Achilles numbers: Difference between revisions

m
m (Python example)
Line 2,334:
def is_Achilles(n):
p = [v for v in factorint(n).values()]
return all(i > 1 for i in p) and gcd(*p) == 1
 
Line 2,394:
[10000, 99999]: 192
[100000, 999999]: 664
</pre>
 
=={{header|Raku}}==
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