Binary digits: Difference between revisions

 

=={{header|0815}}==

}:b: Treat the queue as a stack and

<:2:= accumulate the binary digits

^:p:

<:a:~$ Output a newline.

 

{{out}}

Note that 0815 reads numeric input in hexadecimal.

 

101

110010

 

=={{header|11l}}==

{{out}}

<pre>

 

=={{header|360 Assembly}}==

BINARY CSECT

USING BINARY,R12

CBIN DC CL32' ' binary value

YREGS

{{out}}

<pre>

strout = $cb1e

</pre>

; C64 - Binary digits

; http://rosettacode.org/wiki/Binary_digits

binstr .repeat 16, $00 ; reserve 16 bytes for the binary digits

.byte $0d, $00 ; newline + null terminator

{{out}}

<pre>

 

=={{header|8080 Assembly}}==

puts: equ 9h ; Print string

org 100h

jmp binlp ; Otherwise, do next bit

binstr: db '0000000000000000' ; Placeholder for string

 

{{out}}

 

=={{header|8086 Assembly}}==

.stack 1024

.data

pop ax

ret

 

=={{header|8th}}==

2 base drop

#50 . cr

{{out}}

<pre>

=={{header|AArch64 Assembly}}==

{{works with|as|Raspberry Pi 3B version Buster 64 bits}}

/* ARM assembly AARCH64 Raspberry PI 3B */

/* program binarydigit.s */

.include "../includeARM64.inc"

 

{{out}}

<pre>

 

=={{header|ACL2}}==

 

(defun bin-string-r (x)

(if (zp x)

"0"

 

=={{header|Action!}}==

CHAR ARRAY a(16)

BYTE i=[0]

PutE()

OD

{{out}}

[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Binary_digits.png Screenshot from Atari 8-bit computer]

=={{header|Ada}}==

 

procedure binary is

bit : array (0..1) of character := ('0','1');

put_line ("Output for" & test'img & " is " & bin_image (test));

end loop;

 

{{out}}

 

=={{header|Aime}}==

o_byte('\n');

o_xinteger(2, 5);

o_xinteger(2, 50);

o_byte('\n');

{{out}}

<pre>0

{{works with|ALGOL 68G|Any - tested with release [http://sourceforge.net/projects/algol68/files/algol68g/algol68g-2.3.3 algol68g-2.3.3].}}

{{wont work with|ELLA ALGOL 68|Any (with appropriate job cards) - tested with release [http://sourceforge.net/projects/algol68/files/algol68toc/algol68toc-1.8.8d/algol68toc-1.8-8d.fc9.i386.rpm/download 1.8-8d] - due to use of '''format'''[ted] ''transput''.}}

 

printf((

50, " => ", []BOOL(BIN 50)[bits width-6+1:], new line,

9000, " => ", []BOOL(BIN 9000)[bits width-14+1:], new line

{{out}}

<pre>

 

=={{header|ALGOL-M}}==

procedure writebin(n);

integer n;

writebin(50);

writebin(9000);

{{out}}

<pre>101

 

A builtin function. Produces a boolean array.

 

 

 

Produces a boolean array.

 

NOTE: Both versions above will yield an empty boolean array for 0.

 

=={{header|ALGOL W}}==

% prints an integer in binary - the number must be greater than zero %

procedure printBinaryDigits( integer value n ) ;

end

 

 

=={{header|AppleScript}}==

 

(The generic showIntAtBase here, which allows us to specify the digit set used (e.g. upper or lower case in hex, or different regional or other digit sets generally), is a rough translation of Haskell's Numeric.showintAtBase)

 

-- showBin :: Int -> String

on unlines(xs)

intercalate(linefeed, xs)

<pre>5 -> 101

50 -> 110010

 

Or using:

on showBin(n)

script binaryChar

end script

showIntAtBase(2, binaryChar, n, "")

{{Out}}

<pre>5 -> 一〇一

At its very simplest, an AppleScript solution would look something like this:

 

set binary to (n mod 2 div 1) as text

set n to n div 2

intToBinary(5) & linefeed & ¬

intToBinary(50) & linefeed & ¬

 

Building a list of single-digit values instead and coercing that at the end can be a tad faster, but execution can be four or five times as fast when groups of text (or list) operations are replaced with arithmetic:

 

set binary to ""

repeat

intToBinary(5) & linefeed & ¬

intToBinary(50) & linefeed & ¬

 

=={{header|ARM Assembly}}==

{{works with|as|Raspberry Pi}}

 

/* ARM assembly Raspberry PI */

.Ls_magic_number_10: .word 0x66666667

 

 

=={{header|Arturo}}==

print as.binary 50

{{out}}

 

=={{header|AutoHotkey}}==

MsgBox % NumberToBinary(50) ;110010

MsgBox % NumberToBinary(9000) ;10001100101000

Result := (InputNumber & 1) . Result, InputNumber >>= 1

Return, Result

 

=={{header|AutoIt}}==

ConsoleWrite(IntToBin(50) & @CRLF)

 

Return $r

EndFunc ;==>IntToBin

 

=={{header|AWK}}==

print tobinary(5)

print tobinary(50)

}

return outstr

 

=={{header|Axe}}==

This example builds a string backwards to ensure the digits are displayed in the correct order. It uses bitwise logic to extract one bit at a time.

