Longest palindromic substrings: Difference between revisions

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(→‎{{header|REXX}}: added the computer programming language REXX.)
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Let given a string s.
Let given a string s.
The goal is to find the longest palindromic substring in s.
The goal is to find the longest palindromic substring in s.

<br><br>
=={{header|REXX}}==
<lang rexx>/*REXX program finds and displays the longest palindromic string(s) in a given string. */
parse arg s . /*obtain optional argument from the CL.*/
if s=='' | s=="," then s= 'babaccd' /*Not specified? Then use the default.*/
L= length(s) /*obtain length of the specified string*/
longest= 0 /*longest palindrome found (so far). */
@.= /*initialize all possible lists to null*/
do j=1 for L /*search for palindromes in the string.*/
do k=j to L; LL= k - j + 1 /*obtain length of possible palindromes.*/
if LL<longest then iterate /*Palindrome length<max? Then skip it.*/
$= substr(s, j, LL) /*obtain a possible palindromic substr.*/
if $\==reverse($) then iterate /*Not a palindrome? Then skip it.*/
longest= max(longest, LL) /*set the longest palindrome to this L.*/
@.LL= @.LL $ /*add a palindromic substring to a list*/
end /*k*/
end /*j*/

if longest==0 then do; say 'no longest palindromic string was found for: ' s; exit 13
end
say ' longest palindromic substrings for string: ' s /*show title.*/
say '────────────────────────────────────────────'copies('─', 2+length(s)) /*show sep. */

do n=1 for words(@.longest) /*show longest palindromic substrings. */
/*show pals. */
say ' (length='longest") " word(@.longest, n)
end /*n*/ /*stick a fork in it, we're all done. */</lang>
{{out|output|text=&nbsp; when using the default input:}}
<pre>
longest palindromic substrings for string: babaccd
─────────────────────────────────────────────────────
(length=3) bab
(length=3) aba
</pre>

=={{header|Ring}}==
=={{header|Ring}}==
<lang ring>
<lang ring>

Revision as of 16:53, 28 September 2020

Longest palindromic substrings is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Let given a string s. The goal is to find the longest palindromic substring in s.



REXX

<lang rexx>/*REXX program finds and displays the longest palindromic string(s) in a given string. */ parse arg s . /*obtain optional argument from the CL.*/ if s== | s=="," then s= 'babaccd' /*Not specified? Then use the default.*/ L= length(s) /*obtain length of the specified string*/ longest= 0 /*longest palindrome found (so far). */ @.= /*initialize all possible lists to null*/

          do j=1   for L                        /*search for palindromes in the string.*/
            do k=j  to L;      LL= k - j + 1    /*obtain length of possible palindromes.*/
            if LL<longest      then iterate     /*Palindrome length<max?  Then skip it.*/
            $= substr(s, j, LL)                 /*obtain a possible palindromic substr.*/
            if $\==reverse($)  then iterate     /*Not a palindrome?       Then skip it.*/
            longest= max(longest, LL)           /*set the longest palindrome to this L.*/
            @.LL= @.LL $                        /*add a palindromic substring to a list*/
            end   /*k*/
          end     /*j*/

if longest==0 then do; say 'no longest palindromic string was found for: ' s; exit 13

                   end

say ' longest palindromic substrings for string: ' s /*show title.*/ say '────────────────────────────────────────────'copies('─', 2+length(s)) /*show sep. */

 do n=1  for words(@.longest)                   /*show longest palindromic substrings. */
             /*show pals. */
 say '    (length='longest")   "   word(@.longest, n)
 end   /*n*/                                    /*stick a fork in it,  we're all done. */</lang>
output   when using the default input:
 longest palindromic substrings for string:  babaccd
─────────────────────────────────────────────────────
    (length=3)    bab
    (length=3)    aba

Ring

<lang ring> load "stdlib.ring"

st = "babaccd" palList = []

for n = 1 to len(st)-1

   for m = n+1 to len(st)
       sub = substr(st,n,m-n)
       if ispalindrome(sub) and len(sub) > 1
          add(palList,[sub,len(sub)])
       ok
   next

next

palList = sort(palList,2) palList = reverse(palList) resList = [] add(resList,palList[1][1])

for n = 2 to len(palList)

   if palList[1][2] = palList[n][2]
      add(resList,palList[n][1])
   ok

next

see "Input: " + st + nl see "Longest palindromic substrings:" + nl see resList </lang>

Output:
Input: babaccd
Longest palindromic substrings:
bab
aba