Number names: Difference between revisions

From Rosetta Code
Content added Content deleted
(Added groovy version)
(Updated D entry)
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<lang d>import std.stdio, std.string;
<lang d>import std.stdio, std.string;


string spellInteger(in long n) pure {
string spellInteger(in long n) pure nothrow {
static immutable tens = ["", "", "twenty", "thirty", "forty",
static immutable tens = ["", "", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"];
"fifty", "sixty", "seventy", "eighty", "ninety"];
Line 856: Line 856:
"quadr", "quint", "sext", "sept", "oct", "non", "dec"];
"quadr", "quint", "sext", "sept", "oct", "non", "dec"];


static string nonZero(in string c, in int n) pure {
static string nonZero(in string c, in int n) pure nothrow {
return n == 0 ? "" : c ~ spellInteger(n);
return n == 0 ? "" : c ~ spellInteger(n);
}
}


static string big(in int e, in int n) pure {
static string big(in int e, in int n) pure nothrow {
switch (e) {
switch (e) {
case 0: return spellInteger(n);
case 0: return spellInteger(n);
Line 880: Line 880:
}
}


if (n < 1000) {
if (n < 0) {
return "minus " ~ spellInteger(-n);
} else if (n < 1000) {
int ni = cast(int)n; // D doesn't infer this.
int ni = cast(int)n; // D doesn't infer this.
if (ni < 0) {
if (ni < 20) {
throw new Exception("spellInteger: negative input.");
} else if (ni < 20) {
return small[ni];
return small[ni];
} else if (ni < 100) {
} else if (ni < 100) {
Line 900: Line 900:


void main() {
void main() {
foreach (i; 0 .. 1_000)
foreach (i; -10 .. 1_000)
writeln(i, " ", spellInteger(i));
writeln(i, " ", spellInteger(i));
}</lang>
}</lang>
Output (shortened):
Output (shortened):
<pre>0 zero
<pre>-10 minus ten
-9 minus nine
-8 minus eight
-7 minus seven
-6 minus six
-5 minus five
-4 minus four
-3 minus three
-2 minus two
-1 minus one
0 zero
1 one
1 one
2 two
2 two
Line 912: Line 922:
6 six
6 six
...
...
988 nine hundred eighty-eight
989 nine hundred eighty-nine
990 nine hundred ninety
991 nine hundred ninety-one
992 nine hundred ninety-two
993 nine hundred ninety-three
994 nine hundred ninety-four
995 nine hundred ninety-five
995 nine hundred ninety-five
996 nine hundred ninety-six
996 nine hundred ninety-six

Revision as of 13:08, 19 February 2012

Task
Number names
You are encouraged to solve this task according to the task description, using any language you may know.

Show how to spell out a number in English. You can use a preexisting implementation or roll your own, but you should support inputs up to at least one million (or the maximum value of your language's default bounded integer type, if that's less). Support for inputs other than positive integers (like zero, negative integers, and floating-point numbers) is optional.

Ada

<lang ada>with Ada.Text_IO;

procedure Integers_In_English is

  type Spellable is range -999_999_999_999_999_999..999_999_999_999_999_999;
  function Spell (N : Spellable) return String is
     function Twenty (N : Spellable) return String is
     begin
        case N mod 20 is
           when  0 => return "zero";
           when  1 => return "one";
           when  2 => return "two";
           when  3 => return "three";
           when  4 => return "four";
           when  5 => return "five";
           when  6 => return "six";
           when  7 => return "seven";
           when  8 => return "eight";
           when  9 => return "nine";
           when 10 => return "ten";
           when 11 => return "eleven";
           when 12 => return "twelve";
           when 13 => return "thirteen";
           when 14 => return "fourteen";
           when 15 => return "fifteen";
           when 16 => return "sixteen";
           when 17 => return "seventeen";
           when 18 => return "eighteen";
           when others => return "nineteen";
        end case;
     end Twenty;
     function Decade (N : Spellable) return String is
     begin
        case N mod 10 is
           when 2 => return "twenty";
           when 3 => return "thirty";
           when 4 => return "forty";
           when 5 => return "fifty";
           when 6 => return "sixty";
           when 7 => return "seventy";
           when 8 => return "eighty";
           when others => return "ninety";
        end case;
     end Decade;
     function Hundred (N : Spellable) return String is
     begin
        if N < 20 then
           return Twenty (N);
        elsif 0 = N mod 10 then
           return Decade (N / 10 mod 10);
        else
           return Decade (N / 10) & '-' & Twenty (N mod 10);
        end if;
     end Hundred;
     function Thousand (N : Spellable) return String is
     begin
        if N < 100 then
           return Hundred (N);
        elsif 0 = N mod 100 then
           return Twenty (N / 100) & " hundred";
        else
           return Twenty (N / 100) & " hundred and " & Hundred (N mod 100);
        end if;
     end Thousand;
     function Triplet
              (  N     : Spellable;
                 Order : Spellable;
                 Name  : String;
                 Rest  : not null access function (N : Spellable) return String
              )  return String is
        High : Spellable := N / Order;
        Low  : Spellable := N mod Order;
     begin
        if High = 0 then
           return Rest (Low);
        elsif Low = 0 then
           return Thousand (High) & ' ' & Name;
        else
           return Thousand (High) & ' ' & Name & ", " & Rest (Low);
        end if;
     end Triplet;
     function Million (N : Spellable) return String is
     begin
        return Triplet (N, 10**3, "thousand", Thousand'Access);
     end Million;
     function Milliard (N : Spellable) return String is
     begin
        return Triplet (N, 10**6, "million", Million'Access);
     end Milliard;
     function Billion (N : Spellable) return String is
     begin
        return Triplet (N, 10**9, "milliard", Milliard'Access);
     end Billion;
     function Billiard (N : Spellable) return String is
     begin
        return Triplet (N, 10**12, "billion", Billion'Access);
     end Billiard;
  begin
     if N < 0 then
        return "negative " & Spell(-N);
     else
       return Triplet (N, 10**15, "billiard", Billiard'Access);
     end if;
  end Spell;
  procedure Spell_And_Print(N: Spellable) is
     Number: constant String := Spellable'Image(N);
     Spaces: constant String(1 .. 20) := (others => ' '); -- 20 * ' '
  begin
     Ada.Text_IO.Put_Line(Spaces(Spaces'First .. Spaces'Last-Number'Length)
                            & Number & ' ' & Spell(N));
  end Spell_And_Print;
  Samples: constant array (Natural range <>) of Spellable
    := (99, 300, 310, 1_501, 12_609, 512_609, 43_112_609, 77_000_112_609,
        2_000_000_000_100, 999_999_999_999_999_999,
        0, -99, -1501, -77_000_112_609, -123_456_789_987_654_321);

begin

  for I in Samples'Range loop
     Spell_And_Print(Samples(I));
  end loop;

end Integers_In_English;</lang> The implementation goes up to 1018-1 and also supports negative and zero inputs. The solution is recursive by the triplets of decimal numbers. Sample output:

                  99 ninety-nine
                 300 three hundred
                 310 three hundred and ten
                1501 one thousand, five hundred and one
               12609 twelve thousand, six hundred and nine
              512609 five hundred and twelve thousand, six hundred and nine
            43112609 forty-three million, one hundred and twelve thousand, six hundred and nine
         77000112609 seventy-seven milliard, one hundred and twelve thousand, six hundred and nine
       2000000000100 two billion, one hundred
  999999999999999999 nine hundred and ninety-nine billiard, nine hundred and ninety-nine billion, nine hundred and ninety-nine milliard, nine hundred and ninety-nine million, nine hundred and ninety-nine thousand, nine hundred and ninety-nine
                   0 zero
                 -99 negative ninety-nine
               -1501 negative one thousand, five hundred and one
        -77000112609 negative seventy-seven milliard, one hundred and twelve thousand, six hundred and nine
 -123456789987654321 negative one hundred and twenty-three billiard, four hundred and fifty-six billion, seven hundred and eighty-nine milliard, nine hundred and eighty-seven million, six hundred and fifty-four thousand, three hundred and twenty-one

ALGOL 68

Works with: ALGOL 68 version Standard - no extensions to language used
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny
Works with: ELLA ALGOL 68 version Any (with appropriate job cards) - tested with release 1.8.8d.fc9.i386

<lang algol68>PROC number words = (INT n)STRING:(

 # returns a string representation of n in words. Currently
 deals with anything from 0 to 999 999 999. #
   []STRING digits = []STRING
     ("zero","one","two","three","four","five","six","seven","eight","nine")[@0];
   []STRING teens = []STRING
     ("ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen")[@0];
   []STRING decades = []STRING
     ("twenty","thirty","forty","fifty","sixty","seventy","eighty","ninety")[@2];

   PROC three digits = (INT n)STRING: (
     # does the conversion for n from 0 to 999. #
       INT tens = n MOD 100 OVER 10;
       INT units = n MOD 10;
       (n >= 100|digits[n OVER 100] + " " + "hundred" + (n MOD 100 /= 0|" and "|"")|"") +
       (tens /= 0|(tens = 1|teens[units]|decades[tens] + (units /= 0|"-"|""))|"") +
       (units /= 0 AND tens /= 1 OR n = 0|digits[units]|"")
     );
   INT m = n OVER 1 000 000;
   INT k = n MOD 1 000 000 OVER 1000;
   INT u = n MOD 1000;
   (m /= 0|three digits(m) + " million"|"") +
   (m /= 0 AND (k /= 0 OR u >= 100)|", "|"") +
   (k /= 0|three digits(k) + " thousand"|"") +
   ((m /= 0 OR k /= 0) AND u > 0 AND u < 100|" and " |: k /= 0 AND u /= 0|", "|"") +
   (u /= 0 OR n = 0|three digits(u)|"")
 );

on logical file end(stand in, (REF FILE f)BOOL: GOTO stop iteration); on value error(stand in, (REF FILE f)BOOL: GOTO stop iteration); DO # until user hits EOF #

 INT n;
 print("n? ");
 read((n, new line));
 print((number words(n), new line))

OD; stop iteration:

 SKIP</lang>

Example input with output:

n? 43112609
forty-three million, one hundred and twelve thousand, six hundred and nine
Translation of: Python
Works with: ALGOL 68 version Standard - no extensions to language used - note size of LONG LONG INT is implementation specific
Works with: ALGOL 68G version Any - tested with release 1.18.0-9h.tiny

<lang Algol68>MODE EXCEPTION = STRUCT(STRING name, PROC VOID handler); EXCEPTION value error = ("Value Error", stop);

PROC raise = (EXCEPTION exception, STRING str error)VOID: (

 put(stand error, (name OF exception,": ",str error, new line));
 handler OF exception

);

MODE LINT = LONG LONG INT;

BOOL locale euro := TRUE;

PROC spell integer = (LINT n)STRING: (

   []STRING tens = []STRING (~, ~, "twenty", "thirty", "forty",
           "fifty", "sixty", "seventy", "eighty", "ninety")[@0];

   []STRING small = []STRING ("zero", "one", "two", "three", "four", "five",
            "six", "seven", "eight", "nine", "ten", "eleven",
            "twelve", "thirteen", "fourteen", "fifteen",
            "sixteen", "seventeen", "eighteen", "nineteen")[@0];

   []STRING bl = []STRING (~, ~, "m", "b", "tr", "quadr",
         "quint", "sext", "sept", "oct", "non", "dec")[@0];