.Axe supports 16-bit integers, so 16 digits are enough

L₁+16→P

End

Disp P,i

 

=={{header|BaCon}}==

OPTION MEMTYPE int

INPUT n$

ELSE

PRINT CHOP$(BIN$(VAL(n$)), "0", 1)

 

=={{header|BASIC}}==

 

==={{header|Applesoft BASIC}}===

1 LET N2 = ABS ( INT (N))

2 LET B$ = ""

7 NEXT N1

8 PRINT B$

{{out}}

<pre>101

 

==={{header|BASIC256}}===

# DecToBin.bas

# BASIC256 1.1.4.0

print a[i] + chr(9) + toRadix(a[i],2) # radix (decimal, base2)

next i

{{out}}

<pre>

 

==={{header|BBC BASIC}}===

PRINT FN_tobase(num%, 2, 0)

NEXT

M% -= 1

UNTIL (N%=FALSE OR N%=TRUE) AND M%<=0

The above is a generic "Convert to any base" program.

Here is a faster "Convert to Binary" program:

PRINT FNbinary(50)

PRINT FNbinary(9000)

N% = N% >>> 1 : REM BBC Basic prior to V5 can use N% = N% DIV 2

UNTIL N% = 0

 

==={{header|Commodore BASIC}}===

Note the <tt>FOR N1 =</tt> ... <tt>TO 0 STEP 0</tt> idiom; the zero step means that the variable is not modified by BASIC, so it's up to the code inside the loop to eventually set <tt>N1</tt> to 0 so that the loop terminates – like a C <tt>for</tt> loop with an empty third clause. After the initialization, it's essentially a "while N1 is not 0" loop, but Commodore BASIC originally didn't have <b>while</b> loops (<tt>DO WHILE</tt> ... <tt>LOOP</tt> was added in BASIC 3.5). The alternative would be a <tt>GOTO</tt>, but the <tt>FOR</tt> loop lends more structure.

 

20 IF N < 0 THEN 70

30 GOSUB 100

130 : N1 = INT(N1/2)

140 NEXT N1

 

{{Out}}

 

==={{header|IS-BASIC}}===

100 DEF BIN$(N)

110 LET N=ABS(INT(N)):LET B$=""

150 LOOP WHILE N>0

160 LET BIN$=B$

 

==={{header|QBasic}}===

N = ABS(INT(N))

B$ = ""

PRINT USING fmt$; 5; BIN$(5)

PRINT USING fmt$; 50; BIN$(50)

 

==={{header|Tiny BASIC}}===

 

This turns into a horrible mess because of the lack of string concatenation in print statements, and the necessity of suppressing leading zeroes.

REM A-O: binary digits with A least significant and N most significant

REM X: number whose binary expansion we want

 

999 PRINT 0 REM zero is the one time we DO want to print a leading zero

 

==={{header|True BASIC}}===

LET N = ABS(INT(N))

LET B$ = ""

PRINT USING "####": 9000;

PRINT " -> "; BIN$(9000)

 

=={{header|Bash}}==

function to_binary () {

if [ $1 -ge 0 ]

echo $number " :> " $(to_binary $number)

done

{{out}}

<pre>

=={{header|Batch File}}==

This num2bin.bat file handles non-negative input as per the requirements with no leading zeros in the output. Batch only supports signed integers. This script also handles negative values by printing the appropriate two's complement notation.

:num2bin IntVal [RtnVar]

setlocal enableDelayedExpansion

if "%~2" neq "" (set %~2=%rtn%) else echo %rtn%

)

 

=={{header|bc}}==

{{trans|dc}}

5

50

9000

 

=={{header|BCPL}}==

 

let writebin(x) be

writebin(50)

writebin(9000)

{{out}}

<pre>101

 

=={{header|Beads}}==

calc main_init

loop across:[5, 50, 9000] val:v

{{out}}

<pre>101

=={{header|Befunge}}==

Reads the number to convert from standard input.

{{out}}

<pre>9000

 

A BQNcrate idiom which returns the digits as a boolean array.

 

 

=={{header|Bracmat}}==

= bit bits

. :?bits

& put$(str$(!dec ":\n" dec2bin$!dec \n\n))

)

{{out}}

<pre>0:

This is almost an exact duplicate of [[Count in octal#Brainf***]]. It outputs binary numbers until it is forced to terminate or the counter overflows to 0.

 

[>>++<< Set up {n 0 2} for divmod magic

[->+>- Then

<[[-]<] Zero the tape for the next iteration

++++++++++. Print a newline

 

=={{header|Burlesque}}==

blsq ) {5 50 9000}{2B!}m[uN

101

110010

10001100101000

 

=={{header|C}}==

===With bit level operations===

#define _CRT_NONSTDC_NO_DEPRECATE // enable old-gold POSIX names in MSVS

 

return EXIT_SUCCESS;

}

{{output}}

<pre>itoa: 5 decimal = 101 binary

===With malloc and log10===

Converts int to a string.

