Longest common subsequence: Difference between revisions
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→{{header|jq}}: ce
(jq) |
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=={{header|jq}}==
We first give a recursive solution, and then use it to write
def recursive_lcs(a; b):
if (a|length) == 0 or (b|length) == 0 then ""
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user 0m0.427s
sys 0m0.005s</lang>
=={{header|Liberty BASIC}}==
<lang lb>
|