   PROC nonzero = (STRING c, LINT n)STRING:
       IF n = 0 THEN "" ELSE c + spell integer(n) FI;

   PROC big =(INT e, LINT n)STRING:
       spell integer(n) + 
       CASE e+1 IN
       #0# "", 
       #1# " thousand"
       OUT
           " " + 
           IF locale euro THEN # handle millard, billard & trillard etc #
             bl[e OVER 2 + 1 ]+"ill" + CASE e MOD 2 IN "ard" OUT "ion" ESAC
           ELSE 
             bl[e]+"illion" 
           FI
       ESAC;

   PROC base1000 rev = (LINT in n, PROC (INT,LINT)VOID yield)VOID: (
       # generates the value of the digits of n in base 1000 #
       # (i.e. 3-digit chunks), in reverse. #
       LINT n := in n;
       FOR e FROM 0 WHILE n /= 0 DO
           LINT r = n MOD 1000;
               n := n OVER 1000;
           yield(e, r)
       OD
   );

   IF n < 1000 THEN
     INT ssn := SHORTEN SHORTEN n;
     IF ssn < 0 THEN
       raise (value error, "spell integer: negative input"); ~
     ELIF ssn < 20 THEN
       small[ssn]
     ELIF ssn < 100 THEN
       INT a = ssn OVER 10,
           b = ssn MOD 10;
       tens[a] + nonzero("-", b)
     ELIF ssn < 1000 THEN
       INT a = ssn OVER 100,
           b = ssn MOD 100;
       small[a] + " hundred" + ( b NE 0 | " and" | "") + nonzero(" ", b)
     FI
   ELSE
       STRING out := "", sep:="";
     # FOR     e,      x IN # base1000 rev(n, # DO # 
          (INT e, LINT x)VOID:
               IF x NE 0 THEN
                   big(e,x) + sep +=: out;
                   sep := IF e = 0 AND x < 100 THEN " and " ELSE ", " FI
               FI
      ) 
    # OD #;
      out
   FI

);

PROC example = (LINT n)VOID:

 print((whole(n,0),": ", spell integer(n), new line));
  1. examples #

LINT prod := 0; FOR i TO 6 DO prod := prod * 10**i + i; example(prod) OD;

example(1278); example(1572); example(2010)</lang>Test output:

1: one
102: one hundred and two
102003: one hundred and two thousand and three
1020030004: one millard, twenty million, thirty thousand and four
102003000400005: one hundred and two billion, three millard, four hundred thousand and five
102003000400005000006: one hundred and two trillion, three billard, four hundred millard, five million and six
1278: one thousand, two hundred and seventy-eight
1572: one thousand, five hundred and seventy-two
2010: two thousand and ten

AutoHotkey

<lang autohotkey>Loop {  ; TEST LOOP

   n = 
   Random Digits, 1, 36               ; random number with up to 36 digits 
   Loop %Digits% { 
       Random Digit, 0, 9             ; can have leading 0s 
       n .= Digit 
   } 
   MsgBox 1, Number Names, % PrettyNumber(n) "`n`n" Spell(n) "`n`n" 
   IfMsgBox Cancel, Break 

}

Spell(n) { ; recursive function to spell out the name of a max 36 digit integer, after leading 0s removed

   Static p1=" thousand ",p2=" million ",p3=" billion ",p4=" trillion ",p5=" quadrillion ",p6=" quintillion " 
        , p7=" sextillion ",p8=" septillion ",p9=" octillion ",p10=" nonillion ",p11=" decillion " 
        , t2="twenty",t3="thirty",t4="forty",t5="fifty",t6="sixty",t7="seventy",t8="eighty",t9="ninety" 
        , o0="zero",o1="one",o2="two",o3="three",o4="four",o5="five",o6="six",o7="seven",o8="eight" 
        , o9="nine",o10="ten",o11="eleven",o12="twelve",o13="thirteen",o14="fourteen",o15="fifteen" 
        , o16="sixteen",o17="seventeen",o18="eighteen",o19="nineteen" 
   n :=RegExReplace(n,"^0+(\d)","$1") ; remove leading 0s from n 
   If  (11 < d := (StrLen(n)-1)//3)   ; #of digit groups of 3 
       Return "Number too big" 
   If (d)                             ; more than 3 digits 
       Return Spell(SubStr(n,1,-3*d)) p%d% ((s:=SubStr(n,1-3*d)) ? ", " Spell(s) : "") 
   i := SubStr(n,1,1) 
   If (n > 99)                        ; 3 digits 
       Return o%i% " hundred" ((s:=SubStr(n,2)) ? " and " Spell(s) : "") 
   If (n > 19)                        ; n = 20..99 
       Return t%i% ((o:=SubStr(n,2)) ? "-" o%o% : "") 
   Return o%n%                        ; n = 0..19 

}

PrettyNumber(n) { ; inserts thousands separators into a number string

   Return RegExReplace( RegExReplace(n,"^0+(\d)","$1"), "\G\d+?(?=(\d{3})+(?:\D|$))", "$0,")

}</lang>

BASIC

Works with: QBasic

<lang qbasic>DECLARE FUNCTION int2Text$ (number AS LONG)

'small DATA "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten" DATA "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" 'tens DATA "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" 'big DATA "thousand", "million", "billion"

DIM SHARED small(1 TO 19) AS STRING, tens(7) AS STRING, big(2) AS STRING

DIM tmpInt AS INTEGER

FOR tmpInt = 1 TO 19

   READ small(tmpInt)

NEXT FOR tmpInt = 0 TO 7

   READ tens(tmpInt)

NEXT FOR tmpInt = 0 TO 2

   READ big(tmpInt)

NEXT


DIM n AS LONG

INPUT "Gimme a number! ", n PRINT int2Text$(n)

FUNCTION int2Text$ (number AS LONG)

   DIM num AS LONG, outP AS STRING, unit AS INTEGER
   DIM tmpLng1 AS LONG
   IF 0 = number THEN
       int2Text$ = "zero"
       EXIT FUNCTION
   END IF
   num = ABS(number)
   DO
       tmpLng1 = num MOD 100
       SELECT CASE tmpLng1
           CASE 1 TO 19
               outP = small(tmpLng1) + " " + outP
           CASE 20 TO 99
               SELECT CASE tmpLng1 MOD 10
                   CASE 0
                       outP = tens((tmpLng1 \ 10) - 2) + " " + outP
                   CASE ELSE
                       outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 MOD 10) + " " + outP
               END SELECT
       END SELECT
       tmpLng1 = (num MOD 1000) \ 100
       IF tmpLng1 THEN
           outP = small(tmpLng1) + " hundred " + outP
       END IF
       num = num \ 1000
       IF num < 1 THEN EXIT DO
      
       tmpLng1 = num MOD 1000
       IF tmpLng1 THEN outP = big(unit) + " " + outP
       unit = unit + 1
   LOOP
   IF number < 0 THEN outP = "negative " + outP
   int2Text$ = RTRIM$(outP)

END FUNCTION</lang>

Sample outputs (including the answer to the ultimate question of life, the universe, and everything):

Gimme a number! 1
one
Gimme a number! 0
zero
Gimme a number! -1
negative one
Gimme a number! 42
forty-two
Gimme a number! 1000000
one million
Gimme a number! 1000000001
one billion one
Gimme a number! &h7fffffff
two billion one hundred forty-seven million four hundred eighty-three thousand six hundred forty-seven

C

<lang c>#include <stdio.h>

  1. include <string.h>

char *ones[] = { 0, "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" }; char *tens[] = { 0, "ten", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety" }; char *llions[] = { 0, "thousand", "million", "billion", "trillion", // "quadrillion", "quintillion", "sextillion", "septillion", // "octillion", "nonillion", "decillion" }; const int maxillion = sizeof(llions) / sizeof(llions[0]) * 3 - 3;

int say_hundred(char *s, int len, int depth, int has_lead) { int c[3], i; for (i = -3; i < 0; i++) { if (len + i >= 0) c[i + 3] = s[len + i] - '0'; else c[i + 3] = 0; } if (!(c[0] + c[1] + c[2])) return 0;

if (c[0]) { printf("%s hundred", ones[c[0]]); has_lead = 1; }

if (has_lead && (c[1] || c[2])) printf((!depth || c[0]) && (!c[0] || !c[1]) ? "and " : c[0] ? " " : "");

if (c[1] < 2) { if (c[1] || c[2]) printf("%s", ones[c[1] * 10 + c[2]]); } else { if (c[1]) { printf("%s", tens[c[1]]); if (c[2]) putchar('-'); } if (c[2]) printf("%s", ones[c[2]]); }

return 1; }

int say_maxillion(char *s, int len, int depth, int has_lead) { int n = len / 3, r = len % 3; if (!r) { n--; r = 3; } char *e = s + r; do { if (say_hundred(s, r, n, has_lead) && n) { has_lead = 1; printf(" %s", llions[n]); if (!depth) printf(", "); else printf(" "); } s = e; e += 3; } while (r = 3, n--);

return 1; }

void say_number(char *s) { int len, i, got_sign = 0;

while (*s == ' ') s++; if (*s < '0' || *s > '9') { if (*s == '-') got_sign = -1; else if (*s == '+') got_sign = 1; else goto nan; s++; } else got_sign = 1;

while (*s == '0') { s++; if (*s == '\0') { printf("zero\n"); return; } }

len = strlen(s); if (!len) goto nan;

for (i = 0; i < len; i++) { if (s[i] < '0' || s[i] > '9') { printf("(not a number)"); return; } } if (got_sign == -1) printf("minus ");

int n = len / maxillion; int r = len % maxillion; if (!r) { r = maxillion; n--; }

char *end = s + len - n * maxillion; int has_lead = 0; do { if ((has_lead = say_maxillion(s, r, n, has_lead))) { for (i = 0; i < n; i++) printf(" %s", llions[maxillion / 3]); if (n) printf(", "); } n--; r = maxillion; s = end; end += r; } while (n >= 0);

printf("\n"); return;

nan: printf("not a number\n"); return; }

int main() { say_number("-42"); say_number("1984"); say_number("10000"); say_number("1024"); say_number("1001001001001"); say_number("123456789012345678901234567890123456789012345678900000001"); return 0; }</lang>output

minus forty-two
one thousand, nine hundred eighty-four
ten thousand, 
one thousand, and twenty-four
one trillion, one billion, one million, one thousand, and one
one hundred twenty-three million four hundred fifty-six thousand seven hundred eighty-nine trillion trillion trillion trillion, twelve billion three hundred forty-five million six hundred seventy-eight thousand nine hundredand one trillion trillion trillion, two hundred thirty-four billion five hundred sixty-seven million eight hundred ninety thousand one hundred twenty-three trillion trillion, four hundred fifty-six billion seven hundred eighty-nine million twelve thousand three hundred forty-five trillion, six hundred seventy-eight billion, nine hundred million, and one

C++

<lang cpp>#include <string>

  1. include <iostream>

using std::string;

const char* smallNumbers[] = {

 "zero", "one", "two", "three", "four", "five",
 "six", "seven", "eight", "nine", "ten",
 "eleven", "twelve", "thirteen", "fourteen", "fifteen",
 "sixteen", "seventeen", "eighteen", "nineteen"

