Sum of divisors: Difference between revisions
Add Fortran
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</pre>
=={{header|Fortran}}==
<lang fortran> program DivSum
implicit none
integer i, j, col, divs(100)
do 10 i=1, 100, 1
10 divs(i) = 1
do 20 i=2, 100, 1
do 20 j=i, 100, i
20 divs(j) = divs(j) + i
col = 0
do 30 i=1, 100, 1
write (*,'(I4)',advance='no') divs(i)
col = col + 1
if (col .eq. 10) then
col = 0
write (*,*)
end if
30 continue
end program </lang>
{{out}}
<pre> 1 3 4 7 6 12 8 15 13 18
12 28 14 24 24 31 18 39 20 42
32 36 24 60 31 42 40 56 30 72
32 63 48 54 48 91 38 60 56 90
42 96 44 84 78 72 48 124 57 93
72 98 54 120 72 120 80 90 60 168
62 96 104 127 84 144 68 126 96 144
72 195 74 114 124 140 96 168 80 186
121 126 84 224 108 132 120 180 90 234
112 168 128 144 120 252 98 171 156 217</pre>
=={{header|FreeBASIC}}==
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