#include <stdio.h>

#include <stdlib.h>

ret[bits] = '\0';

return ret;

 

{{out}}

 

=={{header|C sharp|C#}}==

 

class Program

}

}

using System.Text;

 

Console.WriteLine(ToBinary(5));

Console.WriteLine(ToBinary(50));

{{out}}

<pre>

 

=={{header|C++}}==

#include <iostream>

#include <limits>

print_bin(9000);

}

{{out}}

<pre>

</pre>

Shorter version using bitset

#include <bitset>

void printBits(int n) { // Use int like most programming languages.

printBits(50);

printBits(9000);

Using >> operator. (1st example is 2.75x longer. Matter of taste.)

int main(int argc, char* argv[]) {

unsigned int in[] = {5, 50, 9000}; // Use int like most programming languages

std::cout << ('0' + b & 1) << (!at ? "\n": ""); // '0' or '1'. Add EOL if last bit of num

}

To be fair comparison with languages that doesn't declare a function like C++ main(). 3.14x shorter than 1st example.

int main(int argc, char* argv[]) { // Usage: program.exe 5 50 9000

for (int i = 1; i < argc; i++) // argv[0] is program name

std::cout << ('0' + b & 1) << (!at ? "\n": ""); // '0' or '1'. Add EOL if last bit of num

}

Using bitwise operations with recursion.

#include <iostream>

 

}

}

{{out}}

<pre>

 

=={{header|Ceylon}}==

void printBinary(Integer integer) =>

printBinary(50);

printBinary(9k);

 

=={{header|Clojure}}==

(Integer/toBinaryString 50)

 

=={{header|CLU}}==

bin: string := ""

while n > 0 do

stream$putl(po, int$unparse(test) || " -> " || binary(test))

end

{{out}}

<pre>5 -> 101

 

=={{header|COBOL}}==

PROGRAM-ID. SAMPLE.

 

display binary_number

stop run.

Free-form, using a reference modifier to index into binary-number.

PROGRAM-ID. binary-conversion.

 

end-perform.

display binary-number.

 

=={{header|CoffeeScript}}==

new Number(n).toString(2)

 

=={{header|Common Lisp}}==

Just print the number with "~b":

 

; or

 

 

=={{header|Component Pascal}}==

BlackBox Component Builder

MODULE BinaryDigits;

IMPORT StdLog,Strings;

END Do;

END BinaryDigits.

Execute: ^Q BinaryDigits.Do <br/>

{{out}}

 

=={{header|Cowgol}}==

 

sub print_binary(n: uint32) is

print_binary(5);

print_binary(50);

{{out}}

<pre>101

{{trans|Ruby}}

Using an array

puts "%b" % n

Using a tuple

{{out}}

<pre>101

 

=={{header|D}}==

import std.stdio;

 

foreach (immutable i; 0 .. 16)

writefln("%b", i);

{{out}}

<pre>0

 

=={{header|Dart}}==

if(n<0)

throw new IllegalArgumentException("negative numbers require 2s complement");

// fails due to precision limit

print(binary(0x123456789abcdef));

 

=={{header|dc}}==

 

{{out}}

 

=={{header|Delphi}}==

program BinaryDigit;

{$APPTYPE CONSOLE}

writeln(' 50: ',IntToBinStr(50));

writeln('9000: '+IntToBinStr(9000));

{{out}}

<pre>

A default <code>ToString</code> method of type <code>Integer</code> is overriden and returns a binary representation of a number:

 

var s = ""

for x in 31^-1..0 {

}

 

{{out}}

=={{header|EasyLang}}==

 

if n > 0

call to2 n div 2 r$

call pr2 5

call pr2 50

 

<pre>

 

=={{header|EchoLisp}}==

;; primitive : (number->string number [base]) - default base = 10

 

110010

10001100101000

 

=={{header|Elena}}==

ELENA 5.0 :

import extensions;

 

console.printLine(n.toString(2))

}

{{out}}

<pre>

=={{header|Elixir}}==

Use <code>Integer.to_string</code> with a base of 2:

IO.puts Integer.to_string(5,2)

Or, using the pipe operator:

5 |> Integer.to_string(2) |> IO.puts

[5,50,9000] |> Enum.each(fn n -> IO.puts Integer.to_string(n,2) end)

 

{{out}}

 

=={{header|Epoxy}}==

var c:""

while a>0 do

iter Value of List do

log(Value+": "+bin(Value,false))

{{out}}

<pre>

 

=={{header|Erlang}}==

{{out}}

<pre>101

 

=={{header|Euphoria}}==

sequence s

s = {}

puts(1, toBinary(5) & '\n')

puts(1, toBinary(50) & '\n')

 

=== Functional/Recursive ===

include std/convert.e

 

printf(1, "%d\n", Bin(5))

printf(1, "%d\n", Bin(50))

 

=={{header|F Sharp|F#}}==

By translating C#'s approach, using imperative coding style (inflexible):

 

Alternatively, by creating a function <code>printBin</code> which prints in binary (more flexible):

 

// define the function

// use the function

[5; 50; 9000]

 

Or more idiomatic so that you can use it with any printf-style function and the <code>%a</code> format specifier (most flexible):

 

open System.IO

 

// use it with printfn with %a

[5; 50; 9000]

Output (either version):

<pre>

 

=={{header|Factor}}==

 

5 >bin print

50 >bin print

 

=={{header|FALSE}}==

 

5 b;!

50 b;!

{{out}}

<pre>101

 

=={{header|FBSL}}==

function Bin(byval n as integer, byval s as string = "") as string

if n > 0 then return Bin(n \ 2, (n mod 2) & s)

 

pause

 

=={{header|FOCAL}}==

01.20 S A=50;D 2

01.30 S A=9000;D 2

02.50 I (-BX)2.4;T !;R

02.60 I (-BD(BX))2.7;T "0";R

{{out}}

<pre>101

 

=={{header|Forth}}==

 

\ HEX is a standard word to change the value of base to 16

decimal

 

 

{{out}}

=={{header|Fortran}}==

Please find compilation instructions and the example run at the start of the FORTRAN90 source that follows. Thank you.

