Solve equations with substitution method: Difference between revisions
Solve equations with substitution method (view source)
Revision as of 22:51, 8 November 2021
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(→{{header|Wren}}: Avoid mutating the second list.) |
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* [[Gaussian elimination]]
=={{header|Julia}}==
<lang julia>function parselinear(s)
ab, c = strip.(split(s, "="))
a, by = strip.(split(ab, "x"))
b = replace(by, r"[\sy]" => "")
b[end] in "-+" && (b *= "1")
b = replace(b, "--" => "")
return map(x -> parse(Float64, x == "" ? "1" : x), [a, b, c])
end
function solvetwolinear(s1, s2)
a1, b1, c1 = parselinear(s1)
a2, b2, c2 = parselinear(s2)
@show a1, b1, c1, a2, b2, c2
X = (b2 * c1 - b1 * c2) / (b2 * a1 - b1 * a2)
Y = (a1 * X - c1 ) / -b1
return X, Y
end
@show solvetwolinear("3x + y = -1", "2x - 3y = -19") # solvetwolinear("3x + y = -1", "2x - 3y = -19") = (-2.0, 5.0)
</lang>
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