Positive decimal integers with the digit 1 occurring exactly twice: Difference between revisions

Added 11l
(add FreeBASIC)
(Added 11l)
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Find positive decimal integers   '''n'''   in which the digit   '''1'''   occurs exactly twice,   where   '''n   <   1,000'''.
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=={{header|11l}}==
<lang 11l>L(n) 1000
I String(n).count(‘1’) == 2
print(n, end' ‘ ’)</lang>
 
{{out}}
<pre>
11 101 110 112 113 114 115 116 117 118 119 121 131 141 151 161 171 181 191 211 311 411 511 611 711 811 911 </pre>
 
=={{header|Action!}}==
1,453

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