!-*- mode: compilation; default-directory: "/tmp/" -*-

!Compilation started at Sun May 19 23:14:14

 

end program bits

 

=={{header|Free Pascal}}==

As part of the RTL (run-time library) that is shipped with every FPC (Free Pascal compiler) distribution, the <tt>system</tt> unit contains the function <tt>binStr</tt>.

The <tt>system</tt> unit is automatically included by ''every'' program and is guaranteed to work on every supported platform.

{$mode ISO}

 

writeLn(binaryNumber(50));

writeLn(binaryNumber(9000));

Note, that the ISO compliant <tt>mod</tt> operation has to be used, which is ensured by the <tt>{$mode}</tt> directive in the second line.

 

=={{header|FreeBASIC}}==

' FreeBASIC v1.05.0 win64

Dim As String fmt = "#### -> &"

Sleep

End

 

{{out}}

=={{header|Frink}}==

The following all provide equivalent output. Input can be arbitrarily-large integers.

9000 -> binary

9000 -> base2

base2[9000]

base[9000, 2]

 

=={{header|FunL}}==

 

{{out}}

We produce the binary number as a 64-bit integer whose digits are all 0s and 1s - this is because Futhark does not have any way to print, nor strings for that matter.

 

fun main(x: i32): i64 =

loop (out = 0i64) = for i < 32 do

in out

in out

 

 

=={{header|FutureBasic}}==

The decimal to binary conversion can be handled with a simple function.

include "NSLog.incl"

 

 

HandleEvents

{{output}}

<pre>

=={{header|Gambas}}==

'''[https://gambas-playground.proko.eu/?gist=03e84768e6ee2af9b7664efa04fa6da8 Click this link to run this code]'''

Dim siBin As Short[] = [5, 50, 9000]

Dim siCount As Short

Next

 

{{out}}

<pre>

 

=={{header|Go}}==

 

import (

fmt.Printf("%b\n", i)

}

{{out}}

<pre>

=={{header|Groovy}}==

Solutions:

n binary

----- ---------------

[5, 50, 9000].each {

printf('%5d %15s\n', it, Integer.toBinaryString(it))

{{out}}

<pre> n binary

 

=={{header|Haskell}}==

import Numeric

import Text.Printf

main = do

putStrLn $ printf "%4s %14s %14s" "N" "toBin" "toBin1"

{{out}}

<pre>

and in terms of first and swap, we could also write this as:

 

import Data.List (unfoldr)

import Data.Tuple (swap)

)

)

{{Out}}

<pre>5 -> 101

=={{header|Icon}} and {{header|Unicon}}==

There is no built-in way to output the bit string representation of an whole number in Icon and Unicon. There are generalized radix conversion routines in the Icon Programming Library that comes with every distribution. This procedure is a customized conversion routine that will populate and use a tunable cache as it goes.

every i := 5 | 50 | 255 | 1285 | 9000 do

write(i," = ",binary(i))

}

return reverse(trim(b,"0")) # nothing extraneous

{{out}}

<pre>5 = 101

 

=={{header|Idris}}==

 

binaryDigit : Integer -> Char

putStrLn (binaryString 50)

putStrLn (binaryString 9000)

{{out}}

<pre>

 

=={{header|J}}==

tobin 5

101

110010

tobin 9000

Algorithm: Remove spaces from the character list which results from formatting the binary list which represents the numeric argument.

 

 

=={{header|Java}}==

public static void main(String[] args) {

System.out.println(Integer.toBinaryString(5));

System.out.println(Integer.toBinaryString(9000));

}

{{out}}

<pre>101

=={{header|JavaScript}}==

===ES5===

return new Number(number)

.toString(2);

// alert() in a browser, wscript.echo in WSH, etc.

print(toBinary(demoValues[i]));

 

===ES6===

The simplest showBinary (or showIntAtBase), using default digit characters, would use JavaScript's standard String.toString(base):

 

"use strict";

 

// MAIN ---

return main();

{{Out}}

<pre>5 -> 101

Or, if we need more flexibility with the set of digits used, we can write a version of showIntAtBase which takes a more specific Int -> Char function as as an argument. This one is a rough translation of Haskell's Numeric.showIntAtBase:

 

"use strict";

 

// MAIN ---

return main();

{{Out}}

<pre>5 -> 一〇一

 

=={{header|Joy}}==

_ == [null] [pop] [2 div swap] [48 + putch] linrec

IN

int2bin == [null] [48 + putch] [_] ifte '\n putch

Using int2bin:

0 int2bin

5 int2bin

50 int2bin

 

=={{header|jq}}==

[ recurse( ./2 | floor; . > 0) % 2 ] | reverse | join("") ;

 

# The task:

{{Out}}

$ jq -n -r -f Binary_digits.jq

{{works with|Julia|1.0}}

 

 

for n in (0, 5, 50, 9000)

for n in (0, 5, 50, 9000)

@printf("%6i → %s\n", n, string(n, base=2, pad=20))

 

{{out}}

 

=={{header|K}}==

tobin' 5 50 9000

("101"

"110010"

 

=={{header|Kotlin}}==

 

fun main(args: Array<String>) {

val numbers = intArrayOf(5, 50, 9000)

for (number in numbers) println("%4d".format(number) + " -> " + Integer.toBinaryString(number))

