

The Measure-Object cmdlet in PowerShell already has this capability:

function Get-Maximum ($a) {
    return ($a | Measure-Object -Maximum).Maximum
}

Prolog

SWI-Prolog already knows max_list.

 ?- max_list([1, 2, 10, 3, 0, 7, 9, 5], M).
M = 10.

can be implemented like this:

max_list(L, V) :-
	select(V, L, R), \+((member(X, R), X > V)).

PureBasic

Procedure.f Max (Array a.f(1))
   Protected last, i, ret.f

   ret = a(0)   
   last = ArraySize(a())
   For i = 1 To last
      If ret < a(i)
         ret = a(i)
      EndIf
   Next
   
   ProcedureReturn ret
EndProcedure

PureBasic: another solution

Procedure.f maxelement(List tl.f())
  ForEach tl() : mx.f=mx*Bool(mx>=tl())+tl()*Bool(mx<tl()) : Next
  ProcedureReturn mx
EndProcedure

NewList testlist.f() : OpenConsole()
For i=0 To 99 : AddElement(testlist()) : testlist()=Sqr(Random(1000)) : Next
Print("Greatest element = "+StrF(maxelement(testlist()),8)) : Input()
Output:
Greatest element = 31.59113884

Python

Numeric values

The built-in Python function max() already does this.

max(values)

Of course this assumes we have a list or tuple (or other sequence like object). (One can even find the max() or min() character of a string since that's treated as a sequence of characters and there are "less than" and "greater than" operations (object methods) associate with those characters).

If we truly were receiving a stream of data then in Python, such streams are usually iterable, meaning they have a way of generating one item at a time from the stream.

max(), (and min()), can take iterables and a key argument which takes a function that can transform each item into a type that we can compare, for example, if the stream were returning string representations of integers, one to a line, you could do

>>> floatstrings = ['1\n', ' 2.3\n', '4.5e-1\n', '0.01e4\n', '-1.2']
>>> max(floatstrings, key = float)
'0.01e4\n'
>>>

Normally we would want the converted form as the maximum and we could just as easily write:

>>> max(float(x) for x in floatstrings)
100.0
>>>

Or you can write your own functional version, of the maximum function, using reduce and lambda

>>> mylist = [47, 11, 42, 102, 13]
>>> reduce(lambda a,b: a if (a > b) else b, mylist)
102

And if you are being lazy but still want to meet this task's requirements :

max(list(map(int,input("").split(","))))

Non-numeric values

'''Non-numeric maxima'''

print(
    f'max a-z: "{max(["epsilon", "zeta", "eta", "theta"])}"'
)
print(
    f'max length: "{max(["epsilon", "zeta", "eta", "theta"], key=len)}"'
)
print(
    'max property k by a-z: ' + str(max([
        {"k": "epsilon", "v": 2},
        {"k": "zeta", "v": 4},
        {"k": "eta", "v": 32},
        {"k": "theta", "v": 16}], key=lambda x: x["k"]))
)
print(
    'max property k by length: ' + str(max([
        {"k": "epsilon", "v": 2},
        {"k": "zeta", "v": 4},
        {"k": "eta", "v": 32},
        {"k": "theta", "v": 16}], key=lambda x: len(x["k"])))
)
print(
    'max property v: ' + str(max([
        {"k": "epsilon", "v": 2},
        {"k": "zeta", "v": 4},
        {"k": "eta", "v": 32},
        {"k": "theta", "v": 16}], key=lambda x: x["v"]))
)
Output:
max a-z: "zeta"
max length: "epsilon"
max property k by a-z: {'k': 'zeta', 'v': 4}
max property k by length: {'k': 'epsilon', 'v': 2}
max property v: {'k': 'eta', 'v': 32}

Q

q)l:2 9 3 8 4 7
q)max l
9

Quackery

[ behead swap witheach max ] is [max] ( [ --> n )

R

v <- c(1, 2, 100, 50, 0)
print(max(v)) # 100

Racket

The "max" function it built in and takes an arbitrary amount of arguments.

