Sort a list of object identifiers: Difference between revisions

From Rosetta Code
Content added Content deleted
Line 773: Line 773:
Data "1.3.6.1.4.1.11.2.17.19.3.4.0.10", "1.3.6.1.4.1.11.2.17.5.2.0.79", "1.3.6.1.4.1.11150.3.4.0"
Data "1.3.6.1.4.1.11.2.17.19.3.4.0.10", "1.3.6.1.4.1.11.2.17.5.2.0.79", "1.3.6.1.4.1.11150.3.4.0"
Dim Base 0, arr(Stack.Size)
Dim Base 0, arr(Stack.Size)
i=0 : While not Empty {let arr(i)=piece$(letter$+".", ".") : i++ }
link arr() to arr$()
i=0 : While not Empty {arr$(i)=piece$(letter$+".", ".") : i++ }
}
}

For i=0 to len(arr())-1 {
For i=0 to len(arr())-1 {
Print join$(arr(i))
Print join$(arr(i))

Revision as of 07:35, 2 November 2018

Task
Sort a list of object identifiers
You are encouraged to solve this task according to the task description, using any language you may know.

Sorting Algorithm
This is a sorting algorithm.   It may be applied to a set of data in order to sort it.     For comparing various sorts, see compare sorts.   For other sorting algorithms,   see sorting algorithms,   or:

O(n logn) sorts

Heap sort | Merge sort | Patience sort | Quick sort

O(n log2n) sorts
Shell Sort

O(n2) sorts
Bubble sort | Cocktail sort | Cocktail sort with shifting bounds | Comb sort | Cycle sort | Gnome sort | Insertion sort | Selection sort | Strand sort

other sorts
Bead sort | Bogo sort | Common sorted list | Composite structures sort | Custom comparator sort | Counting sort | Disjoint sublist sort | External sort | Jort sort | Lexicographical sort | Natural sorting | Order by pair comparisons | Order disjoint list items | Order two numerical lists | Object identifier (OID) sort | Pancake sort | Quickselect | Permutation sort | Radix sort | Ranking methods | Remove duplicate elements | Sleep sort | Stooge sort | [Sort letters of a string] | Three variable sort | Topological sort | Tree sort

Object identifiers (OID) are strings used to identify objects in network data.


Task

Show how to sort a list of OIDs, in their natural sort order.

Details
  • An OID consists of one or more non-negative integers in base 10, separated by dots. It starts and ends with a number.
  • Their natural sort order is lexicographical with regard to the dot-separated fields, using numeric comparison between fields.
Test case
Input (list of strings) Output (list of strings)

1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11150.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11150.3.4.0

1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Related tasks

C#

<lang csharp>using System; using System.Linq; using System.Collections.Generic;

public class Program { 

   public static void Main() {
       var oids = new [] {
           "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
           "1.3.6.1.4.1.11.2.17.5.2.0.79",
           "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
           "1.3.6.1.4.1.11150.3.4.0.1",
           "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
           "1.3.6.1.4.1.11150.3.4.0"
       };

       var comparer = Comparer<string>.Create((a, b) => {
           int c = a.Split('.').Select(int.Parse)

.Zip(b.Split('.').Select(int.Parse), 

                   (i, j) => i.CompareTo(j)).FirstOrDefault(x => x != 0);
           return c != 0 ? c : a.Length.CompareTo(b.Length);
       });

       Array.Sort(oids, comparer);

       Console.WriteLine(string.Join(Environment.NewLine, oids));
   }

}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

C++

<lang Cpp>#include <string>

  1. include <vector>
  2. include <algorithm>
  3. include <boost/tokenizer.hpp>
  4. include <iostream>

std::vector<std::string> splitOnChar ( std::string & s , const char c ) { 

  typedef boost::tokenizer<boost::char_separator<char>> tokenizer ;
  std::vector<std::string> parts ;
  boost::char_separator<char> sep( &c ) ;
  tokenizer tokens( s , sep ) ;
  for ( auto it = tokens.begin( ) ; it != tokens.end( ) ; it++ ) 
     parts.push_back( *it ) ;
  return parts ;

}

bool myCompare ( const std::string & s1 , const std::string & s2 ) { 

  std::string firstcopy( s1 ) ;
  std::string secondcopy ( s2 ) ;
  std::vector<std::string> firstparts( splitOnChar ( firstcopy, '.' ) ) ;
  std::vector<std::string> secondparts( splitOnChar ( secondcopy, '.' ) ) ;
  std::vector<int> numbers1( firstparts.size( ) ) ;
  std::vector<int> numbers2( secondparts.size( ) ) ;
  std::transform( firstparts.begin( ) , firstparts.end( ) , numbers1.begin( ) ,

[]( std::string st ) { return std::stoi( st , nullptr ) ; } ) ; 

  std::transform( secondparts.begin( ) , secondparts.end( ) , numbers2.begin( ) ,

[]( std::string st ) { return std::stoi( st , nullptr ) ; } ) ; 

  auto it1 = numbers1.begin( ) ;
  auto it2 = numbers2.begin( ) ;
  while ( *it1 == *it2 ) {
     it1++ ;
     it2++ ;
  }
  if ( it1 == numbers1.end( )  || it2 == numbers2.end( )  )
     return std::lexicographical_compare( s1.begin( ) , s1.end( ) , s2.begin( ) , s2.end( ) ) ;
  return *it1 < *it2 ;

