Positive decimal integers with the digit 1 occurring exactly twice: Difference between revisions
Positive decimal integers with the digit 1 occurring exactly twice (view source)
Revision as of 21:31, 1 January 2023
, 1 year agoAdded PL/M
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{{out}}
<pre>11 101 110 112 113 114 115 116 117 118 119 121 131 141 151 161 171 181 191 211 311 411 511 611 711 811 911</pre>
=={{header|PL/M}}==
{{works with|8080 PL/M Compiler}} ... under CP/M (or an emulator)
<syntaxhighlight lang="plm">
100H: /* FIND NUMBERS BELOW 1000 WHERE 1 OCCURS TWICE IN THIER DECIMAL */
/* REPRESENTATION */
/* CP/M SYSTEM CALL AND I/O ROUTINES */
BDOS: PROCEDURE( FN, ARG ); DECLARE FN BYTE, ARG ADDRESS; GOTO 5; END;
PR$CHAR: PROCEDURE( C ); DECLARE C BYTE; CALL BDOS( 2, C ); END;
PR$STRING: PROCEDURE( S ); DECLARE S ADDRESS; CALL BDOS( 9, S ); END;
PR$NL: PROCEDURE; CALL PR$CHAR( 0DH ); CALL PR$CHAR( 0AH ); END;
PR$NUMBER: PROCEDURE( N ); /* PRINTS A NUMBER IN THE MINIMUN FIELD WIDTH */
DECLARE N ADDRESS;
DECLARE V ADDRESS, N$STR ( 6 )BYTE, W BYTE;
V = N;
W = LAST( N$STR );
N$STR( W ) = '$';
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
DO WHILE( ( V := V / 10 ) > 0 );
N$STR( W := W - 1 ) = '0' + ( V MOD 10 );
END;
CALL PR$STRING( .N$STR( W ) );
END PR$NUMBER;
/* TASK */
DECLARE ( I, V, COUNT, ONE$COUNT ) ADDRESS;
COUNT = 0;
DO I = 10 TO 999;
V = I;
ONE$COUNT = 0;
DO WHILE V > 0;
IF V MOD 10 = 1 THEN DO;
ONE$COUNT = ONE$COUNT + 1;
END;
V = V / 10;
END;
IF ONE$COUNT = 2 THEN DO;
CALL PR$CHAR( ' ' );
IF I < 100 THEN CALL PR$CHAR( ' ' );
CALL PR$NUMBER( I );
IF ( COUNT := COUNT + 1 ) MOD 10 = 0 THEN CALL PR$NL;
END;
END;
EOF
</syntaxhighlight>
{{out}}
<pre>
11 101 110 112 113 114 115 116 117 118
119 121 131 141 151 161 171 181 191 211
311 411 511 611 711 811 911
</pre>
=={{header|Python}}==
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