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Talk:Van der Corput sequence: Difference between revisions
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→displaying of terms: added whitespace.
(questioning validity of most outputs -- ~~~~) |
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__TOC__
== Python output ==
Looks to me like the base 2 sample output for the Python example is actually base 3?--[[User:Tikkanz|Tikkanz]] 08:34, 11 March 2011 (UTC)
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== displaying of terms ==
In every reference I've looked at, the 2nd term of the van der Corput
'''.1'''
<br><br>I suggest that trailing zeroes illegitimatizes the terms.
<br><br>I suggest that trailing zeroes illegitimize the terms. Mathematically, of course, .1 is equal to .100 (except to an engineer, where trailing zeroes signify more precision). -- [[User:Gerard Schildberger|Gerard Schildberger]] 03:28, 26 March 2012 (UTC)▼
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==Generation of the image in the task description==
My windows machine has packed up so I am using Ipython on Ubuntu. I did the following to create the image:
<lang python>In [211]: from __future__ import division
In [212]: def vdc(n, base=2):
...: vdc, denom = 0,1
...: while n:
...: denom *= base
...: n, remainder = divmod(n, base)
...: vdc += remainder / denom
...: return vdc
In [213]: plt.plot([(random.random()*0.5, 0.5+vdc(i)*0.5) for i in range(2500)], '.')
Out[213]:
[<matplotlib.lines.Line2D at 0x12c73f2c>,
<matplotlib.lines.Line2D at 0x1311fe4c>]
In [214]: plt.title('Distribution: Van der Corput (top) vs pseudorandom')
Out[214]: <matplotlib.text.Text at 0x12ed6fcc>
In [215]: </lang>
--[[User:Paddy3118|Paddy3118]] 21:59, 7 August 2012 (UTC)
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