Operator precedence: Difference between revisions

adding lambdatalk
(add Standard ML (https://smlfamily.github.io/Basis/top-level-chapter.html#section:4))
(adding lambdatalk)
Line 1,285:
=={{header|Kotlin}}==
This is well-documented [https://kotlinlang.org/docs/reference/grammar.html on the Kotlin language website].
 
=={{header|Lambdatalk}}==
<lang Scheme>
As with Common Lisp and Scheme, Lambdatalk uses s-expressions so there is no need for operator precedence.
Such an expression "1+2*3+4" is written {+ 1 {* 2 3} 4}
</lang>
 
=={{header|LIL}}==