Talk:Averages/Mean angle: Difference between revisions

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-2.28847549044e-17j
-2.28847549044e-17j
:The angle is then calculated from whatever nonzero components that this small non-zero number happens to have. Getting an angle from a mean this small is unstable, because any tiny change (perhaps by a different order of calculations, resulting in different behavior of the error) would result in a radically different angle. --[[User:Spoon!|Spoon!]] 05:35, 10 July 2012 (UTC)
:The angle is then calculated from whatever nonzero components that this small non-zero number happens to have. Getting an angle from a mean this small is unstable, because any tiny change (perhaps by a different order of calculations, resulting in different behavior of the error) would result in a radically different angle. --[[User:Spoon!|Spoon!]] 05:35, 10 July 2012 (UTC)

::Hmm - I did rush this as I was very tired. This draft task might start a little shakily but I did try to gather the essence of something that had not occurred to me before last night and I intend to tidy-up so please criticise away and make/suggest improvements. I am feeling quite sheepish about having computed average times (another circular mean), for so long and not been actively aware of what I had been doing. --[[User:Paddy3118|Paddy3118]] 06:55, 10 July 2012 (UTC)

:: Which reminds me that I should work on a similar task for mean times. --[[User:Paddy3118|Paddy3118]] 06:55, 10 July 2012 (UTC)

Revision as of 06:55, 10 July 2012

Accuracy

Huh, the mean angle of 90, 180, 270 and 360 is "-90.0 degrees"? Doesn't that sound a little fruity? --Ledrug 23:31, 9 July 2012 (UTC)

Well, if done exactly, the mean of those complex numbers should be 0, and then the angle would be, well, undefined, or perhaps whatever default the library picks (like 0). But what is actually happening in this case is that the mean of those complex numbers is not calculated to be exactly 0, due to floating-point error when converting between degrees and radians, and then converting between rectangular and polar coordinates. It is a very small number that is very close to 0
>>> print sum(rect(1, radians(d)) for d in [90, 180, 270, 360])
-2.28847549044e-17j
The angle is then calculated from whatever nonzero components that this small non-zero number happens to have. Getting an angle from a mean this small is unstable, because any tiny change (perhaps by a different order of calculations, resulting in different behavior of the error) would result in a radically different angle. --Spoon! 05:35, 10 July 2012 (UTC)
Hmm - I did rush this as I was very tired. This draft task might start a little shakily but I did try to gather the essence of something that had not occurred to me before last night and I intend to tidy-up so please criticise away and make/suggest improvements. I am feeling quite sheepish about having computed average times (another circular mean), for so long and not been actively aware of what I had been doing. --Paddy3118 06:55, 10 July 2012 (UTC)
Which reminds me that I should work on a similar task for mean times. --Paddy3118 06:55, 10 July 2012 (UTC)