Unique characters in each string: Difference between revisions

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{{trans|Python}}
 
<langsyntaxhighlight lang="11l">V LIST = [‘1a3c52debeffd’, ‘2b6178c97a938stf’, ‘3ycxdb1fgxa2yz’]
 
print(sorted(Set(Array(LIST.join(‘’))).filter(ch -> all(:LIST.map(w -> w.count(@ch) == 1)))))</langsyntaxhighlight>
 
{{out}}
Line 28:
 
=={{header|Action!}}==
<langsyntaxhighlight Actionlang="action!">DEFINE MAX="128"
CHAR ARRAY uniq(MAX)
 
Line 94:
FI
OD
RETURN</langsyntaxhighlight>
{{out}}
[https://gitlab.com/amarok8bit/action-rosetta-code/-/raw/master/images/Unique_characters_in_each_string.png Screenshot from Atari 8-bit computer]
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=={{header|Ada}}==
<langsyntaxhighlight Adalang="ada">with Ada.Text_Io;
 
procedure Unique_Characters is
Line 133:
2 => Occurences ("2b6178c97a938stf"),
3 => Occurences ("3ycxdb1fgxa2yz")));
end Unique_Characters;</langsyntaxhighlight>
{{out}}
<pre>1 2 3 a b c</pre>
 
=={{header|ALGOL 68}}==
<langsyntaxhighlight lang="algol68">BEGIN # find the characters that occur once only in each element of a list #
# of stings #
OP UNIQUEINEACH = ( []STRING s )STRING:
Line 170:
STRING unique = UNIQUEINEACH []STRING( "1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz" );
FOR c FROM LWB unique TO UPB unique DO print( ( " ", unique[ c ] ) ) OD
END</langsyntaxhighlight>
{{out}}
<pre>
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The filtering here is case sensitive, the sorting dependent on locale.
 
<langsyntaxhighlight lang="applescript">use AppleScript version "2.4" -- OS X 10.10 (Yosemite) or later
use framework "Foundation"
 
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end uniqueCharactersInEachString
 
uniqueCharactersInEachString({"1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"})</langsyntaxhighlight>
 
{{output}}
<langsyntaxhighlight lang="applescript">{"1", "2", "3", "a", "b", "c"}</langsyntaxhighlight>
 
===Core language only===
This can be case-insensitive if required. (Just leave out the 'considering case' statement round the call to the handler). The requirement for AppleScript 2.3.1 is only for the 'use' command which loads the "Heap Sort" script. If "Heap Sort"'s instead loaded with the older 'load script' command or copied into the code, this will work on systems as far back as Mac OS X 10.5 (Leopard) and possibly earlier. Same output as above.
 
<langsyntaxhighlight lang="applescript">use AppleScript version "2.3.1" -- OS X 10.9 (Mavericks) or later
use sorter : script "Heap Sort" -- <https://www.rosettacode.org/wiki/Sorting_algorithms/Heapsort#AppleScript>
 
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considering case
uniqueCharactersInEachString({"1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"})
end considering</langsyntaxhighlight>
 
=={{header|Arturo}}==
 
<langsyntaxhighlight lang="rebol">arr: ["1a3c52debeffd" "2b6178c97a938stf" "3ycxdb1fgxa2yz"]
uniques: split first arr
 
Line 266:
]
 
print sort uniques</langsyntaxhighlight>
 
{{out}}
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=={{header|AWK}}==
<syntaxhighlight lang="awk">
<lang AWK>
# syntax: GAWK -f UNIQUE_CHARACTERS_IN_EACH_STRING.AWK
#
Line 305:
exit(0)
}
</syntaxhighlight>
</lang>
{{out}}
<pre>
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3 strings, 43 characters, 20 different, 6 unique: 123abc
</pre>
 
=={{header|BQN}}==
<syntaxhighlight lang="bqn">(∧∘(∊/⊣)´ (∊∧∊⌾⌽)⊸/¨) "1a3c52debeffd"‿"2b6178c97a938stf"‿"3ycxdb1fgxa2yz"</syntaxhighlight>
{{out}}
<pre>"123abc"</pre>
 