}

int main( ) { 

  std::vector<std::string> arrayOID { "1.3.6.1.4.1.11.2.17.19.3.4.0.10" ,
     "1.3.6.1.4.1.11.2.17.5.2.0.79" ,
     "1.3.6.1.4.1.11.2.17.19.3.4.0.4" ,
     "1.3.6.1.4.1.11150.3.4.0.1" ,
     "1.3.6.1.4.1.11.2.17.19.3.4.0.1" ,
     "1.3.6.1.4.1.11150.3.4.0" } ;
  std::sort( arrayOID.begin( ) , arrayOID.end( ) , myCompare ) ;
  for ( std::string s : arrayOID ) 
     std::cout << s << '\n' ;
  return 0 ;

}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Common Lisp

<lang lisp>(defun oid->list (oid) 

 (loop for start = 0 then (1+ pos)
       for pos = (position #\. oid :start start)
       collect (parse-integer oid :start start :end pos)
       while pos))

(defun list< (list1 list2) 

 (loop for e1 in list1
       for e2 in list2
       do (cond ((< e1 e2)
                 (return t))
                ((> e1 e2)
                 (return nil)))
       finally (return (< (length list1) (length list2)))))

(defun sort-oids (oids) 

 (sort oids #'list< :key #'oid->list))

(defun main () 

 (let ((oids (list "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
                   "1.3.6.1.4.1.11.2.17.5.2.0.79"
                   "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
                   "1.3.6.1.4.1.11150.3.4.0.1"
                   "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
                   "1.3.6.1.4.1.11150.3.4.0")))
   (dolist (oid (sort-oids oids))
     (write-line oid))))</lang>
Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Elixir

<lang elixir>defmodule Sort_by_OID do 

 def numbers(list) do
   Enum.sort_by(list, fn oid ->
     String.split(oid, ".") |> Enum.map(&String.to_integer/1)
   end)
 end

end

~w[ 

 1.3.6.1.4.1.11.2.17.19.3.4.0.10
 1.3.6.1.4.1.11.2.17.5.2.0.79
 1.3.6.1.4.1.11.2.17.19.3.4.0.4
 1.3.6.1.4.1.11150.3.4.0.1
 1.3.6.1.4.1.11.2.17.19.3.4.0.1
 1.3.6.1.4.1.11150.3.4.0

] |> Sort_by_OID.numbers |> Enum.each(fn oid -> IO.puts oid end)</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Factor

Factor provides the human<=> word which converts numbers in a string to integers before comparing them. <lang factor>USING: io qw sequences sorting sorting.human ;

qw{ 

   1.3.6.1.4.1.11.2.17.19.3.4.0.10
   1.3.6.1.4.1.11.2.17.5.2.0.79
   1.3.6.1.4.1.11.2.17.19.3.4.0.4
   1.3.6.1.4.1.11150.3.4.0.1
   1.3.6.1.4.1.11.2.17.19.3.4.0.1
   1.3.6.1.4.1.11150.3.4.0

} [ human<=> ] sort [ print ] each</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Go

<lang go>package main

import ( 

   "fmt"
   "log"
   "math/big"
   "sort"
   "strings"

)

var testCases = []string{ 

   "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
   "1.3.6.1.4.1.11.2.17.5.2.0.79",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
   "1.3.6.1.4.1.11150.3.4.0.1",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
   "1.3.6.1.4.1.11150.3.4.0",

}

// a parsed representation type oid []big.Int

// "constructor" parses string representation func newOid(s string) oid { 

   ns := strings.Split(s, ".")
   os := make(oid, len(ns))
   for i, n := range ns {
       if _, ok := os[i].SetString(n, 10); !ok || os[i].Sign() < 0 {
           return nil
       }
   }
   return os

}

// "stringer" formats into string representation func (o oid) String() string { 

   s := make([]string, len(o))
   for i, n := range o {
       s[i] = n.String()
   }
   return strings.Join(s, ".")

}

func main() { 

   // parse test cases
   os := make([]oid, len(testCases))
   for i, s := range testCases {
       os[i] = newOid(s)
       if os[i] == nil {
           log.Fatal("invalid OID")
       }
   }
   // sort
   sort.Slice(os, func(i, j int) bool {
       // "less" function must return true if os[i] < os[j]
       oi := os[i]
       for x, v := range os[j] {
           // lexicographic defintion: less if prefix or if element is <
           if x == len(oi) || oi[x].Cmp(&v) < 0 {
               return true
           }
           if oi[x].Cmp(&v) > 0 {
               break
           }
       }
       return false
   })
   // output sorted list
   for _, o := range os {
       fmt.Println(o)
   }

}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Haskell

Data.List

<lang Haskell>import Data.List ( sort , intercalate )

splitString :: Eq a => (a) -> [a] -> a splitString c [] = [] splitString c s = let ( item , rest ) = break ( == c ) s 