};

string spellHundreds(unsigned n) {

 string res;
 if (n > 99) {
   res = smallNumbers[n/100];
   res += " hundred";
   n %= 100;
   if (n) res += " and ";
 }
 if (n >= 20) {
   static const char* Decades[] = {
     "", "", "twenty", "thirty", "forty",
     "fifty", "sixty", "seventy", "eighty", "ninety"
   };
   res += Decades[n/10];
   n %= 10;
   if (n) res += "-";
 }
 if (n < 20 && n > 0)
   res += smallNumbers[n];
 return res;

}


const char* thousandPowers[] = {

 " billion", " million",  " thousand", "" };

typedef unsigned long Spellable;

string spell(Spellable n) {

 if (n < 20) return smallNumbers[n];
 string res;
 const char** pScaleName = thousandPowers;
 Spellable scaleFactor = 1000000000;	// 1 billion
 while (scaleFactor > 0) {
   if (n >= scaleFactor) {
     Spellable h = n / scaleFactor;
     res += spellHundreds(h) + *pScaleName;
     n %= scaleFactor;
     if (n) res += ", ";
   }
   scaleFactor /= 1000;
   ++pScaleName;
 }
 return res;

}

int main() {

  1. define SPELL_IT(x) std::cout << #x " " << spell(x) << std::endl;
 SPELL_IT(      99);
 SPELL_IT(     300);
 SPELL_IT(     310);
 SPELL_IT(    1501);
 SPELL_IT(   12609);
 SPELL_IT(  512609);
 SPELL_IT(43112609);
 SPELL_IT(1234567890);
 return 0;

}</lang> Sample output:

99 ninety-nine
300 three hundred
310 three hundred and ten
1501 one thousand, five hundred and one
12609 twelve thousand, six hundred and nine
512609 five hundred and twelve thousand, six hundred and nine
43112609 forty-three million, one hundred and twelve thousand, six hundred and nine
1234567890 one billion, two hundred and thirty-four million, five hundred and sixty-seven thousand, eight hundred and ninety

C#

Works with: C sharp version 2.0+, works for numbers between 0 and 999,999,999

<lang csharp>using System;

class NumberNamer {

   static readonly string[] incrementsOfOne =
           { "zero",    "one",     "two",       "three",    "four",
             "five",    "six",     "seven",     "eight",    "nine",
             "ten",     "eleven",  "twelve",    "thirteen", "fourteen",
             "fifteen", "sixteen", "seventeen", "eighteen", "nineteen" };
   static readonly string[] incrementsOfTen =
           { "",      "",      "twenty",  "thirty", "fourty",
             "fifty", "sixty", "seventy", "eighty", "ninety" };
   const string millionName = "million",
                thousandName = "thousand",
                hundredName = "hundred",
                andName = "and";


   public static string GetName( int i ) {
       string output = "";
       if( i >= 1000000 ) {
           output += ParseTriplet( i / 1000000 ) + " " + millionName;
           i %= 1000000;
           if( i == 0 ) return output;
       }
       if( i >= 1000 ) {
           if( output.Length > 0 ) {
               output += ", ";
           }
           output += ParseTriplet( i / 1000 ) + " " + thousandName;
           i %= 1000;
           if( i == 0 ) return output;
       }
       if( output.Length > 0 ) {
           output += ", ";
       }
       output += ParseTriplet( i );
       return output;
   }


   static string ParseTriplet( int i ) {
       string output = "";
       if( i >= 100 ) {
           output += incrementsOfOne[i / 100] + " " + hundredName;
           i %= 100;
           if( i == 0 ) return output;
       }
       if( output.Length > 0 ) {
           output += " " + andName + " ";
       }
       if( i >= 20 ) {
           output += incrementsOfTen[i / 10];
           i %= 10;
           if( i == 0 ) return output;
       }
       if( output.Length > 0 ) {
           output += " ";
       }
       output += incrementsOfOne[i];
       return output;
   }

}


class Program { // Test class

   static void Main( string[] args ) {
       Console.WriteLine( NumberNamer.GetName( 1 ) );
       Console.WriteLine( NumberNamer.GetName( 234 ) );
       Console.WriteLine( NumberNamer.GetName( 31337 ) );
       Console.WriteLine( NumberNamer.GetName( 987654321 ) );
   }

} /* Sample output: one two hundred and thirty four thirty one thousand, three hundred and thirty seven nine hundred and eighty seven million, six hundred and fifty four thousand, three hundred and twenty one

  • /</lang>

Clojure

Translation of: Common Lisp

<lang clojure>(clojure.pprint/cl-format nil "~R" 1234) => "one thousand, two hundred thirty-four"</lang>

CoffeeScript

Translation of: Python

<lang coffeescript> spell_integer = (n) ->

 tens = [null, null, "twenty", "thirty", "forty",
     "fifty", "sixty", "seventy", "eighty", "ninety"]

 small = ["zero", "one", "two", "three", "four", "five",
      "six", "seven", "eight", "nine", "ten", "eleven",
      "twelve", "thirteen", "fourteen", "fifteen",
      "sixteen", "seventeen", "eighteen", "nineteen"]

 bl = [null, null, "m", "b", "tr", "quadr",
     "quint", "sext", "sept", "oct", "non", "dec"]

 divmod = (n, d) ->
   [Math.floor(n / d), n % d]
 nonzero = (c, n) ->
   if n == 0 
     ""
   else
     c + spell_integer n

 big = (e, n) ->
   if e == 0
     spell_integer n
   else if e == 1
     spell_integer(n) + " thousand"
   else
     spell_integer(n) + " " + bl[e] + "illion"

 base1000_rev = (n) ->
   # generates the value of the digits of n in base 1000
   # (i.e. 3-digit chunks), in reverse.
   chunks = []
   while n != 0
     [n, r] = divmod n, 1000
     chunks.push r
   chunks
   
 if n < 0
   throw Error "spell_integer: negative input"
 else if n < 20
   small[n]
 else if n < 100
   [a, b] = divmod n, 10
   tens[a] + nonzero("-", b)
 else if n < 1000
   [a, b] = divmod n, 100
   small[a] + " hundred" + nonzero(" ", b)
 else
   chunks = (big(exp, x) for x, exp in base1000_rev(n) when x)
   chunks.reverse().join ', '

  1. example

console.log spell_integer 1278 console.log spell_integer 1752 console.log spell_integer 2010 console.log spell_integer 4000123007913 </lang>

output <lang> > coffee spell_number.coffee one thousand, two hundred seventy-eight one thousand, seven hundred fifty-two two thousand, ten four trillion, one hundred twenty-three million, seven thousand, nine hundred thirteen </lang>

Common Lisp

<lang lisp>(format nil "~R" 1234) => "one thousand two hundred thirty-four"</lang>

D

<lang d>import std.stdio, std.string;

string spellInteger(in long n) pure nothrow {

   static immutable tens = ["", "", "twenty", "thirty", "forty",
       "fifty", "sixty", "seventy", "eighty", "ninety"];
   static immutable small = "zero one two three four five six
       seven eight nine ten eleven twelve thirteen fourteen
       fifteen sixteen seventeen eighteen nineteen".split();
   static immutable bl = ["", "", "m", "b", "tr",
       "quadr", "quint", "sext", "sept", "oct", "non", "dec"];
   static string nonZero(in string c, in int n) pure nothrow {
       return n == 0 ? "" : c ~ spellInteger(n);
   }
   static string big(in int e, in int n) pure nothrow {
       switch (e) {
           case 0: return spellInteger(n);
           case 1: return spellInteger(n) ~ " thousand";
           default: return spellInteger(n) ~ " " ~ bl[e] ~ "illion";
       }
   }
   /// Generates the value of the digits of n in
   /// base 1000 (i.e. 3-digit chunks), in reverse.
   static int[] base1000Reverse(in long nn) pure nothrow {
       long n = nn;
       int[] result;
       while (n) {
           result ~= n % 1000;
           n /= 1000;
       }
       return result;
   }
   if (n < 0) {
       return "minus " ~ spellInteger(-n);
   } else if (n < 1000) {
       int ni = cast(int)n; // D doesn't infer this.
       if (ni < 20) {
           return small[ni];
       } else if (ni < 100) {
           return tens[ni / 10] ~ nonZero("-", ni % 10);
       } else // ni < 1000
           return small[ni / 100] ~ " hundred" ~
                  nonZero(" ", ni % 100);
   } else {
       string[] pieces;
       foreach_reverse (e, x; base1000Reverse(n))
           pieces ~= big(e, x);
       return pieces.join(", ");
   }

}

void main() {

   foreach (i; -10 .. 1_000)
       writeln(i, " ", spellInteger(i));

}</lang> Output (shortened):

-10 minus ten
-9 minus nine
-8 minus eight
-7 minus seven
-6 minus six
-5 minus five
-4 minus four
-3 minus three
-2 minus two
-1 minus one
0 zero
1 one
2 two
3 three
4 four
5 five
6 six
...
988 nine hundred eighty-eight
989 nine hundred eighty-nine
990 nine hundred ninety
991 nine hundred ninety-one
992 nine hundred ninety-two
993 nine hundred ninety-three
994 nine hundred ninety-four
995 nine hundred ninety-five
996 nine hundred ninety-six
997 nine hundred ninety-seven
998 nine hundred ninety-eight
999 nine hundred ninety-nine

Euphoria

Translation of: BASIC

<lang euphoria>function abs(atom i)

   if i < 0 then
       return -i
   else
       return i
   end if

end function

constant small = {"one", "two", "three", "four", "five", "six", "seven", "eight",

   "nine", "ten","eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen",
   "seventeen", "eighteen", "nineteen"}

constant tens = {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty",

   "ninety"}

constant big = {"thousand", "million", "billion"}

function int2text(atom number)

   atom num
   integer unit, tmpLng1
   sequence outP
   outP = ""
   num = 0
   unit = 1
   tmpLng1 = 0
   
   if number = 0 then
       return "zero"
   end if
   
   num = abs(number)
   while 1 do
       tmpLng1 = remainder(num,100)
       if tmpLng1 > 0 and tmpLng1 < 20 then
           outP = small[tmpLng1] & ' ' & outP
       elsif tmpLng1 >= 20 then
           if remainder(tmpLng1,10) = 0 then
               outP = tens[floor(tmpLng1/10)-1] & ' ' & outP
           else
               outP = tens[floor(tmpLng1/10)-1] & '-' & small[remainder(tmpLng1, 10)] & ' ' & outP
           end if
       end if
       
       tmpLng1 = floor(remainder(num, 1000) / 100)
       if tmpLng1 then
           outP = small[tmpLng1] & " hundred " & outP
       end if
       
       num = floor(num/1000)
       if num < 1 then
           exit
       end if
       
       tmpLng1 = remainder(num,1000)
       if tmpLng1 then
           outP = big[unit] & ' ' & outP
       end if
       
       unit = unit + 1
   end while
   
   if number < 0 then
       outP = "negative " & outP
   end if
   
   return outP[1..$-1]

end function

puts(1,int2text(900000001) & "\n") puts(1,int2text(1234567890) & "\n") puts(1,int2text(-987654321) & "\n") puts(1,int2text(0) & "\n")</lang>

Output:

nine hundred million one
one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety
negative nine hundred eighty-seven million six hundred fifty-four thousand three hundred twenty-one
zero

