Repeat a string: Difference between revisions
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=={{header|PowerBASIC}}== |
=={{header|PowerBASIC}}== |
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<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang> |
<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang> |
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=={{header|Pure}}== |
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str_repeat is defined by pattern-matching: repeating any string 0 times results in the empty string; while |
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repeating it more than 0 times results in the concatenation of the string and (n-1) further repeats. |
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<lang pure> |
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> str_repeat 0 s = ""; |
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> str_repeat n s = s + (str_repeat (n-1) s) if n>0; |
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> str_repeat 5 "ha"; |
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"hahahahaha" |
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> |
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</lang> |
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=={{header|Python}}== |
=={{header|Python}}== |
Revision as of 11:40, 25 October 2009
You are encouraged to solve this task according to the task description, using any language you may know.
Take a string and repeat it some number of times. Example: repeat("ha", 5) => "hahahahaha"
C
<lang c>
- include <stdio.h>
- include <stdlib.h>
- include <string.h>
char * string_repeat( int n, const char * s ) {
size_t slen = strlen(s); char * dest = (char *)calloc(n*slen, sizeof(char));
int i; char * p; for ( i=0, p = dest; i < n; ++i, p += slen ) { memcpy(p, s, slen); } return dest;
}
int main() {
printf("%s\n", string_repeat(5, "ha"));
}
</lang>
Clojure
<lang clojure>(apply str (apply concat (repeat 5 "ha")))</lang>
E
<lang e>"ha" * 5</lang>
Haskell
<lang haskell>concat $ replicate 5 "ha"</lang>
J
<lang j>
5 ((* #) $ ]) 'ha'
hahahahaha </lang>
Java
There's no function or operator to do this in Java, so you have to do it yourself. <lang java5>public static String repeat(String str, int times){
StringBuilder ret = new StringBuilder(); for(int i = 0;i < times;i++) ret.append(str); return ret.toString();
}
public static void main(String[] args){
System.out.println(repeat("ha", 5));
}</lang>
JavaScript
This solution creates an array of n+1 null elements, then joins them using the target string as the delimiter <lang javascript>String.prototype.repeat = function(n) {
return new Array(1 + parseInt(n, 10)).join(this);
}
alert("ha".repeat(5)); // hahahahaha</lang>
OCaml
<lang ocaml>let string_repeat s n =
let len = String.length s in let res = String.create(n * len) in for i = 0 to pred n do String.blit s 0 res (i * len) len; done; (res)
- </lang>
testing in the toplevel: <lang ocaml># string_repeat "Hiuoa" 3 ;; - : string = "HiuoaHiuoaHiuoa"</lang>
Alternately: <lang ocaml>let string_repeat s n =
String.concat "" (Array.to_list (Array.make n s))
- </lang>
Or: <lang ocaml>let string_repeat s n =
Array.fold_left (^) "" (Array.make n s)
- </lang>
Perl
<lang perl>"ha" x 5</lang>
Perl 6
<lang perl6>"ha" x 5</lang>
(Note that the x
operator isn't quite the same as in Perl 5: it now only creates strings. To create lists, use xx
.)
PHP
<lang php>str_repeat("ha", 5)</lang>
PowerBASIC
<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang>
Pure
str_repeat is defined by pattern-matching: repeating any string 0 times results in the empty string; while repeating it more than 0 times results in the concatenation of the string and (n-1) further repeats.
<lang pure> > str_repeat 0 s = ""; > str_repeat n s = s + (str_repeat (n-1) s) if n>0; > str_repeat 5 "ha"; "hahahahaha" > </lang>
Python
<lang python>"ha" * 5 # ==> "hahahahaha"</lang>
Ruby
<lang ruby>"ha" * 5 # ==> "hahahahaha"</lang>
Tcl
<lang tcl>string repeat "ha" 5 ;# => hahahahaha</lang>