Textonyms: Difference between revisions
Added Swift solution
(Added Swift solution) |
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Line 2,394:
["49376746242", ["hydrophobia", "hydrophobic"]]
["2668368466", ["contention", "convention"]]
</pre>
=={{header|Swift}}==
<lang swift>import Foundation
func textCharacter(_ ch: Character) -> Character? {
switch (ch) {
case "a", "b", "c":
return "2"
case "d", "e", "f":
return "3"
case "g", "h", "i":
return "4"
case "j", "k", "l":
return "5"
case "m", "n", "o":
return "6"
case "p", "q", "r", "s":
return "7"
case "t", "u", "v":
return "8"
case "w", "x", "y", "z":
return "9"
default:
return nil
}
}
func textString(_ string: String) -> String? {
var result = String()
result.reserveCapacity(string.count)
for ch in string {
if let tch = textCharacter(ch) {
result.append(tch)
} else {
return nil
}
}
return result
}
func compareByWordCount(pair1: (key: String, value: [String]),
pair2: (key: String, value: [String])) -> Bool {
if pair1.value.count == pair2.value.count {
return pair1.key < pair2.key
}
return pair1.value.count > pair2.value.count
}
func compareByTextLength(pair1: (key: String, value: [String]),
pair2: (key: String, value: [String])) -> Bool {
if pair1.key.count == pair2.key.count {
return pair1.key < pair2.key
}
return pair1.key.count > pair2.key.count
}
func findTextonyms(_ path: String) throws {
var dict = Dictionary<String, [String]>()
let contents = try String(contentsOfFile: path, encoding: String.Encoding.ascii)
var count = 0
for line in contents.components(separatedBy: "\n") {
if line.isEmpty {
continue
}
let word = line.lowercased()
if let text = textString(word) {
if var words = dict[text] {
words.append(word)
dict[text] = words
} else {
dict[text] = [word]
}
count += 1
}
}
var textonyms = Array(dict.filter{$0.1.count > 1})
print("There are \(count) words in '\(path)' which can be represented by the digit key mapping.")
print("They require \(dict.count) digit combinations to represent them.")
print("\(textonyms.count) digit combinations represent Textonyms.")
let top = min(5, textonyms.count)
print("\nTop \(top) by number of words:")
textonyms.sort(by: compareByWordCount)
for (text, words) in textonyms.prefix(top) {
print("\(text) = \(words.joined(separator: ", "))")
}
print("\nTop \(top) by length:")
textonyms.sort(by: compareByTextLength)
for (text, words) in textonyms.prefix(top) {
print("\(text) = \(words.joined(separator: ", "))")
}
}
do {
try findTextonyms("unixdict.txt")
} catch {
print(error.localizedDescription)
}</lang>
{{out}}
<pre>
There are 24978 words in 'unixdict.txt' which can be represented by the digit key mapping.
They require 22903 digit combinations to represent them.
1473 digit combinations represent Textonyms.
Top 5 by number of words:
269 = amy, any, bmw, bow, box, boy, cow, cox, coy
729 = paw, pax, pay, paz, raw, ray, saw, sax, say
2273 = acre, bard, bare, base, cape, card, care, case
726 = pam, pan, ram, ran, sam, san, sao, scm
426 = gam, gao, ham, han, ian, ibm, ibn
Top 5 by length:
25287876746242 = claustrophobia, claustrophobic
7244967473642 = schizophrenia, schizophrenic
666628676342 = onomatopoeia, onomatopoeic
49376746242 = hydrophobia, hydrophobic
2668368466 = contention, convention
</pre>
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