Combinations with repetitions: Difference between revisions
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→{{header|R}}: Syntax highlighting.
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=={{header|R}}==
The idiomatic solution is to just use a library.
<lang
combinations(3, 2, c("iced", "jam", "plain"), set = FALSE, repeats.allowed = TRUE)
nrow(combinations(10, 3, repeats.allowed = TRUE))</lang>
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