                     ( _ , next ) = break ( /= c ) rest

in item : splitString c next

convertIntListToString :: [Int] -> String convertIntListToString = intercalate "." . map show

orderOID :: [String] -> [String] orderOID = map convertIntListToString . sort . map ( map read . splitString '.' )

oid :: [String] oid = ["1.3.6.1.4.1.11.2.17.19.3.4.0.10" , 

   "1.3.6.1.4.1.11.2.17.5.2.0.79" ,
   "1.3.6.1.4.1.11.2.17.19.3.4.0.4" ,
   "1.3.6.1.4.1.11150.3.4.0.1" ,
   "1.3.6.1.4.1.11.2.17.19.3.4.0.1" ,
   "1.3.6.1.4.1.11150.3.4.0"]

main :: IO ( ) main = do 

  mapM_ putStrLn $ orderOID oid</lang>
Output:
3.6.1.4.1.11.2.17.5.2.0.79
3.6.1.4.1.11.2.17.19.3.4.0.1
3.6.1.4.1.11.2.17.19.3.4.0.4
3.6.1.4.1.11.2.17.19.3.4.0.10
3.6.1.4.1.11150.3.4.0
3.6.1.4.1.11150.3.4.0.1

Data.Text

(To use split :: (Char -> Bool) -> Text -> [Text] in the standard libraries, we would have to temporarily convert the strings from [Char] to Text with pack and unpack)

<lang haskell>import Data.Text (pack, split, unpack) import Data.List (sort, intercalate)

-- SORTING OBJECT IDENTIFIERS ------------------------------------------------ oidSort :: [String] -> [String] oidSort = 

 fmap (intercalate "." . fmap show) .
 sort . fmap (fmap readInt . splitString '.')

-- GENERIC FUNCTIONS --------------------------------------------------------- splitString :: Char -> String -> [String] splitString c s = unpack <$> split (c ==) (pack s)

readInt :: String -> Int readInt xs = read xs :: Int

-- TEST ---------------------------------------------------------------------- main :: IO () main = 

 mapM_ putStrLn $
 oidSort
   [ "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
   , "1.3.6.1.4.1.11.2.17.5.2.0.79"
   , "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
   , "1.3.6.1.4.1.11150.3.4.0.1"
   , "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
   , "1.3.6.1.4.1.11150.3.4.0"
   ]</lang>
Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Where Data.List.Split is available (https://hackage.haskell.org/package/split-0.2.3.1/docs/Data-List-Split.html) we can alternatively write:

<lang haskell>import Data.List.Split (splitOn) import Data.List (sort, intercalate)

-- SORTING OBJECT IDENTIFIERS ------------------------------------------------ oidSort :: [String] -> [String] oidSort = 

 fmap (intercalate "." . fmap show) . sort . fmap (fmap readInt . splitOn ".")

readInt :: String -> Int readInt x = read x :: Int</lang>

jq

<lang jq>def data: [ 

"1.3.6.1.4.1.11.2.17.19.3.4.0.10",
"1.3.6.1.4.1.11.2.17.5.2.0.79",
"1.3.6.1.4.1.11.2.17.19.3.4.0.4",
"1.3.6.1.4.1.11150.3.4.0.1",
"1.3.6.1.4.1.11.2.17.19.3.4.0.1",
"1.3.6.1.4.1.11150.3.4.0"
];

data | map( split(".") | map(tonumber) ) | sort | map(join("."))</lang>

Output:
[
  "1.3.6.1.4.1.11.2.17.5.2.0.79",
  "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
  "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
  "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
  "1.3.6.1.4.1.11150.3.4.0",
  "1.3.6.1.4.1.11150.3.4.0.1"
]

J

Data:

<lang J>oids=:<@-.&' ';._2]0 :0 

 1.3.6.1.4.1.11.2.17.19.3.4.0.10
 1.3.6.1.4.1.11.2.17.5.2.0.79
 1.3.6.1.4.1.11.2.17.19.3.4.0.4
 1.3.6.1.4.1.11150.3.4.0.1
 1.3.6.1.4.1.11.2.17.19.3.4.0.1
 1.3.6.1.4.1.11150.3.4.0

)</lang>

In other words, for each line in that script, remove the spaces and put the rest in a box.

Sorting:

<lang J> >(/: __&".;._1&.('.'&,)&>) oids 1.3.6.1.4.1.11.2.17.5.2.0.79 1.3.6.1.4.1.11.2.17.19.3.4.0.1 1.3.6.1.4.1.11.2.17.19.3.4.0.4 1.3.6.1.4.1.11.2.17.19.3.4.0.10 1.3.6.1.4.1.11150.3.4.0 1.3.6.1.4.1.11150.3.4.0.1 </lang>

In other words, for our sort key, we break the contents of each box by an initial '.' and treat the remainder as numbers.

We also pull the result out of its boxes for display purposes.

Java

Works with: Java version 8 or higher

<lang java> package com.rosettacode;

import java.util.Comparator; import java.util.stream.Stream;

public class OIDListSorting { 

   public static void main(String[] args) {

       final String dot = "\\.";

       final Comparator<String> oids_comparator = (o1, o2) -> {
           final String[] o1Numbers = o1.split(dot), o2Numbers = o2.split(dot);
           for (int i = 0; ; i++) {
               if (i == o1Numbers.length && i == o2Numbers.length)
                   return 0;
               if (i == o1Numbers.length)
                   return -1;
               if (i == o2Numbers.length)
                   return 1;
               final int nextO1Number = Integer.valueOf(o1Numbers[i]), nextO2Number = Integer.valueOf(o2Numbers[i]);
               final int result = Integer.compare(nextO1Number, nextO2Number);
               if (result != 0)
                   return result;
           }
       };

       Stream.of("1.3.6.1.4.1.11.2.17.19.3.4.0.10", "1.3.6.1.4.1.11.2.17.5.2.0.79", "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
                 "1.3.6.1.4.1.11150.3.4.0.1", "1.3.6.1.4.1.11.2.17.19.3.4.0.1", "1.3.6.1.4.1.11150.3.4.0")
               .sorted(oids_comparator)
               .forEach(System.out::println);
   }