Fortran

Works with: Fortran version 90 and later

<lang fortran>program spell

 implicit none
 integer :: e
 integer :: i
 integer :: m
 integer :: n
 character (9), dimension (19), parameter :: small =       &
   & (/'one      ', 'two      ', 'three    ', 'four     ', &
   &   'five     ', 'six      ', 'seven    ', 'eight    ', &
   &   'nine     ', 'ten      ', 'eleven   ', 'twelve   ', &
   &   'thirteen ', 'fourteen ', 'fifteen  ', 'sixteen  ', &
   &   'seventeen', 'eighteen ', 'nineteen '/)
 character (7), dimension (2 : 9), parameter :: tens =        &
   & (/'twenty ', 'thirty ', 'forty  ', 'fifty  ', 'sixty  ', &
   &   'seventy', 'eighty ', 'ninety '/)
 character (8), dimension (3), parameter :: big = &
   & (/'thousand', 'million ', 'billion '/)
 character (256) :: r
 do
   read (*, *, iostat = i) n
   if (i /= 0) then
     exit
   end if
   if (n == 0) then
     r = 'zero'
   else
     r = 
     m = abs (n)
     e = 0
     do
       if (m == 0) then
         exit
       end if
       if (modulo (m, 1000) > 0) then
         if (e > 0) then
           r = trim (big (e)) // ' ' // r
         end if
         if (modulo (m, 100) > 0) then
           if (modulo (m, 100) < 20) then
             r = trim (small (modulo (m, 100))) // ' ' // r
           else
             if (modulo (m, 10) > 0) then
               r = trim (small (modulo (m, 10))) // ' ' // r
               r = trim (tens (modulo (m, 100) / 10)) // '-' // r
             else
               r = trim (tens (modulo (m, 100) / 10)) // ' ' // r
             end if
           end if
         end if
         if (modulo (m, 1000) / 100 > 0) then
           r = 'hundred' // ' ' // r
           r = trim (small (modulo (m, 1000) / 100)) // ' ' // r
         end if
       end if
       m = m / 1000
       e = e + 1
     end do
     if (n < 0) then
       r = 'negative' // ' ' // r
     end if
   end if
   write (*, '(a)') trim (r)
 end do

end program spell</lang> Sample input:

-1
0
1
42
2147483647

Output:

negative one
zero
one
forty-two
two billion one hundred forty-seven million four hundred eighty-three thousand six hundred forty-seven

Go

Positive integers, to MaxInt64 <lang go>package main

import "fmt"

func main() {

   for _, n := range []int64{12, 1048576, 9e18} {
       fmt.Println(say(n))
   }

}

var small = []string{"", "one", "two", "three", "four", "five", "six",

   "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen",
   "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"}

var tens = []string{"ones", "ten", "twenty", "thirty", "forty",

   "fifty", "sixty", "seventy", "eighty", "ninety"}

var illions = []string{"thousand", "million", "billion",

   "trillion", "quadrillion", "quintillion"}

func say(n int64) string {

   switch {
   case n < 1:
   case n < 20:
       return small[n]
   case n < 100:
       t := tens[n/10]
       s := n % 10
       if s > 0 {
           t += " " + small[s]
       }
       return t
   case n < 1000:
       h := small[n/100] + " hundred"
       s := n % 100
       if s > 0 {
           h += " " + say(s)
       }
       return h
   default:
       sx := say(n % 1000)
       for i := 0; n >= 1000; i++ {
           n /= 1000
           p := n % 1000
           if p > 0 {
               ix := say(p) + " " + illions[i]
               if sx > "" {
                   ix += " " + sx
               }
               sx = ix
           }
       }
       return sx
   }
   return ""

}</lang> Output:

twelve
one million forty eight thousand five hundred seventy six
nine quintillion

Groovy

<lang groovy>def divMod(BigInteger number, BigInteger divisor) {

   def qr = number.divideAndRemainder(divisor)
   [div:qr[0], remainder:qr[1]]

}

def toText(value) {

   value = value as BigInteger
   def units = ['zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine', 'ten',
           'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
   def tens = [, , 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
   def big = [, 'thousand'] + ['m', 'b', 'tr', 'quadr', 'quint', 'sext', 'sept', 'oct', 'non', 'dec'].collect { "${it}illion"}
   if (value < 0) {
       "negative ${toText(-value)}"
   } else if (value < 20) {
       units[value]
   } else if (value < 100) {
       divMod(value, 10).with { "${tens[div]} ${units[remainder]}".replace(' zero', ) }
   } else if (value < 1000) {
       divMod(value, 100).with { "${toText(div)} hundred and ${toText(remainder)}".replace(' and zero', ) }
   } else {
       def chunks = []
       while (value != 0) {
           divMod(value, 1000).with {
               chunks << remainder
               value = div
           }
       }
       if (chunks.size() > big.size()) {
           throw new IllegalArgumentException("Number overflow")
       }
       def text = []
       (0..<chunks.size()).each { index ->
           if (chunks[index] > 0) {
               text << "${toText(chunks[index])}${index == 0 ?  : ' ' + big[index]}"
               if (index == 0 && chunks[index] < 100) {
                   text << "and"
               }
           }
       }
       text.reverse().join(', ').replace(', and,', ' and')
   }

}

// Add this method to all Numbers Number.metaClass.toText = { toText(delegate) }

println toText(29) println 40.toText() println toText(401) println 9003.toText() println toText(8011673) println 8000100.toText() println 4629436.toText() 948623487512387455323784623842314234.toText().split(',').each { println it.trim() }

def verifyToText(expected, value) {

   println "Checking '$expected' == $value"
   def actual = value.toText()
   assert expected == actual

}

verifyToText 'nineteen', 19 verifyToText 'one thousand, two hundred and thirty four', 1234 verifyToText 'twenty three million, four hundred and fifty nine thousand, six hundred and twelve', 23459612 verifyToText 'one thousand, nine hundred and ninety nine', 1999 verifyToText 'negative six hundred and one', -601 verifyToText 'twelve billion and nineteen', 12000000019 verifyToText 'negative one billion, two hundred and thirty four million, five hundred and sixty seven thousand, eight hundred and ninety', -1234567890 verifyToText 'one hundred and one', 101 verifyToText 'one thousand and one', 1001 verifyToText 'one million, one hundred and one', 1000101 verifyToText 'one million and forty five', 1000045 verifyToText 'one million and fifteen', 1000015 verifyToText 'one billion, forty five thousand and one', 1000045001</lang> Output:

twenty nine
forty
four hundred and one
nine thousand and three
eight million, eleven thousand, six hundred and seventy three
eight million, one hundred
four million, six hundred and twenty nine thousand, four hundred and thirty six
nine hundred and forty eight decillion
six hundred and twenty three nonillion
four hundred and eighty seven octillion
five hundred and twelve septillion
three hundred and eighty seven sextillion
four hundred and fifty five quintillion
three hundred and twenty three quadrillion
seven hundred and eighty four trillion
six hundred and twenty three billion
eight hundred and forty two million
three hundred and fourteen thousand
two hundred and thirty four
Checking 'nineteen' == 19
Checking 'one thousand, two hundred and thirty four' == 1234
Checking 'twenty three million, four hundred and fifty nine thousand, six hundred and twelve' == 23459612
Checking 'one thousand, nine hundred and ninety nine' == 1999
Checking 'negative six hundred and one' == -601
Checking 'twelve billion and nineteen' == 12000000019
Checking 'negative one billion, two hundred and thirty four million, five hundred and sixty seven thousand, eight hundred and ninety' == -1234567890
Checking 'one hundred and one' == 101
Checking 'one thousand and one' == 1001
Checking 'one million, one hundred and one' == 1000101
Checking 'one million and forty five' == 1000045
Checking 'one million and fifteen' == 1000015
Checking 'one billion, forty five thousand and one' == 1000045001


Haskell

<lang haskell>import Data.List (intercalate, unfoldr)

spellInteger :: Integer -> String spellInteger n

| n <    0  = "negative " ++ spellInteger (-n)
| n <   20  = small n
| n <  100  = let (a, b) = n `divMod` 10
              in  tens a ++ nonzero '-' b
| n < 1000  = let (a, b) = n `divMod` 100
              in  small a ++ " hundred" ++ nonzero ' ' b
| otherwise = intercalate ", " $ map big $ reverse $
              filter ((/= 0) . snd) $ zip [0..] $ unfoldr uff n
where nonzero :: Char -> Integer -> String
      nonzero _ 0 = ""
      nonzero c n = c : spellInteger n
      uff :: Integer -> Maybe (Integer, Integer)
      uff 0 = Nothing
      uff n = Just $ uncurry (flip (,)) $ n `divMod` 1000
      small, tens :: Integer -> String
      small = (["zero", "one", "two", "three", "four", "five",
           "six", "seven", "eight", "nine", "ten", "eleven",
           "twelve", "thirteen", "fourteen", "fifteen", "sixteen",
           "seventeen", "eighteen", "nineteen"] !!) . fromEnum
      tens = ([undefined, undefined, "twenty", "thirty", "forty",
          "fifty", "sixty", "seventy", "eighty", "ninety"] !!) .
          fromEnum
      big :: (Int, Integer) -> String
      big (0, n) = spellInteger n
      big (1, n) = spellInteger n ++ " thousand"
      big (e, n) = spellInteger n ++ ' ' : (l !! e) ++ "illion"
        where l = [undefined, undefined, "m", "b", "tr", "quadr",
                  "quint", "sext", "sept", "oct", "non", "dec"]</lang>

HicEst

<lang HicEst>SUBROUTINE NumberToWords(number)

CHARACTER outP*255, small*130, tens*80, big*80
REAL ::   decimal_places = 7
INIT( APPENDIX("#literals"), small, tens, big)
num = ABS( INT(number) )
order = 0
outP = ' '
DO i = 1, num + 1
  tmp = MOD(num, 100)
  IF(tmp > 19) THEN
      EDIT(Text=tens, ITeM=INT(MOD(tmp/10, 10)), Parse=medium)
      IF( MOD(tmp, 10) ) THEN
          EDIT(Text=small, ITeM=MOD(tmp,10)+1, Parse=mini)
          outP = medium // '-' // mini // ' ' // outP
      ELSE
          outP = medium // ' ' // outP
      ENDIF
  ELSEIF(tmp > 0) THEN
      EDIT(Text=small, ITeM=tmp+1, Parse=mini)
      outP = mini // ' '// outP
  ELSEIF(number == 0) THEN
      outP = 'zero'
  ENDIF
  tmp = INT(MOD(num, 1000) / 100)
  IF(tmp) THEN
      EDIT(Text=small, ITeM=tmp+1, Parse=oneto19)
      outP = oneto19 // ' hundred ' // outP
  ENDIF
  num = INT(num /1000)
  IF( num == 0) THEN
      IF(number < 0) outP = 'minus ' // outP
      fraction = ABS( MOD(number, 1) )
      IF(fraction) WRITE(Text=outP, APPend) ' point'
      DO j = 1, decimal_places
        IF( fraction >= 10^(-decimal_places) ) THEN
            num = INT( 10.01 * fraction )
            EDIT(Text=small, ITeM=num+1, Parse=digit)
            WRITE(Text=outP, APPend) ' ', digit
            fraction = 10*fraction - num
        ENDIF
      ENDDO
      OPEN(FIle="temp.txt", APPend)
      WRITE(FIle="temp.txt", Format='F10, " = ", A', CLoSe=1) number, outP
      RETURN
  ENDIF
  order = order + 1
  EDIT(Text=big, ITeM=order, Parse=kilo)
  IF( MOD(num, 1000) ) outP = kilo // ' and '// outP
ENDDO

END

CALL NumberToWords( 0 ) CALL NumberToWords( 1234 ) CALL NumberToWords( 1234/100 ) CALL NumberToWords( 10000000 + 1.2 ) CALL NumberToWords( 2^15 ) CALL NumberToWords( 0.001 ) CALL NumberToWords( -EXP(1) )

  1. literals
SMALL= zero one two three four five six seven eight nine ten &
eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen
TENS=ten twenty thirty forty fifty sixty seventy eighty ninety
BIG=thousand million billion trillion quadrillion</lang>

<lang HicEst>0 = zero 1234 = one thousand and two hundred thirty-four 12.34 = twelve point three four 10000001.2 = ten million and one point two 32768 = thirty-two thousand and seven hundred sixty-eight 1E-3 = point zero zero one -2.7182818 = minus two point seven one eight two eight one eight</lang>

Icon and Unicon

<lang Icon>link numbers # commas, spell

procedure main(arglist) every x := !arglist do

  write(commas(x), " -> ",spell(x))

end</lang>

numbers:spell was used as a based for this procedure.