=={{header|Delphi}}==
{{works with|Delphi|6.0}}
{{libheader|SysUtils,StdCtrls}}
 
 
<syntaxhighlight lang="Delphi">
 
var SA: array [0..2] of string = ('1a3c52debeffd', '2b6178c97a938stf', '3ycxdb1fgxa2yz');
 
 
function CharsAppearingOnce(S: string): string;
{Return all character that only occur once}
var SL: TStringList;
var I,Inx: integer;
begin
SL:=TStringList.Create;
try
{Store each character and store a count}
{of the number of occurances in the object}
for I:=1 to Length(S) do
begin
{Check to see if letter is already in list}
Inx:=SL.IndexOf(S[I]);
{Increment the count if it is, otherwise store it}
if Inx>=0 then SL.Objects[Inx]:=Pointer(Integer(SL.Objects[Inx])+1)
else SL.AddObject(S[I],Pointer(1));
end;
{Sort the list}
SL.Sort;
{Now return letters with a count of one}
Result:='';
for I:=0 to SL.Count-1 do
if integer(SL.Objects[I])<2 then Result:=Result+SL[I];
finally SL.Free; end;
end;
 
 
function CommonToAllStrs(SA: array of string): string;
{Get all the letters shared by all the strings in SA}
var I,J,Cnt: integer;
var S1: string;
var C: char;
begin
Result:='';
{Exit if empty array}
if Length(SA)<1 then exit;
{Get the first string}
S1:=SA[0];
for I:=1 to Length(S1) do
begin
{Character from 1st string }
C:=S1[I];
{Count # of occurences}
Cnt:=1;
for J:=1 to High(SA) do
if Pos(C,SA[J])>0 then Inc(Cnt);
{grab it if it appears in all other string}
if Cnt=Length(SA) then Result:=Result+C;
end;
end;
 
procedure ShowCharsAppearOnce(Memo: TMemo);
var I: integer;
var S: string;
var SS: array of string;
begin
SetLength(SS,0);
{Get all single appearance characters}
for I:=0 to High(SA) do
begin
SetLength(SS,Length(SS)+1);
SS[High(SS)]:=CharsAppearingOnce(SA[I]);
end;
{Get the ones shared by all string}
S:=CommonToAllStrs(SS);
Memo.Lines.Add(S);
end;
</syntaxhighlight>
{{out}}
<pre>
123abc
 
Elapsed Time: 1.238 ms.
 
</pre>
 
 
=={{header|F_Sharp|F#}}==
<langsyntaxhighlight lang="fsharp">
// Unique characters in each string: Nigel Galloway. May 12th., 2021
let fN g=g|>Seq.countBy id|>Seq.filter(fun(_,n)->n=1)
let fUc g=g|>List.map fN|>Seq.concat|>Seq.countBy id|>Seq.filter(fun(_,n)->n=List.length g)|>Seq.map(fun((n,_),_)->n)|>Seq.sort
printfn "%s" (fUc ["1a3c52debeffd";"2b6178c97a938stf";"3ycxdb1fgxa2yz"]|>Array.ofSeq|>System.String)
</syntaxhighlight>
</lang>
{{out}}
<pre>
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=={{header|Factor}}==
{{works with|Factor|0.99 2021-02-05}}
<langsyntaxhighlight lang="factor">USING: io kernel sequences.interleaved sets sorting ;
 
{ "1a3c52debeffd" "2b6178c97a938sf" "3ycxdb1fgxa2yz" }
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! intersect-all obtain elements present in every string -> "1a3c2bf"
! [ duplicates ] gather obtain elements that repeat within a single string -> "efd798xy"
! without from the first string, remove elements that are in the second -> "1a3c2b"</langsyntaxhighlight>
{{out}}
<pre>
Line 344 ⟶ 436:
 
