Long year: Difference between revisions

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(julia example)
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Most years have 52 weeks, some have 53, according to [https://en.wikipedia.org/wiki/ISO_week_date#Weeks_per_year ISO8601].
Most years have 52 weeks, some have 53, according to [https://en.wikipedia.org/wiki/ISO_week_date#Weeks_per_year ISO8601].
Write a function which determines if a given year is long (53 weeks) or not, and demonstrate it.
Write a function which determines if a given year is long (53 weeks) or not, and demonstrate it.


=={{header|Julia}}==
<lang julia>using Dates

has53weeks(year) = week(Date(year, 12, 28)) == 53

println(" Year 53 weeks?\n----------------")
for year in 1990:2021
println(year, " ", has53weeks(year) ? "Yes" : "No")
end
</lang>{{out}}
<pre>
Year 53 weeks?
----------------
1990 No
1991 No
1992 Yes
1993 No
1994 No
1995 No
1996 No
1997 No
1998 Yes
1999 No
2000 No
2001 No
2002 No
2003 No
2004 Yes
2005 No
2006 No
2007 No
2008 No
2009 Yes
2010 No
2011 No
2012 No
2013 No
2014 No
2015 Yes
2016 No
2017 No
2018 No
2019 No
2020 Yes
2021 No
</pre>





Revision as of 23:14, 9 January 2020

Long year is a draft programming task. It is not yet considered ready to be promoted as a complete task, for reasons that should be found in its talk page.

Most years have 52 weeks, some have 53, according to ISO8601. Write a function which determines if a given year is long (53 weeks) or not, and demonstrate it.


Julia

<lang julia>using Dates

has53weeks(year) = week(Date(year, 12, 28)) == 53

println(" Year 53 weeks?\n----------------") for year in 1990:2021

   println(year, "   ", has53weeks(year) ? "Yes" : "No")

end

</lang>

Output:
 Year  53 weeks?
----------------
1990   No
1991   No
1992   Yes
1993   No
1994   No
1995   No
1996   No
1997   No
1998   Yes
1999   No
2000   No
2001   No
2002   No
2003   No
2004   Yes
2005   No
2006   No
2007   No
2008   No
2009   Yes
2010   No
2011   No
2012   No
2013   No
2014   No
2015   Yes
2016   No
2017   No
2018   No
2019   No
2020   Yes
2021   No


Perl 6

Works with: Rakudo version 2019.11

December 28 is always in the last week of the year. (By ISO8601) <lang perl6>sub is-long ($year) { Date.new("$year-12-28").week[1] == 53 }

  1. Testing

say "Long years in the 20th century:\n", (1900..^2000).grep: *.&is-long; say "\nLong years in the 21st century:\n", (2000..^2100).grep: *.&is-long; say "\nLong years in the 22nd century:\n", (2100..^2200).grep: *.&is-long;</lang>

Output:
Long years in the 20th century:
(1903 1908 1914 1920 1925 1931 1936 1942 1948 1953 1959 1964 1970 1976 1981 1987 1992 1998)

Long years in the 21st century:
(2004 2009 2015 2020 2026 2032 2037 2043 2048 2054 2060 2065 2071 2076 2082 2088 2093 2099)

Long years in the 22nd century:
(2105 2111 2116 2122 2128 2133 2139 2144 2150 2156 2161 2167 2172 2178 2184 2189 2195)

Ruby

<lang ruby> require 'date'

def long_year?(year = Date.today.year)

 Date.new(year, 12, 28).cweek == 53

end

(2020..2030).each{|year| puts "#{year} is long? #{ long_year?(year) }." } </lang>

Output:
2020 is long? true.
2021 is long? false.
2022 is long? false.
2023 is long? false.
2024 is long? false.
2025 is long? false.
2026 is long? true.
2027 is long? false.
2028 is long? false.
2029 is long? false.
2030 is long? false.