<lang Icon>procedure spell(n) #: spell out integer (short scale)

  local m, i
  static scale 
  initial {
     scale := [ "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion","septillion"]  
     every scale[i := 1 to *scale ] := [ integer(repl("999",i + 1)), -3 * i, " "||scale[i] ]
     push(scale,[999,2," hundred"])
    }
  n := integer(n) | stop(image(n)," is not an integer")
  if n < 0 then return "negative " || spell(-n)
  if n <= 12 then return {
     "0zero,1one,2two,3three,4four,5five,6six,7seven,8eight,_
        9nine,10ten,11eleven,12twelve," ? {
           tab(find(n))
           move(*n)
           tab(find(","))
           }
     }
  else if n <= 19 then return {
     spell(n[2] || "0") ?
        (if ="for" then "four" else tab(find("ty"))) || "teen"
     }
  else if n <= 99 then return {
     "2twen,3thir,4for,5fif,6six,7seven,8eigh,9nine," ? {
        tab(find(n[1]))
        move(1)
        tab(find(",")) || "ty" ||
           (if n[2] ~= 0 then "-" || spell(n[2]) else "")
        }
     }
  else if n <= scale[i := 1 to *scale,1] then return {     # generalize based on scale
     spell(n[1:scale[i,2]]) || scale[i,3] ||
        (if (m := n[scale[i,2]:0]) ~= 0 then " and " || spell(m) else "")   
     }
  else fail                                                # really big

end</lang> Sample output:

#spell.exe 5 11 15 67 10132767 65535 -1234567890123456

5 -> five
11 -> eleven
15 -> fifteen
67 -> sixty-seven
10,132,767 -> ten million and one hundred and thirty-two thousand and seven hundred and sixty-seven
65,535 -> sixty-five thousand and five hundred and thirty-five
-1,234,567,890,123,456 -> negative one quadrillion and two hundred and thirty-four trillion and five hundred and sixty-seven billion and eight hundred and ninety million and one hundred and twenty-three thousand and four hundred and fifty-six

Inform 7

Works with: Z-machine

<lang inform7>say 32767 in words;</lang>

<lang inform7>say 2147483647 in words;</lang>

J

Solutions: <lang j>u=. ;:'one two three four five six seven eight nine' v=. ;:'ten eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen' t=. ;:'twenty thirty forty fifty sixty seventy eighty ninety' EN100=:  ; u , v , , t ,&.>/ ;'-',&.>u

z=.  ; 'thousand' ; (;:'m b tr quadr quint sext sept oct non'),&.> <'illion' u=. ;:'un duo tre quattuor quin sex septen octo novem' t=. (;:'dec vigint trigint quadragint quinquagint sexagint septuagint octogint nonagint'),&.><'illion' ENU=: z , (, t ,~&.>/ ;u) , <'centillion'

en3=: 4 : 0

'p q'=. 0 100#:y
(p{::EN100),((*p)#' hundred'),((p*&*q)#x),q{::EN100

)

en=: 4 : 0

d=. 1000&#.^:_1 y
assert. (0<:y) *. ((=<.)y) *. d <:&# ENU
c=. x&en3&.> (*d)#d
((0=y)#'zero') , (-2+*{:d) }. ; , c,.(<' '),.(ENU{~I.&.|.*d),.<', '

)

uk=: ' and '&en NB. British us=: ' ' &en NB. American</lang>

Example:

   uk 123456789
one hundred and twenty-three million, four hundred and fifty-six thousand, seven hundred and eighty-nine
   us 123456789
one hundred twenty-three million, four hundred fifty-six thousand, seven hundred eighty-nine
   us 1234567890123456789012345678901234567890123456789012345678901234567890x
one duovigintillion, two hundred thirty-four unvigintillion, five hundred sixty-seven vigintillion, eight hundred ninety novemdecillion, one hundred twenty-three octodecillion, four hundred fifty-six septendecillion, seven hundred eighty-nine sexdecillion, twelve quindecillion, three hundred forty-five quattuordecillion, six hundred seventy-eight tredecillion, nine hundred one duodecillion, two hundred thirty-four undecillion, five hundred sixty-seven decillion, eight hundred ninety nonillion, one hundred twenty-three octillion, four hundred fifty-six septillion, seven hundred eighty-nine sextillion, twelve quintillion, three hundred forty-five quadrillion, six hundred seventy-eight trillion, nine hundred one billion, two hundred thirty-four million, five hundred sixty-seven thousand, eight hundred ninety

Java

Translation of: BASIC

<lang java>public class Int2Words {

   static String[] small = {"one", "two", "three", "four", "five", "six",
       "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen",
       "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"};
   static String[] tens = {"twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty",
       "ninety"};
   static String[] big = {"thousand", "million", "billion", "trillion"};
   public static void main(String[] args) {
       System.out.println(int2Text(900000001));
       System.out.println(int2Text(1234567890));
       System.out.println(int2Text(-987654321));
       System.out.println(int2Text(0));
   }
   public static String int2Text(long number) {
       long num = 0;
       String outP = "";
       int unit = 0;
       long tmpLng1 = 0;
       if (number == 0) {
           return "zero";
       }
       num = Math.abs(number);
       for (;;) {
           tmpLng1 = num % 100;
           if (tmpLng1 >= 1 && tmpLng1 <= 19) {
               outP = small[(int) tmpLng1 - 1] + " " + outP;
           } else if (tmpLng1 >= 20 && tmpLng1 <= 99) {
               if (tmpLng1 % 10 == 0) {
                   outP = tens[(int) (tmpLng1 / 10) - 2] + " " + outP;
               } else {
                   outP = tens[(int) (tmpLng1 / 10) - 2] + "-"
                           + small[(int) (tmpLng1 % 10) - 1] + " " + outP;
               }
           }
           tmpLng1 = (num % 1000) / 100;
           if (tmpLng1 != 0) {
               outP = small[(int) tmpLng1 - 1] + " hundred " + outP;
           }
           num /= 1000;
           if (num == 0) {
               break;
           }
           tmpLng1 = num % 1000;
           if (tmpLng1 != 0) {
               outP = big[unit] + " " + outP;
           }
           unit++;
       }
       if (number < 0) {
           outP = "negative " + outP;
       }
       return outP.trim();
   }

}</lang> Output:

nine hundred million one
one billion two hundred thirty-four million five hundred sixty-seven thousand eight hundred ninety
negative nine hundred eighty-seven million six hundred fifty-four thousand three hundred twenty-one
zero

Recursive

<lang java>public class NumberToWordsConverter { // works upto 9999999

final private static String[] units = {"Zero","One","Two","Three","Four", "Five","Six","Seven","Eight","Nine","Ten", "Eleven","Twelve","Thirteen","Fourteen","Fifteen", "Sixteen","Seventeen","Eighteen","Nineteen"}; final private static String[] tens = {"","","Twenty","Thirty","Forty","Fifty", "Sixty","Seventy","Eighty","Ninety"};

public static String convert(Integer i) { // if( i < 20) return units[i]; if( i < 100) return tens[i/10] + ((i % 10 > 0)? " " + convert(i % 10):""); if( i < 1000) return units[i/100] + " Hundred" + ((i % 100 > 0)?" and " + convert(i % 100):""); if( i < 1000000) return convert(i / 1000) + " Thousand " + ((i % 1000 > 0)? " " + convert(i % 1000):"") ; return convert(i / 1000000) + " Million " + ((i % 1000000 > 0)? " " + convert(i % 1000000):"") ; } }</lang>

Joy

<lang Joy> DEFINE units == [ "zero" "one" "two" "three" "four" "five" "six" "seven" "eight" "nine" "ten"

 "eleven" "twelve" "thirteen" "fourteen" "fifteen" "sixteen" "seventeen"
 "eighteen" "nineteen" ];

tens == [ "ten" "twenty" "thirty" "forty" "fifty" "sixty" "seventy" "eighty" "ninety" ];

convert6 == [1000000 <] [1000 div swap convert " thousand " putchars convert3] [1000000 div swap convert " million " putchars convert3] ifte;

convert5 == [null] [] [" and " putchars convert] ifte;

convert4 == [1000 <] [100 div swap units of putchars " hundred" putchars convert5] [convert6] ifte;

convert3 == [null] [] [32 putch convert] ifte;

convert2 == [100 <] [10 div swap pred tens of putchars convert3] [convert4] ifte;

convert == [20 <] [units of putchars] [convert2] ifte. </lang>

<lang logo>make "numbers {one two three four five six seven eight nine ten

    eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen}

make "tens {twenty thirty forty fifty sixty seventy eighty ninety}@2

make "thou [[] thousand million billion trillion] ; expand as desired

to to.english.thou :n :thou

 if :n = 0    [output []]
 if :n < 20   [output sentence item :n :numbers  first :thou]
 if :n < 100  [output (sentence item int :n/10 :tens
                                to.english.thou modulo :n 10 [[]]
                                first :thou)]
 if :n < 1000 [output (sentence item int :n/100 :numbers
                                "hundred
                                to.english.thou modulo :n 100 [[]]
                                first :thou)]
 output (sentence to.english.thou int :n/1000 butfirst :thou
                  to.english.thou modulo :n 1000 :thou)

end

to to.english :n

 if :n = 0 [output "zero]
 if :n > 0 [output to.english.thou :n :thou]
 [output sentence "negative to.english.thou minus :n :thou]

end

print to.english 1234567  ; one million two hundred thirty four thousand five hundred sixty seven</lang>

Lua

<lang lua>words = {"one ", "two ", "three ", "four ", "five ", "six ", "seven ", "eight ", "nine "} levels = {"thousand ", "million ", "billion ", "trillion ", "quadrillion ", "quintillion ", "sextillion ", "septillion ", "octillion ", [0] = ""} iwords = {"ten ", "twenty ", "thirty ", "forty ", "fifty ", "sixty ", "seventy ", "eighty ", "ninety "} twords = {"eleven ", "twelve ", "thirteen ", "fourteen ", "fifteen ", "sixteen ", "seventeen ", "eighteen ", "nineteen "}

function digits(n)

 local i, ret = -1
 return function()
   i, ret = i + 1, n % 10

if n > 0 then

     n = math.floor(n / 10)

return i, ret end

 end

end

level = false function getname(pos, dig) --stateful, but effective.

 level = level or pos % 3 == 0
 if(dig == 0) then return "" end
 local name = (pos % 3 == 1 and iwords[dig] or words[dig]) .. (pos % 3 == 2 and "hundred " or "")
 if(level) then name, level = name .. levels[math.floor(pos / 3)], false end
 return name

end

local val, vword = io.read() + 0, ""

for i, v in digits(val) do

 vword = getname(i, v) .. vword

end

for i, v in ipairs(words) do

 vword = vword:gsub("ty " .. v, "ty-" .. v)
 vword = vword:gsub("ten " .. v, twords[i])

end

if #vword == 0 then print "zero" else print(vword) end</lang>

MAXScript

This example is incorrect. Please fix the code and remove this message.