}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Julia

Works with: Julia version 0.6

<lang julia>oidlist = ["1.3.6.1.4.1.11.2.17.19.3.4.0.10", 

          "1.3.6.1.4.1.11.2.17.5.2.0.79",
          "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
          "1.3.6.1.4.1.11150.3.4.0.1",
          "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
          "1.3.6.1.4.1.11150.3.4.0"]

sort!(oidlist; lt=lexless, 

   by=x -> parse.(Int, String.(split(x, "."))))

println.(oidlist)</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Kotlin

<lang scala>// version 1.0.6

class Oid(val id: String): Comparable<Oid> { 

   override fun compareTo(other: Oid): Int {
       val splits1 = this.id.split('.')
       val splits2 = other.id.split('.')
       val minSize = if (splits1.size < splits2.size) splits1.size else splits2.size
       for (i in 0 until minSize) {
           if (splits1[i].toInt() < splits2[i].toInt()) return -1
           else if (splits1[i].toInt() > splits2[i].toInt()) return 1
       }
       return splits1.size.compareTo(splits2.size)
   }

   override fun toString() = id

}

fun main(args: Array<String>) { 

   val oids = arrayOf(
       Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.10"),
       Oid("1.3.6.1.4.1.11.2.17.5.2.0.79"),
       Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.4"),
       Oid("1.3.6.1.4.1.11150.3.4.0.1"),
       Oid("1.3.6.1.4.1.11.2.17.19.3.4.0.1"),
       Oid("1.3.6.1.4.1.11150.3.4.0")
   )
   println(oids.sorted().joinToString("\n"))

}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Lua

Using the in-built table.sort with a custom compare function. <lang Lua>local OIDs = { 

   "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
   "1.3.6.1.4.1.11.2.17.5.2.0.79",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
   "1.3.6.1.4.1.11150.3.4.0.1",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
   "1.3.6.1.4.1.11150.3.4.0"

}

function compare (a, b) 

   local aList, bList, Na, Nb = {}, {}
   for num in a:gmatch("%d+") do table.insert(aList, num) end
   for num in b:gmatch("%d+") do table.insert(bList, num) end
   for i = 1, math.max(#aList, #bList) do
       Na, Nb = tonumber(aList[i]) or 0, tonumber(bList[i]) or 0
       if Na ~= Nb then return Na < Nb end
   end

end

table.sort(OIDs, compare) for _, oid in pairs(OIDs) do print(oid) end</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Using Coroutine

<lang lua> local function oidGen(s) 

 local wrap, yield = coroutine.wrap, coroutine.yield
 return wrap(function()
   for n in s:gmatch"%d+"do yield(tonumber(n))end
 end)

end

local function oidCmp(a,b) 

 local agen,bgen = oidGen(a),oidGen(b)
 local n,m = agen(),bgen()
 while n and m do
   if n~=m then return n<m end
   n,m = agen(),bgen()
 end
 return m and true or false -- bgen longer with previous equal

end

local OIDs = { 

   "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
   "1.3.6.1.4.1.11.2.17.5.2.0.79",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
   "1.3.6.1.4.1.11150.3.4.0.1",
   "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
   "1.3.6.1.4.1.11150.3.4.0"

}

table.sort(OIDs, oidCmp) for _, oid in pairs(OIDs) do print(oid) end </lang>

M2000 Interpreter

In this example we have to change dot to #, to make each number as an integer one. <lang M2000 Interpreter> Module CheckIt { 

     Flush ' empty stack of values
     Data "1.3.6.1.4.1.11.2.17.19.3.4.0.4" ,  "1.3.6.1.4.1.11.2.17.19.3.4.0.1",  "1.3.6.1.4.1.11150.3.4.0.1"
     Data "1.3.6.1.4.1.11.2.17.19.3.4.0.10", "1.3.6.1.4.1.11.2.17.5.2.0.79",  "1.3.6.1.4.1.11150.3.4.0"
     \\ Inventories of type queue can get same keys, and have sort where numbers (float type) as part of key count as numbers
     Inventory queue OID
     \\ prepare keys (replace dot to #)
     While not empty {
           Append OID, Replace$(".","#", letter$)
     }
     Sort Ascending OID
     n=Each(OID)
     a$=""
     While n {
           \\ replace # to dot
           a$+=Replace$("#",".", Eval$(n))+{
           }
     }
     Clipboard a$
     Report a$

} Checkit </lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Using Piece$() and Stack Sort

We use a stack (a linked list) to save numbers, and a function to check piece by piece for "Grater than" only

piece$(a$,".")(i) works from 0

piece$(a$,".", i) works from 1

piece$(a$,".") export a pointer to an array with each piece on it


<lang M2000 Interpreter> GT=lambda (a$, b$)->{ 

     def i
     do {
           m$=piece$(a$,".")(i)
           n$=piece$(b$,".")(i)
           i++
     } until n$="" or m$="" or m$<>n$
     if n$="" then =m$<>"":exit
     if m$="" then =False:exit
     =val(m$)>val(n$)