 

{{out}}

 

=={{header|Lambdatalk}}==

{def dec2bin

{lambda {:dec}

9000 -> 10001100101000

 

 

=={{header|Lang5}}==

{{out}}

<pre>[

 

If one is simple printing the results and doesn't need to use them (e.g., assign them to any variables, etc.), this is very concise:

(: io format '"~.2B~n~.2B~n~.2B~n" (list 5 50 9000))

 

If, however, you do need to get the results from a function, you can use <code>(: erlang integer_to_list ... )</code>. Here's a simple example that does the same thing as the previous code:

(: lists foreach

(lambda (x)

(list (: erlang integer_to_list x 2))))

(list 5 50 9000))

{{out|note=for both examples}}

<pre>

 

=={{header|Liberty BASIC}}==

print a;"=";dec2bin$(a)

next

wend

end function

 

=={{header|Little Man Computer}}==

 

The maximum integer in LMC is 999, so 90000 in the task is here replaced by 900.

// Little Man Computer, for Rosetta Code.

// Read numbers from user and display them in binary.

nrDigits DAT

diff DAT

{{out}}

<pre>

=={{header|LLVM}}==

{{trans|C}}

; source_filename = "binary.c"

; target datalayout = "e-m:w-i64:64-f80:128-n8:16:32:64-S128"

!0 = !{i32 1, !"wchar_size", i32 2}

!1 = !{i32 7, !"PIC Level", i32 2}

{{out}}

<pre>0

 

=={{header|Locomotive Basic}}==

20 PRINT BIN$(50)

{{out}}

<pre>101

 

=={{header|LOLCODE}}==

HOW IZ I DECIMULBINUR YR DECIMUL

I HAS A BINUR ITZ ""

VISIBLE I IZ DECIMULBINUR YR 50 MKAY

VISIBLE I IZ DECIMULBINUR YR 9000 MKAY

 

{{out}}

=={{header|Lua}}==

===Lua - Iterative===

local bin = ""

while n > 0 do

print(dec2bin(5))

print(dec2bin(50))

{{out}}

<pre>101

===Lua - Recursive===

{{works with|Lua|5.3+}}

bin = (n&1) .. (bin or "") -- use n%2 instead of n&1 for Lua 5.1/5.2

return n>1 and dec2bin(n//2, bin) or bin -- use math.floor(n/2) instead of n//2 for Lua 5.1/5.2

print(dec2bin(5))

print(dec2bin(50))

{{out}}

<pre>101

 

=={{header|M2000 Interpreter}}==

Module Checkit {

Form 90, 40

}

Checkit

{{out}}

<pre style="height:30ex;overflow:scroll">

matches the binary representation of the input, e.g. <code>BINARY.(5)</code> is <code>101</code>.

 

INTERNAL FUNCTION(NUM)

 

VECTOR VALUES FMT = $I4,2H: ,I16*$

{{out}}

<pre> 5: 101

 

=={{header|Maple}}==

> convert( 50, 'binary' );

110010

> convert( 9000, 'binary' );

10001100101000

 

=={{header|Mathematica}} / {{header|Wolfram Language}}==

 

=={{header|MATLAB}} / {{header|Octave}}==

dec2bin(50)

The output is a string containing ascii(48) (i.e. '0') and ascii(49) (i.e. '1').

 

=={{header|Maxima}}==

[n: first(arg), b: if length(arg) > 1 then second(arg) else 10, v: [ ], q],

do (

/*

10001100101000

 

=={{header|MAXScript}}==

-- MAXScript: Output decimal numbers from 0 to 16 as Binary : N.H. 2019

for k = 0 to 16 do

print binString

)

{{out}}

Output to MAXScript Listener:

 

=={{header|Mercury}}==

:- interface.

 

print_binary_digits(N, !IO) :-

io.write_string(int_to_base_string(N, 2), !IO),

 

=={{header|min}}==

{{works with|min|0.19.3}}

 

(

) :bin

 

{{out}}

<pre>

=={{header|MiniScript}}==

=== Iterative ===

result = ""

while n

print binary(50)

print binary(9000)

 

=== Recursive ===

if n == 0 then

if result == "" then return "0" else return result

print binary(50)

print binary(9000)

{{out}}

<pre>

 

=={{header|mLite}}==

(0, b) = implode ` map (fn x = if int x then chr (x + 48) else x) b

| (n, b) = binary (n div 2, n mod 2 :: b)

| n = binary (n, [])

;

 

==== from the REPL ====

 

=={{header|Modula-2}}==

FROM FormatString IMPORT FormatString;

FROM Terminal IMPORT Write,WriteLn,ReadChar;

 

ReadChar

 

=={{header|Modula-3}}==

 

IMPORT IO, Fmt;

num := 150;

IO.Put(Fmt.Int(num, 2) & "\n");

{{out}}

<pre>

 

=={{header|NetRexx}}==

options replace format comments java crossref symbols nobinary

 

w_ = list.word(n_)

say w_.right(20)':' getBinaryDigits(w_)

{{out}}

<pre>

=={{header|NewLisp}}==

 

;;; Using the built-in "bits" function

;;; For integers up to 9,223,372,036,854,775,807

;;; Example

(println (big-bits 1234567890123456789012345678901234567890L))

<pre>

Output:

 

=={{header|Nim}}==

## Calculates how many digits `x` has when each digit covers `r` bits.

result = 1

 

for i in 0..15:

{{out}}

<pre>0

 

===Version using strformat===

 

for n in 0..15:

 

{{out}}

 

=={{header|Oberon-2}}==

MODULE BinaryDigits;

IMPORT Out;

OutBin(42); Out.Ln;

END BinaryDigits.