Details: It does not support values up to one million.

This example isn't a very succinct way to solve the problem, but the way it works should be quite obvious. The function will work for values up to 1000 <lang MAXScript>fn NumberToWord myNum = ( local Result = "" while myNum != 0 do ( Result += case of ( (myNum >= 1000):(myNum -= 1000; "one thousand") (myNum > 900): (myNum -= 900 ; "nine hundred and") (myNum == 900): (myNum -= 900 ; "nine hundred") (myNum > 800): (myNum -= 800 ; "eight hundred and") (myNum == 800): (myNum -= 900 ; "eight hundred") (myNum > 700): (myNum -= 700 ; "seven hundred and") (myNum == 700): (myNum -= 900 ; "seven hundred") (myNum > 600): (myNum -= 600 ; "six hundred and") (myNum == 600): (myNum -= 900 ; "six hundred") (myNum > 500): (myNum -= 500 ; "five hundred and") (myNum == 500): (myNum -= 900 ; "five hundred") (myNum > 400): (myNum -= 400 ; "four hundred and") (myNum == 400): (myNum -= 900 ; "four hundred") (myNum > 300): (myNum -= 300 ; "three hundred and") (myNum == 300): (myNum -= 900 ; "three hundred") (myNum > 200): (myNum -= 200 ; "two hundred and") (myNum == 200): (myNum -= 900 ; "two hundred") (myNum > 100): (myNum -= 100 ; "one hundred and") (myNum == 100): (myNum -= 100 ; "one hundred") (myNum >= 90): (myNum -= 90  ; "ninety") (myNum >= 80): (myNum -= 80  ; "eighty") (myNum >= 70): (myNum -= 70  ; "seventy") (myNum >= 60): (myNum -= 60  ; "sixty") (myNum >= 50): (myNum -= 50  ; "fifty") (myNum >= 40): (myNum -= 40  ; "fourty") (myNum >= 30): (myNum -= 30  ; "thirty") (myNum >= 20): (myNum -= 20  ; "twenty") (myNum >= 19): (myNum -= 19  ; "nineteen") (myNum >= 18): (myNum -= 18  ; "eighteen") (myNum >= 17): (myNum -= 17  ; "seventeen") (myNum >= 16): (myNum -= 16  ; "sixteen") (myNum >= 15): (myNum -= 15  ; "fifteen") (myNum >= 14): (myNum -= 14  ; "fourteen") (myNum >= 13): (myNum -= 13  ; "thirteen") (myNum >= 12): (myNum -= 12  ; "twelve") (myNum >= 11): (myNum -= 11  ; "eleven") (myNum >= 10): (myNum -= 10  ; "ten") (myNum >= 9): (myNum -= 9  ; "nine") (myNum >= 8): (myNum -= 8  ; "eight") (myNum >= 7): (myNum -= 7  ; "seven") (myNum >= 6): (myNum -= 6  ; "six") (myNum >= 5): (myNum -= 5  ; "five") (myNum >= 4): (myNum -= 4  ; "four") (myNum >= 3): (myNum -= 3  ; "three") (myNum >= 2): (myNum -= 2  ; "two") (myNum >= 1): (myNum -= 1  ; "one") ) if myNum != 0 then result += " " ) result )</lang>

Example: <lang MAXScript>NumberToWord(123)</lang>

OCaml

<lang ocaml>let div_mod n d = (n / d, n mod d) let join = String.concat ", " ;;

let rec nonzero = function

 | _, 0 -> ""
 | c, n -> c ^ (spell_integer n)

and tens n =

 [| ""; ""; "twenty"; "thirty"; "forty"; "fifty";
            "sixty"; "seventy"; "eighty"; "ninety" |].(n)

and small n =

 [| "zero"; "one"; "two"; "three"; "four"; "five";
    "six"; "seven"; "eight"; "nine"; "ten"; "eleven";
    "twelve"; "thirteen"; "fourteen"; "fifteen";
    "sixteen";"seventeen"; "eighteen"; "nineteen" |].(n)

and bl = [| ""; ""; "m"; "b"; "tr"; "quadr"; "quint";

                   "sext"; "sept"; "oct"; "non"; "dec" |]

and big = function

 | 0, n -> (spell_integer n)
 | 1, n -> (spell_integer n) ^ " thousand"
 | e, n -> (spell_integer n) ^ " " ^ bl.(e) ^ "illion"

and uff acc = function

 | 0 -> List.rev acc
 | n ->
     let a, b = div_mod n 1000 in
     uff (b::acc) a

and spell_integer = function

 | n when n < 0 -> invalid_arg "spell_integer: negative input"
 | n when n < 20 -> small n
 | n when n < 100 ->
     let a, b = div_mod n 10 in
     (tens a) ^ nonzero("-", b)
 | n when n < 1000 ->
     let a, b = div_mod n 100 in
     (small a) ^ " hundred" ^ nonzero(" ", b)
 | n ->
     let seg = (uff [] n) in
     let _, segn =
       (* just add the index of the item in the list *)
       List.fold_left
         (fun (i,acc) v -> (succ i, (i,v)::acc))
         (0,[])
         seg
     in
     let fsegn =
       (* remove right part "zero" *)
       List.filter
         (function (_,0) -> false | _ -> true)
         segn
     in
     join(List.map big fsegn)
</lang>

PARI/GP

<lang parigp>Eng(n:int)={ my(tmp,s=""); if (n >= 1000000, tmp = n\1000000; s = Str(Eng(tmp), " million"); n -= tmp * 1000000; if (!n, return(s)); s = Str(s, " ") ); if (n >= 1000, tmp = n\1000; s = Str(Eng(tmp), " thousand"); n -= tmp * 1000; if (!n, return(s)); s = Str(s, " ") ); if (n >= 100, tmp = n\100; s = Str(Edigit(tmp), " hundred"); n -= tmp * 100; if (!n, return(s)); s = Str(s, " ") ); if (n < 20, return (Str(s, ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "ninteen"][n])) ); tmp = n\10; s = Str(s, [0, "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"][tmp]); n -= tmp * 10; if (n, Str(s, "-", Edigit(n)), s) }; Edigit(n)={ ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"][n] };</lang>

Perl

<lang perl>use Lingua::EN::Numbers 'num2en';

print num2en(123456789), "\n";</lang>

Perl 6

Works with: niecza

Apart from the $m++ this can be viewed as a purely functional program; we use nested gather/take constructs to avoid accumulators. The negative and zero detection is done in the string domain because mono's big integers seem to blow up somewhere before a centillion. <lang perl6>constant @I = <zero one two three four five six seven eight nine

              ten  eleven twelve thirteen fourteen fifteen sixteen seventeen eighteen nineteen>;

constant @X = <0 X twenty thirty forty fifty sixty seventy eighty ninety>; constant @C = @I X~ ' hundred'; constant @M = (<0 thousand>,

   ((<m b tr quadr quint sext sept oct non>,
   (map { (, <un duo tre quattuor quin sex septen octo novem>).flat X~ $_ },
   <dec vigint trigint quadragint quinquagint sexagint septuagint octogint nonagint>),
   'cent').flat X~ 'illion')).flat;

sub int-name ($num) {

   if $num.substr(0,1) eq '-' { return "negative {int-name($num.substr(1))}" }
   if $num eq '0' { return @I[0] }
   my $m = 0;
   return join ', ', reverse gather for $num.flip.comb(/\d ** 1..3/) {
       my ($i,$x,$c) = .comb;
       if $i or $x or $c {
           take join ' ', gather {
               if $c { take @C[$c] }
               if $x and $x == 1 { take @I[$i+10] }
               else {
                   if $x { take @X[$x] }
                   if $i { take @I[$i] }
               }
               take @M[$m] // die "WOW! ZILLIONS!\n" if $m;
           }
       }
       $m++;
   }

}

while ne (my $n = prompt("Number: ")) {

   say int-name($n);

}</lang> Output:

Number: 0
zero
Number: 17
seventeen
Number: -1,234,567,890          
negative one billion, two hundred thirty four million, five hundred sixty seven thousand, eight hundred ninety
Number: 42 000
forty two thousand
Number: 1001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001001
one novemseptuagintillion, one octoseptuagintillion, one septenseptuagintillion, one sexseptuagintillion, one quinseptuagintillion, one quattuorseptuagintillion, one treseptuagintillion, one duoseptuagintillion, one unseptuagintillion, one septuagintillion, one novemsexagintillion, one octosexagintillion, one septensexagintillion, one sexsexagintillion, one quinsexagintillion, one quattuorsexagintillion, one tresexagintillion, one duosexagintillion, one unsexagintillion, one sexagintillion, one novemquinquagintillion, one octoquinquagintillion, one septenquinquagintillion, one sexquinquagintillion, one quinquinquagintillion, one quattuorquinquagintillion, one trequinquagintillion, one duoquinquagintillion, one unquinquagintillion, one quinquagintillion, one novemquadragintillion, one octoquadragintillion, one septenquadragintillion, one sexquadragintillion, one quinquadragintillion, one quattuorquadragintillion, one trequadragintillion, one duoquadragintillion, one unquadragintillion, one quadragintillion, one novemtrigintillion, one octotrigintillion, one septentrigintillion, one sextrigintillion, one quintrigintillion, one quattuortrigintillion, one tretrigintillion, one duotrigintillion, one untrigintillion, one trigintillion, one novemvigintillion, one octovigintillion, one septenvigintillion, one sexvigintillion, one quinvigintillion, one quattuorvigintillion, one trevigintillion, one duovigintillion, one unvigintillion, one vigintillion, one novemdecillion, one octodecillion, one septendecillion, one sexdecillion, one quindecillion, one quattuordecillion, one tredecillion, one duodecillion, one undecillion, one decillion, one nonillion, one octillion, one septillion, one sextillion, one quintillion, one quadrillion, one trillion, one billion, one million, one thousand, one
Number: 198723483017417
one hundred ninety eight trillion, seven hundred twenty three billion, four hundred eighty three million, seventeen thousand, four hundred seventeen

