Rosetta Code

Talk:Parse EBNF/Tests

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Revision as of 01:51, 9 September 2011 by rosettacode>Kernigh (I guess because it never defines a production for ''bar''.)

Why the example provided at the bottom of the page

{ foo = bar . }

is not a valid EBNF grammar, according to the accepted definition?

I guess because it never defines a production for bar. --Kernigh 01:51, 9 September 2011 (UTC)
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