Talk:Smallest enclosing circle problem: Difference between revisions

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Did you mean to say 2-dimensional space instead of n-dimensional space? -- Gerard Schildberger (talk) 22:58, 2 November 2020 (UTC)

3-dimensional space would require a sphere to contain a given set of points. -- Gerard Schildberger (talk) 22:58, 2 November 2020 (UTC)

4-dimensional space would require a hypersphere (or glome) to contain a given set of points. -- Gerard Schildberger (talk) 22:58, 2 November 2020 (UTC)

Any Dr. Who fans around or anyone who owns a TARDIS? -- Gerard Schildberger (talk) 23:03, 2 November 2020 (UTC)

As long as we are using Euclidean space, isn't this just a matter of finding the largest distance between any 2 of the points and dividing by 2? The minumum radius center is the midpoint of the longest connecting line segment?? --Wherrera (talk) 23:38, 2 November 2020 (UTC)

Revision as of 23:04, 2 November 2020 (view source) rosettacode>Gerard Schildberger m (→‎task wording: added a query.) ← Older edit		Revision as of 23:38, 2 November 2020 (view source) Wherrera (talk \| contribs) No edit summary Newer edit →
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	Any Dr. Who fans around or anyone who owns a TARDIS?     -- [[User:Gerard Schildberger\|Gerard Schildberger]] ([[User talk:Gerard Schildberger\|talk]]) 23:03, 2 November 2020 (UTC)		Any Dr. Who fans around or anyone who owns a TARDIS?     -- [[User:Gerard Schildberger\|Gerard Schildberger]] ([[User talk:Gerard Schildberger\|talk]]) 23:03, 2 November 2020 (UTC)

			As long as we are using Euclidean space, isn't this just a matter of finding the largest distance between any 2 of the points and dividing by 2? The minumum radius center is the midpoint of the longest connecting line segment?? --[[User:Wherrera\|Wherrera]] ([[User talk:Wherrera\|talk]]) 23:38, 2 November 2020 (UTC)