} Stack new { 

     \\ data push to end of stack (we use it as FIFO)
     data "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
     data "1.3.6.1.4.1.11.2.17.5.2.0.79"
     data "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
     data "1.3.6.1.4.1.11150.3.4.0.1"
     data "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
     data "1.3.6.1.4.1.11150.3.4.0"
     If Stack.Size>1 then {
           Do {
                 addone=0
                 For i=1 to Stack.Size-1 {
                       \\ if peek item i > peek item i+1 then get i+1 to top, and send to i
                       \\ stack is a linked list, so moving items done with pointers only
                       if Gt(stackitem$(i), stackitem$(i+1)) then Shift i+1 : ShiftBack i : addone--
                 }
           } Until Not addone
     }
     While not empty {
           Print Letter$
     }

} </lang>

Using a function which split pieces one time. We have to insert one more item, by append a "." to a$ and b$ <lang M2000 Interpreter> 

     GT=lambda (a$, b$)->{
           def i=-1
           dim Base 0,  a$(), b$()
           a$()=piece$(a$+".", ".")
           b$()=piece$(b$+".", ".")
           do {
                 i++
           } until a$(i)="" or b$(i)="" or a$(i)<>b$(i)
           if  b$(i)="" then =a$(i)<>"":exit
           if a$(i)="" then =False:exit
           =val(a$(i))>val(b$(i))     
     }

</lang>

Using QuickSort

We can make any OID as array of numbers and we can put all OIDs in an array to sort by a custom Quick Sort, where we place the compare function as a lambda function. Swaps made to pointers of arrays of OIDs. There is no need to use PIECE$() in compare function.

Note that QuickSort need Lower or Equal

There is a Let numeric_expression = string_expression Normally this numeric_expression = string_expression is a syntax error, but Let is a two part statement, a Push to stack and a Read from stack: Push string_expression : Read numeric_expression So first executed the string expression which return a pointer to array and then the read statement get this pointer;


<lang M2000 Interpreter> Group Quick { Private: 

     Function partition {
              Read &A(), p, r
              x = A(r)
              i = p-1
              For j=p to r-1 {
                  If .LE(A(j), x) Then {
                         i++
                         Swap A(i),A(j)
                      }
               }
               Swap A(i+1),A(r)
              = i+1
           }

Public: 

     LE=Lambda->False
     Function quicksort {
          Read &A(), p, r
          If p < r Then {
            q = .partition(&A(), p, r)
            Call .quicksort(&A(), p, q - 1)
            Call .quicksort(&A(), q + 1, r)
         }
     }

} \\ no easy way to join ; \\ n^ is the cursor from iterator n Function join$(a$()) { 

     n=each(a$(), 1, -2)
     k$=""
     while n {
           overwrite k$, ".", n^:=array$(n)
     }
     =k$

} Stack New { 

           Data "1.3.6.1.4.1.11.2.17.19.3.4.0.4" ,  "1.3.6.1.4.1.11.2.17.19.3.4.0.1",  "1.3.6.1.4.1.11150.3.4.0.1"
           Data "1.3.6.1.4.1.11.2.17.19.3.4.0.10", "1.3.6.1.4.1.11.2.17.5.2.0.79",  "1.3.6.1.4.1.11150.3.4.0"
           Dim  Base 0, arr(Stack.Size)
           link arr() to arr$()
           i=0 :  While not Empty {arr$(i)=piece$(letter$+".", ".") : i++ }

}

For i=0 to len(arr())-1 { 

     Print join$(arr(i))

} Quick.LE=lambda (a, b)->{ 

     Link a, b to a$(), b$()
      def i=-1
      do {
            i++
      } until a$(i)="" or b$(i)="" or a$(i)<>b$(i)
      if  b$(i)="" then =a$(i)="":exit
      if a$(i)="" then =true:exit
      =val(a$(i))<=val(b$(i))

} Call Quick.quicksort(&arr(), 0, Len(arr())-1) For i=0 to len(arr())-1 { 

     Print join$(arr(i))

}

</lang>

Perl

<lang perl>my @OIDs = qw( 

   1.3.6.1.4.1.11.2.17.19.3.4.0.10
   1.3.6.1.4.1.11.2.17.5.2.0.79
   1.3.6.1.4.1.11.2.17.19.3.4.0.4
   1.3.6.1.4.1.11150.3.4.0.1
   1.3.6.1.4.1.11.2.17.19.3.4.0.1
   1.3.6.1.4.1.11150.3.4.0

);

my @sorted = 

   map { $_->[0] }
   sort { $a->[1] cmp $b->[1] }
   map { [$_, join , map { sprintf "%8d", $_ } split /\./, $_] }
   @OIDs;

print "$_\n" for @sorted;</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Alternately, you can sort them as "version strings", which is a Perl syntax allowing you to specify a character string in the source code with the characters' codes specified as a dot-delimited sequence of integers.

<lang perl>my @sorted = 

   map { $_->[0] }
   sort { $a->[1] cmp $b->[1] }
   map { [$_, eval "v$_"] }
   @OIDs;</lang>

Perl 6

The sort routine accepts a sort key callback as the first argument. Here we generate a list of integers as the sort key for each OID, which gets sorted lexicographically with numeric comparison by default.