 

{{out}}

 

=={{header|Objeck}}==

function : Main(args : String[]) ~ Nil {

5->ToBinaryString()->PrintLine();

9000->ToBinaryString()->PrintLine();

}

{{out}}

<pre>

 

=={{header|OCaml}}==

if d < 0 then invalid_arg "bin_of_int" else

if d = 0 then "0" else

let () =

let d = read_int () in

 

=={{header|Oforth}}==

 

=={{header|Ol}}==

(print (number->string 5 2))

(print (number->string 50 2))

(print (number->string 9000 2))

{{Out}}

<pre>

=={{header|OxygenBasic}}==

The Assembly code uses block structures to minimise the use of labels.

 

function BinaryBits(sys n) as string

 

print BinaryBits 0xaa 'result 10101010

 

=={{header|Panda}}==

{{out}}

<pre>0

 

=={{header|PARI/GP}}==

 

=={{header|Pascal}}==

{{works with|Free Pascal}}

FPC compiler Version 2.6 upwards.The obvious version.

{$MODE objFPC}

uses

IntBinTest(5);IntBinTest(50);IntBinTest(5000);

IntBinTest(0);IntBinTest(NativeUint(-1));

{{out}}

<pre> 5 101

Beware of the endianess of the constant.

I check performance with random Data.

program IntToPcharTest;

uses

Writeln(cnt/rounds+1:6:3);

FreeMem(s);

{{out}}

<pre>

 

=={{header|Peloton}}==

 

<@ saybaslit>0</@>

<@ saybaslit>50</@>

<@ saybaslit>9000</@>

 

=={{header|Perl}}==

printf "%b\n", $_;

<pre>

101

 

=={{header|Phix}}==

<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%b\n"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">5</span><span style="color: #0000FF;">)</span>

<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%b\n"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">50</span><span style="color: #0000FF;">)</span>

<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%b\n"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">9000</span><span style="color: #0000FF;">)</span>

{{out}}

<pre>

 

=={{header|Phixmonti}}==

"The decimal value " print dup print " should produce an output of " print

20 int>bit

5 printBinary

50 printBinary

 

Other solution

by Galileo, 05/2022 #/

 

50 printBinary

9000 printBinary

{{out}}

<pre>The decimal value 5 should produce an output of 101

 

=={{header|PHP}}==

echo decbin(5);

echo decbin(50);

{{out}}

<pre>101

 

=={{header|Picat}}==

println(to_binary_string(I))

 

{{out}}

 

=={{header|PicoLisp}}==

-> "101"

 

 

: (bin 9000)

 

=={{header|Piet}}==

=={{header|PL/I}}==

Displays binary output trivially, but with leading zeros:

{{out}}

<pre>Output: 0011001

</pre>

With leading zero suppression:

 

put string(text) edit (25) (b);

 

put string(text) edit (2147483647) (b);

{{out}}

<pre>

 

=={{header|PL/M}}==

 

/* CP/M BDOS CALL */

 

CALL BDOS(0,0);

{{out}}

<pre>101

=={{header|PowerBASIC}}==

Pretty simple task in PowerBASIC since it has a built-in BIN$-Function. Omitting the second parameter ("Digits") means no leading zeros in the result.

#COMPILE EXE

#DIM ALL

PRINT STR$(d(i)) & ": " & BIN$(d(i)) & " (" & BIN$(d(i), 32) & ")"

NEXT i

{{out}}<pre>

5: 101 (00000000000000000000000000000101)

=={{header|PowerShell}}==

{{libheader|Microsoft .NET Framework}}

{{out}}

<pre>101

 

=={{header|Processing}}==

println(Integer.toBinaryString(50)); // 110010

Processing also has a binary() function, but this returns zero-padded results

println(binary(50)); // 00000000110010

 

=={{header|Prolog}}==

{{works with|SWI Prolog}}

{{works with|GNU Prolog}}

binary(X) :- format('~2r~n', [X]).

main :- maplist(binary, [5,50,9000]), halt.

{{out}}

<pre>101

 

=={{header|PureBasic}}==

PrintN(Bin(5)) ;101

PrintN(Bin(50)) ;110010

Print(#CRLF$ + #CRLF$ + "Press ENTER to exit"): Input()

CloseConsole()

{{out}}

<pre>101

===String.format() method===

{{works with|Python|3.X and 2.6+}}

 

0

1101

1110

 

===Built-in bin() function===

{{works with|Python|3.X and 2.6+}}

 

0

1101

1110

Pre-Python 2.6:

>>> bin = lambda n: ''.join(oct2bin[octdigit] for octdigit in '%o' % n).lstrip('0') or '0'

>>> for i in range(16): print(bin(i))

1101

1110

 

===Custom functions===

 

Defined in terms of a more general '''showIntAtBase''' function:

 

 

 

if __name__ == '__main__':

{{Out}}

<pre>Mapping showBinary over integer list:

 

Or, using a more specialised function to decompose an integer to a list of boolean values:

 

 

# MAIN -------------------------------------------------

if __name__ == '__main__':

{{Out}}

<pre>Mapping a composed function:

 

=={{header|QB64}}==

Print DecToBin$(5)

Print DecToBin$(50)

 

 

 

=={{header|Quackery}}==

Quackery provides built-in radix control, much like Forth.