(max 12 9 8 17 1)
Output:
17

To use with a list, there is apply:

(apply max '(12 9 8 17 1))

However, if you want to write the function yourself:

(define (my-max l)
  (define (max-h l greatest)
    (cond [(empty? l) greatest]
          [(> (first l) greatest) (max-h (rest l) (first l))]
          [else (max-h (rest l) greatest)]))
  (if (empty? l) empty (max-h l (first l))))

or with a "for" loop:

(define (my-max l)
  (for/fold ([max #f]) ([x l])
    (if (and max (> max x)) max x)))

Raku

(formerly Perl 6) The built-in function works with any type that defines ordering.

say max 10, 4, 5, -2, 11;
say max <zero one two three four five six seven eight nine>;

# Even when the values and number of values aren't known until runtime
my @list = flat(0..9,'A'..'H').roll((^60).pick).rotor(4,:partial)».join.words;
say @list, ': ', max @list;
Sample output:
11
zero
[6808 013C 6D5B 4219 29G9 DC13 CA4F 55F3 AA06 0AGF DAB0 2]: DC13

RapidQ

functioni FindMax(...) as double
    dim x as integer
        
    for x = 1 to ParamValCount
        IF ParamVal(x) > Result THEN Result = ParamVal(x)
    next
End functioni

Print FindMax(50, 20, 65, 20, 105)

Rascal

Rascal has a built-in function that gives the greatest element of a list

rascal>import List;
ok

rascal>max([1,2,3,4]);
int: 4

Raven

[ 1 2 3 4 ] max "%d\n" print
Output:
4

Randomly generated list size and elements

100 choose as $cnt
[ ]  as $lst
0 $cnt 1 range each drop 100 choose $lst push
$lst print
$lst max "max value: %d\n" print

REBOL

REBOL [
    Title: "Maximum Value"
    URL: http://rosettacode.org/wiki/Maximum_Value
]

max: func [
	"Find maximum value in a list."
	values [series!] "List of values."
] [
	first maximum-of values 
]

print ["Max of"  mold d: [5 4 3 2 1]  "is"  max d]
print ["Max of"  mold d: [-5 -4 -3 -2 -1]  "is"  max d]
Output:
Max of [5 4 3 2 1] is 5
Max of [-5 -4 -3 -2 -1] is -1

Red

Red []
list: [1 2 3 5 4]
print  last sort list

REXX

The numbers in the list may be any valid REXX number   (integer, negative, floating point, etc.)

using a list

/*REXX program finds the  greatest element  in a list (of the first 25 reversed primes).*/
$ = reverse(2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97)
say 'list of numbers = '  $                      /*show the original list of numbers.   */
big=word($, 1)                                   /*choose an initial biggest number.    */
# = words($);        do j=2  to #                /*traipse through the list,  find max. */
                     big=max(big, word($, j) )   /*use the  MAX  BIF to find the biggie.*/
                     end   /*j*/
say                                              /*stick a fork in it,  we're all done. */
say 'the biggest value in a list of '     #      " numbers is: "     big
output   when using the default (internal) input:
list of numbers =  79 98 38 97 37 17 76 16 95 35 74 34 14 73 13 92 32 91 71 31 11 7 5 3 2

the biggest value in a list of  25  numbers is:  98

using an array

/*REXX program finds the  greatest element  in a list (of the first 25 reversed primes).*/
@.=;       @.1 = 2;    @.2 = 3;    @.3 = 5;    @.4 = 7;    @.5 =11;    @.6 =31;    @.7 =71
           @.8 =91;    @.9 =32;    @.10=92;    @.11=13;    @.12=73;    @.13=14;    @.14=34
           @.15=74;    @.16=35;    @.17=95;    @.18=16;    @.19=76;    @.20=17;    @.21=37
           @.22=97;    @.23=38;    @.24=98;    @.25=79
big=@.1                                          /*choose an initial biggest number.    */
                do #=2  while @.#\==''           /*traipse through whole array of nums. */
                big = max(big, @.#)              /*use a BIF to find the biggest number.*/
                end   /*#*/ 
                                                 /*stick a fork in it,  we're all done. */
say 'the biggest value in an array of '      #-1       " elements is: "           big
output   when using the default (internal) input:
the biggest value in an array of  25  elements is:  98

using a list from the terminal

/*REXX program finds the  greatest element  in a list of numbers entered at the terminal*/
say '──────────────────  Please enter a list of numbers  (separated by blanks or commas):'
parse pull $;           #=words($)               /*get a list of numbers from terminal. */
$=translate($, , ',')                            /*change all commas  (,)  to  blanks.  */
big=word($,1);          do j=2  to #             /*traipse through the list of numbers. */
                        big=max(big, word($,j))  /*use a BIF for finding the max number.*/
                        end   /*j*/
say                                              /*stick a fork in it,  we're all done. */
say '────────────────── The biggest value in the list of '    #    " elements is: "    big

Programming note:   the   max   BIF normalizes the number returned (eliding the leading superfluous zeroes).