<lang perl6>.say for sort *.comb(/\d+/)».Int, < 

   1.3.6.1.4.1.11.2.17.19.3.4.0.10
   1.3.6.1.4.1.11.2.17.5.2.0.79
   1.3.6.1.4.1.11.2.17.19.3.4.0.4
   1.3.6.1.4.1.11150.3.4.0.1
   1.3.6.1.4.1.11.2.17.19.3.4.0.1
   1.3.6.1.4.1.11150.3.4.0

>;</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Alternatively, using the sprintf-based approach used by the Perl solution, for comparison (input elided):

<lang perl6>.say for sort *.split('.').fmt('%08d'), <...>;</lang>

Or if using a third-party module is acceptable:

<lang Perl6>use Sort::Naturally;

.say for sort &naturally, <...>;</lang>

Phix

I would normally recommend a tagsort, but we can avoid the extra routine and tagset here. <lang Phix>sequence strings = {"1.3.6.1.4.1.11.2.17.19.3.4.0.10", 

                   "1.3.6.1.4.1.11.2.17.5.2.0.79",
                   "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
                   "1.3.6.1.4.1.11150.3.4.0.1",
                   "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
                   "1.3.6.1.4.1.11150.3.4.0"}

constant len = length(strings) sequence sortable = repeat(0,len)

for i=1 to len do 

   sequence si = split(strings[i],'.')
   for j=1 to length(si) do
       si[j] = to_number(si[j])
   end for
   sortable[i] = {si,i}

end for sortable = sort(sortable) for i=1 to len do 

   ?strings[sortable[i][2]]

end for</lang> 

"1.3.6.1.4.1.11.2.17.5.2.0.79"
"1.3.6.1.4.1.11.2.17.19.3.4.0.1"
"1.3.6.1.4.1.11.2.17.19.3.4.0.4"
"1.3.6.1.4.1.11.2.17.19.3.4.0.10"
"1.3.6.1.4.1.11150.3.4.0"
"1.3.6.1.4.1.11150.3.4.0.1"

PicoLisp

<lang PicoLisp>(for I 

  (by
     '((L) (mapcar format (split (chop L) ".")))
     sort
     (quote
        "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
        "1.3.6.1.4.1.11.2.17.5.2.0.79"
        "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
        "1.3.6.1.4.1.11150.3.4.0.1"
        "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
        "1.3.6.1.4.1.11150.3.4.0" ) )
  (prinl I) )</lang>
Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Python

We need to split the input and map each part to int otherwise elements gets compared as a string <lang Python> data = [ 

   '1.3.6.1.4.1.11.2.17.19.3.4.0.10',
   '1.3.6.1.4.1.11.2.17.5.2.0.79',
   '1.3.6.1.4.1.11.2.17.19.3.4.0.4',
   '1.3.6.1.4.1.11150.3.4.0.1',
   '1.3.6.1.4.1.11.2.17.19.3.4.0.1',
   '1.3.6.1.4.1.11150.3.4.0'

]

for s in sorted(data, key=lambda x: list(map(int, x.split('.')))): 

   print(s)

</lang>

Racket

<lang racket>#lang racket (require data/order)

allows for key caching

(define (oid->oid-key o) 

 (map string->number (string-split o ".")))

(define oid-key< (order-<? datum-order))

(module+ test 

 (require rackunit)
 (check-equal?
  (sort
   '("1.3.6.1.4.1.11.2.17.19.3.4.0.10"
     "1.3.6.1.4.1.11.2.17.5.2.0.79"
     "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
     "1.3.6.1.4.1.11150.3.4.0.1"
     "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
     "1.3.6.1.4.1.11150.3.4.0")
   oid-key<
   #:key oid->oid-key
   #:cache-keys? #t)
  '("1.3.6.1.4.1.11.2.17.5.2.0.79"
    "1.3.6.1.4.1.11.2.17.19.3.4.0.1"
    "1.3.6.1.4.1.11.2.17.19.3.4.0.4"
    "1.3.6.1.4.1.11.2.17.19.3.4.0.10"
    "1.3.6.1.4.1.11150.3.4.0"
    "1.3.6.1.4.1.11150.3.4.0.1")))</lang>

Tests run with no output, indicating success.

REXX

This REXX version supports negative integers in the OID. <lang rexx>/*REXX program performs a sort of OID (Object IDentifiers ◄── used in Network data).*/ 

         $= 1.3.6.1.4.1.11.2.17.19.3.4.0.10 ,   /* ◄──┐                                */
            1.3.6.1.4.1.11.2.17.5.2.0.79    ,   /* ◄──┤                                */
            1.3.6.1.4.1.11.2.17.19.3.4.0.4  ,   /* ◄──┼─◄─ six OID numbers (as a list).*/
            1.3.6.1.4.1.11150.3.4.0.1       ,   /* ◄──┤                                */
            1.3.6.1.4.1.11.2.17.19.3.4.0.1  ,   /* ◄──┤                                */
            1.3.6.1.4.1.11150.3.4.0             /* ◄──┘                                */

call gen /*generate an array (@.) from the OIDs.*/ call show 'before sort ───► ' /*display the @ array before sorting.*/ 

    say copies('░', 79)                         /*display fence, separate before &after*/

call adj 1; call bSort #; call adj 0 /*expand/sort/shrink the internal OID's*/ call show ' after sort ───► ' /*display the @ array after sorting. */ exit /*stick a fork in it, we're all done. */ /*──────────────────────────────────────────────────────────────────────────────────────*/ bSort: procedure expose @.; parse arg n; m=n-1 /*N: is the number of @ array elements.*/ 

        do m=m  for m  by -1  until ok;   ok=1  /*keep sorting the @ array until done. */
           do j=1  for m;  _=j+1;  if @.j>@._  then parse value @.j @._ 0 with @._ @.j ok
           end   /*j*/                          /* [↑]  swap two out─of─order elements.*/
        end      /*m*/;          return         /* [↑]  use a simple  bubble  sort.    */

