Partition an integer x into n primes: Difference between revisions

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     integer {v,n} = tests[i]
     object res = partition(v,n)
-    res = iff(res=0?"not possible":sprint(res))
+    res = iff(res=0?"not possible":substitute(trim(sprint(res),"{}"),","," + "))
     printf(1,"Partition %d into %d primes: %s\n",{v,n,res})
 end for</lang>
 {{out}}
 <pre>
-Partition 99809 into 1 primes: {99809}
+Partition 99809 into 1 primes: 99809
-Partition 18 into 2 primes: {5,13}
+Partition 18 into 2 primes: 5 + 13
-Partition 19 into 3 primes: {3,5,11}
+Partition 19 into 3 primes: 3 + 5 + 11
 Partition 20 into 4 primes: not possible
-Partition 2017 into 24 primes: {2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,53,59,61,67,71,73,79,97,1129}
+Partition 2017 into 24 primes: 2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 + 31 + 37 + 41 + 43 + 47 + 53 + 59 + 61 + 67 + 71 + 73 + 79 + 97 + 1129
-Partition 22699 into 1 primes: {22699}
+Partition 22699 into 1 primes: 22699
-Partition 22699 into 2 primes: {2,22697}
+Partition 22699 into 2 primes: 2 + 22697
-Partition 22699 into 3 primes: {3,5,22691}
+Partition 22699 into 3 primes: 3 + 5 + 22691
-Partition 22699 into 4 primes: {2,3,43,22651}
+Partition 22699 into 4 primes: 2 + 3 + 43 + 22651
-Partition 40355 into 3 primes: {3,139,40213}
+Partition 40355 into 3 primes: 3 + 139 + 40213
 </pre>