=={{header|FreeBASIC}}==
<langsyntaxhighlight lang="freebasic">function count_char( s as string, c as string ) as uinteger
'count occurrences of character c in string s
dim as integer i, r = 0
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next i
 
print uniq</langsyntaxhighlight>
{{out}}<pre>123abc</pre>
 
=={{header|FutureBasic}}==
<syntaxhighlight lang="futurebasic">
local fn StringCharacterIsUnique( string as CFStringRef, chr as CFStringRef ) as BOOL
long count = 0, length = len(string)
CFRange range = fn StringRangeOfString( string, chr )
while ( range.location != NSNotFound )
count++
range.location++
range = fn StringRangeOfStringWithOptionsInRange( string, chr, 0, fn CFRangeMake(range.location,length-range.location) )
wend
end fn = (count == 1)
 
void local fn DoIt
CFArrayRef strings = @[@"1a3c52debeffd",@"2b6178c97a938stf",@"3ycxdb1fgxa2yz"]
CFStringRef chr
CFMutableArrayRef array = fn MutableArrayWithCapacity(0)
long i, j, count, length = len(strings[0])
for i = 0 to length - 1
chr = mid(strings[0],i,1)
if ( fn StringCharacterIsUnique( strings[0], chr ) )
count = 1
for j = 1 to len(strings) - 1
if ( fn StringCharacterIsUnique( strings[j], chr ) )
count++
end if
next
if ( count == len(strings) ) then MutableArrayAddObject( array, chr )
end if
next
MutableArraySortUsingSelector( array, @"compare:" )
print fn ArrayComponentsJoinedByString( array, @" " )
end fn
 
fn DoIt
 
HandleEvents
</syntaxhighlight>
 
{{out}}
<pre>
1 2 3 a b c
</pre>
 
=={{header|Go}}==
<langsyntaxhighlight lang="go">package main
 
import (
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sort.Slice(chars, func(i, j int) bool { return chars[i] < chars[j] })
fmt.Println(string(chars))
}</langsyntaxhighlight>
 
{{out}}
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=={{header|Haskell}}==
<langsyntaxhighlight lang="haskell">import qualified Data.Map.Strict as M
import Data.Maybe (fromJust)
import qualified Data.Set as S
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"2b6178c97a938stf",
"3ycxdb1fgxa2yz"
]</langsyntaxhighlight>
{{Out}}
<pre>123abc</pre>
 
=={{header|J}}==
<syntaxhighlight lang="j"> /:~@> (e. # [)&.>/ (-. -.@~: # ])&.> '1a3c52debeffd';'2b6178c97a938stf';'3ycxdb1fgxa2yz'
123abc</syntaxhighlight>
 
=={{header|JavaScript}}==
<langsyntaxhighlight lang="javascript">(() => {
"use strict";
 
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wordCount = ws.length;
 
return sort([
...foldrws.slice(1).reduceRight(
(a, x) => compose(intersect, charSet(x)(
) charSet(a)
charSet(ws[0]),
)charSet(ws[0])
ws.slice(1)
)]
.filter(c => wordCount === charFreqs[c])
.filterslice(c => wordCount === charFreqs[c])
).joinsort("");
.join("");
})() : "";
 
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"3ycxdb1fgxa2yz"
]);
 
 
// --------------------- GENERIC ---------------------
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}
), {}
);
 
 
// compose (<<<) :: (b -> c) -> (a -> b) -> a -> c
const compose = (...fs) =>
// A function defined by the right-to-left
// composition of all the functions in fs.
fs.reduce(
(f, g) => x => f(g(x)),
x => x
);
 
 
// foldr :: (a -> b -> b) -> b -> [a] -> b
const foldr = f =>
// Note that that the signature of foldr differs
// from that of foldl - the positions of
// current value and accumulator in f are reversed
acc => xs => [...xs].reduceRight(
(a, x) => f(x)(a),
acc
);
 
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// The intersection of two sets.
b => new Set([...a].filter(i => b.has(i)));
 
 
// sort :: Ord a => [a] -> [a]
const sort = xs =>
// An A-Z sorted copy of xs.
[...xs].slice().sort(
(a, b) => a < b ? -1 : (a > b ? 1 : 0)
);
 
 
// MAIN ---
return main();
})();</langsyntaxhighlight>
{{Out}}
<pre>123abc</pre>
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'''Helper functions'''
<langsyntaxhighlight lang="jq"># bag of words
def bow(stream):
reduce stream as $word ({}; .[($word|tostring)] += 1);
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elif (.[0]|length) == 0 then empty
else [.[0], [ .[1:] | intersections]] | ios
end;</langsyntaxhighlight>
 
