One-dimensional cellular automata
One dimensional cellular automata
You are encouraged to solve this task according to the task description, using any language you may know.
Assume an array of cells with an initial distribution of live and dead cells, and imaginary cells off the end of the array having fixed values.
Cells in the next generation of the array are calculated based on the value of the cell and its left and right nearest neighbours in the current generation. If, in the folowing table, a live cell is represented by 1 and a dead cell by 0 then to generate the value of the cell at a particular index in the array of cellular values you use the following table:
000 -> 0 # 001 -> 0 # 010 -> 0 # Dies without enough neighbours 011 -> 1 # Needs one neighbour to survive 100 -> 0 # 101 -> 1 # Two neighbours giving birth 110 -> 1 # Needs one neighbour to survive 111 -> 0 # Starved to death.
Python
<python>import random
printdead, printlive = '_#' maxgenerations = 10 cellcount = 20 offendvalue = '0'
universe = .join(random.choice('01') for i in range(cellcount))
neighbours2newstate = {
'000': '0', '001': '0', '010': '0', '011': '1', '100': '0', '101': '1', '110': '1', '111': '0', }
for i in range(maxgenerations):
print "Generation %3i: %s" % ( i, universe.replace('0', printdead).replace('1', printlive) ) universe = offendvalue + universe + offendvalue universe = .join(neighbours2newstate[universe[i:i+3]] for i in range(cellcount))
</python> Sample output:
Generation 0: _###_##_#_#_#_#__#__ Generation 1: _#_#####_#_#_#______ Generation 2: __##___##_#_#_______ Generation 3: __##___###_#________ Generation 4: __##___#_##_________ Generation 5: __##____###_________ Generation 6: __##____#_#_________ Generation 7: __##_____#__________ Generation 8: __##________________ Generation 9: __##________________