Ordered partitions: Difference between revisions

Added C#
m (→‎{{header|C++}}: Remove vanity tags)
(Added C#)
Line 559:
({ 2 4 },{ },{ 1 3 },),
({ 3 4 },{ },{ 1 2 },),</pre>
 
=={{header|C sharp}}==
<lang csharp>using System;
using System.Linq;
using System.Collections.Generic;
 
public static class OrderedPartitions
{
public static void Main() {
var input = new [] { new[] { 0, 0, 0, 0, 0 }, new[] { 2, 0, 2 }, new[] { 1, 1, 1 } };
foreach (int[] sizes in input) {
foreach (var partition in Partitions(sizes)) {
Console.WriteLine(partition.Select(set => set.Delimit(", ").Encase('{','}')).Delimit(", ").Encase('(', ')'));
}
Console.WriteLine();
}
}
 
static IEnumerable<IEnumerable<int[]>> Partitions(params int[] sizes) {
var enumerators = new IEnumerator<int[]>[sizes.Length];
var unused = Enumerable.Range(1, sizes.Sum()).ToSortedSet();
var arrays = sizes.Select(size => new int[size]).ToArray();
 
for (int s = 0; s >= 0; ) {
if (s == sizes.Length) {
yield return arrays;
s--;
}
if (enumerators[s] == null) {
enumerators[s] = Combinations(sizes[s], unused.ToArray()).GetEnumerator();
} else {
unused.UnionWith(arrays[s]);
}
if (enumerators[s].MoveNext()) {
enumerators[s].Current.CopyTo(arrays[s], 0);
unused.ExceptWith(arrays[s]);
s++;
} else {
enumerators[s] = null;
s--;
}
}
}
 
static IEnumerable<T[]> Combinations<T>(int count, params T[] array) {
T[] result = new T[count];
foreach (int pattern in BitPatterns(array.Length - count, array.Length)) {
for (int b = 1 << (array.Length - 1), i = 0, r = 0; b > 0; b >>= 1, i++) {
if ((pattern & b) == 0) result[r++] = array[i];
}
yield return result;
}
}
 
static IEnumerable<int> BitPatterns(int ones, int length) {
int initial = (1 << ones) - 1;
int blockMask = (1 << length) - 1;
for (int v = initial; v >= initial; ) {
yield return v;
if (v == 0) break;
 
int w = (v | (v - 1)) + 1;
w |= (((w & -w) / (v & -v)) >> 1) - 1;
v = w & blockMask;
}
}
 
static string Delimit<T>(this IEnumerable<T> source, string separator) => string.Join(separator, source);
static string Encase(this string s, char start, char end) => start + s + end;
}</lang>
{{out}}
<pre>
({}, {}, {}, {}, {})
 
({1, 2}, {}, {3, 4})
({1, 3}, {}, {2, 4})
({1, 4}, {}, {2, 3})
({2, 3}, {}, {1, 4})
({2, 4}, {}, {1, 3})
({3, 4}, {}, {1, 2})
 
({1}, {2}, {3})
({1}, {3}, {2})
({2}, {1}, {3})
({2}, {3}, {1})
({3}, {1}, {2})
({3}, {2}, {1})</pre>
 
=={{header|Common Lisp}}==
196

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