'''The task'''
<langsyntaxhighlight lang="jq">def once_in_each_string:
# convert each string to an array of the constituent characters
map((explode | map([.]|implode)))
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["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
| [once_in_each_string]
</syntaxhighlight>
</lang>
{{out}}
<pre>
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=={{header|Julia}}==
<langsyntaxhighlight lang="julia">list = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
 
onceineachstring(list) = filter(c -> all(w -> count(x -> x == c, w) == 1, list), (sort ∘ unique ∘ prod)(list))
 
println(onceineachstring(list))
</langsyntaxhighlight>{{out}}<pre>
['1', '2', '3', 'a', 'b', 'c']
</pre>
 
=={{header|Mathematica}}/{{header|Wolfram Language}}==
<syntaxhighlight lang="mathematica">sets = Characters /@ {"1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"};
uniques = Sort[Select[Tally[#], Last/*EqualTo[1]][[All, 1]]] & /@ sets;
Intersection @@ uniques</syntaxhighlight>
{{out}}
<pre>{"1", "2", "3", "a", "b", "c"}</pre>
 
=={{header|Nim}}==
<langsyntaxhighlight Nimlang="nim">import strutils, tables
 
var result = AllChars
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result = result * uniqueChars # Intersection.
 
echo result</langsyntaxhighlight>
 
{{out}}
Line 613 ⟶ 734:
=={{header|Pascal}}==
{{works with|Extended Pascal}}
<langsyntaxhighlight lang="pascal">program uniqueCharactersInEachString(output);
 
type
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\brief calls `uniqueCharacters` for several strings
\param sample the `array` of strings
\return characters appearing once in at least oneevery \param sample member
}
function allUniqueCharacters(
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{ `type of` is an Extended Pascal extension. }
i: type of sampleMinimum;
lonelyLettersuniqueInEverySample: characters value [chr(0)..maxChar];
begin
for i := sampleMinimum to sampleMaximum do
begin
lonelyLettersuniqueInEverySample := lonelyLettersuniqueInEverySample +* uniqueCharacters(sample[i])
end;
allUniqueCharacters := lonelyLettersuniqueInEverySample
end;
 
Line 696 ⟶ 817:
end;
writeLn
end.</langsyntaxhighlight>
{{out}}
1 2 3 5 6 a b c d f g s t z
 
=={{header|Perl}}==
<langsyntaxhighlight lang="perl">#!/usr/bin/perl
 
use strict; # https://rosettacode.org/wiki/Unique_characters_in_each_string
Line 711 ⟶ 832:
$chars !~ /$_.*$_/ && # the 'only once in each string' test
@strings == $chars =~ s/$_//g, # the 'in every string' test
$chars =~ /./g ]}\n";</langsyntaxhighlight>
{{out}}
<pre>
Line 718 ⟶ 839:
 
=={{header|Phix}}==
<!--<langsyntaxhighlight Phixlang="phix">(phixonline)-->
<span style="color: #008080;">include</span> <span style="color: #000000;">builtins</span><span style="color: #0000FF;">\</span><span style="color: #000000;">sets</span><span style="color: #0000FF;">.</span><span style="color: #000000;">e</span>
Line 730 ⟶ 851:
<span style="color: #000000;">res</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">intersection</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">apply</span><span style="color: #0000FF;">(</span><span style="color: #004600;">true</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">filter</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">apply</span><span style="color: #0000FF;">(</span><span style="color: #000000;">set</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">sort</span><span style="color: #0000FF;">),</span><span style="color: #000000;">once</span><span style="color: #0000FF;">}))</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"found %d unique common characters: %s\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">res</span><span style="color: #0000FF;">),</span><span style="color: #000000;">res</span><span style="color: #0000FF;">})</span>
<!--</langsyntaxhighlight>-->
{{out}}
<pre>
found 6 unique common characters: 123abc
</pre>
 
=={{header|Picat}}==
<syntaxhighlight lang="picat">import ordset.
 
main =>
L = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"],
U = [new_ordset([C : C = 1 in counts(S)]) : S in L],
println(fold(intersection,U.first,U.tail)).
 