/*──────────────────────────────────────────────────────────────────────────────────────*/ gen: #=words($); L=length(#); do i=1 for #; @.i=word($,i); end; return 

                      /*length of the  number  of words in $.*/

/*──────────────────────────────────────────────────────────────────────────────────────*/ adj: arg LZ; do j=1 for #; x=translate(@.j, , .); y= /*construct X version. */ 

                  do k=1  for words(x);           _=word(x, k)  /*get a number in  X.  */
                  if LZ  then y=y right(_,90,0);  else y=y  _+0 /*add│elide leading 0's*/
                  end   /*k*/                                   /*adjust number, append*/
               @.j = translate( space(y), ., ' ')               /*reconstitute number. */
               end      /*j*/                                   /*LZ: Leading Zero(s). */
      return                                                    /*──  ─       ─        */

/*──────────────────────────────────────────────────────────────────────────────────────*/ show: do a=1 for #; say right("OID number",20) right(a,L) arg(1) @.a; end; return</lang>

output   when using the (internal) default input:
          OID number 1 before sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.10
          OID number 2 before sort ───►  1.3.6.1.4.1.11.2.17.5.2.0.79
          OID number 3 before sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.4
          OID number 4 before sort ───►  1.3.6.1.4.1.11150.3.4.0.1
          OID number 5 before sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.1
          OID number 6 before sort ───►  1.3.6.1.4.1.11150.3.4.0
░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░░
          OID number 1  after sort ───►  1.3.6.1.4.1.11.2.17.5.2.0.79
          OID number 2  after sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.1
          OID number 3  after sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.4
          OID number 4  after sort ───►  1.3.6.1.4.1.11.2.17.19.3.4.0.10
          OID number 5  after sort ───►  1.3.6.1.4.1.11150.3.4.0
          OID number 6  after sort ───►  1.3.6.1.4.1.11150.3.4.0.1

Ring

<lang Ring>

/* 

+--------------------------------------------------------------
+        Program Name : SortOIDNumeric.ring
+        Date         : 2016-07-14
+        Author       : Bert Mariani
+        Purpose      : Sort OID List in Numeric Order
+--------------------------------------------------------------
  • /

oldOidList = [ ".1.3.6.1.4.1.11.2.17.19.3.4.0.10", ".1.3.6.1.4.1.11.2.17.5.2.0.79", ".1.3.6.1.4.1.11.2.17.19.3.4.0.4", ".1.3.6.1.4.1.11150.3.4.0.1", ".1.3.6.1.4.1.11.2.17.19.3.4.0.1", ".1.3.6.1.4.1.11150.3.4.0" ] 

       ### SHOW BEFORE SORT
       See nl + "oldOIDList Before Sort" +nl
       See  oldOidList

   #---------------------

    delChar = "."
    nulChar = ""
    padChar = " "
    padSize = 6
    newDotPadList = []

   ### Split list into lines
   for line in oldOidList

       ### Split line by . into components
       noDotList  = str2list( substr(line, delChar, nl) )

       ### Pad components with left blanks to make equal size
       newPadList  = PadStringList(noDotList, padChar, padSize)

       ### Join the components back to a line
       newDotPadString  = JoinStringList(delChar, newPadList)

       ### Create new list - Alpha
       Add(newDotPadList, newDotPadString)
   next

   ### Sorts Alpha list
   newDotPadListSorted = sort(newDotPadList)

        ### SHOW ALPHA INTERMEDIATE OUTPUT
        See nl + "newDotPadListSorted Intermediate Sort" +nl
        See  newDotPadListSorted

   ### Remove blanks for original look
   newOidList = RemovePadCharList( newDotPadListSorted, padChar, nulChar)

   ###--------------------

       ### SHOW AFTER SORT - NUMERIC
       See nl + "newOIDList Final Sort" +nl
       See  newOidList


      1. --------------------------------------------------------------------
      2. Function: PadStringList
      3. newList = PadStringList(oldList, padChar, padSize )
      4. --------------------------------------------------------------------

Func PadStringList oldList, padChar, padSize 

   newList = []
   for line in oldList
       newPadSize = padSize - len(line)
       newLine = Copy( padChar, newPadSize) + line
       Add(newList, newLine)
   next

   ### First line in all blank because of leading dot - remove
   Del(newList,1)

return newList

      1. ------------------------------------------------------------
      2. FUNC JoinStringList
      3. newString = JoinStringList( joinChar, oldList)
      4. ------------------------------------------------------------

Func JoinStringList joinChar, OldList 

   newString = ""
   for line in OldList
       newString = newString + joinChar + line
   next

return newString

      1. ---------------------------------------------------------------------
      2. FUNC RemovePadCharList
      3. newOidList = RemovePadCharList( oldList, padChar, nulChar)
      4. ---------------------------------------------------------------------

Func RemovePadCharList oldList, padChar, nulChar 

   newList = []
   for line in oldList
         noPadString = substr(line, padChar, nulChar)
       Add(newList, noPadString)
   next

return newList

      1. -----------------------------------------------------------

>;</lang>

Output:

newOIDList Final Sort
.1.3.6.1.4.1.11.2.17.5.2.0.79
.1.3.6.1.4.1.11.2.17.19.3.4.0.1
.1.3.6.1.4.1.11.2.17.19.3.4.0.4
.1.3.6.1.4.1.11.2.17.19.3.4.0.10
.1.3.6.1.4.1.11150.3.4.0
.1.3.6.1.4.1.11150.3.4.0.1

