UPC: Difference between revisions

Content added Content deleted
(add PicoLisp)
Line 489: Line 489:
{7,0,6,4,6,6,7,4,3,0,3,0}
{7,0,6,4,6,6,7,4,3,0,3,0}
{6,5,3,4,8,3,5,4,0,4,3,5}
{6,5,3,4,8,3,5,4,0,4,3,5}
</pre>

=={{header|PicoLisp}}==
<lang PicoLisp>(de l2n (Lst)
(case Lst
((0 0 0 1 1 0 1) 0)
((0 0 1 1 0 0 1) 1)
((0 0 1 0 0 1 1) 2)
((0 1 1 1 1 0 1) 3)
((0 1 0 0 0 1 1) 4)
((0 1 1 0 0 0 1) 5)
((0 1 0 1 1 1 1) 6)
((0 1 1 1 0 1 1) 7)
((0 1 1 0 1 1 1) 8)
((0 0 0 1 0 1 1) 9) ) )
(de convs (Lst Flg)
(make
(for L Lst
(link
(if2 (= "#" L) Flg 0 1 1 0) ) ) ) )
(de getL (Lst)
(make
(cut 3 'Lst)
(do 6
(link (convs (cut 7 'Lst))) )
(cut 5 'Lst)
(do 6
(link (convs (cut 7 'Lst) T)) ) ) )
(de parse (Str)
(let Lst
(make
(link (clip (chop Str)))
(link (reverse (car (made)))) )
(find
'((N) (fully num? N))
(mapcar '((L) (mapcar l2n (getL L))) Lst) ) ) )
(de upc (Str)
(let Lst (parse Str)
(cons
Lst
(%
(apply + (mapcar * Lst (circ 3 1)))
10 ) ) ) )
(setq *U
(quote
" # # # ## # ## # ## ### ## ### ## #### # # # ## ## # # ## ## ### # ## ## ### # # # "
" # # # ## ## # #### # # ## # ## # ## # # # ### # ### ## ## ### # # ### ### # # # "
" # # # # # ### # # # # # # # # # # ## # ## # ## # ## # # #### ### ## # # "
" # # ## ## ## ## # # # # ### # ## ## # # # ## ## # ### ## ## # # #### ## # # # "
" # # ### ## # ## ## ### ## # ## # # ## # # ### # ## ## # # ### # ## ## # # # "
" # # # # ## ## # # # # ## ## # # # # # #### # ## # #### #### # # ## # #### # # "
" # # # ## ## # # ## ## # ### ## ## # # # # # # # # ### # # ### # # # # # "
" # # # # ## ## # # ## ## ### # # # # # ### ## ## ### ## ### ### ## # ## ### ## # # "
" # # ### ## ## # # #### # ## # #### # #### # # # # # ### # # ### # # # ### # # # "
" # # # #### ## # #### # # ## ## ### #### # # # # ### # ### ### # # ### # # # ### # # " ) )
(for L (mapcar upc *U)
(println (if (car L) @ 'invalid)) )</lang>
{{out}}
<pre>
(9 2 4 7 7 3 2 7 1 0 1 9)
(4 0 3 9 4 4 4 4 1 0 5 0)
(8 3 4 9 9 9 6 7 6 7 0 6)
(9 3 9 8 2 5 1 5 8 8 1 1)
invalid
(3 1 6 3 1 3 7 1 8 7 1 7)
(2 1 4 5 7 5 8 7 5 6 0 8)
(8 1 8 7 7 8 8 4 1 8 1 3)
(7 0 6 4 6 6 7 4 3 0 3 0)
(6 5 3 4 8 3 5 4 0 4 3 5)
</pre>
</pre>