% Return a map of occurrences of each element in the list L
counts(L) = Map =>
Map = new_map(),
foreach(E in L)
Map.put(E,Map.get(E,0)+1)
end.</syntaxhighlight>
 
{{out}}
<pre>123abc</pre>
 
=={{header|PicoLisp}}==
<langsyntaxhighlight PicoLisplang="picolisp">(de acc (V K N)
(if (assoc K (val V))
(inc (nth (cadr @) N))
Line 757 ⟶ 896:
"1a3c52debeffd"
"2b6178c97a938stf"
"3ycxdb1fgxa2yz" ) ) )</langsyntaxhighlight>
{{out}}
<pre>
Line 764 ⟶ 903:
 
=={{header|Python}}==
<langsyntaxhighlight lang="python">LIST = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
 
print(sorted([ch for ch in set([c for c in ''.join(LIST)]) if all(w.count(ch) == 1 for w in LIST)]))
</langsyntaxhighlight>{{out}}
<pre>
['1', '2', '3', 'a', 'b', 'c']
</pre>
 
 
Or, avoiding intermediate lists.
 
<syntaxhighlight lang="python">LIST = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
print(sorted(ch for ch in set("".join(LIST)) if all(w.count(ch) == 1 for w in LIST)))</syntaxhighlight>
 
{{out}}
<pre>
['1', '2', '3', 'a', 'b', 'c']
</pre>
 
 
We can also avoid concatenating all strings in the input list.
 
<syntaxhighlight lang="python">from itertools import chain
 
LIST = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
 
print(
sorted(
ch
for ch in set(chain.from_iterable(LIST))
if all(w.count(ch) == 1 for w in LIST)
)
)</syntaxhighlight>
 
{{out}}
<pre>
['1', '2', '3', 'a', 'b', 'c']
</pre>
 
 
Or, avoid calling <code>count()</code> for every distinct character in every string in the input list.
 
<syntaxhighlight lang="python">from collections import Counter
 
LIST = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
 
print(
sorted(
set.intersection(
*(
set(char for char, count in counts.items() if count == 1)
for counts in (Counter(s) for s in LIST)
)
)
)
)</syntaxhighlight>
 
{{out}}
<pre>
['1', '2', '3', 'a', 'b', 'c']
</pre>
 
=={{header|Quackery}}==
 
<syntaxhighlight lang="Quackery"> [ 0 128 of
swap witheach
[ 2dup peek
1+ unrot poke ] ] is countchars ( $ --> [ )
 
[ [] swap witheach
[ 1 = join ] ] is justones ( [ --> [ )
 
[ witheach
[ over i^ peek +
swap i^ poke ] ] is addnests ( [ [ --> [ )
 
[ [] swap witheach
[ 3 = if [ i^ join ] ] ] is threesfound ( [ --> $ )
 
$ "1a3c52debeffd" nested
$ "2b6178c97a938stf" nested join
$ "3ycxdb1fgxa2yz" nested join
 
witheach [ countchars justones ]
2 times addnests
threesfound
witheach [ emit sp ]</syntaxhighlight>
 
{{out}}
 
<pre>1 2 3 a b c </pre>
 
=={{header|Raku}}==
 
<syntaxhighlight lang="raku" perl6line>my $strings = <1a3c52debeffd 2b6178c97a938stf 3ycxdb1fgxa2yz>;
 
put sort keys [∩] $strings.map: *.comb.Bag.grep: *.value == 1</langsyntaxhighlight>
{{out}}
<pre>1 2 3 a b c</pre>
Line 790 ⟶ 1,013:
 
On an &nbsp;'''EBCDIC'''&nbsp; machine, &nbsp; the lowercase letters and the uppercase letters &nbsp; aren't &nbsp; contiguous.
<langsyntaxhighlight lang="rexx">/*REXX pgm finds and shows characters that are unique in each string and once only. */
parse arg $ /*obtain optional arguments from the CL*/
if $='' | $="," then $= '1a3c52debeffd' "2b6178c97a938stf" '3ycxdb1fgxa2yz'
Line 813 ⟶ 1,036:
say 'unique characters are: ' @ /*display the unique characters found. */
say
say 'Found ' L " unique characters." /*display the # of unique chars found. */</langsyntaxhighlight>
{{out|output|text=&nbsp; when using the default input:}}
<pre>
Line 822 ⟶ 1,045:
 