2 base put ( Numbers will be output in base 2 now. )

( Bases from 2 to 36 (inclusive) are supported. )

base release ( It's best to clean up after ourselves. )

( Numbers will be output in base 10 now. )

 

A user-defined conversion might look something like this:

[ [] swap

[ 2 /mod digit

50 bin echo$ cr

9000 bin echo$ cr

{{out}}

<pre>

 

=={{header|R}}==

dec2bin <- function(num) {

ifelse(num == 0,

cat(dec2bin(anumber),"\n")

}

'''output'''

<pre>

 

=={{header|Racket}}==

#lang racket

;; Option 1: binary formatter

;; Option 2: explicit conversion

(for ([i 16]) (displayln (number->string i 2)))

 

=={{header|Raku}}==

(formerly Perl 6)

{{works with|Rakudo|2015.12}}

<pre>

101

Alternatively:

 

<pre>101

110010

 

=={{header|RapidQ}}==

'Convert Integer to binary string

Print "bin 5 = ", bin$(5)

Print "bin 9000 = ",bin$(9000)

sleep 10

 

=={{header|Red}}==

 

foreach number [5 50 9000] [

print reduce [ pad/left number 5 binstr ]

]

'''output'''

<pre> 5 101

 

=={{header|Retro}}==

 

=={{header|REXX}}==

Note: &nbsp; some REXX interpreters have a &nbsp; '''D2B''' &nbsp; [Decimal to Binary] &nbsp; BIF ('''b'''uilt-'''i'''n '''f'''unction).

<br>Programming note: &nbsp; this REXX version depends on &nbsp; '''numeric digits''' &nbsp; being large enough to handle leading zeroes in this manner (by adding a zero (to the binary version) to force superfluous leading zero suppression).

numeric digits 1000 /*ensure we can handle larger numbers. */

@.=; @.1= 0

y=x2b( d2x(@.j) ) + 0 /*force removal of extra leading zeroes*/

say right(@.j,20) 'decimal, and in binary:' y /*display the number to the terminal. */

{{out|output}}

<pre>

This version handles the case of zero as a special case more elegantly.

<br>The following versions depend on the setting of &nbsp; '''numeric digits''' &nbsp; such that the number in decimal can be expressed as a whole number.

@.=; @.1= 0

@.2= 5

if y=='' then y=0 /*handle the special case of 0 (zero).*/

say right(@.j,20) 'decimal, and in binary:' y /*display the number to the terminal. */

{{out|output|text=&nbsp; is identical to the 1^st REXX version.}} <br><br>

 

===concise version===

This version handles the case of zero a bit more obtusely, but concisely.

@.=; @.1= 0

@.2= 5

y=word( strip( x2b( d2x( @.j )), 'L', 0) 0, 1) /*elides all leading 0s, if null, use 0*/

say right(@.j,20) 'decimal, and in binary:' y /*display the number to the terminal. */

{{out|output|text=&nbsp; is identical to the 1^st REXX version.}} <br><br>

 

===conforming version===

This REXX version conforms to the strict output requirements of this task (just show the binary output without any blanks).

numeric digits 200 /*ensure we can handle larger numbers. */

@.=; @.1= 0

if y=='' then y=0 /*handle the special case of 0 (zero).*/

say y /*display binary number to the terminal*/

{{out|output}}

<pre>

 

=={{header|Ring}}==

see "Number to convert : "

give a

else see 0 ok

next

 

=={{header|Ruby}}==

puts "%b" % n

or

puts n.to_s(2)

{{out}}

<pre>101

 

=={{header|Run BASIC}}==

while 2^(n+1) < a

n = n + 1

print 0;

end if

{{out}}

<pre>Number to convert:?9000

 

=={{header|Rust}}==

for i in 0..8 {

println!("{:b}", i)

}

Outputs:

<pre>0

 

=={{header|S-lang}}==

{

variable m = 0x40000000, prn = 0, bs = "";

() = printf("%s\n", int_to_bin(5));

() = printf("%s\n", int_to_bin(50));

{{out}}

<pre>101

=={{header|Scala}}==

Scala has an implicit conversion from <code>Int</code> to <code>RichInt</code> which has a method <code>toBinaryString</code>.

res0: String = 101

 

 

scala> (9000 toBinaryString)

 

=={{header|Scheme}}==

(display (number->string 50 2)) (newline)

 

=={{header|Seed7}}==

This example uses the [http://seed7.sourceforge.net/libraries/integer.htm#%28in_integer%29radix%28in_integer%29 radix] operator to write a number in binary.