PHP

<lang php>$orderOfMag = array('Hundred', 'Thousand,', 'Million,', 'Billion,', 'Trillion,'); $smallNumbers = array('Zero', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen'); $decades = array(, , 'Twenty', 'Thirty', 'Forty', 'Fifty', 'Sixty', 'Seventy', 'Eighty', 'Ninety');

function NumberToEnglish($num, $count = 0){

  global $orderOfMag, $smallNumbers, $decades;
  $isLast = true;
  $str = ;
  if ($num < 0){
     $str = 'Negative ';
     $num = abs($num);
  }
  (int) $thisPart = substr((string) $num, -3);
  if (strlen((string) $num) > 3){
     // Number still too big, work on a smaller chunk
     $str .= NumberToEnglish((int) substr((string) $num, 0, strlen((string) $num) - 3), $count + 1);
     $isLast = false;
  }
  // do translation stuff
  if (($count == 0 || $isLast) && ($str ==  || $str == 'Negative '))
     // This is either a very small number or the most significant digits of the number. Either way we don't want a preceeding "and"
     $and = ;
  else
     $and = ' and ';
  if ($thisPart > 99){
     // Hundreds part of the number chunk
     $str .= ($isLast ?  : ' ') . "{$smallNumbers[$thisPart/100]} {$orderOfMag[0]}";
     if(($thisPart %= 100) == 0){
        // There is nothing else to do for this chunk (was a multiple of 100)
        $str .= " {$orderOfMag[$count]}";
        return $str;
     }
     $and = ' and ';  // Set up our and string to the word "and" since there is something in the hundreds place of this chunk
  }
  if ($thisPart >= 20){
     // Tens part of the number chunk
     $str .= "{$and}{$decades[$thisPart /10]}";
     $and = ' '; // Make sure we don't have any extranious "and"s
     if(($thisPart %= 10) == 0)
        return $str . ($count != 0 ? " {$orderOfMag[$count]}" : );
  }
  if ($thisPart < 20 && $thisPart > 0)
     // Ones part of the number chunk
     return $str . "{$and}{$smallNumbers[(int) $thisPart]} " . ($count != 0 ? $orderOfMag[$count] : );
  elseif ($thisPart == 0 && strlen($thisPart) == 1)
     // The number is zero
     return $str . "{$smallNumbers[(int)$thisPart]}";

}</lang> Example: <lang php>NumberToEnglish(0); NumberToEnglish(12); NumberToEnglish(123); NumberToEnglish(1234567890123); NumberToEnglish(65535); NumberToEnglish(-54321);</lang> Returns:

Zero
Twelve
One Hundred and Twenty Three
One Trillion, Two Hundred and Thirty Four Billion, Five Hundred and Sixty Seven Million, Eight Hundred and Ninety Thousand, One Hundred and Twenty Three
Sixty Five Thousand, Five Hundred and Thirty Five
Negative Fifty Four Thousand, Three Hundred and Twenty One

PicoLisp

<lang PicoLisp>(de numName (N)

  (cond
     ((=0 N) "zero")
     ((lt0 N) (pack "minus " (numName (- N))))
     (T (numNm N)) ) )

(de numNm (N)

  (cond
     ((=0 N))
     ((> 14 N)
        (get '("one" "two" "three" "four" "five" "six" "seven" "eight" "nine" "ten" "eleven" "twelve" "thirteen") N) )
     ((= 15 N) "fifteen")
     ((= 18 N) "eighteen")
     ((> 20 N) (pack (numNm (% N 10)) "teen"))
     ((> 100 N)
        (pack
           (get '("twen" "thir" "for" "fif" "six" "seven" "eigh" "nine") (dec (/ N 10)))
           "ty"
           (unless (=0 (% N 10))
              (pack "-" (numNm (% N 10))) ) ) )
     ((rank N '((100 . "hundred") (1000 . "thousand") (1000000 . "million")))
        (pack (numNm (/ N (car @))) " " (cdr @) " " (numNm (% N (car @)))) ) ) )</lang>

PL/I

<lang PL/I> declare integer_names (0:20) character (9) varying static initial

     ('zero',  'one',   'two',  'three', 'four',   'five', 'six',
      'seven', 'eight', 'nine', 'ten',   'eleven', 'twelve',
      'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen',
      'eighteen', 'nineteen', 'twenty' );
  declare x(10) character (7) varying static initial
     ('ten', 'twenty', 'thirty', 'fourty', 'fifty',
      'sixty', 'seventy', 'eighty', 'ninety', 'hundred');
  declare y(0:5) character (10) varying static initial
     (, , ' thousand ', ' million ', ' billion ', ' trillion ');
  declare (i, j, m, t) fixed binary (31);
  declare (units, tens, hundreds, thousands) fixed binary (7);
  declare (h, v, value) character (200) varying;
  declare (d, k, n) fixed decimal (15);
  declare three_digits fixed decimal (3);
     value = ;
     i = 5;
     k = n;
     do d = 1000000000000 repeat d/1000 while (d > 0);
        i = i - 1;
        three_digits = k/d;
        k = mod(k, d);
        if three_digits = 0 then iterate;
        units = mod(three_digits, 10);
        t = three_digits / 10;
        tens = mod(t, 10);
        hundreds = three_digits / 100;
        m = mod(three_digits, 100);
        if m <= 20 then
           v = integer_names(m);
        else if units = 0 then
           v = ;
        else
           v = integer_names(units);
        if tens >= 2 & units ^= 0 then
           v = x(tens) || v;
        else if tens > 2 & units = 0 then
           v = v || x(tens);
        if units + tens = 0 then
           if n > 0 then  v = ;
        if hundreds > 0 then
           h = integer_names(hundreds) || ' hundred ';
        else
           h = ;
        if three_digits > 100 & (tens + units > 0) then
           v = 'and ' || v;
        if i = 1 & value ^=  & three_digits <= 9 then
           v = 'and ' || v;
        value = value ||h || v || y(i);
     end;
     put skip edit (trim(N), ' = ', value) (a);</lang>

PowerBASIC

Translation of: BASIC

Note that the PB compiler seems to have some bugs related to the QUAD data type; see the sample output below the code.

<lang powerbasic>FUNCTION int2Text (number AS QUAD) AS STRING

   IF 0 = number THEN
       FUNCTION = "zero"
       EXIT FUNCTION
   END IF
   DIM num AS QUAD, outP AS STRING, unit AS LONG
   DIM tmpLng1 AS QUAD
   DIM small(1 TO 19) AS STRING, tens(7) AS STRING, big(5) AS STRING
   DIM tmpInt AS LONG, dcnt AS LONG
   ARRAY ASSIGN small() = "one", "two", "three", "four", "five", "six", _
                          "seven", "eight", "nine", "ten", "eleven", _
                          "twelve", "thirteen", "fourteen", "fifteen", _
                          "sixteen", "seventeen", "eighteen", "nineteen"
   ARRAY ASSIGN tens() = "twenty", "thirty", "forty", "fifty", "sixty", _
                         "seventy", "eighty", "ninety"
   ARRAY ASSIGN big() = "thousand", "million", "billion", "trillion", _
                        "quadrillion", "quintillion"
   num = ABS(number)
   DO
       tmpLng1 = num MOD 100
       SELECT CASE tmpLng1
           CASE 1 TO 19
               outP = small(tmpLng1) + " " + outP
           CASE 20 TO 99
               SELECT CASE tmpLng1 MOD 10
                   CASE 0
                       outP = tens((tmpLng1 \ 10) - 2) + " " + outP
                   CASE ELSE
                       outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 MOD 10) + " " + outP
               END SELECT
       END SELECT
       tmpLng1 = (num MOD 1000) \ 100
       IF tmpLng1 THEN
           outP = small(tmpLng1) + " hundred " + outP
       END IF
       num = num \ 1000
       IF num < 1 THEN EXIT DO
       tmpLng1 = num MOD 1000
       IF tmpLng1 THEN outP = big(unit) + " " + outP
       unit = unit + 1
   LOOP
   IF number < 0 THEN outP = "negative " + outP
   FUNCTION = RTRIM$(outP)

END FUNCTION


FUNCTION PBMAIN () AS LONG

   DIM n AS QUAD
   #IF %DEF(%PB_CC32)
       INPUT "Gimme a number! ", n
   #ELSE
       n = VAL(INPUTBOX$("Gimme a number!", "Now!"))
   #ENDIF
   ? int2Text(n)

END FUNCTION</lang>

Sample output:

Gimme a number! 1111111111111111111
one quintillion one hundred eleven quadrillion one hundred eleven trillion one h
undred eleven billion one hundred eleven million one hundred eleven thousand one
hundred ten

PureBasic

The range of integers handled has been set at an obscene 45 digits. <lang PureBasic>DataSection

 numberNames:
 ;small
 Data.s "one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten"
 Data.s "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"
 ;tens
 Data.s "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"
 ;big, non-Chuquet system 
 Data.s "thousand", "million", "billion", "trillion", "quadrillion", "quintillion", "sextillion"
 Data.s "septillion", "octillion", "nonillion", "decillion", "undecillion", "duodecillion"
 Data.s "tredecillion"

EndDataSection

Procedure.s numberWords(number.s)

 ;handles integers from -1E45 to +1E45
 Static isInitialized = #False
 Static Dim small.s(19)
 Static Dim tens.s(9)
 Static Dim big.s(14)
 
 If Not isInitialized
   Restore numberNames
   For i = 1 To 19
     Read.s small(i)
   Next
   For i = 2 To 9
     Read.s tens(i)
   Next
   For i = 1 To 14
     Read.s big(i)
   Next
   isInitialized = #True
 EndIf 
 
 For i = 1 To Len(number)
   If Not FindString("- 0123456789", Mid(number,i,1), 1)
     number = Left(number, i - 1) ;trim number to the last valid character
     Break ;exit loop
   EndIf 
 Next 
 
 Protected IsNegative = #False
 number = Trim(number)
 If Left(number,1) = "-"
   IsNegative = #True
   number = Trim(Mid(number, 2))
 EndIf 
 
 If CountString(number, "0") = Len(number)
   ProcedureReturn "zero"
 EndIf 
 
 If Len(number) > 45
   ProcedureReturn "Number is too big!"
 EndIf 
 
 Protected num.s = number, output.s, unit, unitOutput.s, working
 
 Repeat
   working = Val(Right(num, 2))
   unitOutput = ""
   Select working
     Case 1 To 19
       unitOutput = small(working)
     Case 20 To 99
       If working % 10
         unitOutput = tens(working / 10) + "-" + small(working % 10)
       Else
         unitOutput = tens(working / 10)
       EndIf 
   EndSelect
   
   working = Val(Right(num, 3)) / 100
   If working
     If unitOutput <> ""
       unitOutput = small(working) + " hundred " + unitOutput
     Else
       unitOutput = small(working) + " hundred"
     EndIf 
   EndIf 
   
   If unitOutput <> "" And unit > 0
     unitOutput + " " + big(unit)
     If output <> ""
       unitOutput + ", "
     EndIf 
   EndIf 
   
   output = unitOutput + output
   
   If Len(num) > 3
     num = Left(num, Len(num) - 3)
     unit + 1
   Else
     Break ;exit loop
   EndIf 
 ForEver
 
 If IsNegative
   output = "negative " + output
 EndIf
 
 ProcedureReturn output

EndProcedure

Define n$ If OpenConsole()

 Repeat
   Repeat
     Print("Give me an integer (or q to quit)! ")
     n$ = Input()
   Until n$ <> ""
   
   If Left(Trim(n$),1) = "q"
     Break ;exit loop
   EndIf 
   PrintN(numberWords(n$))
 ForEver 
 CloseConsole()

EndIf </lang> Sample output:

Give me an integer (or q to quit)! 3
three
Give me an integer (or q to quit)! -1327
negative one thousand, three hundred twenty-seven
Give me an integer (or q to quit)! 0
zero
Give me an integer (or q to quit)! 100000000002000000000000000300000000000000004
one hundred tredecillion, two decillion, three hundred quadrillion, four

