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Word break problem: Difference between revisions

m
Line 12:
String val
[String] parsed
F (val, [String] &parsed = [String]())
.val = val
.parsed = copy(parsed)
 
F word_break(s, dictionary)
Line 29:
V parsed_new = copy(node.parsed)
parsed_new [+]= word
queue [+]= Node(val_new, &parsed_new)
R matches
 
1,481

edits

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