Ruby

<lang ruby>%w[ 

 1.3.6.1.4.1.11.2.17.19.3.4.0.10
 1.3.6.1.4.1.11.2.17.5.2.0.79
 1.3.6.1.4.1.11.2.17.19.3.4.0.4
 1.3.6.1.4.1.11150.3.4.0.1
 1.3.6.1.4.1.11.2.17.19.3.4.0.1
 1.3.6.1.4.1.11150.3.4.0

] .sort_by{|oid| oid.split(".").map(&:to_i)} .each{|oid| puts oid}</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Sidef

<lang ruby>func sort_OIDs(ids) { 

   ids.sort_by { |id|
       id.split('.').map { Num(_) }
   }

}

var OIDs = %w( 

   1.3.6.1.4.1.11.2.17.19.3.4.0.10
   1.3.6.1.4.1.11.2.17.5.2.0.79
   1.3.6.1.4.1.11.2.17.19.3.4.0.4
   1.3.6.1.4.1.11150.3.4.0.1
   1.3.6.1.4.1.11.2.17.19.3.4.0.1
   1.3.6.1.4.1.11150.3.4.0

)

sort_OIDs(OIDs).each { .say }</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1

Tcl

<lang Tcl>

  1. Example input data:

set oid_list [list \ 

                 1.3.6.1.4.1.11.2.17.19.3.4.0.10 \
                 1.3.6.1.4.1.11.2.17.5.2.0.79 \
                 1.3.6.1.4.1.11.2.17.19.3.4.0.4 \
                 1.3.6.1.4.1.11150.3.4.0.1 \
                 1.3.6.1.4.1.11.2.17.19.3.4.0.1 \
                 1.3.6.1.4.1.11150.3.4.0 ]

set oid2_lists [list ] set dots_max 0 set i 0 foreach oid $oid_list { 

   set oid_list [split $oid "."]
   set dot_count [llength $oid_list]
   incr dot_count -1
   if { $dot_count > $dots_max } {
       set dots_max $dot_count
   }
   set dots_arr(${i}) $dot_count
   lappend oid2_lists $oid_list
   incr i

}

  1. pad for strings of different dot counts

set oid3_lists [list] for {set ii 0} {$ii < $i} {incr ii} { 

   set oid_list [lindex $oid2_lists $ii]
   set add_fields [expr { $dots_max - $dots_arr(${ii}) } ]
   if { $add_fields > 0 } {
       for {set j 0} {$j < $add_fields} {incr j} {
           lappend oid_list -1
       }
   }
   lappend oid3_lists $oid_list

} for {set n $dots_max} {$n >= 0 } {incr n -1} { 

   set oid3_lists [lsort -integer -index $n -increasing $oid3_lists]

}

  1. unpad strings of different dot counts

set oid4_lists [list] for {set ii 0} {$ii < $i} {incr ii} { 

   set oid_list [lindex $oid3_lists $ii]
   set j [lsearch -exact -integer $oid_list -1]
   if { $j > -1 } {
       set oid2_list [lrange $oid_list 0 ${j}-1]
       lappend oid4_lists $oid2_list
   } else {
       lappend oid4_lists $oid_list
   }

} foreach oid_list $oid4_lists { 

   puts [join $oid_list "."]

} </lang>

Output:
% source sort-a-list-of-oids.tcl
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1


zkl

Translation of http://rosettacode.org/wiki/Natural_sorting#zkl

Basically, blow apart each line into a list of numbers and sort that. <lang zkl>fcn sortOIDS(oids){ // oids is not modified, a new list is created 

  // pad each oid with a terminal (-1) so zip won't short cut
  oids=oids.pump(List(),fcn(oid){ (oid + ".-1").split(".").apply("toInt") });
  oids.sort(  // in place sort
     fcn(a,b){ // a & b are (x,y,z,...-1), eg (0,4,2,54,-1), (4,6,-1)

a.zip(b).reduce(fcn(_,[(a,b)]){ // if one list longer, zip truncates if(a==b) return(True); // continue to next field return(Void.Stop,a<b); // OIDa<OIDb == cmp this field },True); 

     });
  oids.pump(List,fcn(list){ list[0,-1].concat(".") }) // back to strings

}</lang> <lang zkl>oids:=List( 

  "1.3.6.1.4.1.11.2.17.19.3.4.0.10",
  "1.3.6.1.4.1.11.2.17.5.2.0.79",
  "1.3.6.1.4.1.11.2.17.19.3.4.0.4",
  "1.3.6.1.4.1.11150.3.4.0.1",
  "1.3.6.1.4.1.11.2.17.19.3.4.0.1",
  "1.3.6.1.4.1.11150.3.4.0");

oids=sortOIDS(oids); oids.pump(Console.println); // print one OID per line</lang>

Output:
1.3.6.1.4.1.11.2.17.5.2.0.79
1.3.6.1.4.1.11.2.17.19.3.4.0.1
1.3.6.1.4.1.11.2.17.19.3.4.0.4
1.3.6.1.4.1.11.2.17.19.3.4.0.10
1.3.6.1.4.1.11150.3.4.0
1.3.6.1.4.1.11150.3.4.0.1
Retrieved from "https://rosettacode.org/wiki/Sort_a_list_of_object_identifiers?oldid=268925"