Repeat a string: Difference between revisions

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=={{header|PowerBASIC}}==
=={{header|PowerBASIC}}==
<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang>
<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang>

=={{header|Pure}}==
str_repeat is defined by pattern-matching: repeating any string 0 times results in the empty string; while
repeating it more than 0 times results in the concatenation of the string and (n-1) further repeats.

<lang pure>
> str_repeat 0 s = "";
> str_repeat n s = s + (str_repeat (n-1) s) if n>0;
> str_repeat 5 "ha";
"hahahahaha"
>
</lang>


=={{header|Python}}==
=={{header|Python}}==

Revision as of 11:40, 25 October 2009

Task
Repeat a string
You are encouraged to solve this task according to the task description, using any language you may know.

Take a string and repeat it some number of times. Example: repeat("ha", 5) => "hahahahaha"

C

<lang c>

  1. include <stdio.h>
  2. include <stdlib.h>
  3. include <string.h>

char * string_repeat( int n, const char * s ) {

 size_t slen = strlen(s);
 char * dest = (char *)calloc(n*slen, sizeof(char));
 int i; char * p;
 for ( i=0, p = dest; i < n; ++i, p += slen ) {
   memcpy(p, s, slen);
 }
 return dest;

}

int main() {

 printf("%s\n", string_repeat(5, "ha"));

}

</lang>

Clojure

<lang clojure>(apply str (apply concat (repeat 5 "ha")))</lang>

E

<lang e>"ha" * 5</lang>

Haskell

<lang haskell>concat $ replicate 5 "ha"</lang>

J

<lang j>

  5 ((* #) $ ]) 'ha'

hahahahaha </lang>

Java

Works with: Java version 1.5+

There's no function or operator to do this in Java, so you have to do it yourself. <lang java5>public static String repeat(String str, int times){

  StringBuilder ret = new StringBuilder();
  for(int i = 0;i < times;i++) ret.append(str);
  return ret.toString();

}

public static void main(String[] args){

 System.out.println(repeat("ha", 5));

}</lang>

JavaScript

This solution creates an array of n+1 null elements, then joins them using the target string as the delimiter <lang javascript>String.prototype.repeat = function(n) {

   return new Array(1 + parseInt(n, 10)).join(this);

}

alert("ha".repeat(5)); // hahahahaha</lang>

OCaml

<lang ocaml>let string_repeat s n =

 let len = String.length s in
 let res = String.create(n * len) in
 for i = 0 to pred n do
   String.blit s 0 res (i * len) len;
 done;
 (res)
</lang>

testing in the toplevel: <lang ocaml># string_repeat "Hiuoa" 3 ;; - : string = "HiuoaHiuoaHiuoa"</lang>

Alternately: <lang ocaml>let string_repeat s n =

 String.concat "" (Array.to_list (Array.make n s))
</lang>

Or: <lang ocaml>let string_repeat s n =

 Array.fold_left (^) "" (Array.make n s)
</lang>

Perl

<lang perl>"ha" x 5</lang>

Perl 6

Works with: Rakudo version #21 "Seattle"

<lang perl6>"ha" x 5</lang>

(Note that the x operator isn't quite the same as in Perl 5: it now only creates strings. To create lists, use xx.)

PHP

<lang php>str_repeat("ha", 5)</lang>

PowerBASIC

<lang powerbasic>MSGBOX REPEAT$(5, "ha")</lang>

Pure

str_repeat is defined by pattern-matching: repeating any string 0 times results in the empty string; while repeating it more than 0 times results in the concatenation of the string and (n-1) further repeats.

<lang pure> > str_repeat 0 s = ""; > str_repeat n s = s + (str_repeat (n-1) s) if n>0; > str_repeat 5 "ha"; "hahahahaha" > </lang>

Python

<lang python>"ha" * 5 # ==> "hahahahaha"</lang>

Ruby

<lang ruby>"ha" * 5 # ==> "hahahahaha"</lang>

Tcl

<lang tcl>string repeat "ha" 5  ;# => hahahahaha</lang>