=={{header|Ring}}==
<langsyntaxhighlight lang="ring">
see "working..." + nl
see "Unique characters in each string are:" + nl
Line 868 ⟶ 1,091:
end
return sum
</syntaxhighlight>
</lang>
{{out}}
<pre>
Line 876 ⟶ 1,099:
Found 6 unique characters in each string
done...
</pre>
 
=={{header|RPL}}==
{{works with|HP|48G}}
≪ → word char
≪ 0
1 word SIZE '''FOR''' j
word j DUP SUB char == +
'''NEXT'''
≫ ≫ '<span style="color:blue">OCCHAR</span>' STO
≪ "" → words char
≪ { } words 1 GET
1 OVER SIZE '''FOR''' j
DUP j DUP SUB 'char' STO
words 1 ≪ char <span style="color:blue">OCCHAR</span> ≫ DOLIST
'''IF''' ΠLIST 1 == '''THEN''' SWAP char + SWAP '''END'''
'''NEXT''' DROP SORT
≫ ≫ '<span style="color:blue">UNICHARS</span>' STO
 
{ "1a3c52debeffd" "2b6178c97a938stf" "3ycxdb1fgxa2yz" } <span style="color:blue">UNICHARS</span>
{{out}}
<pre>
1: { "1" "2" "3" "a" "b" "c" }
</pre>
 
=={{header|Ruby}}==
<langsyntaxhighlight lang="ruby">arr = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
 
uniqs_in_str = arr.map{|str| str.chars.tally.filter_map{|char, count| char if count == 1} }
puts uniqs_in_str.inject(&:intersection).sort.join(" ")
</syntaxhighlight>
</lang>
{{out}}
<pre>1 2 3 a b c</pre>
 
=={{header|Transd}}==
<syntaxhighlight lang="Scheme">#lang transd
 
MainModule: {
_start: (lambda locals: pos Position<String>() b Bool()
(for c in (sort "1a3c52debeffd") do (= b true)
(for str in ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"] do
(= pos (find str c))
(if (or (is-end pos) (find Range(in: str (+ (get-idx pos) 1) -0) c))
(= b false)))
(if b (textout c " "))
) )
}</syntaxhighlight>
{{out}}
<pre>
1 2 3 a b c
</pre>
 
=={{header|Wren}}==
{{libheader|Wren-seq}}
{{libheader|Wren-sort}}
<langsyntaxhighlight ecmascriptlang="wren">import "./seq" for Lst
import "./sort" for Sort
 
var strings = ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]
Line 903 ⟶ 1,168:
Sort.insertion(uniqueChars)
System.print("Found %(uniqueChars.count) unique character(s) common to each string, namely:")
System.print(uniqueChars.join(" "))</langsyntaxhighlight>
 
{{out}}
Line 911 ⟶ 1,176:
</pre>
 
=={{header|V (Vlang)}}==
{{trans|go}}
<syntaxhighlight lang="v (vlang)">fn main() {
strings := ["1a3c52debeffd", "2b6178c97a938stf", "3ycxdb1fgxa2yz"]!
mut u := map[rune]int{}
Line 935 ⟶ 1,200:
chars.sort()
println(chars.string())
}</langsyntaxhighlight>
 
{{out}}
Line 943 ⟶ 1,208:
 
=={{header|XPL0}}==
<langsyntaxhighlight XPL0lang="xpl0">char List, Counter(128), Unique(3, 128);
int Char, I, J;
string 0; \use null-terminated string convention
Line 960 ⟶ 1,225:
if Unique(0, Char) & Unique(1, Char) & Unique(2, Char) then
[ChOut(0, Char); ChOut(0, ^ )];
]</langsyntaxhighlight>
 
{{out}}
Line 969 ⟶ 1,234:
=={{header|Yabasic}}==
{{trans|FreeBASIC}}
<langsyntaxhighlight lang="yabasic">sub count_char(s$, c$)
local i, r
r = 0
Line 996 ⟶ 1,261:
print uniq$
end</langsyntaxhighlight>
{{out}}
<pre>123abc</pre>
9,476

edits