If this is undesirable, then the   do   loop (shown above) can be replaced with:

···;                    do j=2  to #;  _=word($,j)
                        if _>big  then big=_
                        end   /*j*/
output   when using the input from the terminal via a user prompt:
──────────────────  Please enter a list of numbers  (separated by blanks or commas):
-12  -3  0  1.1  1e2  99.2  00245                   ◄■■■■■■■■■■ user input 

────────────────── The biggest value in the list of  7  elements is:  245

list of any strings

/* REXX ***************************************************************
* If the list contains any character strings, the following will work
* Note the use of >> (instead of >) to avoid numeric comparison
* Note that max() overrides the builtin function MAX
* 30.07.2013 Walter Pachl
**********************************************************************/
list='Walter Pachl living in Vienna'
Say max(list)
list='8 33 -12'
Say max(list)
Exit
max: Procedure
Parse Arg l
max=word(l,1)
Do i=2 To words(l)
  If word(l,i)>>max Then
    max=word(l,i)
  End
Return max
output   when using an   ASCII   system:
living
8    
output   when using an   EBCDIC   system:
Walter
8    

output when using a list which is:   12 111111 1 (lexigraphically 12 is greater than 111111)

12

Ring

aList = [1,2,4,5,10,6,7,8,9]
see max(aList)
Output:
10

RPL

Works with: HP version 48
{ 2 718 28 18 28 46 } ≪ MAX ≫ STREAM
Output:
1: 718

Ruby

max is a method of all Enumerables

values.max

Run BASIC

list$= "1 12 -55 46 41 3.66 19"
while word$(list$,i+1," ") <> ""
  mx = max(mx,val(word$(list$,i+1," ")))
  i = i + 1
wend
print mx

Rust

This is built in functionality for everything that can be iterated over. It returns an Option<T>, meaning Some(e) if there are elements in the iterator and None if it is empty.

fn main() {
    let nums = [1,2,39,34,20];
    println!("{:?}", nums.iter().max());
    println!("{}", nums.iter().max().unwrap());
}
Output:
Some(39)
39

S-lang

Starting w/an array, this is trivial:

variable a = [5, -2, 0, 4, 666, 7];
print(max(a));

output: 666

If a is a list instead of an array, then:

a = {5, -2, 0, 4, 666, 7};
print(max(list_to_array(a)));

Scala

Library: Scala
def noSweat(list: Int*) = list.max
// Test
assert(noSweat(1, 3, 12, 7) == 12)

Scheme

The built-in Scheme function max takes the max of all its arguments.

(max 1 2 3 4)
(apply max values) ; find max of a list

Seed7

$ include "seed7_05.s7i";

const func integer: max (in array integer: values) is func
  result
    var integer: max is 0;
  local
    var integer: index is 0;
  begin
    max := values[1];
    for index range 2 to length(values) do
      if values[index] > max then
        max := values[index];
      end if;
    end for;
  end func;

const proc: main is func
  begin
    writeln(max([] (1, 2, 6, 4, 3)));
  end func;
Output:
6

Self

Using reduceWith: it is very simple to find the maximum value among a collection.

(1 & 2 & 3 & 4 & 20 & 10 & 9 & 8) asVector reduceWith: [:a :b | a max: b] "returns 20"

Or, since it's "built-in", you can simply do:

(1 & 2 & 3 & 4 & 20 & 10 & 9 & 8) asVector max. "returns 20"

SenseTalk

put the max of (1, 5, 666, -1000, 3)
put the highest value of [88,-2,6,55,103,0]

Output:

666
103

Sidef

max method returns the greatest element in a list. It works only if the array's elements have the same type (e.g.: strings, numbers).

values.max;

Slate

#(1 2 3 4 20 10 9 8) reduce: [| :a :b | a max: b]

Smalltalk

Using fold it is very simple to find the maximum value among a collection.