Python

<lang python>def spell_integer(n):

   tens = [None, None, "twenty", "thirty", "forty",
           "fifty", "sixty", "seventy", "eighty", "ninety"]
   small = ["zero", "one", "two", "three", "four", "five",
            "six", "seven", "eight", "nine", "ten", "eleven",
            "twelve", "thirteen", "fourteen", "fifteen",
            "sixteen", "seventeen", "eighteen", "nineteen"]
   bl = [None, None, "m", "b", "tr", "quadr",
         "quint", "sext", "sept", "oct", "non", "dec"]
   def nonzero(c, n):
       return "" if n == 0 else c + spell_integer(n)
   def big(e, n):
       if e == 0:
           return spell_integer(n)
       elif e == 1:
           return spell_integer(n) + " thousand"
       else:
           return spell_integer(n) + " " + bl[e] + "illion"
   def base1000_rev(n):
       # generates the value of the digits of n in base 1000
       # (i.e. 3-digit chunks), in reverse.
       while n != 0:
           n, r = divmod(n, 1000)
           yield r
   if n < 0:
       return "negative " + spell_integer(-n)
   elif n < 20:
       return small[n]
   elif n < 100:
       a, b = divmod(n, 10)
       return tens[a] + nonzero("-", b)
   elif n < 1000:
       a, b = divmod(n, 100)
       return small[a] + " hundred" + nonzero(" ", b)
   else:
       return ", ".join([big(e, x) for e, x in
                         enumerate(base1000_rev(n)) if x][::-1])
  1. example

print spell_integer(1278) print spell_integer(1752) print spell_integer(2010)</lang>

one thousand, two hundred seventy-eight
one thousand, seven hundred fifty-two
two thousand, ten

REXX

See Number names/REXX.

Ruby

Works with: Ruby version 1.8.7+
Works with: Ruby version 1.9.2+

<lang ruby>SMALL = %w(zero one two three four five six seven eight nine ten

          eleven twelve thirteen fourteen fifteen sixteen seventeen
          eighteen nineteen)

TENS = %w(wrong wrong twenty thirty forty fifty sixty seventy

         eighty ninety)

BIG = [nil, "thousand"] +

     %w( m b tr quadr quint sext sept oct non dec).map{ |p| "#{p}illion" }


def wordify number

 if number < 0
   "negative #{wordify -number}"
 elsif number < 20
   SMALL[number]
 elsif number < 100
   div, mod = number.divmod(10)
   "#{TENS[div]}-#{wordify mod}".chomp("-zero")
 elsif number < 1000
   div, mod = number.divmod(100)
   "#{wordify div} hundred and #{wordify mod}".chomp(" and zero")
 else
   # separate into 3-digit chunks
   chunks = []
   div = number
   while div != 0
     div, mod = div.divmod(1000)
     chunks << mod # will store smallest to largest
   end
   if chunks.length > BIG.length
     raise ArgumentError, "Integer value too large."
   end
   chunks.map{ |c| wordify c }.
          zip(BIG). # zip pairs up corresponding elements from the two arrays
          find_all { |c| c[0] != 'zero' }.
          map{ |c| c.join ' '}. # join ["forty", "thousand"]
          reverse.
          join(', '). # join chunks
          strip
 end

end

[-1123, 0, 1, 20, 123, 200, 220, 1245, 2000, 2200, 2220, 467889, 23_000_467,

 23_234_467, 2_235_654_234, 12_123_234_543_543_456,
 123890812938219038290489327894327894723897432].each do |n|
 print "#{n}: "
 begin
   puts "'#{wordify n}'"
 rescue => e
   puts "Error: #{e}"
 end

end</lang>

-1123: 'negative one thousand, one hundred and twenty-three'
0: 'zero'
1: 'one'
20: 'twenty'
123: 'one hundred and twenty-three'
200: 'two hundred'
220: 'two hundred and twenty'
1245: 'one thousand, two hundred and forty-five'
2000: 'two thousand'
2200: 'two thousand, two hundred'
2220: 'two thousand, two hundred and twenty'
467889: 'four hundred and sixty-seven thousand, eight hundred and eighty-nine'
23000467: 'twenty-three million, four hundred and sixty-seven'
23234467: 'twenty-three million, two hundred and thirty-four thousand, four hundred and sixty-seven'
2235654234: 'two billion, two hundred and thirty-five million, six hundred and fifty-four thousand, two hundred and thirty-four'
12123234543543456: 'twelve quadrillion, one hundred and twenty-three trillion, two hundred and thirty-four billion, five hundred and forty-three million, five hundred and forty-three thousand, four hundred and fifty-six'
123890812938219038290489327894327894723897432: Error: Integer value too large.

Seed7

The library wrinum.s7i contains the function str(ENGLISH, ...) which converts an integer to its written english equivalent.

<lang seed7>$ include "seed7_05.s7i";

 include "stdio.s7i";
 include "wrinum.s7i";

const proc: main is func

 local
   var integer: number is 0;
 begin
   for number range 1 to 999999 do
     writeln(str(ENGLISH, number));
   end for;
 end func;</lang>

Tcl

<lang tcl>proc int2words {n} {

   if { ! [regexp -- {^(-?\d+)$} $n -> n]} {
       error "not a decimal integer"
   }
   if {$n == 0} {
       return zero
   }
   if {$n < 0} {
       return "negative [int2words [expr {abs($n)}]]"
   }
   if {[string length $n] > 36} {
       error "value too large to represent"
   }
   
   set groups [get_groups $n]
   set l [llength $groups]
   foreach group $groups {
       incr l -1
       # ensure any group with a leading zero is not treated as octal
       set val [scan $group %d]
       if {$val > 0} {
           lappend result [group2words $val $l]
       }
   }
   return [join $result ", "]

}

set small {"" one two three four five six seven eight nine ten eleven twelve

          thirteen fourteen fifteen sixteen seventeen eighteen nineteen}

set tens {"" "" twenty thirty forty fifty sixty seventy eighty ninety} set powers {"" thousand} foreach p {m b tr quadr quint sext sept oct non dec} {lappend powers ${p}illion}

proc group2words {n level} {

   global small tens powers
   if {$n < 20} {
       lappend result [lindex $small $n]
   } elseif {$n < 100} {
       lassign [divmod $n 10] a b
       set result [lindex $tens $a]
       if {$b > 0} {
           append result - [lindex $small $b]
       }
   } else {
       lassign [divmod $n 100] a b
       lappend result [lindex $small $a] hundred
       if {$b > 0} {
           lappend result and [group2words $b 0]
       }
   }
   return [join [concat $result [lindex $powers $level]]]

}

proc divmod {n d} {

   return [list [expr {$n / $d}] [expr {$n % $d}]]

}

proc get_groups {num} {

   # from http://wiki.tcl.tk/5000
   while {[regsub {^([-+]?\d+)(\d\d\d)} $num {\1 \2} num]} {}
   return [split $num]

}

foreach test {

       0 -0 5 -5 10 25 99 100 101 999 1000 1008 1010 54321 1234567890
       0x7F
       123456789012345678901234567890123456
       1234567890123456789012345678901234567

} {

   catch {int2words $test} result
   puts "$test -> $result"

}</lang> produces

0 -> zero
-0 -> zero
5 -> five
-5 -> negative five
10 -> ten
25 -> twenty-five
99 -> ninety-nine
100 -> one hundred
101 -> one hundred and one
999 -> nine hundred and ninety-nine
1000 -> one thousand
1008 -> one thousand, eight
1010 -> one thousand, ten
54321 -> fifty-four thousand, three hundred and twenty-one
1234567890 -> one billion, two hundred and thirty-four million, five hundred and sixty-seven thousand, eight hundred and ninety
0x7F -> not a decimal integer
123456789012345678901234567890123456 -> one hundred and twenty-three decillion, four hundred and fifty-six nonillion, seven hundred and eighty-nine octillion, twelve septillion, three hundred and forty-five sextillion, six hundred and seventy-eight quintillion, nine hundred and one quadrillion, two hundred and thirty-four trillion, five hundred and sixty-seven billion, eight hundred and ninety million, one hundred and twenty-three thousand, four hundred and fifty-six
1234567890123456789012345678901234567 -> value too large to represent

Visual Basic

Translation of: BASIC

If one were to use variants further and get them to play nice as Decimal, this could theoretically be extended up to the octillion range. <lang vb>Option Explicit

Private small As Variant, tens As Variant, big As Variant

Sub Main()

   small = Array("one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", _
                 "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen", _
                 "eighteen", "nineteen")
   tens = Array("twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety")
   big = Array("thousand", "million", "billion")
   Dim tmpInt As Long
   tmpInt = Val(InputBox("Gimme a number!", "NOW!", Trim$(Year(Now)) & IIf(Month(Now) < 10, "0", "") & _
                Trim$(Month(Now)) & IIf(Day(Now) < 10, "0", "") & Trim$(Day(Now))))
   MsgBox int2Text$(tmpInt)

End Sub

Function int2Text$(number As Long)

   Dim num As Long, outP As String, unit As Integer
   Dim tmpLng1 As Long
   If 0 = number Then
       int2Text$ = "zero"
       Exit Function
   End If
   num = Abs(number)
   Do
       tmpLng1 = num Mod 100
       Select Case tmpLng1
           Case 1 To 19
               outP = small(tmpLng1 - 1) + " " + outP
           Case 20 To 99
               Select Case tmpLng1 Mod 10
                   Case 0
                       outP = tens((tmpLng1 \ 10) - 2) + " " + outP
                   Case Else
                       outP = tens((tmpLng1 \ 10) - 2) + "-" + small(tmpLng1 Mod 10) + " " + outP
               End Select
       End Select
       tmpLng1 = (num Mod 1000) \ 100
       If tmpLng1 Then
           outP = small(tmpLng1 - 1) + " hundred " + outP
       End If
       num = num \ 1000
       If num < 1 Then Exit Do
       tmpLng1 = num Mod 1000
       If tmpLng1 Then outP = big(unit) + " " + outP
       unit = unit + 1
   Loop
   If number < 0 Then outP = "negative " & outP
   int2Text$ = Trim$(outP)

End Function</lang>

Example output (in a msgbox) is identical to the BASIC output.

Visual Basic .NET

Platform: .NET

Works with: Visual Basic .NET version 9.0+

This solution works for integers up to 1000. It should be fairly ovbious how it works, and so can be extended if needed.

<lang vbnet>Module Module1

   Sub Main()
       Dim i As Integer
       Console.WriteLine("Enter a number")
       i = Console.ReadLine()
       Console.WriteLine(words(i))
       Console.ReadLine()
   End Sub
   
   Function words(ByVal Number As Integer) As String
       Dim small() As String = {"zero", "one", "two", "three", "four", "five", "six", "seven", "eight",
        "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen", "sixteen", "seventeen",
        "eighteen", "nineteen"}
       Dim tens() As String = {"", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", "ninety"}
       Select Case Number
           Case Is < 20
               words = small(Number)
           Case 20 To 99
               words = tens(Number \ 10) + " " + small(Number Mod 10)
           Case 100 To 999
               words = small(Number \ 100) + " hundred " + IIf(((Number Mod 100) <> 0), "and ", "") + words(Number Mod 100)
           Case 1000
               words = "one thousand"
       End Select
   End Function

End Module</lang>