Arithmetic derivative: Difference between revisions
→{{header|jq}}: jq good enough for D(10^16)
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=={{header|jq}}==
For this task, gojq (the Go implementation of jq) is used
for numerical accuracy, though the C implementation has sufficient accuracy at least for D(10^16).
See [[Prime_decomposition#jq]] for the def of factors/0 used here.
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D(10^20) / 7 = 200000000000000000000
</pre>
=={{header|Julia}}==
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