Dice game probabilities: Difference between revisions

<lang rust>// Returns a vector containing the number of ways each possible sum of face

// values can occur.

let mut result = vec![1.0; faces + 1];

for d in 2..=dice {

let mut tmp = vec![0.0; d * faces + 1];

for j in 1..=faces {

tmp[i + j] += result[i];

}

 

let totals1 = get_totals(dice1, faces1);

let totals2 = get_totals(dice2, faces2);

let mut wins = 0.0;

let mut total = 0.0;

for j in dice2..totals2.len() {

let n = totals1[i] * totals2[j];

}

}

}