#(1 2 3 4 20 10 9 8) fold: [:a :b | a max: b] "returns 20"

Or, since it's "built-in", you can simply do:

Works with: Pharo version 1.4
Works with: Smalltalk/X
#(1 2 3 4 20 10 9 8) max. "returns 20"

using #inject:into:

| list |
list := #(1 2 3 4 20 10 9 8).
list inject: (list at: 1) into: [ :number :each |
  number max: each ]

SNOBOL4

while   a = trim(input)     :f(stop)
        max = gt(a,max) a   :(while)
stop    output = max
end

Standard ML

Comparisons are specific for each type. Here is a max function for a list of ints:

fun max_of_ints [] = raise Empty
  | max_of_ints (x::xs) = foldl Int.max x xs
- max_of_ints [4,3,5,9,2,3];
val it = 9 : int

Stata

Use the summarize command to compute the maximum value of a variable:

qui sum x
di r(max)

Mata has also several functions to compute minimum or maximum of a vactor or matrix:

a = 1,5,3,4,2,7,9,8
max(a)

Swift

Works with: Swift version 2.x
if let x = [4,3,5,9,2,3].maxElement() {
  print(x) // prints 9
}
Works with: Swift version 1.x
let x = maxElement([4,3,5,9,2,3])
println(x) // prints 9

Tailspin

Simplest is to use the built-in collector

[1, 5, 20, 3, 9, 7] ... -> ..=Max&{by: :(), select: :()} -> !OUT::write
// outputs 20

// This is how the Max-collector is implemented in the standard library:
processor Max&{by:, select:}
  @:[];
  sink accumulate
    <?($@Max <=[]>)
      | ?($(by) <$@Max(1)..>)>  @Max: [$(by), $(select)];
  end accumulate
  source result
    $@Max(2) !
  end result
end Max

But here is how to find the max more manually/programmatically, it is pretty easy as well

templates max
  @: $(1);
  $(2..last)... -> #
  $@!
  when <$@..> do @: $;
end max

[1, 5, 20, 3, 9, 7] -> max -> !OUT::write
// outputs 20

Can also be written as an inline templates

[1, 5, 20, 3, 9, 7] -> \(@: $(1); $(2..last)... -> # $@ ! when <$@..> do @: $;\) -> !OUT::write
// outputs 20

Or we can do just the matching in an inline templates referencing the outer state

templates max
  @: $(1);
  $(2..last)... -> \(<$@max..> @max: $;\) -> !VOID
  $@!
end max

[1, 5, 20, 3, 9, 7] -> max -> !OUT::write
// outputs 20

Tcl

Works with: Tcl version 8.5

Use the {*} expansion operator to substitute the list value with its constituent elements

package require Tcl 8.5

set values {4 3 2 7 8 9}
::tcl::mathfunc::max {*}$values ;# ==> 9

TI-83 BASIC

The builtin max function can be applied to lists. max({1, 3, 2.

TI-89 BASIC

The builtin max function can be applied to lists. max({1, 3, 2}) = 3.

Transd

#lang transd

MainModule: {
    _start: (λ 
        (textout (max 9 6 2 11 3 4) " ")
        (with v [1, 45, 7, 274, -2, 34]
            (textout (max-element v) " ") 
            (textout (max-element-idx v))
    ))
}
Output:
11 274 3

Trith

[1 -2 3.1415 0 42 7] [max] foldl1

TUSCRIPT

$$ MODE TUSCRIPT
LOOP n,list="2'4'0'3'1'2'-12"
IF (n==1)          greatest=VALUE(list)
IF (list>greatest) greatest=VALUE(list)
ENDLOOP
PRINT greatest
Output:
4

uBasic/4tH

Since uBasic/4tH has a stack, it's only logical to use it.

Push 13, 0, -6, 2, 37, -10, 12         ' Push values on the stack
Print "Maximum value = " ; FUNC(_FNmax(7))
End                                    ' We pushed seven values

_FNmax Param(1)
  Local(3)

  d@ = -(2^31)                         ' Set maximum to a tiny value

  For b@ = 1 To a@                     ' Get all values from the stack
    c@ = Pop()
    If c@ > d@ THEN d@ = c@            ' Change maximum if required
  Next
Return (d@)                            ' Return the maximum

UNIX Shell

Works with: bash version 3
Works with: pdksh
max() {
  local m=$1
  shift
  while [ $# -gt 0 ]
  do
    [ "$m" -lt "$1" ] && m=$1
    shift
  done
  echo "$m"
} 

max 10 9 11 57 1 12
Works with: Bourne Shell
max() {
  m=$1  # Bourne Shell has no local command.
  shift
  while [ $# -gt 0 ]
  do
    [ "$m" -lt "$1" ] && m=$1
    shift
  done
  echo "$m"
}

Ursa

The max function:

def max (int<> list)
	decl int max i
	set max list<0>
	
	for (set i 1) (< i (- (size list) 1)) (inc i)
		if (> list<i> max)
			set max list<i>
		end if
	end for
	
	return max
end max

In use: (assuming the function is in the file max.u)

cygnus/x ursa v0.75 (default, release 0)
[Oracle Corporation JVM 1.8.0_51 on Mac OS X 10.10.5 x86_64]
> import "max.u"
> decl int<> list
> append 5 1 7 3 9 2 list
> out (max list) endl console
9
> _

Ursala

The built-in $^ operator takes a binary predicate of any type to a function extracting the maximum value from a non-empty list of that type. In this case it is used with fleq, the partial order relation on floating point numbers.

