Triplet of three numbers: Difference between revisions
Added 11l
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Numbers '''n''' such that the three numbers '''n-1''', '''n+3''', and '''n+5''' are all prime, where '''n < 6,000.'''
<br><br>
=={{header|11l}}==
{{trans|Python}}
<lang 11l>V n = 6000
V p = [0B] * 6000
L(i) 2 .< Int(round(sqrt(n)))
I !p[i]
L(j) (i * 2 .< n).step(i)
p[j] = 1B
L(i) 3 .< n
I (p[i - 1] | p[i + 3] | p[i + 5])
L.continue
E
print(f:‘{i:4}: {i - 1:4} {i + 3:4} {i + 5:4}’)</lang>
{{out}}
<pre>
8: 7 11 13
14: 13 17 19
38: 37 41 43
68: 67 71 73
98: 97 101 103
104: 103 107 109
194: 193 197 199
224: 223 227 229
278: 277 281 283
308: 307 311 313
458: 457 461 463
614: 613 617 619
824: 823 827 829
854: 853 857 859
878: 877 881 883
1088: 1087 1091 1093
1298: 1297 1301 1303
1424: 1423 1427 1429
1448: 1447 1451 1453
1484: 1483 1487 1489
1664: 1663 1667 1669
1694: 1693 1697 1699
1784: 1783 1787 1789
1868: 1867 1871 1873
1874: 1873 1877 1879
1994: 1993 1997 1999
2084: 2083 2087 2089
2138: 2137 2141 2143
2378: 2377 2381 2383
2684: 2683 2687 2689
2708: 2707 2711 2713
2798: 2797 2801 2803
3164: 3163 3167 3169
3254: 3253 3257 3259
3458: 3457 3461 3463
3464: 3463 3467 3469
3848: 3847 3851 3853
4154: 4153 4157 4159
4514: 4513 4517 4519
4784: 4783 4787 4789
5228: 5227 5231 5233
5414: 5413 5417 5419
5438: 5437 5441 5443
5648: 5647 5651 5653
5654: 5653 5657 5659
5738: 5737 5741 5743
</pre>
=={{header|Action!}}==
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