Sorting algorithms/Bubble sort: Difference between revisions
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{{out}}
<pre>1 2 3 4 5 6 7 8 9 10</pre>
=={{header|Befunge}}==
<syntaxhighlight lang="befunge">
000p&: v >20g:7g\1+7g2v
v00p7g00 _10p0>20p20g:7g\1+7g`|0p7+1g02p7g0<
>g1+00p&:^ |-\g00:+1g02 <
0 >$10gv
|-\g00:+1 <
>1->:7g\:#v_$>:#._25*,@
^ <
</syntaxhighlight>
=={{header|C}}==
Line 3,207 ⟶ 3,219:
=={{header|EasyLang}}==
<syntaxhighlight lang="easylang">
repeat
swap a[i] a[i + 1]
.
.
until
.
.
array[] = [ 5 1 19 25 12 1 14 7 ]
print array[]
</syntaxhighlight>
Line 3,520 ⟶ 3,525:
=={{header|Elena}}==
{{trans|C#}}
ELENA
<syntaxhighlight lang="elena">import system'routines;
import extensions;
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madeChanges := false;
itemCount -= 1;
for(int i := 0
{
if (list[i] > list[i + 1])
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(1 2 3)
</syntaxhighlight>
=={{header|GDScript}}==
Here is an implementation of Bubble Sort algorithm in GDScript for array of primitive types:
<syntaxhighlight lang="gdscript">
extends Node2D
func BubbleSort(_array : Array) -> void:
for i in range(_array.size() - 1):
var swapped : bool = false
for j in range(_array.size() - i - 1):
if _array[j] > _array[j + 1]:
var tmp = _array[j]
_array[j] = _array[j + 1]
_array[j + 1] = tmp
swapped = true
if not swapped:
break
return
func _ready() -> void:
var array : Array = range(-10, 10)
array.shuffle()
print("Initial array:")
print(array)
BubbleSort(array)
print("Sorted array:")
print(array)
return
</syntaxhighlight>
Possible output:
{{out}}
<pre>
Initial array:
[-7, -6, 2, -8, 4, -1, -3, -5, 5, -10, -4, 7, 3, 8, 0, -9, 6, 9, -2, 1]
Sorted array:
[-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
</pre>
If you need to sort objects, this can be done in way like this:
<syntaxhighlight lang="gdscript">
class Comparable:
var Value
func _init(_val):
self.Value = _val
func compare(_other : Comparable) -> int:
# Here is the simple implementation of compare
# for primitive type wrapper.
return self.Value - _other.Value
func BubbleSortObjects(_array : Array) -> void:
for i in range(_array.size() - 1):
var swapped : bool = false
for j in range(_array.size() - i - 1):
if _array[j].compare(_array[j + 1]) > 0:
var tmp = _array[j]
_array[j] = _array[j + 1]
_array[j + 1] = tmp
swapped = true
if not swapped:
break
return
</syntaxhighlight>
This approach is slow though. To sort array of primitive types use Array.sort() method instead.
To sort array of objects you can use Array.sort_custom(func : Callable) method.
=={{header|Go}}==
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1 2 3 4 5 6 7 8 9</pre>
=={{header|Maxima}}==
<syntaxhighlight lang="maxima">
bubble_sort(u) := block(
[n: length(u), swapped: true, temp],
while swapped do (
swapped: false,
for i: 1 thru n - 1 do (
if u[i] > u[i + 1] then (
temp: u[i],
u[i]: u[i + 1],
u[i + 1]: temp,
swapped: true
)
)
),
u
);
/* Example */
/* sample:[3,65,6,24,24,89,2,59,6]$
bubble_sort(%);
[2,3,6,6,24,24,59,65,89]
*/
</syntaxhighlight>
=={{header|MAXScript}}==
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=={{header|Standard ML}}==
Assumes a list of integers.
<syntaxhighlight lang="sml">
fun bubble_select [] = []
| bubble_select [a] = [a]
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fun bubblesort [] = []
| bubblesort (x::xs) =bubble_select (x::(bubblesort xs))
</syntaxhighlight>
=={{header|Stata}}==
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=={{header|Wren}}==
Based on the pseudo-code in the Wikipedia article.
<syntaxhighlight lang="
var n = a.count
if (n < 2) return
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}
var
for (a in
System.print("Before: %(a)")
bubbleSort.call(a)
|