#import flo

#cast %e

example = fleq$^ <-1.,-2.,0.,5.,4.,6.,1.,-5.>
Output:
6.000000e+00

V

Assuming it is a list of positive numbers

[4 3 2 7 8 9] 0 [max] fold
=9

If it is not

[4 3 2 7 8 9] dup first [max] fold
=9

VBA

Option Explicit

Sub Main()
Dim a
   a = Array(1, 15, 19, 25, 13, 0, -125, 9)
   Debug.Print Max_VBA(a)
End Sub

Function Max_VBA(Arr As Variant) As Long
Dim i As Long, temp As Long
   temp = Arr(LBound(Arr))
   For i = LBound(Arr) + 1 To UBound(Arr)
      If Arr(i) > temp Then temp = Arr(i)
   Next i
   Max_VBA = temp
End Function
Output:
25

VBScript

Function greatest_element(arr)
	tmp_num = 0
	For i = 0 To UBound(arr)
		If i = 0 Then
			tmp_num = arr(i)
		ElseIf arr(i) > tmp_num Then
			tmp_num = arr(i)
		End If
	Next
	greatest_element = tmp_num
End Function

WScript.Echo greatest_element(Array(1,2,3,44,5,6,8))
Output:
44

Vim Script

for numbers (not floats):

max([1, 3, 2])

result: 3

for strings (with configurable ignore-case):

function! Max(list, ...)
    " {list}    list of strings
    " {a:1}     'i': ignore case, 'I': match case, otherwise use 'ignorecase' option
    if empty(a:list)
        return 0
    endif
    let gt_op = a:0>=1 ? get({'i': '>?', 'I': '>#'}, a:1, '>') : '>'
    let cmp_expr = printf('a:list[idx] %s maxval', gt_op)
    let maxval = a:list[0]
    let len = len(a:list)
    let idx = 1
    while idx < len
        if eval(cmp_expr)
            let maxval = a:list[idx]
        endif
        let idx += 1
    endwhile
    return maxval
endfunction

Visual Basic

Public Function ListMax(anArray())
    'return the greatest element in array anArray
    'use LBound and UBound to find its length
    n0 = LBound(anArray)
    n = UBound(anArray)
    theMax = anArray(n0)
    For i = (n0 + 1) To n
        If anArray(i) > theMax Then theMax = anArray(i)
    Next
    ListMax = theMax
End Function


Public Sub ListMaxTest()
    Dim b()
    'test function ListMax
    'fill array b with some numbers:
    b = Array(5992424433449#, 4534344439984#, 551344678, 99800000#)
    'print the greatest element
    Debug.Print "Greatest element is"; ListMax(b())
End Sub

Result:

ListMaxTest
Greatest element is 5992424433449

V (Vlang)

fn max<T>(list []T) T {
    mut max := list[0]
    for i in 1..list.len {
        if list[i] > max {
            max = list[i]
        }
    }
    return max
}
fn main() {
    println('int max: ${max<int>([5,6,4,2,8,3,0,2])}')
    println('float max: ${max<f64>([1e4, 1e5, 1e2, 1e9])}')
}
Output:
int max: 8
float max: 1e9

Wart

Wart defines max in terms of the more general best.

def (best f seq)
  if seq
    ret winner car.seq
      each elem cdr.seq
        if (f elem winner)
          winner <- elem

def (max ... args)
  (best (>) args)

(>) is > while suppressing infix expansion.

WDTE

let s => import 'stream';
let a => import 'arrays';

let max list =>
  a.stream list
  -> s.extent 1 >
  -> at 0
  ;

extent is a standard library function that returns a sorted list of the elements of a stream that fit the given function best, so > results in the maximum element.

