Remove duplicate elements

Remove duplicate elements
You are encouraged to solve this task according to the task description, using any language you may know.

Given an Array, derive a data structure containing a sequence of elements, derive a sequence of elements in which all duplicates are removed.

Ada

Compiler: GNAT-gpl 2007

with Ada.Containers.Ordered_Sets;
with Ada.Text_IO; use Ada.Text_IO;

procedure Unique_Set is
   package Int_Sets is new Ada.Containers.Ordered_Sets(Integer);
   use Int_Sets;
   Nums : array (Natural range <>) of Integer := (1,2,3,4,5,5,6,7,1);
   Unique : Set;
   Set_Cur : Cursor;
   Success : Boolean;
begin
   for I in Nums'range loop
      Unique.Insert(Nums(I), Set_Cur, Success);
   end loop;
   Set_Cur := Unique.First;
   loop
      Put_Line(Item => Integer'Image(Element(Set_Cur)));
      exit when Set_Cur = Unique.Last;
      Set_Cur := Next(Set_Cur);
   end loop;
end Unique_Set;

AppleScript

set array to {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"}
set unique to {}
repeat with i in array
    -- very important -- list index starts at 1 not 0
    if (i is not in unique) then
        set unique to unique & i
    end if
end repeat

C++

#include <set>
#include <iostream>
using namespace std;

int main( int argc, char* argv[] ) {
    typedef set<int> TyHash;
    int data[] = {1, 2, 3, 2, 3, 4};

    TyHash hash(data, data + 6);

    cout << "Set items:" << endl;
    for (TyHash::iterator iter = hash.begin(); iter != hash.end(); iter++)
          cout << *iter << " ";
    cout << endl;
}

C#

Compiler: MSVS 2005

 List<int> nums = new List<int>( new int { 1, 1, 2, 3, 4, 4 } );
 List<int> unique = new List<int>();
 foreach( int i in nums )
   if( !unique.Contains( i ) )
     unique.Add( i );

Common Lisp

To remove duplicates non-destructively:

(remove-duplicates '(1 3 2 9 1 2 3 8 8 1 0 2))
> (9 3 8 1 0 2)

Or, to remove duplicates in-place:

(delete-duplicates '(1 3 2 9 1 2 3 8 8 1 0 2))
> (9 3 8 1 0 2)

D

void main() {
    int[] data = [1, 2, 3, 2, 3, 4];
    int[int] hash;
    foreach(el; data)
        hash[el] = 0;
}

E

[1,2,3,2,3,4].asSet().getElements()

Erlang

List = [1, 2, 3, 2, 2, 4, 5, 5, 4, 6, 6, 5].
Set = sets:from_list(List).

Forth

Forth has no built-in hashtable facility, so the easiest way to achieve this goal is to take the "uniq" program as an example.

The work uniq, if given a sorted array of cells, will remove the duplicate entries and return the new length of the array. For simplicity, uniq has been written to process cells (which are to Forth what "int" is to C), but could easily be modified to handle a variety of data types through deferred procedures, etc.

The input data is assumed to be sorted.

\ Increments a2 until it no longer points to the same value as a1
\ a3 is the address beyond the data a2 is traversing.
: skip-dups ( a1 a2 a3 -- a1 a2+n )
    dup rot ?do
      over @ i @ <> if drop i leave then
    cell +loop ;

\ Compress an array of cells by removing adjacent duplicates
\ Returns the new count
: uniq ( a n -- n2 )
   over >r             \ Original addr to return stack
   cells over + >r     \ "to" addr now on return stack, available as r@
   dup begin           ( write read )
      dup r@ <
   while
      2dup @ swap !    \ copy one cell
      cell+ r@ skip-dups
      cell 0 d+        \ increment write ptr only
   repeat  r> 2drop  r> - cell / ;

Here is another implementation of "uniq" that uses a popular parameters and local variables extension words. It is structurally the same as the above implementation, but uses less overt stack manipulation.

: uniqv { a n \ r e -- n }
    a n cells+ to e
    a dup to r
    \ the write address lives on the stack
    begin
      r e <
    while
      r @ over !
      r cell+ e skip-dups to r
      cell+
    repeat
    a - cell / ;

To test this code, you can execute:

create test 1 , 2 , 3 , 2 , 6 , 4 , 5 , 3 , 6 ,
here test - cell / constant ntest
: .test ( n -- ) 0 ?do test i cells + ? loop ; 

test ntest 2dup cell-sort uniq .test

output

1 2 3 4 5 6 ok

Haskell

import List

values = [1,2,3,2,3,4]
unique = nub values

IDL

 result = uniq( array[sort( array )] )

Java

 //Using Java 1.5/5.0
 Object[] data = new Object[] {1, 2, 3, "a", "b", "c", 2, 3, 4, "b", "c", "d"};
 Set uniqueSet = new HashSet(Arrays.asList(data));
 Object[] unique = uniqueSet.toArray();

Perl

Interpreter: Perl

use List::MoreUtils qw(uniq);
my @uniq = uniq qw(1 2 3 a b c 2 3 4 b c d);

Without modules:

my %seen;
my @uniq = grep {!$seen{$_}++} qw(1 2 3 a b c 2 3 4 b c d);

PHP

 $list = array(1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd');
 $unique_list = array_unique($list);

Pop11

;;; Initial array
lvars ar = {1 2 3 2 3 4};
;;; Create a hash table
lvars ht= newmapping([], 50, 0, true);
;;; Put all array as keys into the hash table
lvars i;
for i from 1 to length(ar) do
   1 -> ht(ar(i))
endfor;

;;; Collect keys into a list
lvars ls = [];
appdata(ht, procedure(x); cons(front(x), ls) -> ls; endprocedure);

Prolog

 uniq(Data,Uniques) :- setof(X,member(X,Data),Uniques).

Example usage:

 ?- uniq([1, 2, 3, 2, 3, 4],Xs).
 Xs = [1, 2, 3, 4]

Python

 data = [1, 2, 3, 'a', 'b', 'c', 2, 3, 4, 'b', 'c', 'd']

Using sets

 unique = list(set(data))

See also http://www.peterbe.com/plog/uniqifiers-benchmark and http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/52560

Ruby

 ary = [1,1,2,1,'redundant',[1,2,3],[1,2,3],'redundant']
 uniq_ary = ary.uniq
 # => [1, 2, "redundant", [1, 2, 3]]

Scala

 val list = List(1,2,3,4,2,3,4,99)
 val l2 = list.removeDuplicates
 // l2: scala.List[scala.Int] = List(1,2,3,4,99)

Tcl

The concept of an "array" in TCL is strictly associative - and since there cannot be duplicate keys, there cannot be a redundant element in an array. What is called "array" in many other languages is probably better represented by the "list" in TCL (as in LISP).

 set result [lsort -unique $listname]