 

 

const proc: main is func

writeln(number radix 2);

end for;

{{out}}

<pre>

 

=={{header|SequenceL}}==

 

toBinaryString(number(0)) :=

toBinaryString(floor(number/2)) ++ val when floor(number/2) > 0

else

 

{{out}}

 

=={{header|Sidef}}==

say n.as_bin;

{{out}}

<pre>101

 

=={{header|Simula}}==

 

PROCEDURE OUTINTBIN(N); INTEGER N;

END;

 

{{out}}

<pre>

=={{header|SkookumScript}}==

 

println(50.binary)

Or looping over a list of numbers:

{{out}}

<pre>101

 

=={{header|Smalltalk}}==

50 printOn: Stdout radix:2

or:

 

=={{header|SNOBOL4}}==

define('bin(n,r)') :(bin_end)

bin bin = le(n,0) r :s(return)

output = bin(50)

output = bin(9000)

{{out}}

<pre>

 

=={{header|SNUSP}}==

/recurse\

$,binary!\@\>?!\@/<@\.#

/<+>- \ div2

\?!#-?/+# mod2

 

=={{header|Standard ML}}==

print (Int.fmt StringCvt.BIN 50 ^ "\n");

 

=={{header|Swift}}==

println(String(num, radix: 2))

{{out}}

<pre>

 

=={{header|Tcl}}==

# Convert to _fixed width_ big-endian 32-bit binary

binary scan [binary format "I" $num] "B*" binval

# Strip useless leading zeros by reinterpreting as a big decimal integer

scan $binval "%lld"

Demonstrating:

puts [num2bin $x]

}

puts [num2bin 5]

puts [num2bin 50]

{{out}}

<pre>

<br>

Or you can use the builtin format:

puts [format "%4u: %b" $n $n]

{{out}}

<pre> 0: 0

=={{header|TI-83 BASIC}}==

Using Standard TI-83 BASIC

:Disp "NUMBER TO"

:Disp "CONVERT:"

:N-1→N

:End

Alternate using a string to display larger numbers.

:Input X

:" "→Str1

:iPart(X)→X

:End

Using the baseInput() "real(25," function from [http://www.detachedsolutions.com/omnicalc/ Omnicalc]

:Disp "NUMBER TO"

:Disp "CONVERT"

:Input "Str1"

 

More compact version:

:" →Str1

:If not(D:"0→Str1

:End

:Disp Str1

 

=={{header|uBasic/4tH}}==

This will convert any decimal number to any base between 2 and 16.

Input "Enter base (1<X<17): "; b

While (b < 2) + (b > 16)

130 Print "D"; : Return

140 Print "E"; : Return

{{out}}

<pre>Enter base (1<X<17): 2

 

=={{header|UNIX Shell}}==

tobinary() {

# We use the bench calculator for our conversion

# Call the function with each of our values

tobinary 5

 

=={{header|VBA}}==

Places is useful for padding the return value with leading 0s (zeros).

 

Option Explicit

 

End If

End Function

{{out}}

<pre>The decimal value 5 should produce an output of : 101

=={{header|Vedit macro language}}==

This implementation reads the numeric values from user input and writes the converted binary values in the edit buffer.

#10 = Get_Num("Give a numeric value, -1 to end: ", STATLINE)

if (#10 < 0) { break }

EOL

Ins_Newline

Example output when values 0, 1, 5, 50 and 9000 were entered:

<pre>

 

=={{header|Vim Script}}==

let n = a:n

let s = ""

echo Num2Bin(5)

echo Num2Bin(50)

 

{{Out}}

=={{header|Visual Basic}}==

{{works with|Visual Basic|VB6 Standard}}

Public Function Bin(ByVal l As Long) As String

Dim i As Long

Debug.Print Bin(9000)

End Sub

{{out}}

<pre>101

 

=={{header|Visual Basic .NET}}==

Sub Main

For Each number In {5, 50, 9000}

Next

End Sub

{{out}}

<pre>101

 

=={{header|Visual FoxPro}}==

*!* Binary Digits

CLEAR

RETURN FLOOR(v)

ENDFUNC

{{out}}

<pre>

This program prints binary numbers until the internal representation of the current integer overflows to -1; it will never do so on some interpreters. It is almost an exact duplicate of [[Count in octal#Whitespace]].

 

 

 

 

 

It was generated from the following pseudo-Assembly.

 

; Increment indefinitely.

0:

3:

pop

 

=={{header|Vlang}}==

for i in 0..16 {

println("${i:b}")

}

{{out}}

<pre>

 

=={{header|VTL-2}}==

20 #=100

30 N=50

180 #=I<18*160

190 ?=""

{{out}}

<pre>101

=={{header|Wortel}}==

Using JavaScripts buildin toString method on the Number object, the following function takes a number and returns a string with the binary representation:

; the following function also casts the string to a number

To output to the console:

Outputs: <pre>

101

=={{header|Wren}}==

{{libheader|Wren-fmt}}

System.print("Converting to binary:")

 

{{out}}

=={{header|X86 Assembly}}==

Translation of XPL0. Assemble with tasm, tlink /t

.code

.486

int 29h ;display character

ret

 

{{out}}

 

=={{header|XPL0}}==

 

proc BinOut(N); \Output N in binary

I:= I+1;

until KeyHit or I=0;

 

{{out}}

 

=={{header|Yabasic}}==

a(0) = 5

a(1) = 50

print a(i) using "####", " -> ", bin$(a(i))

next i

 

=={{header|Z80 Assembly}}==

{{trans|8086 Assembly}}

 

PrintChar equ &BB5A ;syscall - prints accumulator to Amstrad CPC's screen

 

call &BB5A

ld a,10

 

 

This is another version. Output of the result over port 0A hex.

; HL contains the value to be converted

ld hl,5

djnz bitloop

 

 

 

=={{header|zkl}}==

 

=={{header|ZX Spectrum Basic}}==

20 LET n=50: GO SUB 1000: PRINT s$

30 LET n=9000: GO SUB 1000: PRINT s$

1070 IF (sf <> 0) THEN LET s$=s$+d$

1080 NEXT l