Wortel

The @maxl returns the maximum value of a list:

@maxl [1 6 4 6 4 8 6 3] ; returns 8

Wren

var max = Fn.new { |a| a.reduce { |m, x| (x > m) ? x : m } }

var a = [42, 7, -5, 11.7, 58, 22.31, 59, -18]
System.print(max.call(a))
Output:
59

XPL0

The set of values is the lengths of the lines of text in the input file.

include c:\cxpl\codes;                  \include 'code' declarations

def  Tab=$09, LF=$0A, CR=$0D, EOF=$1A;

int  CpuReg, Hand;
char CmdTail($80);
int  I, Max, C;

[\Copy file name on command line, which is in the Program Segment Prefix (PSP)
\ ES=CpuReg(11), to the CmdTail array, which is in our Data Segment = CpuReg(12)
CpuReg:= GetReg;                        \point to copy of CPU registers
Blit(CpuReg(11), $81, CpuReg(12), CmdTail, $7F);
Hand:= FOpen(CmdTail, 0);               \open file for input and get its handle
FSet(Hand, ^I);                         \assign handle to device 3
OpenI(3);                               \initialize file for input

Max:= 0;                                \scan file for longest line
repeat  I:= 0;
        repeat  C:= ChIn(3);
                case C of
                  CR, LF, EOF:  [];     \don't count these characters
                  Tab:  [I:= I+8 & ~7]  \(every 8th column)
                other   I:= I+1;        \count all other characters
        until   C=LF or C=EOF;
        if I > Max then Max:= I;
until   C = EOF;
Text(0, "Longest line = ");  IntOut(0, Max);  CrLf(0);
]

Example of running the program on its source code:

maxline maxline.xpl
Longest line = 80

XSLT

The desired value is the first in a sequence that has been sorted numerically in descending order.

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
	<xsl:output method="text"/>

	<xsl:template match="/">
		<xsl:for-each select="/*/*">
			<!-- without data-type="number", items are sorted alphabetically -->
			<xsl:sort data-type="number" order="descending"/>
			<xsl:if test="position() = 1">
				<xsl:value-of select="."/>
			</xsl:if>
		</xsl:for-each>
	</xsl:template>
</xsl:stylesheet>

Sample input:

<numbers>
	<number>3</number>
	<number>1</number>
	<number>12</number>
	<number>7</number>
</numbers>
Output:
 12

Yabasic

l$ = "1,1234,62,234,12,34,6"

dim n$(1)

n = token(l$, n$(), ", ")

for i = 1 to n
	t$ = n$(i)
	if t$ > m$ then m$ = t$ end if            // or: if t$ > m$ m$ = t$
	if val(t$) > m then m = val(t$) end if	  // or: if val(t$) > m m = val(t$)
next

print "Alphabetic order: ", m$, ", numeric order: ", m

Yacas

Input:

Max({1, 3, 3, 7})
Max({Pi,Exp(1)+2/5,17*Cos(6)/5,Sqrt(91/10)})
Max({1,6,Infinity})
Max({})
Output:
 7
(17*Cos(2*Pi-6))/5
Infinity
Undefined

Yorick

The built-in function max does this. Interactive example:

> foo = [4, 3, 2, 7, 8, 9]
> max(foo)
9

Zig

Works with: 0.10.x, 0.11.x, 0.12.0-dev.1389+42d4d07ef

/// Asserts that `input` is not empty (len >= 1).
pub fn max(comptime T: type, input: []const T) T {
    var max_elem: T = input[0];
    for (input[1..]) |elem| {
        max_elem = @max(max_elem, elem);
    }
    return max_elem;
}

zkl

(1).max(1,2,3)     //-->3
(66).max(1,2,3.14) //-->66

If given a list, the max of the list is returned. The number/object just selects the method to call. Notice the difference between Int.max and Float.max.

(66).max(T(1,2,3)) //-->3
(66).max(T(1,2,3.14)) //-->3
(6.6).max(T(1,2,3.14)) //-->3.14

For other object types, you could use:

fcn max{ vm.arglist.reduce(fcn(p,n){ if(p < n) n else p }) }
max(2,1,-40,50,2,4,2) //-->50
max(2) //-->2
max("foo","bar") //-->"foo"
max("3",4,"5") //-->"5" only if strings contain only digits

Zoea

program: max 
  case: 1
        input: [7,3,5,9,2,6] 
        output: 9 
  case: 2 
        input: [1,5,3,2,7] 
        output: 7

ZX Spectrum Basic

10 PRINT "Values"''
20 LET z=0
30 FOR x=1 TO INT (RND*10)+1
40 LET y=RND*10-5
50 PRINT y
60 LET z=(y AND y>z)+(z AND y<z)
70 NEXT x
80 PRINT '"Max. value = ";z